Homeschool · Diploma track · Grade 9

Biology: The Living Earth

A full year of high school biology for grade 9, built to be the student's whole course in the subject rather than a supplement. California teaches biology as The Living Earth, which means the organism is never studied on its own: every idea is followed out to the ecosystem it sits in and back down to the molecule it runs on. Eleven units take the year from how biological evidence works through ecosystems, cells, DNA, inheritance and evolution to a planet that is measurably changing. Every claim in this course is tied to the evidence for it, because a biology student who can recite a mechanism but cannot say how anyone found it out has learned the wrong thing.

DIPLOMA TRACK CA NGSS LIVING EARTH GRADE 9 MODEL ANSWERS 75 LESSONS 860 PRACTICE QUESTIONS 6 ESSAY PROMPTS None. This is a complete course and does not assume other instruction.

Course overview

What this year covers

California's high school biology course is called The Living Earth, and the name is the syllabus. The state's three-course science model puts biology first, in grade nine, and folds Earth system content into it, so photosynthesis is taught as the thing that built the atmosphere and the carbon cycle is taught as the thing human beings are currently changing. The eleven units follow that logic. The year opens with how biological evidence actually works, because a student who cannot tell a controlled experiment from an anecdote cannot evaluate anything that follows. It then works outside in: ecosystems and the flow of energy, populations, the cycles of matter, then down into the cell, the molecule and the gene, and back out to evolution, speciation and a changing planet. Every performance expectation in HS-LS1 through HS-LS4 is covered, along with the Earth and human sustainability standards California includes in this course. Every lesson ends with ten questions, every unit with a ten-question review, and the year with six pieces of scientific writing that have full model responses.

  • U1Unit 1: How Biology Knows Things7 lessons
  • U2Unit 2: Ecosystems, Energy and Trophic Structure7 lessons
  • U3Unit 3: Populations and Communities7 lessons
  • U4Unit 4: Matter Cycles and the Earth System6 lessons
  • U5Unit 5: Cells, Membranes and Transport7 lessons
  • U6Unit 6: Energy in the Cell7 lessons
  • U7Unit 7: DNA, Genes and Proteins7 lessons
  • U8Unit 8: Cell Division, Meiosis and Variation6 lessons
  • U9Unit 9: Inheritance7 lessons
  • U10Unit 10: Evolution, Mechanism and Evidence7 lessons
  • U11Unit 11: Speciation, Biodiversity and a Changing Planet7 lessons

All eleven units are open, 75 lessons in all. Every lesson opens with the method, one extended worked example, and ten practice problems. Every problem has a full worked solution, so you can find the step where yours went wrong. Each unit closes with a ten-problem mixed review.

Free preview: open any 5 lessons without an account. The counter on the left keeps track.

Lesson 1.1 · Unit 1 · NGSS practice 1

What makes a question scientific, and what biology cannot settle

Biology can tell you how many offspring a population produces, which allele a child inherited, and what happens to a leaf kept in the dark for a week. It cannot tell you whether a wolf is more valuable than a sheep. The difference is not that one question is harder. It is that only one of them names an observation that could come out either way.

The key ideas
  1. A testable question names an observation you could actually make and specifies what would count as each possible answer.
  2. An untestable question is not a bad question. Questions of value, ethics and meaning are real questions; they are simply not settled by measurement, and science claiming to settle them is science overreaching.
  3. A hypothesis proposes a mechanism and predicts an observation. "Plants grow taller with fertilizer" is a prediction. "Plants grow taller with fertilizer because nitrogen is required to build proteins" is a hypothesis: it says why, so it can be wrong in an informative way.
  4. A hypothesis must be falsifiable. You must be able to state, before you collect data, which result would make you abandon it. If no possible result would, you are not testing anything.
  5. Comparative words need a criterion. "Is this plant healthier?" means nothing until health is defined as height, mass, leaf count or seed yield. Fixing the criterion is part of writing the question.
  6. Observation and experiment answer different questions. An observational study records what is already there. An experiment changes one thing on purpose. Only the second can support a claim about cause.

Where students lose marks: calling any sentence a hypothesis. A hypothesis is not a topic ("my hypothesis is fertilizer") and not a restatement of the question. It is a proposed explanation, stated so that a specific result would contradict it.

Worked example

The task. Turn the vague question "Is fertilizer good for plants?" into something a fourteen year old with a windowsill could actually answer.

Step one: find the word doing no work. "Good" is undefined. Good for what? Taller stems, greener leaves, more seeds and longer life are different outcomes, and fertilizer could improve one while harming another.

Step two: choose one measurable outcome. Pick stem height in centimeters after fourteen days. It is easy to measure, it is a number rather than a judgment, and two people measuring the same plant will agree.

Step three: name the thing you will change. Presence of fertilizer: one group gets the recommended dose, one group gets none. Everything else stays the same, which is the subject of lesson 1.2.

Step four: write the question. "Does adding the recommended dose of a nitrogen fertilizer increase the mean stem height of radish seedlings after fourteen days, compared with no fertilizer?" Every word is now checkable.

Step five: write the hypothesis, with a mechanism. "Adding nitrogen fertilizer increases mean stem height, because nitrogen is a component of the amino acids a seedling needs to build new tissue, and the soil supply limits growth." The clause after "because" is what makes it a hypothesis.

Step six: state what would falsify it. If the fertilized group's mean height is the same as or lower than the unfertilized group's, the hypothesis as stated is wrong. Writing this down before collecting data is what stops you explaining away whatever you get.

Step seven: notice what the study still cannot tell you. It cannot tell you whether using the fertilizer is a good idea. That depends on cost, on runoff into a nearby pond, and on what you want the plants for. Those are real considerations, and the experiment is silent on all of them.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What two things must a testable question name?
    Show the full solution

    An observation you could actually make, and what would count as each possible answer

  2. What does a hypothesis have that a prediction does not?
    Show the full solution

    A proposed mechanism: it says why, not only what will happen

  3. What does it mean for a hypothesis to be falsifiable?
    Show the full solution

    You can state in advance a possible result that would show it is wrong

  4. Which type of study can support a claim about cause, and why?
    Show the full solution

    An experiment, because the investigator changes one thing on purpose rather than recording what is already there

  5. Rewrite "Is this soil better?" so that it is measurable.
    Show the full solution

    Any version that fixes a criterion, for example "Does this soil produce a greater mean dry mass of bean plants after thirty days?"

  6. "Some species are more important than others." Explain why biology cannot settle this, and what it can contribute.
    Show the full solution

    Importance is a judgment about value, and no measurement returns a value. Biology can measure how many other species depend on a given one, what happens to a community when it is removed, and how much of an ecosystem process it performs, all of which are real and relevant findings. But turning those numbers into "more important" requires deciding what we are trying to protect and why, which is a question about goals rather than about organisms. Science informs the decision without making it. Value is not measurable, though the consequences that inform the judgment are

  7. A student writes: "My hypothesis is that I will test whether light affects algae." Explain what is wrong with it and fix it.
    Show the full solution

    This states an intention, not an explanation. It predicts nothing, so no result could contradict it, and a claim that cannot be contradicted teaches nothing when the data arrive. A hypothesis must propose a mechanism and commit to an outcome. A corrected version: "Increasing light intensity increases the rate of oxygen production in pond algae, because light supplies the energy for the light-dependent reactions of photosynthesis, and light is the limiting factor at low intensity." It states an intention rather than a falsifiable explanation

  8. Why is it important to write down the falsifying result before collecting data?
    Show the full solution

    Because afterwards it is very easy to reinterpret whatever happened as support. If the fertilized plants grow less, an investigator who has not committed in advance can decide the dose was wrong, the season was unusual or the effect takes longer, and keep the hypothesis regardless of the evidence. Fixing the falsifying result first means the data get a genuine chance to overturn the idea, which is the only way a test is informative. It prevents reinterpreting any outcome as support after the fact

  9. A study finds that towns with more veterinarians have more cases of a cattle disease. Explain why this does not show that veterinarians cause the disease.
    Show the full solution

    Nothing was changed on purpose, so this is an observational study and a third factor can produce both patterns at once. Towns with more cattle will have both more veterinarians and more cases of a cattle disease, and herd size is doing the work in both columns. The two measurements rise together without either causing the other. Distinguishing the possibilities requires either holding herd size constant or changing veterinarian numbers deliberately, which nobody would do. A third factor, herd size, produces both patterns

  10. Give a question about photosynthesis that biology can answer and one it cannot, and say what makes the difference.
    Show the full solution

    Answerable: "Does raising carbon dioxide concentration from 0.04 percent to 0.10 percent increase the rate of oxygen production in pond weed at constant light and temperature?" It names a change, a measurement and a comparison. Not answerable by measurement: "Should we raise carbon dioxide concentration in greenhouses?" That depends on cost, on energy use and on what else the greenhouse is for. The difference is that the first specifies an observation that could come out either way, while the second requires weighing goods against each other. The first names a possible observation; the second requires a value judgment

Lesson 1.2 · Unit 1 · NGSS practice 3

Variables, controls, and the shape of a fair test

An experiment is an argument with a hole in it, and the hole is every difference between your groups that you did not intend. If the fertilized seedlings also sat closer to the window, the experiment cannot separate fertilizer from light, and no amount of careful measuring afterwards repairs it. Controlling variables is not tidiness. It is the entire logic of the method.

The key ideas
  1. The independent variable is the one thing you deliberately change. There is exactly one per experiment.
  2. The dependent variable is what you measure to see whether the change mattered. It depends on the independent variable, which is where the name comes from.
  3. Controlled variables are everything else you deliberately hold the same: temperature, light, water, soil, the age of the seeds. These are not "the control".
  4. The control group is the group that does not receive the treatment, and it exists to tell you what would have happened anyway. Without it you cannot tell a real effect from normal growth.
  5. A confounding variable is one that changes along with your independent variable. It makes the result uninterpretable rather than merely imprecise, because two explanations fit the data equally well.
  6. Blind measurement protects the dependent variable. If the person measuring knows which group is which, expectation quietly shifts borderline readings.

Where students lose marks: confusing "the control" with "the controlled variables". The control is a group; controlled variables are conditions. Naming the constants when asked for the control group loses the point outright.

Worked example

The investigation. Does temperature affect the germination rate of radish seeds? The figures below are constructed so the arithmetic is checkable.

Step one: name the independent variable. Temperature. Two levels: 20 degrees Celsius and 30 degrees Celsius. One variable, deliberately changed.

Step two: name the dependent variable. The percentage of seeds that germinate within five days. Percentage rather than count, so that dishes with different seed numbers could still be compared.

Step three: list the controlled variables. Same seed batch and age, 50 seeds per dish, same volume of water (10 mL), same dish and paper, same darkness, same five day window. Each is a thing that could change germination on its own.

Step four: identify the control group. Here the 20 degree dish is the comparison condition, representing ordinary room temperature. It answers "what would have happened without the warming".

Step five: read the results. At 20 degrees, 44 of 50 seeds germinate, which is 88 percent. At 30 degrees, 47 of 50 germinate, which is 94 percent. The difference is 6 percentage points.

Step six: introduce a confound and watch the argument collapse. Suppose the 30 degree dish had been given 15 mL of water instead of 10 mL. The warmer dish is now also the wetter dish. Higher germination could come from either, and the data cannot separate them. The experiment has not become less accurate; it has become unable to answer its own question.

Step seven: state the conclusion at the right strength. With the confound removed, the fair statement is that germination was 6 percentage points higher at 30 degrees in this trial. Whether that difference is larger than ordinary variation between dishes is a separate question, and it is the subject of lesson 1.3.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. How many independent variables should an experiment have?
    Show the full solution

    Exactly one

  2. What is the difference between the control group and the controlled variables?
    Show the full solution

    The control group is a group that goes untreated; controlled variables are conditions held the same across all groups

  3. Define a confounding variable.
    Show the full solution

    A variable that changes along with the independent variable, so two explanations fit the results equally well

  4. In the worked example, name the dependent variable and its units.
    Show the full solution

    Percentage of seeds germinating within five days, in percent

  5. Why is measurement sometimes done without knowing which group is which?
    Show the full solution

    Because expectation shifts borderline readings when the measurer knows what result is hoped for

  6. A student waters one tray daily and another every three days, and also places the daily tray on a warmer shelf. Explain precisely what is wrong.
    Show the full solution

    Two things differ between the trays: watering frequency and temperature. If the daily tray grows better, the cause could be the extra water, the extra warmth, or both acting together, and the data cannot distinguish them. This is a confound rather than sloppiness, because collecting more measurements from the same setup will not help. The fix is to put both trays on the same shelf so that watering frequency is the only deliberate difference. Two variables changed together, so the result has two equally good explanations

  7. Why does an experiment need a control group at all, if the treated group is measured carefully?
    Show the full solution

    Because a measurement on its own has nothing to be compared against. Radish seedlings grow whether or not you add fertilizer, so observing that the treated plants reached 18 cm tells you nothing until you know what untreated plants reached in the same fortnight. The control group supplies that baseline, and it must experience everything the treated group experiences except the treatment itself, so that the difference between them can be attributed to one cause. It supplies the baseline showing what would have happened anyway

  8. A drug trial gives the treatment group a tablet and the control group nothing at all. Explain the flaw and how to fix it.
    Show the full solution

    The groups differ in two ways: the drug, and the experience of being given and taking a tablet. The second can change reported outcomes on its own through expectation, so improvement cannot be assigned to the drug. The fix is to give the control group an identical tablet containing no active ingredient, so that the only difference between the groups is the substance being tested, and ideally to keep both patients and assessors unaware of who received which. Taking a tablet is itself a difference; give the control an inactive one

  9. In the germination example, why report a percentage rather than the number of seeds?
    Show the full solution

    A count depends on how many seeds were placed in the dish, so 44 germinating means something quite different out of 50 than out of 200. Converting to a percentage removes that dependence and makes dishes with different seed numbers directly comparable, both within this experiment and against anyone else's results. It also makes the comparison easier to state: 88 percent against 94 percent is immediately readable in a way that 44 against 47 is not, once the denominators differ. Percentages stay comparable when the number of seeds differs

  10. Design a fair test of whether soil pH affects bean seedling height. Name each variable type.
    Show the full solution

    Independent variable: soil pH, set at several levels such as 5, 6, 7 and 8 using buffered solutions. Dependent variable: mean stem height in centimeters after twenty one days. Controlled variables: seed variety and batch, number of seeds per pot, soil type and volume, water volume and frequency, light and temperature, and pot position rotated to even out any bench effects. The pH 7 pots serve as the comparison condition since that is ordinary soil, and every pH level needs several pots so that variation between pots can be judged. pH is independent, height is dependent, everything else is held constant across several replicate pots

Lesson 1.3 · Unit 1 · NGSS practice 4

Sample size, variation, and why one organism proves nothing

Two plants of the same variety, grown side by side in the same soil with the same water, will not reach the same height. That is not experimental error. Living things vary, and the variation is as real as the average. Any conclusion drawn from a single organism is a conclusion about that organism.

The key ideas
  1. Biological variation is signal, not noise. Individuals of a species differ genetically and developmentally, and that difference is the raw material evolution acts on. It cannot be eliminated, only accounted for.
  2. A sample of one tells you about one. With no measure of how much individuals normally differ, you cannot tell whether a gap between two organisms is caused by your treatment or is ordinary.
  3. Replication means repeating the measurement on different individuals, not measuring the same plant three times. Measuring one plant repeatedly tells you about your ruler.
  4. The mean summarizes the center and is the sum of the values divided by how many there are.
  5. The spread matters as much as the mean. The range is the largest value minus the smallest. Two groups with identical means and very different spreads are not the same result.
  6. Overlapping spreads weaken a claim. If the tallest untreated plant is taller than the shortest treated plant, the groups overlap, and a difference in means needs more individuals before it can be trusted.

Where students lose marks: reporting a mean with no indication of spread, then treating a small difference as established. "The treatment group was taller" is not a finding until you say by how much and how much the individuals varied.

Worked example

The data. Five bean seedlings per group, height in centimeters after fourteen days. The figures are constructed so the arithmetic is checkable.

GroupHeights (cm)
No fertilizer1214111315
Fertilizer1621141920

Step one: find each mean. Untreated: 12 plus 14 plus 11 plus 13 plus 15 is 65, and 65 divided by 5 is 13.0 cm. Treated: 16 plus 21 plus 14 plus 19 plus 20 is 90, and 90 divided by 5 is 18.0 cm.

Step two: state the difference. The treated mean is 5.0 cm greater, which is an increase of about 38 percent over 13.0 cm.

Step three: find each range. Untreated runs from 11 to 15, a range of 4 cm. Treated runs from 14 to 21, a range of 7 cm.

Step four: check whether the groups overlap. The tallest untreated plant is 15 cm and the shortest treated plant is 14 cm, so the groups overlap between 14 and 15 cm. One treated plant is shorter than three untreated ones.

Step five: say what the overlap does and does not mean. It does not mean the fertilizer had no effect. It means that if you had grown one plant per group and happened to pick the 15 cm untreated plant and the 14 cm treated plant, you would have concluded the opposite. The mean difference survives the overlap; a single comparison would not have.

Step six: notice that the treated group varies more. Its range is nearly twice the untreated range. That is itself a result worth reporting: the fertilizer may help some individuals far more than others, which a mean alone hides.

Step seven: state the conclusion honestly. In this trial, the fertilized group had a mean height 5.0 cm greater, with more variation between individuals and some overlap between the groups. Five plants per group is a small sample, and repeating with more plants would be the obvious next step.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Calculate the mean of 4, 7, 7, 10 and 12.
    Show the full solution

    The sum is 40, and 40 divided by 5 is 8.0

  2. What is the range of that set?
    Show the full solution

    12 minus 4, which is 8

  3. What does replication mean in an experiment?
    Show the full solution

    Repeating the measurement on different individuals, not remeasuring the same one

  4. In the worked example, which group varied more, and by how much?
    Show the full solution

    The fertilized group, with a range of 7 cm against 4 cm

  5. Why is measuring one plant three times not replication?
    Show the full solution

    It measures the precision of your ruler, not the variation between individuals

  6. Two groups both have a mean height of 15 cm. Group A ranges from 14 to 16 cm and group B from 4 to 26 cm. Explain why these are not the same result.
    Show the full solution

    The means are identical but the groups behave completely differently. In group A every individual is close to 15 cm, so the mean describes each plant well and a prediction about a new plant would be reliable. In group B individuals range from very small to very large, so the mean describes almost nobody and predicting a new plant from it would be nearly worthless. The spread tells you how much the mean can be trusted as a summary, which is why reporting it is not optional. The mean summarizes group A well and group B badly

  7. A student concludes that a plant food works because their treated plant grew 3 cm taller than their untreated plant. Explain the flaw.
    Show the full solution

    With one plant in each group there is no way to know how much two untreated plants would have differed from each other. Ordinary variation between individuals of the same variety can easily produce a 3 cm gap, as the worked example shows, where untreated plants ranged across 4 cm with no treatment at all. The comparison cannot separate an effect of the plant food from normal variation, so the conclusion is unsupported regardless of how carefully the two plants were measured. One plant per group gives no measure of ordinary variation

  8. Explain why increasing the number of individuals per group strengthens a conclusion.
    Show the full solution

    Each individual carries its own random departure from the group's typical value, and those departures partly cancel when averaged. With more individuals the mean of the sample sits closer to the value that would be obtained from the whole population, so the same measured difference between groups becomes less likely to have arisen from an unlucky selection of individuals. Larger samples also give a better picture of the spread itself, which is what a claim about a difference has to be judged against. Random individual differences cancel out, so the sample mean is a better estimate

  9. The treated group in the worked example contained one plant shorter than three untreated plants. Does this refute the conclusion? Explain.
    Show the full solution

    No. The claim is about the average effect on a group, not a promise that every treated individual will exceed every untreated one. Individuals vary for many reasons at once, including seed quality and position, and the treatment shifts the distribution rather than setting each plant's height. A single overlapping individual is exactly what an overlapping range describes. What the overlap does mean is that a conclusion drawn from one plant per group would have been unreliable, which is an argument for larger samples rather than against the finding. The claim concerns group means, and overlap between individuals is expected

  10. Explain why biological variation should not be described as experimental error.
    Show the full solution

    Experimental error is a failure of measurement or procedure that better technique could reduce, such as a misread ruler or an unevenly watered tray. Variation between individuals is not a failure at all: organisms of the same species genuinely differ in their genes and their development, and they would still differ under perfect technique. Treating that variation as error suggests it could be removed, when in fact it is the material natural selection acts on and one of the central facts of the subject. It is a real property of living things, not a flaw in the method

Lesson 1.4 · Unit 1 · NGSS practice 4

Reading biological data, and the graph that misleads

A graph is an argument in a picture, and like any argument it can be made honestly or dishonestly with the same true numbers. The skill this lesson builds is boring and valuable: describe what the data do before you explain why, and check the axes before you believe the shape.

The key ideas
  1. Describe before you explain. First say what the values do (rise, fall, peak, level off, and by how much). Only then say why. Students who explain first usually describe a trend the data do not show.
  2. Match the graph type to the data. A line graph needs a continuous independent variable such as time or distance. Separate categories take a bar chart, and joining category bars with a line implies values in between that do not exist.
  3. The independent variable goes on the horizontal axis, the dependent on the vertical, both labeled with units.
  4. A truncated vertical axis exaggerates. Starting the scale at 95 rather than 0 can turn a two percent difference into a picture of a cliff. Always read where the axis begins.
  5. Quote figures when you describe. "Oxygen fell from 8.2 to 2.4 milligrams per liter over the first two kilometers" is a description. "Oxygen went down" is not.
  6. A trend is not a mechanism. The graph shows what happened; the explanation comes from biology you bring to it.

Where students lose marks: writing "the graph increases". The graph does not increase; the measured quantity does. Name the variable, give the direction, and quote the numbers with units.

Worked example

The data. Dissolved oxygen measured downstream of a sewage outfall. The figures are constructed so the pattern is clear.

Distance downstream (km)0124816
Dissolved oxygen (mg/L)8.23.12.44.06.58.0

Step one: choose the graph type. Distance is continuous, so a line graph is right. Distance goes on the horizontal axis, dissolved oxygen on the vertical, both with units.

Step two: describe the overall shape. Oxygen falls steeply, reaches a minimum, then recovers. The curve is a sag, and naming the shape before the numbers helps organize the description.

Step three: quantify the fall. From 8.2 mg/L at the outfall to 2.4 mg/L at 2 km: a drop of 5.8 mg/L, which is about 71 percent of the starting value, across only two kilometers.

Step four: locate the minimum and the recovery. The lowest value, 2.4 mg/L, occurs at 2 km. By 16 km oxygen has returned to 8.0 mg/L, close to the 8.2 mg/L measured at the outfall itself.

Step five: note that the recovery is slower than the fall. Oxygen loses 5.8 mg/L in 2 km but needs 14 km to regain 5.6 mg/L. Describing the asymmetry is the part most students miss.

Step six: now explain. Organic matter in sewage feeds bacteria, whose aerobic respiration consumes dissolved oxygen faster than the river can absorb it from the air. As the organic matter is used up downstream, bacterial numbers fall, consumption drops below the rate of reaeration, and oxygen climbs back. Every part of this explanation comes from biology, not from the graph.

Step seven: check how the axis could mislead. Plotted from 0 to 10 mg/L the sag is dramatic and honest. Plotted from 2 to 9 mg/L it would look catastrophic; plotted from 0 to 100 it would look like nothing happened. The numbers are identical in all three.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Which axis carries the independent variable?
    Show the full solution

    The horizontal axis

  2. When is a bar chart correct rather than a line graph?
    Show the full solution

    When the independent variable is separate categories rather than a continuous quantity

  3. In the worked example, what is the minimum oxygen value and where does it occur?
    Show the full solution

    2.4 mg/L at 2 km downstream

  4. By how much does oxygen fall between 0 and 2 km?
    Show the full solution

    From 8.2 to 2.4 mg/L, a fall of 5.8 mg/L

  5. What is wrong with the sentence "the graph increases"?
    Show the full solution

    The graph does not increase; the measured quantity does, and it must be named with units

  6. Explain how starting a vertical axis at 95 rather than 0 can mislead, without any number being false.
    Show the full solution

    Every plotted value can be perfectly accurate while the picture is misleading, because the eye judges the size of a difference from the height of the bars or the steepness of the line rather than from the numbers. If two values are 96 and 98 and the axis runs from 95 to 100, the second bar appears three times the height of the first, suggesting a large effect where the real difference is about two percent. Nothing is fabricated; the scale has simply been chosen to magnify. The eye reads relative heights, which a truncated scale exaggerates

  7. Why is describing the trend before explaining it worth the extra sentence?
    Show the full solution

    Because an explanation offered first tends to determine what you think you see. A student who begins with "bacteria used up the oxygen" will often describe a steady decline and miss the recovery entirely, since the explanation they reached for does not include one. Describing first forces the actual shape into view, including the parts that need accounting for, and it is also how these questions are marked: the description and the explanation earn separate credit. Explaining first makes you describe the data you expected rather than the data present

  8. The recovery takes far longer than the fall. Suggest a biological reason.
    Show the full solution

    The fall is driven by bacterial respiration, which is fast because the sewage supplies a large concentrated pulse of organic matter and bacterial populations can grow rapidly. The recovery depends on oxygen dissolving back into the water from the atmosphere, which happens only at the surface and at a rate set by turbulence and surface area rather than by biology. A fast biological process removes the oxygen and a slow physical process replaces it, so the curve is steep going down and gradual coming back. Fast bacterial consumption against slow physical reaeration

  9. A student joins the tops of four bars showing mean masses of four different species with a line. Explain why this is wrong.
    Show the full solution

    A line asserts that values exist between the plotted points, so joining the bars claims there are organisms partway between two species with intermediate masses. Species are separate categories, not points on a continuous scale, and the order of the bars is arbitrary, so the line's slope carries no meaning and would change if the bars were rearranged. A bar chart keeps the categories distinct, which is the honest representation of this kind of data. A line implies intermediate values, and species are discrete categories

  10. What could you not conclude from this graph alone, even though the pattern is clear?
    Show the full solution

    You could not conclude that the sewage outfall caused the oxygen sag, because nothing was changed on purpose and no comparison river was measured. The pattern is consistent with that explanation, but an unmeasured factor changing along the same stretch, such as a change in depth, flow rate or temperature, could also lower oxygen. Supporting the causal claim would need either upstream measurements, a comparable river without an outfall, or records from before the outfall existed. That the outfall caused the sag, since nothing was controlled or compared

Lesson 1.5 · Unit 1 · NGSS practice 7

Claim, evidence and reasoning: the structure biology grades

Most biology answers that lose marks are not wrong. They are incomplete in the same place every time: the student states an answer, quotes a number, and stops, leaving the reader to work out why the number supports the answer. That missing sentence has a name, and writing it deliberately is a learnable skill.

The key ideas
  1. The claim answers the question in one sentence. It is a position, not a description of what you did.
  2. The evidence is specific data that bear on the claim: values, units, comparisons, and where they came from. "The results showed a difference" is not evidence.
  3. The reasoning states the biological principle that makes the evidence count as support. This is the sentence students omit.
  4. Evidence must be selected, not dumped. Quoting every number you collected is not evidence; choosing the ones that bear on the claim is.
  5. A strong answer names what the evidence cannot show. Stating a limit is not weakness; it is the difference between a conclusion and an overclaim.
  6. The test for reasoning: could a reader who accepts your numbers still reject your claim? If so, the reasoning is missing.

Where students lose marks: restating the evidence in different words and calling it reasoning. "The treated group was taller, which shows the fertilizer made them taller" repeats the data. Reasoning explains the mechanism that connects the two.

Worked example

The task. Using the river data from lesson 1.4, answer: what happened to dissolved oxygen downstream of the outfall, and why?

Step one: write a weak answer first, so the gap is visible. "Oxygen went down and then went back up because of the sewage." This has a claim buried in it, almost no evidence, and no mechanism.

Step two: write the claim. "Dissolved oxygen fell sharply immediately downstream of the outfall and recovered gradually over the following fourteen kilometers."

Step three: select the evidence. Three figures carry the argument: 8.2 mg/L at the outfall, a minimum of 2.4 mg/L at 2 km, and 8.0 mg/L by 16 km. The intermediate values at 1, 4 and 8 km support the shape but are not all needed.

Step four: write the evidence sentence with units. "Oxygen fell from 8.2 mg/L at the outfall to a minimum of 2.4 mg/L at 2 km, a loss of 5.8 mg/L, then rose to 8.0 mg/L by 16 km."

Step five: write the reasoning, naming the biology. "Sewage supplies organic matter that bacteria use as an energy source. Aerobic respiration by the growing bacterial population consumes dissolved oxygen faster than it dissolves in from the atmosphere, so the concentration falls. Downstream the organic matter has been used up, bacterial numbers and oxygen demand fall, and reaeration restores the concentration."

Step six: apply the test. Could a reader accept the three figures and still deny the claim? Before step five, yes: the numbers alone are equally consistent with a change in water temperature. After step five the mechanism links the outfall to the shape, and the argument holds together.

Step seven: state the limit. "These data are consistent with the outfall causing the sag but do not establish it, since no upstream or comparison measurements were taken and no variable was controlled." This sentence earns credit rather than losing it.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Name the three parts of the structure.
    Show the full solution

    Claim, evidence, reasoning

  2. Which part do students most often leave out?
    Show the full solution

    The reasoning

  3. What makes a statement evidence rather than description?
    Show the full solution

    Specific values with units, selected because they bear on the claim

  4. State the test for whether reasoning is present.
    Show the full solution

    Could a reader accept the evidence and still reject the claim? If so, reasoning is missing

  5. Why does naming a limit earn credit?
    Show the full solution

    It distinguishes a supported conclusion from an overclaim

  6. Explain why "the treated plants were taller, which shows the fertilizer worked" contains no reasoning.
    Show the full solution

    The second clause repeats the first in different words rather than connecting it to any biology. It does not say what fertilizer contains, what a plant uses that substance for, or why a shortage of it would limit height, so a reader who accepts the heights is given no principle for preferring the fertilizer explanation over better light or better drainage. Reasoning would supply that principle: nitrogen is needed to build amino acids and proteins, and where soil nitrogen limits growth, adding it allows more tissue to be built. It restates the evidence instead of naming the mechanism

  7. Write a claim, evidence and reasoning answer for the germination data in lesson 1.2 (88 percent at 20 degrees, 94 percent at 30 degrees).
    Show the full solution

    Claim: germination was higher at the warmer temperature in this trial. Evidence: 47 of 50 seeds germinated at 30 degrees Celsius, which is 94 percent, against 44 of 50 at 20 degrees, which is 88 percent, a difference of 6 percentage points. Reasoning: germination depends on enzyme-controlled reactions that mobilize the seed's stored food, and raising the temperature toward the enzymes' optimum increases the frequency of successful collisions between enzyme and substrate, so the reactions proceed faster and more seeds reach germination within the five day window. Limit: with one dish per temperature there is no measure of variation between dishes. Claim, then figures with units, then the enzyme mechanism, then the limit

  8. Why is quoting every number collected a weakness rather than thoroughness?
    Show the full solution

    Because selecting evidence is itself part of the argument, and a reader cannot tell which figures you think matter if you supply all of them equally. An answer that lists twelve values has not shown that it knows which two carry the claim, and it buries the comparison that does the work. Choosing the starting value, the minimum and the recovery value demonstrates understanding of the shape of the result, whereas reproducing the table demonstrates only that the table exists. Selection shows which data bear on the claim; a data dump hides it

  9. A student claims a pond is polluted because they found few fish. Identify what is missing and supply it.
    Show the full solution

    The claim has almost no evidence and no reasoning. Evidence would need specific figures, such as the number of fish per sampling effort compared with a similar unpolluted pond, along with a measurement bearing directly on pollution such as dissolved oxygen or nitrate concentration. Reasoning would then have to connect them: many pollutants raise the growth of bacteria or algae whose respiration lowers dissolved oxygen below the level fish require, so a low oxygen reading alongside low fish numbers supports the claim in a way that fish numbers alone cannot. Both a comparative measurement and the oxygen mechanism linking it to fish numbers

  10. Explain why a good answer says what its evidence cannot establish.
    Show the full solution

    Because the strength of a conclusion is part of the conclusion, and claiming more than the data support is a specific error rather than enthusiasm. Observational data can show that two things occur together but cannot by themselves rule out a third factor or a reversed direction of cause, and an answer that says so is demonstrating exactly the judgment the question tests. It also directs the reader to what would settle the matter, which is the next step in any real investigation. Stating the strength of a conclusion is part of drawing it

Lesson 1.6 · Unit 1 · NGSS practice 2

Models in biology: what they are for, and where each one breaks

A food chain is not a claim that foxes eat only rabbits. A Punnett square is not a claim that exactly three of four offspring will be tall. Both are models: deliberate simplifications kept because they make something predictable. A model you cannot criticize is a model you do not understand.

The key ideas
  1. A model is a simplification built for a purpose. It keeps the features that matter for one question and discards the rest, which is what makes it useful rather than what makes it wrong.
  2. Physical models are things you can handle: a cell made of gelatin, a plastic DNA helix, a beaker standing for a lake.
  3. Mathematical models use equations or arithmetic to predict a quantity: exponential growth, the ten percent rule, the Lincoln index.
  4. Conceptual models are diagrams and schemes: food webs, the carbon cycle, a phylogenetic tree.
  5. Every model carries assumptions, and naming them is part of using it. Exponential growth assumes unlimited resources; the biological species concept assumes sexual reproduction.
  6. A model is judged by whether it predicts well enough for the purpose, not by whether it is realistic. A perfectly realistic model of an ecosystem would be the ecosystem.

Where students lose marks: treating a model's simplification as an error to be pointed out for credit. Saying "a food chain is unrealistic" earns nothing. Saying "a food chain cannot show that a fox also eats beetles, so it understates how a fox population would survive losing rabbits" is the answer.

Worked example

The model. The food chain: grass → rabbit → fox. Examine it as a model rather than as a fact.

Step one: state what it is for. It shows the direction of energy transfer through a sequence of organisms, and it makes the trophic position of each one explicit. That is a narrow purpose, and for that purpose it works.

Step two: state what it predicts. Remove the grass and both other populations must fall. Energy entering the fox is a small fraction of that entering the rabbit. Both predictions are correct and neither is obvious without the model.

Step three: name the assumptions. That each organism occupies one trophic level, that each eats only the organism below it, and that no energy enters or leaves except along the arrows.

Step four: find a case the model handles badly. A fox that also eats beetles and berries occupies more than one trophic level at once. The chain cannot represent this, so it will overstate how badly a fox population suffers when rabbits decline.

Step five: find a second failure. The chain has no decomposers, so matter appears to leave the system at the fox and never return. As a model of energy flow that is acceptable; as a model of matter cycling it is simply wrong, which is why unit 4 needs different diagrams.

Step six: choose the repair that suits the purpose. For the question "what happens to foxes if rabbits decline", replace the chain with a food web, which keeps alternative prey. For "how much energy reaches the top", keep the chain, because the extra links would obscure the arithmetic.

Step seven: state the general rule. The right question about a model is never "is it true" but "is it adequate for this purpose, and where does it fail". Every model in this course will be introduced with that pair of questions.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Name the three kinds of model and give an example of each.
    Show the full solution

    Physical (a gelatin cell), mathematical (exponential growth), conceptual (a food web)

  2. What assumption does exponential growth make?
    Show the full solution

    That resources are unlimited

  3. By what standard is a model judged?
    Show the full solution

    Whether it predicts well enough for its purpose, not whether it is realistic

  4. Give one thing the grass to rabbit to fox chain cannot represent.
    Show the full solution

    An organism feeding at more than one trophic level, or the decomposers

  5. Why is "this model is unrealistic" not an answer?
    Show the full solution

    All models simplify; the answer must name the specific prediction the simplification gets wrong

  6. Explain why a more realistic model is not automatically a better model.
    Show the full solution

    Adding detail costs clarity and usually costs predictive power that can actually be used. A food web including every species in a meadow would be more realistic than a four-link chain and far less useful for calculating how much energy reaches the top consumer, because the arithmetic would be buried in hundreds of arrows whose values nobody has measured. A model earns its detail only when that detail changes the answer to the question being asked, which is why the purpose has to be fixed first. Detail that does not change the answer costs clarity for nothing

  7. A Punnett square predicts a 3 to 1 ratio, but a cross produces 26 tall and 14 short. Explain whether the model has failed.
    Show the full solution

    No. The square models probability per offspring, not a guaranteed tally, so the prediction is that each offspring has a three in four chance of being tall, and departures from the exact ratio are expected in small samples. Forty offspring predicts thirty tall and ten short; twenty six and fourteen is a plausible outcome of chance around that expectation, in the same way that forty coin tosses rarely give exactly twenty heads. The model would be in trouble if large samples consistently departed from three to one, which is how non-Mendelian patterns were discovered. It predicts probabilities, and small samples vary around them

  8. Why must the assumptions of a model be stated when the model is used?
    Show the full solution

    Because the assumptions define the conditions under which the model's predictions can be trusted, and a reader cannot judge a conclusion without them. Exponential growth predicts a population will double indefinitely, which is correct only while resources remain unlimited, so applying it to a population near its carrying capacity produces a confident and wildly wrong forecast. Stating the assumption tells the reader where the boundary is and signals when a different model is needed. They set the conditions under which the prediction is valid

  9. Suggest a case the biological species concept handles badly, and say why that does not make it useless.
    Show the full solution

    It defines a species by the ability to interbreed and produce fertile offspring, so it cannot be applied to bacteria, which reproduce asexually, or to organisms known only as fossils, where no breeding test is possible. That does not make it useless: for sexually reproducing living animals it captures exactly the boundary that matters, because populations that exchange genes evolve together and populations that do not diverge. A tool with a stated domain is useful inside it. It fails for asexual and fossil organisms but works where gene flow is the relevant boundary

  10. You want to know how quickly a disease will spread through a school. What kind of model would you use, and what would you have to assume?
    Show the full solution

    A mathematical model, since the question asks for a rate and a number infected over time rather than a description. It would have to assume something about how many people each infected person contacts per day, the probability that a contact transmits, how long a person stays infectious, and that mixing is reasonably even across the school. Each assumption is a place the prediction could fail, particularly even mixing, since friendship groups and year groups make contact far from random. A mathematical model, assuming contact rate, transmission probability, infectious period and even mixing

Lesson 1.7 · Unit 1 · NGSS crosscutting concept 3

Scale and measurement, from the molecule to the biosphere

This course will ask you to move between a water molecule and the Pacific Ocean in a single lesson, and the moves only work if the sizes mean something to you. Biology spans about eighteen orders of magnitude, and almost every important constraint in the subject comes from something being too big or too small for a process to work.

The key ideas
  1. An order of magnitude is a factor of ten. Two things differing by three orders of magnitude differ by a factor of a thousand.
  2. The prefixes you need: milli is one thousandth, micro is one millionth, nano is one billionth. A millimeter is 1000 micrometers; a micrometer is 1000 nanometers.
  3. The working sizes: a water molecule is a fraction of a nanometer, DNA is about 2 nanometers across, a typical bacterium is 1 to 2 micrometers long, a typical animal cell is 10 to 100 micrometers, and the smallest thing an unaided eye resolves is about 100 micrometers.
  4. Surface area and volume do not scale together. Double a cube's side and its surface area rises fourfold while its volume rises eightfold, so the ratio of surface to volume halves.
  5. That ratio governs exchange. Everything entering or leaving a cell crosses its surface, while everything needing supply is in its volume, which is why cells are small and why unit 5 returns to this.
  6. Always carry the units. A number without units is not a measurement, and most arithmetic mistakes in this course are unit mistakes.

Where students lose marks: writing that a cell is "small" or a molecule "very small". These are not measurements. Give a figure with a unit, or a comparison with a factor: "a bacterium is roughly ten times shorter than a typical animal cell".

Worked example

The question. Why can a cell not simply grow larger when it needs more resources? Work the arithmetic on cubes, which behave like cells for this purpose.

Step one: take a cube of side 1 cm. Surface area is 6 faces times 1 times 1, which is 6 square centimeters. Volume is 1 times 1 times 1, which is 1 cubic centimeter.

Step two: form the ratio. 6 divided by 1 is 6. For every unit of volume there are 6 units of surface.

Step three: double the side to 2 cm. Surface area is 6 times 2 times 2, which is 24 square centimeters. Volume is 2 times 2 times 2, which is 8 cubic centimeters. The ratio is 24 divided by 8, which is 3.

Step four: double again to 4 cm. Surface area is 6 times 4 times 4, which is 96 square centimeters. Volume is 4 times 4 times 4, which is 64 cubic centimeters. The ratio is 96 divided by 64, which is 1.5.

Step five: read the pattern. Each doubling of the side halves the surface to volume ratio: 6, then 3, then 1.5. Surface grows with the square of the side while volume grows with the cube.

Step six: connect it to the cell. Oxygen, glucose and waste all cross the membrane, whose area is the surface. The demand for them is set by the living material inside, which is the volume. As a cell grows, demand outruns supply, and beyond some size the center cannot be served.

Step seven: state the consequences you will meet later. Cells divide rather than enlarge; cells specialized for absorption are folded or projecting to raise area without raising volume; and large organisms need transport systems because they cannot rely on diffusion across an outer surface.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. How many nanometers are in one micrometer?
    Show the full solution

    1000

  2. Give the approximate length of a typical bacterium.
    Show the full solution

    About 1 to 2 micrometers

  3. A cube has a side of 3 cm. Find its surface area, volume and ratio.
    Show the full solution

    Surface area 54 square centimeters, volume 27 cubic centimeters, ratio 2

  4. What happens to the surface to volume ratio as an object gets larger?
    Show the full solution

    It decreases

  5. Why is "a cell is very small" not an acceptable answer?
    Show the full solution

    It is not a measurement; give a figure with units or a comparison with a factor

  6. A typical animal cell is about 20 micrometers across and DNA is about 2 nanometers wide. How many orders of magnitude separate them?
    Show the full solution

    Convert to the same unit first. 20 micrometers is 20000 nanometers, and DNA is 2 nanometers, so the cell is 10000 times wider. Ten thousand is ten to the fourth power, so they differ by four orders of magnitude. Doing the conversion before the division is the whole of the method here, and mixing micrometers with nanometers is the commonest way to get an answer wrong by a factor of a thousand. Four orders of magnitude, a factor of 10000

  7. Explain why the small intestine is lined with millions of projections.
    Show the full solution

    Absorption happens across a surface, and the quantity of food to be absorbed is set by the volume of the gut contents, so a smooth tube of that diameter would present far too little area for the demand. Folding the lining into villi and covering those in microvilli raises the surface area enormously without increasing the volume of the organ, which is the same trick as increasing a cube's surface without increasing its bulk. The ratio, not the absolute area, is what the problem is about. It raises surface area without raising volume, improving the exchange ratio

  8. Why do very large organisms need circulatory systems while a single-celled one does not?
    Show the full solution

    A single-celled organism has a high surface to volume ratio and a very short distance from its membrane to any point inside, so diffusion alone delivers oxygen and removes waste fast enough. As body size rises, the ratio falls and the distances grow, and diffusion becomes hopelessly slow over centimeters rather than micrometers. A circulatory system solves both problems at once by moving fluid in bulk to within diffusion distance of every cell, which is why size and transport systems appear together across the animal kingdom. Falling surface to volume ratio and longer diffusion distances make diffusion alone insufficient

  9. Two cells are cubes of side 10 and 20 micrometers. Which meets its needs more easily, and by what factor do their ratios differ?
    Show the full solution

    The smaller one. For side 10 micrometers the surface area is 600 and the volume 1000 in consistent units, giving a ratio of 0.6. For side 20 the surface is 2400 and the volume 8000, giving 0.3. The ratios differ by a factor of two, so the smaller cell has twice as much membrane serving each unit of its contents and can supply its interior more easily, which is the general reason cells divide rather than continuing to grow. The smaller cell, with twice the surface per unit volume

  10. Why does this course insist on units at every step?
    Show the full solution

    Because a number in biology is meaningless without them and because carrying them catches mistakes automatically. Writing 20 when the figure is 20 micrometers and comparing it with 2 nanometers produces an answer wrong by a factor of a thousand, and the error is invisible until the units are restored. Units also make an answer checkable by someone else, which matters when a result is going to be used, and they force you to notice when a calculation has produced something in the wrong kind of quantity altogether. Units give a number meaning and catch conversion errors automatically

Unit 1 review · How Biology Knows Things

Ten questions across the whole unit

Questions 1 to 5 check that you hold the terms. Questions 6 to 10 require you to reason across the seven lessons.

  1. What must a testable question specify?
    Show the full solution

    An observation you could make, and what would count as each possible answer

  2. Name the three kinds of variable in a controlled experiment.
    Show the full solution

    Independent, dependent and controlled

  3. Calculate the mean and range of 6, 9, 9, 12 and 14.
    Show the full solution

    The sum is 50, so the mean is 10.0; the range is 14 minus 6, which is 8

  4. Name the three parts of a claim, evidence and reasoning answer.
    Show the full solution

    The claim, the evidence, and the reasoning that links them

  5. A cube has a side of 5 cm. Give its surface area, volume and ratio.
    Show the full solution

    Surface area 150 square centimeters, volume 125 cubic centimeters, ratio 1.2

  6. A student tests fertilizer but also moves the treated tray to a sunnier shelf. Explain why collecting more data will not rescue the experiment.
    Show the full solution

    Two variables changed together, so any difference between the trays has two equally good explanations and the data cannot distinguish them. This is a confound rather than imprecision: more measurements from the same setup produce a more precise estimate of an uninterpretable difference. The only remedy is to redesign so that fertilizer is the single deliberate difference, which is why controlling variables has to happen before data collection rather than after. A confound cannot be fixed by more data, only by redesign

  7. Explain why a mean should always be reported with some measure of spread.
    Show the full solution

    The mean alone does not say how well it describes the individuals it summarizes. Two groups can share a mean of 15 cm while one ranges from 14 to 16 and the other from 4 to 26, and in the second the mean describes almost nobody. Spread also determines whether a difference between two group means can be trusted, since heavily overlapping groups need larger samples before a gap in the means means anything. Spread shows how well the mean represents the group and whether a difference is trustworthy

  8. Explain why describing a trend before explaining it is worth the extra sentence.
    Show the full solution

    An explanation reached for first tends to determine what you think you see, so a student who begins with a mechanism often describes the data that mechanism predicts rather than the data present, and misses features such as a recovery or an asymmetry that need accounting for. Describing first forces the actual shape into view. It also matches how such questions are marked, since description and explanation earn separate credit. Explaining first makes you describe expected data rather than actual data

  9. A model of a food chain omits decomposers. Explain when this matters and when it does not.
    Show the full solution

    It does not matter for tracing energy through the grazing pathway, which is what a chain is built to show, and adding decomposers would clutter that calculation. It matters enormously for any question about matter, because without decomposers the diagram implies nutrients leave the system at the top consumer and never return, which is false. The rule from lesson 1.6 applies: ask whether the simplification changes the answer to the question being asked. Fine for energy flow through the grazing chain, wrong for any question about matter cycling

  10. Why does this course insist on units at every step?
    Show the full solution

    A number without units is not a measurement, and carrying them catches mistakes automatically. Comparing 20 micrometers with 2 nanometers by treating both as bare numbers gives an answer wrong by a factor of a thousand, and the error is invisible until the units are restored. Units also make an answer checkable by someone else and force you to notice when a calculation has produced a quantity of the wrong kind altogether. Units give a number meaning and catch conversion errors automatically

Lesson 2.1 · Unit 2 · HS-LS2-3

Why life needs a constant energy input

A rock left alone stays a rock. An organism left alone dies, and then decays into simpler things. Staying alive means continuously rebuilding structures that are continuously falling apart, and rebuilding costs energy that has to come from somewhere outside the organism. Every ecosystem on earth is organized around that bill.

The key ideas
  1. Autotrophs make their own food from simple inorganic molecules. Photoautotrophs use light; chemoautotrophs use energy released by chemical reactions.
  2. Heterotrophs cannot, and must take in organic molecules built by something else. Every animal, every fungus and most bacteria are heterotrophs.
  3. Producers are the entry point. Energy enters an ecosystem only through autotrophs, which is why they are counted as the first trophic level.
  4. Nearly all of it is sunlight. Photosynthesis captures light energy as chemical energy in glucose, and almost every food web on the planet traces back to that step.
  5. Deep sea vents are the real exception. Chemoautotrophic bacteria oxidize hydrogen sulfide from the vent and build sugars with the energy released, supporting a community that never receives light.
  6. The capture is inefficient. Only a small percentage of the light falling on a plant ends up as chemical energy, because most is reflected, transmitted, or the wrong wavelength.

Where students lose marks: saying plants "get energy from the soil". Soil supplies water and mineral ions, both essential, but neither is an energy source. The energy comes from light, and the carbon comes from the air.

Worked example

The figures. Energy budget for one square meter of grassland over one year. The numbers are constructed so the arithmetic is checkable, and the efficiency they give is the right order of magnitude for temperate grassland.

QuantityEnergy (kJ per square meter per year)
Sunlight reaching the ground1,000,000
Captured by photosynthesis (gross)10,000
Used in plant respiration4,000

Step one: find the capture efficiency. 10,000 divided by 1,000,000 is 0.01, which is 1 percent. Ninety nine percent of the arriving light never becomes chemical energy at all.

Step two: account for the missing 99 percent. Some is reflected off leaf surfaces, some passes straight through, some falls on bare soil between plants, and much of it is at wavelengths chlorophyll does not absorb, which is exactly why leaves look green: green light is the part being rejected.

Step three: subtract the plant's own running costs. The plant respires to stay alive, using 4,000 kJ. What remains is 10,000 minus 4,000, which is 6,000 kJ stored as new plant material.

Step four: identify what is available to the next level. Only that 6,000 kJ, the new growth, can be eaten. The energy already spent on respiration has left the ecosystem as heat and cannot be recovered by anything.

Step five: state the fraction reaching a herbivore. 6,000 out of the original 1,000,000 of sunlight is 0.6 percent. Before a single animal has eaten anything, more than 99 percent of the energy is gone.

Step six: draw the consequence. This is why producers must outweigh consumers, why the sun must keep shining rather than delivering one large deposit, and why an ecosystem cut off from its energy source collapses within a season rather than continuing to recycle.

Step seven: check the vent community against the same logic. At a hydrothermal vent the entry point is chemical rather than light, but the structure is identical: autotrophs capture energy from outside the community, everything else eats them or each other, and the supply must be continuous.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Define an autotroph.
    Show the full solution

    An organism that makes its own organic molecules from inorganic ones, using light or chemical energy

  2. Through what kind of organism does energy enter almost every ecosystem?
    Show the full solution

    A producer, which is an autotroph, usually photosynthetic

  3. What energy source supports a hydrothermal vent community?
    Show the full solution

    Chemical energy from compounds such as hydrogen sulfide, used by chemoautotrophic bacteria

  4. In the worked example, what percentage of sunlight is captured by photosynthesis?
    Show the full solution

    1 percent, since 10,000 divided by 1,000,000 is 0.01

  5. How much energy is available to herbivores in the worked example, and why is it less than the amount captured?
    Show the full solution

    6,000 kJ, because 4,000 kJ was used in the plant's own respiration

  6. Explain why a plant is not "getting energy from the soil", and say what the soil does supply.
    Show the full solution

    Soil supplies water and dissolved mineral ions such as nitrate, magnesium and phosphate, all of which the plant genuinely needs, but none of them is an energy source: the plant cannot release useful energy by taking up a nitrate ion. The energy for building sugars comes from light absorbed by chlorophyll, and the carbon comes from carbon dioxide in the air. Minerals are raw materials for particular molecules, magnesium for chlorophyll itself and nitrogen for amino acids, which is a different role from fueling the process. Soil supplies raw materials, not energy; light supplies the energy

  7. Why must an ecosystem's energy supply be continuous, when its matter can be used over and over?
    Show the full solution

    Because every energy transfer within the ecosystem loses some energy as heat, and heat disperses into the surroundings where no organism can capture it again. Matter behaves differently: a carbon atom released as carbon dioxide can be fixed again by a plant tomorrow, so the same atoms circulate indefinitely. Energy makes a one way trip from the sun through the organisms and out as heat, so unless it keeps arriving the system runs down. Energy degrades to heat and leaves; matter stays and can be reused

  8. A grassland captures 1 percent of the light that falls on it. Explain why this is not evidence that plants are poorly built.
    Show the full solution

    Most of the loss is not the plant's failure. A large share of the light misses leaves entirely and lands on soil, much of the rest is at wavelengths no pigment absorbs, and some passes through thin leaves or reflects off waxy surfaces. Of the light that is actually absorbed by chlorophyll, the conversion is far more efficient than one percent. The figure describes the whole field including its gaps and its unusable wavelengths, not the performance of the biochemical machinery. Most light never reaches a pigment, so the field figure understates the process

  9. Suppose a cave community receives no light and no chemical energy source, but does receive organic debris washed in from outside. Is it an ecosystem with no producers? Explain.
    Show the full solution

    It is a community with no producers of its own, which is possible only because it is not a closed system. The organic debris was built by producers somewhere else, usually plants on the surface, so the energy still entered the biosphere through photosynthesis and has simply been imported. Such communities exist and are entirely dependent on that import: interrupt the inflow and they starve, because nothing inside the cave can fix energy from non-living sources. Its energy is imported from producers elsewhere, so it depends on them

  10. Why are producers counted as the first trophic level rather than the sun?
    Show the full solution

    Trophic levels describe feeding relationships among organisms, and the sun is not an organism and is not eaten. The producers are the first living step, the point at which energy becomes stored in organic molecules that something else can consume, so counting begins there. The distinction also keeps the levels meaningful: every subsequent level is defined by what it eats, and there is no sense in which a plant eats the sun. Trophic levels count feeding relationships, and the sun is neither an organism nor eaten

Lesson 2.2 · Unit 2 · HS-LS2-3, HS-LS2-4

Trophic levels, food chains and food webs

A food chain is a sentence about who eats whom. A food web is the paragraph that admits most organisms eat several things and are eaten by several others. Both are models, in the sense of lesson 1.6, and knowing which to use depends entirely on the question you are asking.

The key ideas
  1. A trophic level is a feeding position, not a species. Level one is producers, level two primary consumers, level three secondary consumers, level four tertiary consumers.
  2. The arrow means "energy flows to". Grass → rabbit means the rabbit eats the grass. Students reverse this constantly, and a reversed arrow is marked wrong.
  3. Herbivore, carnivore and omnivore describe diet; primary and secondary consumer describe position. An omnivore occupies more than one trophic level at once.
  4. A food web shows alternative routes, which is what lets it predict the effect of removing one species. A chain cannot do this.
  5. The same species can sit at different levels in different chains within one web, which is why "what trophic level is a fox" often has no single answer.
  6. Webs are always incomplete. Even a detailed web omits most species, especially decomposers and parasites, and states nothing about how much energy each arrow carries.

Where students lose marks: drawing arrows from the consumer to the food, as if the arrow meant "eats". The arrow follows the energy. If you can say the sentence "energy passes from the grass to the rabbit", the arrow points at the rabbit.

Worked example

The web. A simplified meadow community, written as a list of feeding relationships so the structure is unambiguous.

OrganismEats
Grass and wildflowersnothing (producers)
Grasshoppergrass
Rabbitgrass, wildflowers
Shrewgrasshopper
Kestrelshrew, grasshopper
Foxrabbit, shrew

Step one: place the producers. Grass and wildflowers are trophic level one. Every path in the web starts here, because this is where energy enters.

Step two: place the primary consumers. Grasshopper and rabbit eat only producers, so both are level two, regardless of how different they are as animals.

Step three: follow one complete chain. Grass → grasshopper → shrew → kestrel. That is four links, and the kestrel is a tertiary consumer at level four in this chain.

Step four: show the kestrel in a second chain. Grass → grasshopper → kestrel makes the kestrel a secondary consumer at level three. Same bird, same day, different trophic level, because the level depends on the route and not on the species.

Step five: use the web to make a prediction. Remove the rabbit. The fox still has shrews, so it does not starve, but shrew numbers should fall under heavier predation, which should in turn relieve pressure on grasshoppers. A food chain containing only grass → rabbit → fox would have predicted the fox collapsing.

Step six: find the indirect effect. If grasshoppers become more numerous because shrews are scarce, grazing pressure on grass rises, and the producers are affected by the loss of a herbivore that never ate grasshoppers. Webs make effects like this visible; chains hide them.

Step seven: state what the web still cannot tell you. It carries no quantities. It does not say whether rabbits were 5 percent or 90 percent of the fox's diet, so the size of every prediction above is unknown. That is the job of the next two lessons.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What does an arrow in a food web mean?
    Show the full solution

    That energy flows in the direction of the arrow, from the food to the consumer

  2. Which trophic level do producers occupy?
    Show the full solution

    The first

  3. In the worked example, name the two primary consumers.
    Show the full solution

    The grasshopper and the rabbit

  4. Give a four-link chain from the worked example.
    Show the full solution

    Grass → grasshopper → shrew → kestrel

  5. What is the difference between a carnivore and a secondary consumer?
    Show the full solution

    Carnivore describes diet; secondary consumer describes feeding position in a particular chain

  6. Explain how one bird can be both a secondary and a tertiary consumer at the same time.
    Show the full solution

    Trophic level is a property of a feeding route rather than of a species. The kestrel eating a grasshopper is three steps from the grass, making it a secondary consumer on that route, while the kestrel eating a shrew that ate a grasshopper is four steps from the grass and a tertiary consumer on that one. Both happen in the same week, so the bird genuinely occupies both positions, and its average trophic level is somewhere between the two depending on how much of each prey it takes. Level depends on the route, and the kestrel feeds along two of them

  7. Why does a food web predict the effect of losing a species better than a food chain?
    Show the full solution

    Because a web contains the alternative routes that make a community resilient, and a chain by construction contains none. If the only model is grass → rabbit → fox, removing rabbits necessarily starves the fox, and the prediction is confident and wrong. The web shows the fox also takes shrews, so the realistic prediction is a shift in diet with knock-on effects further down, which is what actually happens in communities where most consumers have more than one prey species. Webs contain alternative routes, so they can model a shift rather than a collapse

  8. Removing the shrew could increase the amount of grass eaten. Explain the chain of reasoning.
    Show the full solution

    The shrew preys on grasshoppers, so removing it reduces the death rate of grasshoppers and their numbers should rise. Grasshoppers eat grass, so more of them means heavier grazing pressure and less grass. The effect travels two steps down the web from an animal that never touched a blade of grass, which is an indirect effect, and it is exactly the kind of prediction a food chain cannot generate because the chain does not show that the shrew and the grass are connected through anything. Fewer shrews means more grasshoppers, and grasshoppers eat grass

  9. A student draws the arrow as rabbit → grass and explains that the rabbit eats the grass. Explain why this is marked wrong.
    Show the full solution

    The convention is not arbitrary: the arrow represents the direction energy moves, and energy moves from the grass into the rabbit when the rabbit eats. Drawing it the other way states that energy flows from the rabbit into the grass, which is false and would make every trophic level in the diagram inverted. Because the whole point of the diagram is to trace energy through the community, a reversed arrow is not a labeling slip but a claim about the biology that is the opposite of the truth. The arrow tracks energy flow, and energy moves into the consumer

  10. What quantity is missing from every food web diagram, and why does it matter?
    Show the full solution

    The amount of energy or biomass passing along each arrow. Without it, every feeding link looks equally important, so a species that makes up ninety percent of a predator's diet is drawn exactly like one that makes up one percent. That makes the web useless for judging the size of an effect: it can say that losing rabbits will affect foxes but not whether the effect is trivial or catastrophic. Quantifying the arrows is what pyramids and productivity measurements in the next lessons are for. The size of each transfer, without which effect sizes cannot be judged

Lesson 2.3 · Unit 2 · HS-LS2-4

The ten percent rule, and why food chains are short

Roughly a tenth of the energy at one trophic level ends up in the level above. That single number explains why there are no herds of top predators, why eating plants feeds more people than eating beef, and why nothing on earth is a sixth level consumer.

The key ideas
  1. About 10 percent of the energy in one trophic level is incorporated into the next. The figure varies between about 5 and 20 percent, and ten is the working estimate.
  2. The other 90 percent has three destinations: it is released as heat by respiration, it is lost in undigested material such as feces, or it is in parts that are never eaten (bones, bark, roots).
  3. The loss is not a leak to be fixed. Respiration is what keeps the consumer alive, so the energy is not wasted; it is spent.
  4. Losses compound. Each step multiplies by about 0.1, so four steps leave about one thousandth of the original energy.
  5. This limits chain length. After four or five links the remaining energy cannot support a viable population of a fifth or sixth consumer.
  6. It also limits predator size and density, which is why top predators are rare, hold large territories and are the first species lost when an ecosystem shrinks.

Where students lose marks: saying the missing 90 percent is "lost" without saying where it went. Name the three routes: respiration as heat, egestion as undigested waste, and uneaten parts. "Lost" on its own earns nothing.

Worked example

The figures. Start with 10,000 kJ of energy stored in the producers of a small ecosystem, and apply a 10 percent transfer at each step.

Step one: producers to primary consumers. 10 percent of 10,000 is 1,000 kJ. Nine thousand kJ never reaches the herbivores.

Step two: primary to secondary consumers. 10 percent of 1,000 is 100 kJ.

Step three: secondary to tertiary consumers. 10 percent of 100 is 10 kJ.

Step four: consider a fourth consumer level. 10 percent of 10 is 1 kJ. One kilojoule cannot sustain an animal for a day, let alone a breeding population, which is why chains of six or seven links are not found.

Step five: state the compounding. From 10,000 kJ to 10 kJ is a factor of one thousand across three transfers, because 0.1 times 0.1 times 0.1 is 0.001. The losses multiply rather than adding.

Step six: run the argument backwards. To build 1 kg of tertiary consumer you need roughly 10 kg of secondary consumer, 100 kg of primary consumer and 1,000 kg of producer. The pyramid shape is forced by the arithmetic.

Step seven: apply it to a real decision. A field of grain fed directly to people delivers about ten times the energy it would deliver as beef, because the cattle spend most of it on their own respiration. That is why diet is a land use question, and the ten percent rule is the reason.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Roughly what fraction of energy passes to the next trophic level?
    Show the full solution

    About 10 percent

  2. Name the three destinations of the energy that does not pass on.
    Show the full solution

    Heat from respiration, undigested material egested as feces, and parts that are never eaten

  3. Starting from 50,000 kJ in producers, how much reaches the secondary consumers?
    Show the full solution

    500 kJ, since 10 percent of 50,000 is 5,000 and 10 percent of that is 500

  4. Why are food chains rarely longer than four or five links?
    Show the full solution

    Because the energy remaining after four or five transfers cannot support a viable population

  5. How much producer biomass roughly supports 1 kg of tertiary consumer?
    Show the full solution

    About 1,000 kg

  6. Explain why calling the missing 90 percent "wasted" is wrong.
    Show the full solution

    Most of it is spent rather than wasted. The largest share goes on respiration, which is the process that powers movement, growth, repair and every other activity that keeps the consumer alive, so an organism that did not lose that energy would be dead. Some is genuinely unavailable rather than misused, such as cellulose an animal cannot digest or bones it does not eat. Calling it waste implies an inefficiency that could be engineered away, when it is a direct consequence of being alive. It is spent on staying alive, chiefly through respiration

  7. Explain why top predators are rare and hold large territories.
    Show the full solution

    Their energy supply is what is left after three or four multiplications by about a tenth, so a very large area of producers stands behind each individual predator. A territory has to contain enough prey, which in turn requires enough of their food, and so on down to the plants, meaning the land needed per predator is roughly a thousand times the land needed per herbivore of the same mass. Low density and large ranges follow directly, and so does their vulnerability when habitat is fragmented. Compounding losses mean each predator needs a very large producer base

  8. A farmer can grow grain and sell it, or feed it to cattle and sell beef. Explain the energy argument.
    Show the full solution

    Feeding the grain to cattle inserts an extra trophic transfer between the crop and the person, and about ninety percent of the energy in the grain is spent on the cattle's own respiration, egested, or held in parts not eaten. The same field therefore delivers roughly ten times more food energy to people as grain than as beef. That is an argument about energy only: it says nothing about protein quality, about land that can support grazing but not crops, or about price, all of which bear on the real decision. Adding a trophic level costs about ninety percent of the energy

  9. Why do the losses multiply rather than add?
    Show the full solution

    Because each transfer takes its percentage of whatever arrives at that level, not of the original amount. The second transfer operates on the thousand kilojoules that survived the first, so it yields a hundred rather than subtracting another fixed quantity. Repeated proportional reductions are a multiplication, so three steps give 0.1 times 0.1 times 0.1, a thousandfold reduction rather than a thirty percent one. This is why chain length collapses the available energy so quickly. Each step takes a proportion of what remains, which compounds

  10. An ecosystem is measured and the transfer between two levels is 18 percent. Does this refute the ten percent rule? Explain.
    Show the full solution

    No, because the rule is a working approximation rather than a constant of nature, and measured values range from roughly five to twenty percent. Transfer efficiency depends on what is being eaten and by what: consumers of other animals digest a larger share of what they swallow than herbivores chewing cellulose, and warm-blooded animals spend far more on respiration than cold-blooded ones. An eighteen percent figure sits within the expected range and invites an explanation, which is how a model should behave. The rule is an approximation with a real range, and 18 percent sits within it

Lesson 2.4 · Unit 2 · HS-LS2-4

Ecological pyramids: energy, biomass and numbers

Three different pyramids get drawn for the same ecosystem, and they do not always agree. An energy pyramid can never be upside down. A numbers pyramid frequently is. Knowing which can invert, and why, is the whole content of this lesson.

The key ideas
  1. A pyramid of energy shows the energy passing through each trophic level over a period of time, usually kilojoules per square meter per year.
  2. A pyramid of biomass shows the mass of living material present at each level at one moment, usually grams per square meter.
  3. A pyramid of numbers shows how many individual organisms are present at each level, regardless of their size.
  4. The energy pyramid can never invert. A level cannot pass on more energy than it received, so each bar must be smaller than the one below.
  5. A numbers pyramid inverts easily, because it ignores size. One oak tree can support thousands of insects, giving a tiny bottom bar.
  6. A biomass pyramid can invert in the sea, because it is a snapshot. Fast-reproducing phytoplankton may have less mass at any instant than the zooplankton they support over time.

Where students lose marks: explaining an inverted biomass pyramid by saying "there are fewer plants". The point is turnover: the phytoplankton are replaced many times over during the period the zooplankton persist, so a snapshot of mass understates the supply.

Worked example

The case. Three pyramids for related communities. The figures are constructed so the comparison is clean.

LevelEnergy (kJ/m²/yr)Oak wood numbersOcean biomass (g/m²)
Producers10,00014
Primary consumers1,0005,00020
Secondary consumers100903

Step one: check the energy column. 10,000, then 1,000, then 100. Each level is a tenth of the one below, so the pyramid narrows upward. This is the only shape an energy pyramid can take.

Step two: explain why it cannot invert. Energy at a level comes entirely from the level below, and some is always lost as heat in respiration. A wider bar higher up would mean energy appearing from nowhere, which the first law of thermodynamics forbids.

Step three: read the oak wood numbers. One tree, 5,000 insects, 90 birds. The base is a single organism, so the pyramid is inverted at the bottom and upright above.

Step four: explain the inversion. A numbers pyramid counts organisms and ignores their size. One oak has an enormous mass and supports thousands of small insects, so counting heads gives a misleading picture of the energy relationship while remaining perfectly accurate as a count.

Step five: read the ocean biomass column. Phytoplankton 4 g/m², zooplankton 20 g/m², small fish 3 g/m². The bottom bar is narrower than the one above it, so this biomass pyramid is inverted.

Step six: explain the ocean inversion with turnover. Phytoplankton divide very rapidly and are eaten almost as fast as they are produced, so the standing mass present at any instant is small while the mass produced over a year is very large. The zooplankton live much longer and accumulate. A snapshot of mass therefore understates what the producers supplied.

Step seven: choose the right pyramid for the question. To compare the productivity of two ecosystems, use energy, because it is the only one that cannot mislead. Use numbers only when the question is genuinely about how many individuals there are.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What does a pyramid of energy measure, and in what units?
    Show the full solution

    Energy passing through each trophic level over time, in kilojoules per square meter per year

  2. Which pyramid can never be inverted?
    Show the full solution

    The pyramid of energy

  3. Give an example of an inverted pyramid of numbers.
    Show the full solution

    One oak tree supporting thousands of insects

  4. What does a pyramid of biomass measure?
    Show the full solution

    The mass of living material at each level at one moment in time

  5. In the worked example, what is the ocean phytoplankton biomass, and why is the pyramid inverted?
    Show the full solution

    4 g/m², and the pyramid inverts because phytoplankton are replaced very rapidly

  6. Explain, using thermodynamics, why an energy pyramid cannot invert.
    Show the full solution

    All the energy at a trophic level arrived from the level beneath it, and energy cannot be created within an organism. Every transfer also releases some energy as heat through respiration, and heat disperses where no organism can recapture it. A level therefore always passes on less than it received, so each bar must be narrower than the one below. An inverted energy pyramid would require a level to contain more energy than was supplied to it, which no biological process can achieve. Energy cannot be created, and each transfer loses some as heat

  7. Explain turnover, and why it lets a biomass pyramid invert.
    Show the full solution

    Turnover is the rate at which organisms in a level are replaced. Phytoplankton may divide once a day and be grazed almost immediately, so the population present at any instant is small even though the mass produced across a year is enormous. Zooplankton live for weeks and accumulate mass. Because a biomass pyramid is a snapshot rather than a measure of production, it captures the small standing crop rather than the large output, and can show less mass at the base than above it. Rapid replacement means a small standing mass supplies a large total production

  8. Why is a numbers pyramid the least useful of the three for comparing ecosystems?
    Show the full solution

    Because it treats every organism as equivalent regardless of size, so one oak counts the same as one aphid. Two ecosystems with identical energy flow can produce entirely different numbers pyramids depending only on whether their producers are large or small, which means the shape carries information about body size rather than about the ecosystem's function. Energy pyramids are comparable between ecosystems because a kilojoule is a kilojoule wherever it is measured. It ignores organism size, so its shape reflects body size rather than energy flow

  9. A student says an inverted biomass pyramid shows the ecosystem is failing. Explain why this is wrong.
    Show the full solution

    Inversion here is a normal feature of open water communities rather than a sign of collapse, and the ocean ones that invert are among the most productive systems on the planet. The inversion arises from the mismatch between a snapshot measurement and a rate: the producers are supplying plenty, they are simply being consumed almost as fast as they appear. Reading it as failure mistakes a property of the measurement for a property of the ecosystem, which is the error lesson 1.6 warns about. It reflects fast turnover, and such systems are highly productive

  10. You want to compare the productivity of a grassland and a forest. Which pyramid do you use and why?
    Show the full solution

    The pyramid of energy, because it measures the rate at which energy moves through each level over a stated period and so answers the question directly. A biomass pyramid would be badly misleading, since a forest holds enormous mass in wood that is not productivity but accumulated past growth, and a grassland with far less standing mass may fix comparable energy each year. A numbers pyramid would compare tree counts with grass plant counts, which bears on nothing. Energy, since it measures rate of flow rather than accumulated mass

Lesson 2.5 · Unit 2 · HS-LS2-3, HS-LS2-4

Decomposers and detritus: the part of the web students forget

Draw a food web from memory and you will almost certainly leave out the organisms that handle most of the material. In many ecosystems more energy passes through the decomposers than through all the grazing animals combined, and without them every nutrient in the system would be locked inside corpses within a few decades.

The key ideas
  1. Decomposers are organisms that feed on dead organic matter, chiefly bacteria and fungi. They secrete enzymes onto the material and absorb the products, which is extracellular digestion.
  2. Detritivores eat dead material in pieces rather than digesting it externally: earthworms, woodlice, dung beetles. They break material up, which increases the surface area available to decomposers.
  3. The detrital food web is a parallel system running alongside the grazing web, fed by leaf litter, dead wood, corpses and feces.
  4. Decomposers return nutrients to inorganic form. Nitrogen locked in protein becomes ammonium; carbon in tissue becomes carbon dioxide. Only in that form can producers take it up again.
  5. Without decomposition there is no matter cycle. Energy would still flow, but the elements would accumulate in dead bodies and the producers would starve of raw materials.
  6. Decomposition is respiration. Decomposers release carbon dioxide exactly as animals do, which makes them a significant term in the carbon budget of unit 4.

Where students lose marks: describing decomposers as organisms that "break things down and return energy to the soil". They return nutrients; the energy is released as heat through their own respiration and leaves the ecosystem like any other respiratory loss.

Worked example

The case. A deciduous woodland drops leaf litter each autumn. Follow one year's litter, using constructed figures that balance.

Fate of the year's litterEnergy (kJ/m²/yr)
Total litter falling6,000
Eaten by detritivores1,500
Decomposed by bacteria and fungi4,200
Remaining as accumulated humus300

Step one: check the accounting. 1,500 plus 4,200 plus 300 is 6,000, which matches the litter fall. Nothing has appeared or vanished, which is the test every energy budget must pass.

Step two: note the share taken by decomposers. 4,200 out of 6,000 is 70 percent. The bacteria and fungi handle far more of this material than the animals do.

Step three: compare with the grazing web. If the same woodland passed 1,000 kJ/m²/yr to its herbivores, then the 6,000 kJ going into litter is six times larger. Most of the energy fixed by a forest is never eaten alive.

Step four: follow the nutrients rather than the energy. The nitrogen in those leaves was in proteins and chlorophyll. Decomposers release it as ammonium, which nitrifying bacteria convert to nitrate, which roots absorb. The nitrogen is back in a tree within a season or two.

Step five: follow the energy instead, and see the difference. The 4,200 kJ the decomposers process is not returned to the soil in any usable form. It powers their own respiration and leaves as heat. Matter cycles; energy does not.

Step six: consider the accumulating fraction. The 300 kJ that resists decomposition builds up as humus, and over geological time material that escapes decomposition entirely is what became coal and oil. That link matters in unit 4.

Step seven: run the thought experiment. Remove the decomposers. Litter accumulates, nitrogen and phosphorus stay locked in undecayed tissue, producers become nutrient limited, and primary productivity falls. The ecosystem is strangled not by lack of energy but by lack of accessible matter.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Name the two main groups of decomposers.
    Show the full solution

    Bacteria and fungi

  2. What is extracellular digestion?
    Show the full solution

    Secreting enzymes onto material outside the body and absorbing the products

  3. How does a detritivore differ from a decomposer?
    Show the full solution

    It eats dead material in pieces rather than digesting it externally

  4. In the worked example, what percentage of litter is handled by bacteria and fungi?
    Show the full solution

    70 percent, since 4,200 divided by 6,000 is 0.7

  5. What form must nitrogen be in before a plant can absorb it?
    Show the full solution

    An inorganic ion such as nitrate or ammonium

  6. Explain why saying decomposers "return energy to the soil" is wrong.
    Show the full solution

    Decomposers respire the organic matter they consume, and respiration releases energy as heat that disperses into the surroundings where nothing can capture it. What returns to the soil is matter: ammonium, phosphate and other inorganic ions that producers can absorb. The confusion matters because it suggests energy circulates in an ecosystem, when the entire structure of this unit rests on energy making a one way trip and matter going round. They return nutrients; the energy leaves as heat from their own respiration

  7. Why does breaking litter into smaller pieces speed decomposition?
    Show the full solution

    Decomposers digest externally, so the rate depends on how much surface the secreted enzymes can act on. Fragmenting a leaf into many small pieces greatly increases total surface area without changing the mass, exactly the surface to volume relationship from lesson 1.7, so more enzyme can work at once and the material is processed faster. This is why detritivores such as earthworms and woodlice accelerate decomposition even though they digest relatively little of the material themselves. Fragmentation raises surface area for extracellular enzymes

  8. Predict what happens to a woodland over fifty years if its decomposers are removed but everything else continues.
    Show the full solution

    Leaf litter and dead wood accumulate instead of being processed, so the nitrogen, phosphorus and other nutrients held in that tissue are never returned to inorganic form. Soil nutrient concentrations fall as living plants continue to take up what remains, and primary productivity declines because producers become nutrient limited. Sunlight still arrives and photosynthesis still works in principle, so the ecosystem fails for want of accessible matter rather than for want of energy. Nutrients lock up in undecayed tissue and producers become nutrient limited

  9. In many forests more energy flows through the detrital web than the grazing web. Suggest why.
    Show the full solution

    Most of a tree's mass is wood, bark and root, which are structural, low in nutrients and difficult or impossible for herbivores to digest, so the great majority of what a forest produces is never eaten while alive. Leaves are shed rather than grazed in most years. All of that material eventually enters the system as dead organic matter, so the detrital pathway receives the bulk of the annual production while the grazing pathway receives the small palatable fraction. Most forest production is woody or shed rather than eaten alive

  10. How are decomposers connected to the existence of coal?
    Show the full solution

    Coal formed from plant material that escaped decomposition, typically because it was buried in waterlogged, oxygen-poor swamp conditions where decomposers could not respire it away. The carbon in that tissue was therefore removed from the fast biological cycle and locked into rock over geological time. Every carbon atom in coal is one that decomposers failed to return to the atmosphere, which is why burning it now releases carbon that has been out of circulation for hundreds of millions of years. Coal is carbon that decomposers never processed, buried out of circulation

Lesson 2.6 · Unit 2 · HS-LS2-3, HS-LS2-5

Primary productivity: gross, net, and what limits it

Productivity is a rate, not an amount. A forest holds a huge mass of wood accumulated over a century; a patch of open ocean holds almost nothing at any instant but may fix comparable carbon each year. Confusing the standing stock with the rate of production is the commonest error in this part of the course.

The key ideas
  1. Gross primary productivity (GPP) is the total energy fixed by producers in a given area and time.
  2. Net primary productivity (NPP) is what remains after the producers' own respiration: NPP equals GPP minus respiration.
  3. NPP is what supports everything else. Only the net figure is available to herbivores, decomposers and every level above.
  4. Productivity is a rate, measured per unit area per unit time, and is different from biomass, which is a standing quantity measured at an instant.
  5. On land the limits are usually temperature and water, which is why productivity falls from tropical forest through grassland to desert.
  6. In the sea the limits are usually light and mineral nutrients, which is why productivity is high where upwelling brings nutrients to lit surface water and low in the open ocean.

Where students lose marks: treating biomass as productivity. A mature forest can have enormous biomass and modest NPP, because most of its energy budget goes on respiring the living tissue it already has.

Worked example

The figures. Constructed so the arithmetic is checkable, with ratios chosen to show a real pattern.

EcosystemGPPRespirationNPP
Tropical forest90,00054,00036,000
Temperate forest60,00036,00024,000
Grassland30,00018,00012,000
Desert3,0002,100900
Open ocean5,0003,0002,000

All values in kJ per square meter per year.

Step one: confirm the relationship. For the tropical forest, 90,000 minus 54,000 is 36,000, which matches the NPP column. Check one other row to be sure: 30,000 minus 18,000 is 12,000 for grassland.

Step two: find the respiration fraction for the forests. 54,000 divided by 90,000 is 0.6, so the tropical forest respires 60 percent of what it fixes. The temperate forest and grassland give the same 60 percent.

Step three: find it for the desert. 2,100 divided by 3,000 is 0.7, so desert plants spend 70 percent of their gross production on respiration, a larger share than any other row.

Step four: explain the desert figure. High temperatures raise respiration rates, while water shortage forces stomata shut for much of the day and limits photosynthesis. The plant is paying more and earning less, so the net left over is very small.

Step five: compare the ocean with the desert. Open ocean NPP is 2,000, more than twice the desert's 900, even though the ocean is often called a biological desert. Per square meter it outproduces the land desert, and because it covers a vast area its total contribution is enormous.

Step six: separate rate from stock. The temperate forest has an NPP of 24,000 and holds decades of accumulated wood. The ocean has an NPP of 2,000 and holds almost no standing biomass, because its producers are microscopic and eaten within days. Neither figure predicts the other.

Step seven: name the limiting factors. Tropical forest is warm and wet, so neither temperature nor water limits it, and it tops the table. Desert is limited by water, and open ocean by nutrients in the lit surface layer. Ranking ecosystems is really ranking their constraints.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Write the relationship between GPP, NPP and respiration.
    Show the full solution

    NPP equals GPP minus respiration by the producers

  2. Which of the two is available to consumers?
    Show the full solution

    Net primary productivity

  3. A meadow has a GPP of 25,000 and respires 15,000 kJ/m²/yr. Find the NPP.
    Show the full solution

    10,000 kJ per square meter per year

  4. Name the two factors that usually limit productivity on land.
    Show the full solution

    Temperature and water availability

  5. Name the two that usually limit it in the ocean.
    Show the full solution

    Light and mineral nutrient supply

  6. Explain why a mature forest can have huge biomass and only moderate NPP.
    Show the full solution

    Biomass is accumulated over a century of past growth, while NPP measures only what is added this year. A mature forest carries an enormous mass of living wood, bark and roots, all of which respire, so a large share of the energy it fixes each year is spent simply maintaining tissue that already exists. The net addition is therefore modest relative to the standing stock. A young growing forest can have far less biomass and higher NPP, which shows the two quantities are independent. Biomass is accumulated stock; NPP is this year's rate, much of which goes on maintenance

  7. Why do desert plants spend a larger fraction of GPP on respiration than forest plants?
    Show the full solution

    Respiration rate rises with temperature, and deserts are hot, so the maintenance cost per unit of tissue is high. At the same time water shortage forces stomata to close for much of the day to limit transpiration, which also blocks carbon dioxide entry and suppresses photosynthesis. The plant therefore has an unusually high bill and an unusually constrained income, so the proportion of gross production consumed by respiration is larger, seventy percent against sixty in the worked figures. Heat raises respiration while closed stomata suppress photosynthesis

  8. The open ocean has low productivity per square meter but contributes a large share of global production. Explain.
    Show the full solution

    Productivity per unit area and total productivity are different quantities, and the ocean wins on area. Open ocean covers the majority of the planet's surface, so even a modest 2,000 kJ per square meter per year multiplied across that area gives an enormous total. Highly productive ecosystems such as tropical forest have far higher rates but occupy a small fraction of the surface. Global contribution is rate multiplied by area, and neither factor alone determines it. Total production is rate times area, and the ocean's area is vast

  9. An area of ocean near a coast is far more productive than open ocean at the same latitude. Suggest why.
    Show the full solution

    Coastal water receives mineral nutrients from rivers and from upwelling that brings deep nutrient-rich water into the lit surface layer, and it is shallow enough that nutrients released by decomposition on the bottom return to where photosynthesis happens. In the open ocean, material that sinks below the lit zone is effectively removed, so surface water becomes nutrient poor even though light is plentiful. Since nutrients rather than light are the limiting factor, the coastal supply raises productivity sharply. Coastal water gets nutrients from rivers and upwelling into the lit layer

  10. Would clearing a temperate forest and planting fast-growing crops raise or lower NPP? Explain what the answer depends on.
    Show the full solution

    It could do either, and the answer depends on how much of the year the ground carries growing plants and how the maintenance cost changes. A crop removes the large respiring mass of wood, which lowers the respiration term and can raise net production during the growing season. But cropland is often bare for months, fixing nothing, while the forest fixed energy for as long as its leaves were out. Comparing them requires annual totals rather than peak rates, plus any irrigation or fertilizer that lifts the crop's limits. Lower maintenance respiration against fewer growing days, so annual totals decide it

Lesson 2.7 · Unit 2 · HS-LS2-3, HS-LS2-4, HS-LS2-5

Energy flows, matter cycles: the distinction the unit rests on

These two sentences look similar and are not: energy moves through an ecosystem, and matter moves around one. Almost every confused answer in ecology comes from blurring them, and almost every clear answer comes from keeping them apart deliberately.

The key ideas
  1. Energy enters once, passes through, and leaves as heat. It makes a one way trip and cannot be reused, which is why the supply must be continuous.
  2. Matter is not created or destroyed within an ecosystem. The same atoms are used again and again, passing between organisms and the non-living environment.
  3. Respiration is where the two part company. It releases energy as heat, which leaves, and returns carbon as carbon dioxide, which stays available.
  4. Decomposers close the matter loop but not the energy loop. They return nutrients to inorganic form while respiring the energy away.
  5. An ecosystem is open to energy and closed to matter, at least approximately. Earth as a whole receives sunlight and loses heat, while its atoms stay put.
  6. The words match the concepts: energy flows, matter cycles. Using the wrong verb is usually marked as a conceptual error rather than a style problem.

Where students lose marks: writing that energy is recycled. Nothing recycles energy. If a sentence has energy going round, it is wrong, and this is one of the few errors that loses a mark every time it appears.

Worked example

The task. Follow one carbon atom and one packet of energy through the same events, and watch their paths diverge.

Step one: both begin together. A carbon dioxide molecule is fixed by a grass plant in photosynthesis. Light energy is captured at the same moment and stored in the chemical bonds of a glucose molecule containing that carbon atom.

Step two: a rabbit eats the grass. The carbon atom and the energy in its bonds both move into the rabbit, still traveling together. Roughly ninety percent of the energy in the grass does not make this journey, as lesson 2.3 showed.

Step three: the rabbit respires. Now they separate. The energy is released, some doing useful work in the rabbit's muscles, all of it eventually becoming heat. The carbon atom is exhaled as carbon dioxide.

Step four: follow the energy. The heat warms the rabbit and the air, disperses, and is radiated to space. No organism can collect it and put it back into a bond. Its part in the ecosystem is over.

Step five: follow the carbon. The carbon dioxide is in the atmosphere, available to any plant. It may be fixed again within days by the same patch of grass. The atom has completed a loop and is back where it started.

Step six: take the alternative route. Suppose the rabbit dies instead. Decomposers respire its tissue, which releases the energy as heat exactly as before and returns the carbon as carbon dioxide and the nitrogen as ammonium. Different path, same divergence.

Step seven: state the conclusion in the right words. Energy flowed from the sun through the grass and the rabbit and out as heat. Carbon cycled from the air through the grass and the rabbit and back to the air. One trip, one loop, and the same events described correctly twice.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Which verb goes with energy, and which with matter?
    Show the full solution

    Energy flows; matter cycles

  2. In what form does energy leave an ecosystem?
    Show the full solution

    As heat

  3. At which process do the paths of a carbon atom and its energy separate?
    Show the full solution

    Respiration

  4. Is an ecosystem open or closed with respect to energy?
    Show the full solution

    Open: energy enters as light and leaves as heat

  5. What do decomposers return, and what do they not return?
    Show the full solution

    They return nutrients in inorganic form; they do not return energy

  6. Explain why the sentence "energy is recycled in an ecosystem" is always wrong.
    Show the full solution

    Every transfer and every metabolic process converts some energy to heat, and heat disperses into the surroundings at a temperature no organism can exploit to do work. Recycling would require collecting that dispersed heat and rebuilding it into chemical bonds, which nothing in biology can do. The energy in an ecosystem is therefore a stream passing through rather than a pool going round, and it must be replenished continuously from outside, which is exactly why the sun cannot stop shining. Energy degrades to dispersed heat, which no organism can recapture

  7. A sealed glass sphere contains water, algae, a shrimp and bacteria, and sits on a windowsill. Explain why it can persist for years.
    Show the full solution

    It is closed to matter and open to energy, which is exactly the condition an ecosystem needs. Light passes through the glass continuously, so the algae can keep fixing energy, while the carbon, nitrogen and other atoms inside are recycled indefinitely between the algae, the shrimp and the bacteria. Nothing material has to enter or leave. Move it into a dark cupboard and it dies within weeks, not because matter ran out but because the energy supply was cut. Light keeps entering while the atoms inside cycle

  8. Why does the ten percent rule apply to energy but not to carbon atoms?
    Show the full solution

    The ten percent rule describes energy lost from the food chain at each transfer, principally as heat through respiration, and that heat genuinely leaves the system. Carbon atoms are not lost in the same sense: the ninety percent that does not enter the next trophic level is still present, as carbon dioxide breathed out, as feces feeding the detrital web, or in uneaten tissue that decomposers process. The energy is gone from the ecosystem; the carbon has merely taken a different route within it. Lost energy leaves as heat, while unpassed carbon stays in the system by another route

  9. Why is the earth as a whole a good example of this distinction?
    Show the full solution

    Almost no matter enters or leaves the planet, so every atom in every living thing has been used many times over and will be used again, which makes the global matter cycles genuinely closed loops. Energy behaves in the opposite way: sunlight arrives continuously and an equivalent amount of heat is radiated back to space, so the planet is a throughput system for energy. The biosphere runs on that steady stream rather than on any stored supply, which is the same structure as the sealed sphere on a larger scale. The planet is closed to matter and open to a continuous energy throughput

  10. Rewrite this sentence correctly: "Decomposers recycle the energy in dead organisms back to the plants."
    Show the full solution

    A correct version: "Decomposers release the energy in dead organisms as heat through their own respiration, and return the nutrients those organisms contained to inorganic forms such as ammonium and phosphate, which plants can absorb." The correction replaces energy with nutrients as the thing returned, names respiration as the fate of the energy, and specifies the inorganic forms, since dead tissue is not directly usable by a root. Each of those three changes fixes a separate error in the original. Nutrients are returned in inorganic form; the energy leaves as heat

Unit 2 review · Ecosystems, Energy and Trophic Structure

Ten questions across the whole unit

Questions 1 to 5 check that you hold the terms. Questions 6 to 10 require you to reason across the seven lessons.

  1. Define an autotroph and give the two energy sources they use.
    Show the full solution

    An organism making its own organic molecules from inorganic ones, using light or chemical energy

  2. What does an arrow in a food web represent?
    Show the full solution

    The direction of energy flow, from the food to the consumer

  3. Starting from 80,000 kJ in producers, how much reaches the tertiary consumers?
    Show the full solution

    80 kJ, since three transfers at 10 percent give 8,000 then 800 then 80

  4. Which ecological pyramid can never be inverted, and why?
    Show the full solution

    The energy pyramid, because a level cannot pass on more energy than it received

  5. Write the relationship between GPP, NPP and respiration.
    Show the full solution

    NPP equals GPP minus respiration by the producers

  6. Explain why the 90 percent that does not pass to the next trophic level should not be called wasted.
    Show the full solution

    Most of it is spent rather than wasted. The largest share powers respiration, which drives movement, growth, repair and every activity that keeps the consumer alive, so an organism that did not lose it would be dead. Some is genuinely unavailable rather than misused, such as cellulose that cannot be digested or bone that is not eaten. Calling it waste implies an inefficiency that could be engineered away. It is spent on staying alive, chiefly through respiration

  7. A biomass pyramid in open ocean is inverted. Explain without using the word fewer.
    Show the full solution

    The explanation is turnover rather than quantity. Phytoplankton divide very rapidly and are grazed almost as fast as they appear, so the mass present at any instant is small even though the mass produced across a year is enormous. Zooplankton live far longer and accumulate. Because a biomass pyramid is a snapshot rather than a measure of production, it captures the small standing crop and understates what the producers actually supplied. Rapid replacement means a small standing mass supplies a large total production

  8. Desert plants respire away 70 percent of their gross production against 60 percent in forests. Explain.
    Show the full solution

    Respiration rate rises with temperature, and deserts are hot, so the maintenance cost per unit of tissue is high. At the same time water shortage forces stomata to close for much of the day to limit transpiration, which also blocks carbon dioxide entry and suppresses photosynthesis. The plant therefore faces an unusually high bill and an unusually constrained income, so a larger proportion of gross production is consumed before anything is left over. Heat raises respiration while closed stomata suppress photosynthesis

  9. Explain why removing a predator can reduce the amount of plant material in an ecosystem.
    Show the full solution

    The predator's prey are usually herbivores, so removing the predator lowers their death rate and their numbers rise. More herbivores means heavier grazing pressure on the producers, so plant biomass falls. The effect travels two steps through the web from an animal that never ate a plant, which is an indirect effect that a food chain cannot generate because it does not show the connection between the predator and the vegetation. Fewer predators means more herbivores, which graze the producers more heavily

  10. Rewrite correctly: "Decomposers recycle the energy in dead organisms back to the plants."
    Show the full solution

    A correct version: decomposers release the energy in dead organisms as heat through their own respiration, and return the nutrients those organisms contained to inorganic forms such as ammonium and phosphate, which plants can absorb. The correction replaces energy with nutrients as the thing returned, names respiration as the fate of the energy, and specifies inorganic forms, since dead tissue is not directly usable by a root. Nutrients are returned in inorganic form; the energy leaves as heat

Lesson 3.1 · Unit 3 · HS-LS2-1

Measuring a population: density, dispersion and sampling

Nobody counts every rabbit in a meadow. Population ecology runs almost entirely on samples, which means the sampling method is not a detail before the biology starts; it is where most of the error lives. Two standard methods cover most cases, and each has assumptions that can be checked.

The key ideas
  1. A population is the individuals of one species in one area at one time, able to interbreed. Two ponds of the same fish are two populations unless fish move between them.
  2. Density is individuals per unit area or volume. It makes populations of different sizes comparable.
  3. Dispersion describes the pattern: clumped (the commonest, from patchy resources or social groups), uniform (from territoriality or competition), or random (rare, and it means individuals are ignoring each other).
  4. Quadrat sampling suits organisms that do not move. Place quadrats at random, count, take the mean per quadrat, and scale up to the total area.
  5. Mark and recapture suits mobile animals. Mark a first sample, release, then take a second sample and see what proportion carries marks.
  6. The Lincoln index is the estimate: total equals the number marked, multiplied by the size of the second sample, divided by the number of marked individuals recaptured.

Where students lose marks: forgetting the assumptions of mark and recapture. Marked animals must mix back into the population, the mark must not affect survival or capture, and nothing may be born, die, enter or leave between the samples. Naming these earns the marks; the arithmetic alone does not.

Worked example

Part one: quadrats. Ten quadrats of one square meter are placed at random in a 2,500 square meter field and the dandelions counted: 3, 5, 2, 4, 6, 3, 4, 5, 2, 6.

Step one: find the mean per quadrat. The counts total 40, and 40 divided by 10 is 4.0 dandelions per square meter.

Step two: scale to the field. 4.0 per square meter times 2,500 square meters gives an estimated 10,000 dandelions.

Step three: check the spread before trusting it. The counts run from 2 to 6, a range of 4 around a mean of 4, which is wide. With ten quadrats this is a rough estimate, and more quadrats would tighten it, exactly as lesson 1.3 argued.

Part two: mark and recapture. In a 4,000 square meter meadow, 60 voles are caught, marked and released. A week later 80 voles are caught, of which 15 carry marks.

Step four: apply the Lincoln index. Total equals 60 times 80 divided by 15. That is 4,800 divided by 15, which is 320 voles.

Step five: convert to a density. 320 divided by 4,000 square meters is 0.08 voles per square meter, which is the figure you would use to compare this meadow with another of different size.

Step six: test the logic of the index. Marked animals made up 60 out of the whole population. In the second sample they made up 15 out of 80, which is 18.75 percent. If that sample is representative, then 60 is 18.75 percent of the population, and 60 divided by 0.1875 is 320. The formula is just that reasoning rearranged.

Step seven: state what would break it. If marking made voles easier for owls to see, marked animals would be under-represented in the second sample, the recapture number would fall, and the estimate would come out too high. Every assumption maps onto a specific direction of error.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Define a population.
    Show the full solution

    The individuals of one species in one area at one time, able to interbreed

  2. Name the three dispersion patterns and say which is commonest.
    Show the full solution

    Clumped, uniform and random; clumped is commonest

  3. Write the Lincoln index in words.
    Show the full solution

    Population equals number marked times size of second sample, divided by number of marked individuals recaptured

  4. Forty are marked, 50 are caught later and 10 are marked. Estimate the population.
    Show the full solution

    40 times 50 divided by 10, which is 200

  5. Which sampling method suits a plant, and which a mouse?
    Show the full solution

    Quadrats for the plant, mark and recapture for the mouse

  6. Explain why quadrats must be placed at random.
    Show the full solution

    Because a person choosing where to put them will not choose neutrally. Quadrats get placed where the plants are interesting to count, or where the ground is easy to walk on, and either bias shifts the mean away from the true density of the whole field. Random placement, generated from coordinates rather than judgment, makes the sample representative so that scaling up is valid. It also means the spread between quadrats genuinely reflects patchiness in the field rather than patchiness in the surveyor's choices. Human placement is biased, and the scaling step assumes a representative sample

  7. A student marks 50 fish, and the next day catches 50 of which 25 are marked. They report a population of 100. Explain why this may be badly wrong.
    Show the full solution

    The arithmetic is right but the assumptions are almost certainly broken. One day is unlikely to be long enough for marked fish to mix evenly back through the lake, so a second sample taken near the release point will be rich in marked fish. That inflates the recapture number, and since the recapture number is the divisor, it drives the estimate down. A population of 100 from a sample of 50 also implies catching half the lake's fish in a day, which should itself prompt suspicion. Too little time for mixing inflates recaptures and understates the population

  8. Why is clumped dispersion the commonest pattern in nature?
    Show the full solution

    Because resources are almost never spread evenly. Water, shade, soil depth and food occur in patches, so organisms accumulate where conditions are tolerable and are absent where they are not. Many species also gain directly from being together, through group defense, shared warmth or easier mate finding, and many plants drop seeds close to the parent. Uniform spacing requires something actively pushing individuals apart, such as territoriality, and true randomness requires individuals to be indifferent to both resources and each other. Resources are patchy and many species benefit from grouping

  9. Explain how marking that makes an animal more visible to predators biases the estimate, and in which direction.
    Show the full solution

    Marked animals would suffer higher mortality than unmarked ones, so by the time of the second sample the marked fraction of the population would be smaller than it should be. Fewer marked individuals would be recaptured, and since the recapture count sits on the bottom of the Lincoln index, a smaller divisor produces a larger answer. The estimate would therefore be too high, and it would be confidently too high, since nothing in the arithmetic signals that anything has gone wrong. Fewer recaptures means a smaller divisor, so the estimate is too high

  10. Why is density often more useful than the total count?
    Show the full solution

    Because a raw count says nothing without the area it came from. Three hundred voles is a crowded meadow or an almost empty forest depending on whether the area is a hectare or a hundred, so totals from different sites cannot be compared. Density divides that out and makes the figure portable: it can be set against another site, against the same site in another year, or against a known carrying capacity. It is also the quantity that actually matters biologically, since competition and disease transmission depend on how close individuals are. Density is comparable between areas and is what competition and disease depend on

Lesson 3.2 · Unit 3 · HS-LS2-1, HS-LS2-2

Exponential growth, and why nothing does it for long

Put a few bacteria in fresh broth and the population does something that looks impossible: it accelerates. Not adding a fixed number each hour, but multiplying. The shape this produces is the J curve, and understanding why it always ends is half of population ecology.

The key ideas
  1. Exponential growth multiplies rather than adds. Each individual contributes offspring, so the more there are, the faster the population grows.
  2. The per capita growth rate is births minus deaths, divided by the population size. It is the growth contributed per individual.
  3. The curve is a J: slow at first because few individuals are reproducing, then steepening without limit.
  4. Doubling time is constant under exponential growth, which is the clearest signature of it. A population that doubles every 20 minutes keeps doing so regardless of size.
  5. It requires unlimited resources, which is the assumption that fails. No environment supplies unlimited food, space or oxygen, and none removes waste indefinitely.
  6. It is still a useful model, because real populations do grow this way briefly: after colonizing new habitat, after a crash, or in a laboratory culture during its early phase.

Where students lose marks: describing exponential growth as "fast growth". Speed is not the point. The defining feature is that the growth rate is proportional to the population size, so the curve steepens rather than staying straight. A slow exponential is still exponential.

Worked example

Part one: bacterial doubling. A culture starts with 500 cells and divides every 20 minutes under ideal conditions.

Step one: count the doublings. Two hours is 120 minutes, and 120 divided by 20 is 6 doublings.

Step two: apply them. Two multiplied by itself six times is 64, so the population is 500 times 64, which is 32,000 cells.

Step three: notice the acceleration. Between 100 and 120 minutes the population goes from 16,000 to 32,000, adding 16,000 cells in twenty minutes. In the first twenty minutes it added only 500. Same rule, same interval, thirty two times the increase.

Step four: extend it absurdly to test the model. Continued for 24 hours that is 72 doublings, giving a mass of bacteria far larger than the culture flask, the laboratory or any reasonable object. The model has not made an arithmetic error; it has run past its assumption.

Part two: per capita growth rate. A population of 1,000 deer records 120 births and 40 deaths in a year, with no migration.

Step five: find the change. 120 births minus 40 deaths is 80 more deer.

Step six: divide by the population. 80 divided by 1,000 is 0.08, so the per capita growth rate is 0.08 per year, or 8 percent.

Step seven: project one more year and see the multiplication. The population is now 1,080, and 8 percent of 1,080 is 86.4, so the next year adds about 86 rather than 80. The rate per individual has not changed; the number of individuals has.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What shape does exponential growth give on a graph?
    Show the full solution

    A J curve

  2. How is per capita growth rate calculated?
    Show the full solution

    Births minus deaths, divided by the population size

  3. A culture of 200 cells doubles every 30 minutes. How many after 2 hours?
    Show the full solution

    Four doublings, so 200 times 16, which is 3,200

  4. What assumption does the exponential model make?
    Show the full solution

    That resources are unlimited

  5. A population of 500 has 90 births and 40 deaths in a year. Find the per capita growth rate.
    Show the full solution

    50 divided by 500, which is 0.10 per year

  6. Explain why "exponential" does not simply mean "fast".
    Show the full solution

    Exponential describes the shape of the relationship rather than the speed. A population growing at one percent a year is growing exponentially, because the increase each year is proportional to the number present, so the curve steepens even though it looks almost flat for decades. A population adding exactly a hundred individuals annually is growing quickly at first but linearly, and its graph is a straight line forever. The distinction is whether the growth rate depends on current size. It means growth proportional to current size, whatever the speed

  7. Why does exponential growth always stop in the real world?
    Show the full solution

    Because its assumption is physically impossible to sustain. Every environment has a finite supply of food, water, space, oxygen and nesting sites, and a finite ability to dilute or remove waste. As the population multiplies, those supplies are divided among more individuals and waste accumulates, so birth rates fall and death rates rise. The population cannot go on multiplying because the conditions that permitted multiplication have been consumed by the multiplying itself. Finite resources and accumulating waste break the unlimited assumption

  8. Why does a bacterial culture grow exponentially at first even though the flask is obviously finite?
    Show the full solution

    Because while the population is small relative to the supply, the resources are effectively unlimited from each cell's point of view: no cell is short of nutrients, nothing is crowded, and waste is too dilute to matter. Under those conditions the model's assumption holds well enough and the prediction is accurate. The flask's limits only begin to bite once the population is large enough to draw down the broth measurably, which is when growth departs from the J curve and the logistic model takes over. While the population is small the resources are effectively unlimited

  9. A species is introduced to an island with no predators. Sketch in words what happens to its numbers and why.
    Show the full solution

    Growth is slow at first because there are few individuals reproducing, then accelerates into a J curve as each generation contributes more breeders, with no predation removing any of them. That cannot continue: food and space on the island are finite, so eventually the population either levels off near what the island can support or, commonly with introductions, overshoots the supply, strips the vegetation and crashes. Which of those happens depends on how quickly the damage to resources builds up relative to the reproduction rate. A J curve, then either leveling off or overshoot and crash as resources run out

  10. Two populations both grow exponentially, one at 2 percent and one at 8 percent per year. Explain why the gap between them widens over time.
    Show the full solution

    Each population multiplies by its own factor every year, and repeated multiplication by different factors separates the totals faster and faster. The faster population is not only adding more individuals but adding them to a base that is itself growing more quickly, so next year's increase is larger again. After one year the difference is small, but the ratio between the two populations grows without limit, which is why small differences in growth rate matter enormously over decades even when they look trivial annually. Repeated multiplication by different factors compounds the difference

Lesson 3.3 · Unit 3 · HS-LS2-1, HS-LS2-2, HS-LS2-6

Logistic growth and carrying capacity

The logistic model takes the exponential model and adds the one thing it was missing: a ceiling. The result is the S curve, and it makes a prediction that surprises most students. A population does not grow fastest when it is largest, nor when it is smallest, but exactly halfway to its limit.

The key ideas
  1. Carrying capacity, written K, is the population size an environment can sustain indefinitely given its resources.
  2. The S curve has three phases: slow initial growth, a steep middle, then a leveling off as the population approaches K.
  3. Growth rate depends on two things at once: how many individuals are reproducing, and how much room is left. In words, growth equals the per capita rate times the population times the fraction of capacity still unused.
  4. Maximum growth occurs at about half of K, where those two terms are best balanced: enough individuals to reproduce, enough resources to support them.
  5. Above K the population shrinks, because deaths exceed births when resources are insufficient.
  6. K is not a fixed constant. It changes with the seasons, with rainfall, with habitat damage, and it can be raised deliberately, which is what agriculture does.

Where students lose marks: saying growth is fastest at carrying capacity because the population is biggest. At K the growth rate is zero. The population is largest there and growing least, which is exactly the counterintuitive part being tested.

Worked example

The setup. A pond supports a carrying capacity of 500 fish. The per capita growth rate under ideal conditions is 0.5 per year. Growth equals 0.5 times the population times the fraction of capacity still unused.

Step one: take a small population, 50 fish. The unused fraction is 1 minus 50 over 500, which is 1 minus 0.1, so 0.9. Growth is 0.5 times 50 times 0.9, which is 22.5 fish per year.

Step two: take half capacity, 250 fish. The unused fraction is 1 minus 0.5, so 0.5. Growth is 0.5 times 250 times 0.5, which is 62.5 fish per year.

Step three: take a large population, 450 fish. The unused fraction is 1 minus 0.9, so 0.1. Growth is 0.5 times 450 times 0.1, which is 22.5 fish per year.

Step four: read the pattern. Growth at 50 fish and at 450 fish is identical, 22.5, and both are far below the 62.5 at 250. The fastest growth is at half of K, and it falls away symmetrically on either side.

Step five: explain each end. At 50 fish resources are abundant but there are too few breeders. At 450 there are plenty of breeders but almost no spare resources. Growth needs both, and only the middle has both.

Step six: check the population at K. At 500 fish the unused fraction is 1 minus 1, which is zero, so growth is zero. The population is at its maximum size and is not growing at all.

Step seven: apply it to a practical decision. A fishery wanting the largest sustainable catch should hold the stock near half of carrying capacity, not near its maximum, because that is where the population replaces itself fastest. Fishing a stock down to a tenth or letting it sit at K both yield less.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What does K stand for?
    Show the full solution

    Carrying capacity, the population an environment can sustain indefinitely

  2. What shape is the logistic curve?
    Show the full solution

    An S curve

  3. At what population size is growth fastest?
    Show the full solution

    At about half of the carrying capacity

  4. What is the growth rate when the population equals K?
    Show the full solution

    Zero

  5. With K of 800 and a per capita rate of 0.5, find the growth at 400 individuals.
    Show the full solution

    0.5 times 400 times 0.5, which is 100 individuals per year

  6. Explain why a population at carrying capacity has zero growth despite being the largest.
    Show the full solution

    Carrying capacity is defined as the size at which the environment's resources exactly support the individuals present, so births and deaths balance. Every new individual would need food, space and other resources that are already fully committed, and the shortfall raises mortality or suppresses reproduction until the balance is restored. The population is large precisely because it has used up the surplus that would allow it to get larger, which is why maximum size and maximum growth never occur together. At K resources exactly support the population, so births equal deaths

  7. Explain why growth is slow at both very low and very high population sizes, for different reasons.
    Show the full solution

    At low numbers resources are abundant per individual, but there are very few individuals reproducing, so the total number of offspring produced is small even though each one has an easy time. At high numbers the opposite holds: there are many potential breeders but almost no spare resources, so reproduction is suppressed and mortality is high. Growth requires both plenty of breeders and plenty of resources, and only a population near half of capacity has a reasonable amount of each. Too few breeders at the bottom, too few resources at the top

  8. A population overshoots K, then falls below it, then rises again in smaller swings. Explain this pattern.
    Show the full solution

    Populations respond to resource shortage with a delay, because individuals already born continue to grow and reproduce for a time after the supply has been outstripped. The population therefore climbs past K before the shortage takes effect, and the resulting mortality is severe enough to carry it below K, at which point resources recover and growth resumes. Each swing is smaller than the last because the mismatch shrinks, producing damped oscillation around the capacity rather than a smooth approach. A lag between resource depletion and population response causes damped oscillation

  9. Why is carrying capacity not a fixed number for a given place?
    Show the full solution

    Because it depends on the resources actually available, and those change. A wet year grows more vegetation and raises K for herbivores; a drought lowers it within months. Habitat loss, a new disease, an introduced competitor or a change in season all shift it, and human action can raise it deliberately through irrigation and fertilizer or lower it through pollution. Treating K as a constant of the landscape leads to badly wrong predictions whenever conditions move, which is most of the time. It tracks available resources, which vary with season, weather and human action

  10. A fishery wants the largest catch it can take year after year. Where should it hold the stock, and why not higher?
    Show the full solution

    At roughly half of carrying capacity, because that is where the population replaces itself fastest and therefore produces the largest surplus that can be removed without shrinking the stock. Holding it near K would mean a large standing population producing almost no net growth, so almost nothing could be taken sustainably. Fishing it far below half is worse still, since too few breeders remain. The counterintuitive result is that a deliberately reduced population yields more than a full one. Near half of K, because that is where net production is greatest

Lesson 3.4 · Unit 3 · HS-LS2-2, HS-LS2-6

Density-dependent and density-independent limits

Two kinds of thing stop populations growing, and they behave completely differently. One gets stronger as the population gets denser, and so can hold numbers near a stable level. The other hits regardless of density, and so cannot. Sorting a described factor into the right category is a standard exam task.

The key ideas
  1. A density-dependent factor has an effect that intensifies as density rises. Competition for food, disease transmission, predation and accumulated waste all qualify.
  2. A density-independent factor hits with the same severity whatever the density. Floods, fire, drought, frost and volcanic eruption all qualify.
  3. Only density-dependent factors can regulate a population, because only they push harder when numbers rise and ease off when numbers fall. That negative feedback is what produces carrying capacity.
  4. Density-independent factors can devastate without regulating. A frost may kill 80 percent of a population whether it was dense or sparse, resetting numbers without setting a level.
  5. Disease is the clearest density-dependent case, because transmission requires contact, and contact rates rise steeply with crowding.
  6. The test to apply: ask whether doubling the density would change the proportion affected. If yes, it is density dependent.

Where students lose marks: classifying by whether the factor is living. Predation is biotic and density dependent; drought is abiotic and density independent, which makes the biotic and abiotic split look identical for a while. It is not. Competition for nest sites is density dependent and abiotic in origin. Use the density test, not the living test.

Worked example

The task. Classify five described factors affecting a rabbit population, applying the density test to each.

Step one: severe winter frost kills rabbits in exposed burrows. Ask whether doubling rabbit density changes the proportion killed. It does not: the frost is as cold either way, and each burrow is exposed or not regardless of how many neighbors exist. Density independent.

Step two: a fungal infection spreads through the warren. Transmission needs contact, and doubling density roughly doubles contact opportunities, so a larger share of a dense population is infected. Density dependent.

Step three: grazing has removed most of the grass. Food shortage arises from the rabbits themselves, and the more rabbits there are, the less each one gets. Density dependent, and the classic case.

Step four: a river floods the meadow. The water rises to the same level whether there are 50 rabbits or 500, drowning those in low burrows either way. Density independent.

Step five: foxes concentrate where rabbits are abundant. Predators move toward dense prey and take a larger share there, so the effect strengthens with density. Density dependent.

Step six: see which ones could produce a carrying capacity. The infection, the food shortage and the predation all push harder as numbers rise and relax as numbers fall. That is negative feedback, and it is what holds a population near a level.

Step seven: see what the others do instead. The frost and the flood knock the population down from wherever it happened to be. They can cause a crash, but they set no level, and after one the population simply resumes growing under the density-dependent factors.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Define a density-dependent factor.
    Show the full solution

    One whose effect intensifies as population density rises

  2. Give two examples of density-independent factors.
    Show the full solution

    Any two of flood, fire, drought, frost, volcanic eruption

  3. Which kind of factor can regulate a population, and why?
    Show the full solution

    Density dependent, because it pushes harder when numbers rise and eases when they fall

  4. State the test for classifying a factor.
    Show the full solution

    Ask whether doubling the density would change the proportion affected

  5. Why is disease usually density dependent?
    Show the full solution

    Because transmission needs contact, and contact rates rise with crowding

  6. Explain why the biotic and abiotic split is not the same as the density dependent and independent split.
    Show the full solution

    The two classifications answer different questions. Biotic and abiotic asks what kind of thing the factor is; density dependence asks how its effect scales with crowding. They often coincide, since competition and disease are both living and density dependent while frost is neither, but not always. Competition for a limited number of nest holes in rock is density dependent even though the holes are abiotic, and a parasite that arrives in a single contaminated water delivery can hit a population regardless of its density. One asks what the factor is, the other how its effect scales with density

  7. Explain how density-dependent factors produce a carrying capacity.
    Show the full solution

    They create negative feedback. As the population rises, competition, disease and predation all intensify, which lowers births and raises deaths until growth stops. If the population then falls, those same pressures relax, births rise above deaths and the population recovers. The result is a level toward which numbers are pushed from both directions, which is exactly what carrying capacity describes. A factor that did not vary with density could never produce this, because it would push equally hard at every size. They provide negative feedback that pushes numbers toward a level from both sides

  8. A hurricane destroys 80 percent of an island's birds. Explain why this does not set a carrying capacity.
    Show the full solution

    The hurricane would have destroyed a similar proportion whatever the population size, so it carries no information about what the island can support. It resets the number to a fifth of whatever it happened to be, producing a crash rather than a level, and it does not push back if the population subsequently grows too large or fall silent if it shrinks. After the storm the population simply resumes growing under the density-dependent factors, and it is those, not the hurricane, that determine where it settles. It hits the same proportion at any density, so it resets numbers without setting a level

  9. Why do epidemics tend to break out in dense populations rather than sparse ones?
    Show the full solution

    Because a pathogen spreads only when an infected individual contacts a susceptible one, and the rate of such contacts climbs steeply with crowding. In a sparse population an infected individual may recover or die before meeting anyone, so the outbreak fails to establish. Above a threshold density each infection produces more than one new infection on average and the disease spreads through the population. This also explains why epidemics often end before infecting everyone: they reduce the density of susceptible individuals below that threshold. Transmission needs contact, and contact rates rise sharply with density

  10. Classify "competition for a limited number of nesting holes in a cliff" and justify it.
    Show the full solution

    Density dependent. Apply the test: doubling the number of birds does not change the number of holes, so a larger share of the population fails to find one and is excluded from breeding. The effect therefore intensifies with density, which is the definition. The fact that the holes themselves are abiotic is irrelevant to this classification, and treating it as abiotic and therefore density independent is the standard mistake this lesson is built to prevent. Density dependent, since a fixed number of holes excludes a larger share as numbers rise

Lesson 3.5 · Unit 3 · HS-LS2-2, HS-LS2-6

Competition, predation, and the cycles they produce

Two species needing the same limited resource cannot both go on using it in exactly the same way. Either one is driven out, or they divide the resource between them. And where a predator depends on one prey species, the two populations produce a pattern so regular it looks designed: a cycle in which the predator's peak always arrives after the prey's.

The key ideas
  1. Intraspecific competition is within a species and is the most intense kind, because the competitors need exactly the same things.
  2. Interspecific competition is between species, and its intensity depends on how much their requirements overlap.
  3. A niche is the full role of a species: what it eats, where it lives, when it is active, what conditions it tolerates. It is not simply its habitat.
  4. The competitive exclusion principle: two species cannot occupy identical niches indefinitely in the same place. One outcompetes the other.
  5. Resource partitioning is the usual escape. Species divide the resource by time, by location or by size, which reduces overlap and allows coexistence.
  6. Predator and prey cycles lag. Prey numbers rise, predators increase in response, heavy predation drives prey down, predators then decline for lack of food, and prey recover. The predator peak follows the prey peak.

Where students lose marks: saying predators "control" prey numbers, as though the arrow ran one way. Each population drives the other. The prey's rise causes the predator's rise, which causes the prey's fall, which causes the predator's fall. Describing only half of the loop loses the mark.

Worked example

The data. A predator and prey cycle, with figures constructed to make the lag unmistakable. Populations in hundreds.

Year1234567
Hares20457040152550
Lynx5814181057

Step one: locate the prey peak. Hares peak in year 3 at 70, then fall to 15 by year 5.

Step two: locate the predator peak. Lynx peak in year 4 at 18, one year after the hares. The lag is the signature of the relationship.

Step three: explain the lag. Predators cannot increase until there is food to support breeding, and raising young takes time. The lynx respond to the abundance of year 3 with the numbers of year 4.

Step four: explain the prey crash. By year 4 there are 18 lynx eating hares, the largest predator pressure in the cycle, and hare numbers fall from 40 to 15.

Step five: explain the predator crash. With only 15 hares in year 5, the lynx cannot feed themselves or their young, and their numbers fall from 18 to 10 and then to 5.

Step six: explain the recovery. With only 5 lynx in year 6, predation pressure is at its lowest, so the surviving hares breed successfully and numbers climb again to 50 by year 7. The cycle restarts.

Step seven: state the causation in both directions. Prey abundance drives predator numbers up; predator abundance drives prey numbers down. Neither population is in charge, and the lag is what turns two linked effects into a repeating cycle rather than a single settling point.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What is the difference between intraspecific and interspecific competition?
    Show the full solution

    Intraspecific is within one species; interspecific is between different species

  2. Define a niche.
    Show the full solution

    The full role of a species: what it eats, where and when it lives, and the conditions it tolerates

  3. State the competitive exclusion principle.
    Show the full solution

    Two species cannot occupy identical niches in the same place indefinitely

  4. In the worked example, in which years do hares and lynx peak?
    Show the full solution

    Hares in year 3, lynx in year 4

  5. Name three ways species partition a resource.
    Show the full solution

    By time of activity, by location within the habitat, and by the size of food taken

  6. Explain why the predator peak comes after the prey peak rather than with it.
    Show the full solution

    Predators convert food into offspring, and that conversion takes time: an abundance of prey must first improve adult survival and breeding condition, then gestation and rearing must follow before the extra predators actually exist. The predator population is therefore responding to conditions that applied months or a year earlier. By the time those extra predators are hunting, the prey population has often already begun to decline, which is why the two curves are offset rather than rising and falling together. Converting abundant prey into more predators takes time

  7. Why is intraspecific competition usually more intense than interspecific?
    Show the full solution

    Because members of the same species have identical requirements. They need the same food of the same size, the same kind of nest site, the same conditions, and they are active at the same times, so the overlap is total. Two different species almost always differ somewhat in what they take or when they take it, so their demands overlap only partly and each has some resources the other does not use. Complete overlap means every individual is competing with every other for exactly the same things. Members of one species have completely overlapping requirements

  8. Two warbler species feed in the same trees and coexist. Explain how this is possible without violating competitive exclusion.
    Show the full solution

    Their niches are not identical even though their habitat is. One may feed mainly in the outer branches near the top while the other works the inner branches lower down, or they may take insects of different sizes or breed at slightly different times. That partitioning reduces the overlap in what each actually uses, so each has a share of the resource the other does not exploit. Competitive exclusion forbids identical niches, not shared habitats, and the distinction between the two is what this question tests. They partition the resource, so their niches differ even in the same tree

  9. A student writes that lynx control hare numbers. Rewrite the claim accurately.
    Show the full solution

    A better version: hare and lynx populations regulate each other through a lagged feedback loop, in which rising hare numbers allow lynx numbers to rise, the increased predation then drives hare numbers down, the resulting food shortage drives lynx numbers down, and reduced predation allows hares to recover. The original sentence describes only one arm of the loop and implies the lynx are the active party, when in fact each population is both cause and effect, which is why the pattern cycles instead of settling. Each population drives the other, so the relationship is a loop rather than one-way control

  10. Predict what happens to hare numbers over several years if lynx are removed entirely, and say what limits them then.
    Show the full solution

    Hare numbers would rise steeply at first, since the main source of mortality has gone, and the cycle would flatten out because its driver has been removed. Growth would not continue indefinitely: other density-dependent factors would take over, chiefly competition for vegetation and the disease transmission that comes with high density, and the population would settle near a carrying capacity set by food supply. It might also overshoot and crash if grazing damaged the vegetation faster than the population responded. They rise until food competition and disease limit them at a new carrying capacity

Lesson 3.6 · Unit 3 · HS-LS2-6, HS-LS2-8

Symbiosis: mutualism, commensalism and parasitism

Close, long-term relationships between species are classified by a simple rule: work out whether each partner gains, loses or is unaffected. Two pluses is mutualism, a plus and a zero is commensalism, a plus and a minus is parasitism. The classification is easy; applying it honestly to a real case is not.

The key ideas
  1. Symbiosis means living together in a close, long-term relationship. It does not mean the relationship is friendly, and parasitism is a form of it.
  2. Mutualism benefits both partners. Nitrogen-fixing bacteria in root nodules receive sugars and supply usable nitrogen; gut bacteria receive food and supply digestion of material the host cannot handle.
  3. Commensalism benefits one and does nothing measurable to the other, such as an epiphyte growing on a branch for the light.
  4. Parasitism benefits one at the other's expense. A tapeworm gains nutrients while the host loses them.
  5. A parasite that kills its host quickly does badly, so long-established parasites are often less harmful than newly arrived ones. Virulence evolves.
  6. True commensalism is hard to demonstrate, because showing an effect of exactly zero requires measuring it, and closer study usually turns up a small cost or benefit.

Where students lose marks: classifying by whether the relationship looks pleasant. Ask what each partner gains or loses in terms of survival and reproduction, and write the two signs down before naming the category.

Worked example

The method. Assign a sign to each partner, then read off the category. Five cases, worked in order.

RelationshipPartner APartner BCategory
Bee and flowering plantgains nectargains pollinationmutualism
Tapeworm and doggains nutrientsloses nutrientsparasitism
Barnacle on whalegains transportno clear effectcommensalism
Rhizobium and legumegains sugarsgains nitrogenmutualism
Mistletoe and oakgains water and mineralsloses themparasitism

Step one: do not start from the category. Ask what each partner gets, in terms that affect survival or reproduction. Nectar is food; pollination is reproduction. Both are real gains, so the bee and the plant are plus and plus.

Step two: notice that neither partner intends anything. The plant is not rewarding the bee. Plants that produced nectar were pollinated more and left more offspring, which is the mechanism of unit 10, not a bargain.

Step three: test the barnacle case properly. The barnacle plainly gains, being carried through food-rich water. Does the whale lose? A heavy load of barnacles adds drag, which costs energy. Small effects like this are why commensalism is so often reclassified on closer inspection.

Step four: apply the test to the legume. The plant supplies sugars from photosynthesis, a genuine cost, and receives nitrogen in usable form, a genuine benefit. Both partners pay and both gain, and the relationship persists because for each the benefit exceeds the cost.

Step five: examine virulence in the tapeworm. A parasite that killed its host in a week would lose its habitat and its route to new hosts. Selection therefore favors parasites that take enough to reproduce while leaving the host functioning, which is why many long-established parasites cause mild chronic infections.

Step six: contrast a newly arrived parasite. A parasite that has recently jumped to a new host species has no such history and may be far more damaging, because nothing has yet selected against killing a host it is not adapted to exploit. Severity is not a fixed property of a parasite.

Step seven: state the general point. The three categories are points on a continuum of costs and benefits, and a relationship can move along it as conditions change. Gut bacteria that aid digestion can become harmful if they reach the bloodstream.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Give the sign pattern for each of the three categories.
    Show the full solution

    Mutualism plus and plus, commensalism plus and zero, parasitism plus and minus

  2. What does symbiosis mean?
    Show the full solution

    A close, long-term relationship between two species, of any kind

  3. Give an example of mutualism involving bacteria.
    Show the full solution

    Rhizobium in legume root nodules, or gut bacteria aiding digestion

  4. Why is a parasite that rapidly kills its host at a disadvantage?
    Show the full solution

    It destroys its own habitat and its route to new hosts before reproducing fully

  5. Why is commensalism hard to demonstrate?
    Show the full solution

    Proving an effect of exactly zero requires measurement, and closer study usually finds a small cost or benefit

  6. Explain why calling mutualism cooperation is misleading.
    Show the full solution

    Cooperation implies intention and an agreement between partners, and neither exists. Each species is doing what increases its own survival and reproduction, and the relationship persists only because for each partner the benefit exceeds the cost. If conditions changed so that one partner gained less than it paid, selection would erode the relationship regardless of how well it had worked before. Describing it as a bargain also invites teleological explanations, which is the single most damaging habit in biology. Neither partner intends anything; each is acting in its own interest

  7. Explain how a mutualism could become a parasitism.
    Show the full solution

    By a change in the balance of costs and benefits rather than a change in category. Gut bacteria that break down material the host cannot digest supply a genuine benefit at a small cost in nutrients, but if the host's immune system is weakened or the bacteria reach tissues outside the gut, the cost rises sharply while the benefit disappears. The species involved have not changed; the accounting has. This is why the three categories are best treated as regions of a continuum rather than fixed labels. The balance of costs and benefits shifts, which is all the categories describe

  8. Explain why virulence is not a fixed property of a parasite.
    Show the full solution

    Virulence is shaped by selection acting on the parasite's own reproductive success, which depends on how long the host survives and how readily it transmits the parasite onward. Where transmission needs a mobile living host, selection favors restraint, and long-established parasites tend toward milder chronic infections. Where transmission happens by a vector or through water and does not need the host to move, high virulence carries less penalty. A parasite newly arrived in an unfamiliar host has had no such selection at all, and is often far more damaging. Selection tunes it to the transmission route and the length of host association

  9. A bird eats insects disturbed by grazing cattle. Classify the relationship and justify it.
    Show the full solution

    Commensalism as usually described: the bird plainly gains an easier food supply, and the cattle appear unaffected, since the insects were disturbed as a side effect of grazing they would have done anyway. It is worth applying the caution from this lesson, though. If the bird also removes biting flies from the cattle, they gain and the relationship is mutualism, and if its presence disturbs grazing it becomes a small cost. Deciding requires measuring the effect on the cattle rather than assuming it is zero. Commensalism on the face of it, but the effect on the cattle should be measured

  10. Why might a plant benefit from housing bacteria that cost it sugars?
    Show the full solution

    Because the nitrogen the bacteria supply is the factor actually limiting the plant's growth, while sugars are not. Plants can make sugars from light and carbon dioxide whenever conditions allow, but they cannot use atmospheric nitrogen, and soil nitrate is frequently in short supply. Paying in the abundant currency to obtain the scarce one is a net gain, which is why legumes can colonize poor soils where other plants fail. The relationship would not persist on soils already rich in nitrogen. It pays in sugars, which it can make, for nitrogen, which limits it

Lesson 3.7 · Unit 3 · HS-LS2-2, HS-LS2-6

Succession: what a disturbed community does next

Clear a patch of ground and leave it alone. What grows there in year one is not what grows there in year fifty, and the sequence is predictable enough to be described in advance. Each stage changes conditions in ways that suit its own successors better than itself, which is the engine of the whole process.

The key ideas
  1. Succession is directional change in a community over time following a disturbance or the exposure of new ground.
  2. Primary succession starts on bare rock or new surfaces with no soil at all: lava flows, land exposed by a retreating glacier, new sand dunes.
  3. Secondary succession starts where soil remains after a fire, flood, clearance or abandoned field. It is far faster, because the hardest step is already done.
  4. Pioneer species arrive first: lichens and mosses on rock, fast growing annual weeds on soil. They tolerate harsh conditions and disperse widely.
  5. Each stage modifies the environment, building soil, adding shade, retaining water and nutrients, which typically favors the next stage and disadvantages itself.
  6. The climax community is the stable end point in the classic model, though ecologists now treat it with caution, since disturbance is frequent and many communities never reach a steady end state.

Where students lose marks: describing succession as species "wanting" to improve the habitat for those that follow. Pioneers change conditions as a side effect of living there. That the change happens to suit their replacements is not a purpose, and phrasing it as one is the teleology error.

Worked example

The case. Primary succession on a lava flow, read as a sequence of stages. A chronosequence like this is built by comparing flows of different known ages rather than by waiting.

Step one: bare rock, year zero. No soil, no water retention, extreme surface temperatures, no nutrients except what the rock itself holds. Almost nothing can establish.

Step two: lichens arrive. They tolerate desiccation, need no soil, and disperse as tiny fragments carried on wind. Their acids slowly weather the rock surface, and their dead tissue adds the first organic matter.

Step three: mosses follow. The thin layer of weathered mineral grains and dead lichen now holds a little water, which is what mosses require. Mosses trap more debris and hold more water, deepening the layer further.

Step four: the first soil supports herbs and grasses. Their roots penetrate cracks, accelerating weathering, and their larger bodies contribute much more organic matter when they die. Soil depth and nutrient content rise together.

Step five: shrubs establish, then trees. Each needs deeper soil than the last, and each casts more shade. This is where the engine becomes visible: the shade cast by shrubs suppresses the light-demanding grasses that built the soil the shrubs needed.

Step six: state the mechanism without teleology. No stage is preparing the ground for the next. Each organism alters its surroundings simply by living and dying there, and those alterations happen to favor species with different requirements. The sequence is a consequence, not a plan.

Step seven: contrast secondary succession. After a forest fire the soil, the seed bank and the nutrients survive. Herbs and grasses appear within months rather than centuries, and woodland can return in decades. The difference in speed is almost entirely the difference between having soil and not having it.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Define succession.
    Show the full solution

    Directional change in a community over time following disturbance or the exposure of new ground

  2. What distinguishes primary from secondary succession?
    Show the full solution

    Primary starts with no soil; secondary starts where soil remains

  3. Name two pioneer species types on bare rock.
    Show the full solution

    Lichens and mosses

  4. Give two properties that make a good pioneer.
    Show the full solution

    Tolerance of harsh conditions and wide dispersal

  5. Why is secondary succession faster?
    Show the full solution

    Soil, nutrients and a seed bank already exist

  6. Explain how a stage can make conditions worse for itself.
    Show the full solution

    Grasses build soil by adding organic matter as they die back each year, and deeper soil is exactly what shrubs and trees require to establish. Once those larger plants arrive they cast shade, and the grasses are light demanding, so their growth is suppressed by the conditions their own accumulated remains made possible. The stage has not made a mistake and is not sacrificing itself; it has simply altered its surroundings in a way that suits a competitor better than it suits itself. Grasses build the soil that supports the shrubs whose shade excludes them

  7. Explain why lichens can colonize bare rock when grasses cannot.
    Show the full solution

    Grasses need soil to anchor roots and to supply water and mineral ions, and bare rock offers none of these. Lichens require no soil at all: they attach directly to the rock surface, absorb water and minerals from rain and dust, and tolerate drying out completely between rainfalls. Their combination of a fungus and a photosynthetic partner means they can also make their own food in place. Those tolerances let them occupy a surface that offers nothing a flowering plant can use. Lichens need no soil and tolerate desiccation; grasses need both

  8. Why is the idea of a climax community now treated with caution?
    Show the full solution

    Because it implies a single stable end state that a site reliably reaches and then holds, and real landscapes rarely behave that way. Fire, storm, disease and flood recur on timescales shorter than the time needed to arrive at such a state, so many communities are permanently somewhere in the middle of recovering from something. The same starting point can also end in different communities depending on which species happen to arrive first. The classic model describes a tendency rather than a destination. Disturbance is frequent and outcomes vary, so a fixed end state is rarely reached

  9. Suggest how an ecologist can study a process that takes centuries.
    Show the full solution

    By substituting space for time, comparing sites of different known ages that are otherwise similar, which is called a chronosequence. Lava flows from eruptions in different centuries, or land exposed at different distances from a retreating glacier, can be surveyed in a single season and arranged in order of age to infer the sequence. The method assumes the sites differ only in age and followed the same path, which is its weakness, so it is strengthened by combining it with long-term records from fixed plots. A chronosequence: compare sites of different known ages instead of waiting

  10. A field is abandoned and a woodland stands there sixty years later. Explain the sequence and why it is secondary succession.
    Show the full solution

    It is secondary because the soil, its nutrients and a bank of buried seeds survived the farming, so the slow work of building soil from rock was not required. Fast growing annual weeds colonize within the first season from that seed bank and from wind-blown seed, followed by perennial grasses and herbs, then shrubs and fast growing light-demanding trees such as birch, and finally slower shade-tolerant trees that can germinate beneath an existing canopy. Each stage alters light and soil conditions in ways that favor the next. Soil and seed bank survived, so weeds give way to grasses, shrubs and then trees

Unit 3 review · Populations and Communities

Ten questions across the whole unit

Questions 1 to 5 check that you hold the terms. Questions 6 to 10 require you to reason across the seven lessons.

  1. Name the three dispersion patterns.
    Show the full solution

    Clumped, uniform and random

  2. Eighty animals are marked, 100 are caught later and 20 are marked. Estimate the population.
    Show the full solution

    80 times 100 divided by 20, which is 400

  3. At what population size is logistic growth fastest?
    Show the full solution

    At about half the carrying capacity

  4. State the test for whether a limiting factor is density dependent.
    Show the full solution

    Ask whether doubling the density would change the proportion affected

  5. Give the sign pattern for mutualism, commensalism and parasitism.
    Show the full solution

    Plus and plus, plus and zero, plus and minus

  6. Explain why only density-dependent factors can produce a carrying capacity.
    Show the full solution

    They create negative feedback. As the population rises, competition, disease and predation all intensify, lowering births and raising deaths until growth stops, and if the population then falls those pressures relax so it recovers. The result is a level toward which numbers are pushed from both directions. A factor whose severity does not vary with density pushes equally hard at every size, so it can cause a crash but cannot set a level. They push back harder as numbers rise and ease as they fall, which is negative feedback

  7. Explain why a population grows slowly both at very low and very high numbers, for different reasons.
    Show the full solution

    At low numbers resources are abundant per individual but there are very few individuals reproducing, so the total number of offspring is small even though each has an easy time. At high numbers the opposite holds: many potential breeders but almost no spare resources, so reproduction is suppressed and mortality rises. Growth needs both plenty of breeders and plenty of resources, and only a population near half of capacity has a reasonable amount of each. Too few breeders at the bottom, too few resources at the top

  8. A predator peak always follows the prey peak. Explain why, and why the relationship is not one-way.
    Show the full solution

    Predators convert food into offspring, and that takes time: abundant prey must first improve survival and breeding condition, then gestation and rearing must follow before extra predators exist. By then prey numbers are often already falling. The relationship runs both ways, since prey abundance drives predator numbers up and predator abundance drives prey numbers down, so each population is both cause and effect and neither controls the other. Converting prey into predators takes time, and each population drives the other

  9. Explain how a stage of succession can make conditions worse for itself.
    Show the full solution

    Grasses build soil by adding organic matter as they die back each year, and deeper soil is exactly what shrubs and trees require to establish. Once those larger plants arrive they cast shade, and since grasses are light demanding their growth is suppressed by conditions their own accumulated remains made possible. Nothing is being sacrificed and no purpose is involved: the stage simply altered its surroundings in a way that suits a competitor better than itself. Grasses build the soil that supports the shrubs whose shade excludes them

  10. Explain why classifying a limiting factor as biotic or abiotic is not the same as classifying it as density dependent or independent.
    Show the full solution

    The two classifications answer different questions: one asks what kind of thing the factor is, the other how its effect scales with crowding. They often coincide, since competition and disease are living and density dependent while frost is neither, but not always. Competition for a fixed number of nest holes in rock is density dependent although the holes are abiotic, so applying the living test instead of the density test gives the wrong answer. One asks what the factor is, the other how its effect scales with density

Lesson 4.1 · Unit 4 · HS-LS2-5

The water cycle and the idea of residence time

Unit 2 ended on a distinction: energy flows through, matter goes round. This unit follows the matter. Water is the place to start, because its cycle is the easiest to see and because it carries a quantitative idea that every other cycle in this unit needs: how long an atom stays in one place before moving on.

The key ideas
  1. A reservoir is a store, measured as an amount: the ocean, the atmosphere, groundwater, ice, living tissue.
  2. A flux is a transfer between reservoirs, measured as an amount per unit time. Evaporation, precipitation and transpiration are fluxes.
  3. The main processes: evaporation from open water, transpiration from plant leaves, condensation into cloud, precipitation, infiltration into soil and rock, and runoff back to the sea.
  4. Transpiration is biological and substantial. A forest moves large volumes of water from soil to atmosphere through its leaves, which is why clearing forest changes local rainfall.
  5. Residence time is reservoir size divided by flux. It gives the average time a molecule spends in that store.
  6. Short residence times mean fast response. A reservoir that turns over in days recovers quickly from a disturbance; one that turns over in millennia does not, which matters for every pollutant.

Where students lose marks: confusing a reservoir with a flux, usually by giving evaporation as a store or the ocean as a process. Check the units: a reservoir is measured in cubic meters, a flux in cubic meters per day.

Worked example

The figures. Constructed so the arithmetic is checkable.

Step one: set up the lake. A lake holds 60,000 cubic meters. Rivers deliver 5,000 cubic meters per day, and the same volume leaves each day, so the lake is at steady state.

Step two: calculate its residence time. 60,000 divided by 5,000 is 12 days. On average a water molecule entering the lake leaves it twelve days later.

Step three: read what that means practically. A pollutant spilled into this lake is largely flushed out within a few weeks, provided it stays dissolved and is not taken up by organisms or bound to sediment.

Step four: set up the groundwater. An aquifer beneath the same valley holds 1,200,000 cubic meters and is recharged at 400 cubic meters per day.

Step five: calculate its residence time. 1,200,000 divided by 400 is 3,000 days, which is about 8.2 years.

Step six: compare the two. The aquifer holds twenty times the water of the lake but receives only a twelfth of the inflow, so its residence time is 250 times longer. Both figures come from the same simple division, and the difference in behavior is enormous.

Step seven: draw the conclusion that matters. Contaminate the lake and the problem clears in weeks. Contaminate the aquifer and it persists for decades, because there is no fast flux to carry it away. Residence time, not reservoir size, predicts how long a problem lasts.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What is the difference between a reservoir and a flux?
    Show the full solution

    A reservoir is a store measured as an amount; a flux is a transfer measured as an amount per unit time

  2. Define transpiration.
    Show the full solution

    Loss of water vapor from plant leaves to the atmosphere

  3. Write the formula for residence time.
    Show the full solution

    Reservoir size divided by flux

  4. A pond holds 9,000 cubic meters with an inflow of 750 per day. Find the residence time.
    Show the full solution

    12 days

  5. Name three processes that move water out of a soil reservoir.
    Show the full solution

    Transpiration by plants, evaporation from the surface, and runoff or drainage

  6. Explain why a long residence time makes pollution harder to deal with.
    Show the full solution

    Residence time measures how quickly a reservoir's contents are replaced, so a long one means there is no substantial flux carrying material away. A contaminant entering such a store is diluted slowly and flushed slowly, and it stays available to organisms drawing on that reservoir for the whole period. An aquifer with a residence time of decades will still contain a pollutant long after the source has been shut off, which is why groundwater contamination is treated far more seriously than an equivalent spill into a fast flowing river. No fast flux removes it, so the contaminant persists for the length of the turnover

  7. A forest is cleared and local rainfall falls. Explain the mechanism.
    Show the full solution

    Trees move large volumes of water from soil to atmosphere by transpiration, drawing it up through roots and releasing it as vapor from their leaves. That vapor is a genuine input to the local atmosphere and contributes to cloud formation and rainfall downwind. Removing the trees removes the flux, so less water enters the air over that area, and rainfall can decline as a result. The cleared ground also sheds more water as runoff rather than storing it, which reinforces the drying. Removing trees removes the transpiration flux that supplied local atmospheric water

  8. Two lakes have the same residence time but one is ten times larger. What can you say about their inflows?
    Show the full solution

    The larger lake must have ten times the inflow. Residence time is reservoir divided by flux, so holding the ratio constant while multiplying the reservoir by ten requires multiplying the flux by ten as well. This is worth noticing because it shows residence time carries no information about the absolute size of either quantity: a small pond fed by a trickle and a great lake fed by a major river can behave identically in how fast their contents are replaced. The larger lake has ten times the inflow

  9. Why is the water cycle described as closed while the energy supply is not?
    Show the full solution

    Water molecules are neither created nor destroyed as they move between ocean, atmosphere, soil and organisms, so the same molecules circulate indefinitely and the planetary total stays effectively constant. The energy driving that circulation behaves differently: sunlight supplies the energy to evaporate water, and that energy is released again as heat when the vapor condenses and eventually radiates to space. The matter goes round while the energy passes through, which is the distinction from lesson 2.7 applied to a specific cycle. The molecules circulate indefinitely while the driving energy passes through once

  10. Suggest why the residence time of water in the atmosphere is only about ten days, despite the atmosphere being enormous.
    Show the full solution

    Because the atmosphere holds very little water relative to how fast water moves through it. Air can carry only a small mass of vapor before it saturates and precipitates, so the reservoir is small, while evaporation from the oceans and transpiration from land supply an immense flux every day. A small store divided by a very large flux gives a short residence time. The physical size of the atmosphere is irrelevant: what matters is the quantity of water it actually contains. A small water store divided by a very large daily flux

Lesson 4.2 · Unit 4 · HS-LS2-5, HS-ESS2-6

The carbon cycle: the fast loop and the slow loop

Carbon moves through two cycles at once, and almost every confusion about climate comes from running them together. One turns over in years and is driven by organisms. The other turns over in millions of years and is driven by geology. Burning fossil fuel is the act of moving carbon from the slow cycle into the fast one.

The key ideas
  1. The main reservoirs are the atmosphere as carbon dioxide, the oceans as dissolved carbon dioxide and carbonate, living biomass, soil organic matter, and rock including fossil fuels.
  2. The fast cycle is biological. Photosynthesis removes carbon dioxide from the air; respiration by plants, animals and decomposers returns it. Turnover is years to decades.
  3. The slow cycle is geological. Carbon is buried in sediment, locked into rock, and returned by weathering and volcanic activity over millions of years.
  4. Fossil fuels are slow-cycle carbon, formed from organisms whose remains escaped decomposition and were buried. Burning them injects that carbon into the fast cycle in decades.
  5. The ocean is the largest accessible sink, absorbing a substantial share of added carbon dioxide, which lowers its pH as carbonic acid forms.
  6. A cycle in balance holds a reservoir steady. When one flux increases without a matching increase elsewhere, the reservoir it feeds grows.

Where students lose marks: saying plants "remove carbon from the atmosphere permanently". Most of it returns within years through respiration and decomposition. Only carbon that escapes decomposition and is buried leaves the fast cycle, which is precisely what makes fossil fuel formation so slow.

Worked example

The figures. A simplified carbon budget in arbitrary units, constructed so the arithmetic is checkable. The atmospheric reservoir starts at 800 units.

FluxDirectionUnits per year
Photosynthesisout of atmosphere120
Respiration and decompositioninto atmosphere120
Fossil fuel burninginto atmosphere10
Net uptake by ocean and landout of atmosphere5

Step one: balance the natural fluxes alone. Photosynthesis removes 120 and respiration with decomposition returns 120. They cancel exactly, so without any other term the atmosphere would stay at 800 indefinitely.

Step two: note what that balance means. The fast cycle is large and it is a loop. Its size is not the issue; a big flux in both directions changes nothing on its own.

Step three: add the fossil fuel term. This adds 10 units per year with no matching natural removal, because the carbon comes from a reservoir the fast cycle was not previously drawing on.

Step four: subtract the extra uptake. The ocean and land absorb 5 units of that addition, so the net change to the atmosphere is 10 minus 5, which is 5 units per year.

Step five: project it. Over ten years the atmosphere gains 10 times 5, which is 50 units, rising from 800 to 850. The imbalance is small relative to the natural fluxes and it accumulates.

Step six: identify the key comparison. The fossil fuel flux of 10 is only about 8 percent of the photosynthesis flux of 120. A small addition matters because it is unmatched, not because it is large.

Step seven: trace the ocean's 5 units. Dissolved carbon dioxide forms carbonic acid, which lowers ocean pH. The sink that slows atmospheric change does so by changing the chemistry of the water, which is a cost rather than a free removal.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Name four carbon reservoirs.
    Show the full solution

    Atmosphere, oceans, living biomass and soil, and rock including fossil fuels

  2. Which two processes drive the fast carbon cycle?
    Show the full solution

    Photosynthesis and respiration, including decomposition

  3. How long does the slow carbon cycle take to turn over?
    Show the full solution

    Millions of years

  4. In the worked example, what is the net annual change to the atmosphere?
    Show the full solution

    An increase of 5 units per year

  5. What happens to ocean pH as it absorbs carbon dioxide, and why?
    Show the full solution

    It falls, because dissolved carbon dioxide forms carbonic acid

  6. Explain why burning fossil fuels is different from burning wood, in carbon cycle terms.
    Show the full solution

    Wood is fast-cycle carbon: the tree fixed it from the atmosphere within the last few decades, and burning it returns carbon that was recently removed, so over the life of a regrowing forest the exchange can be close to balanced. Fossil fuel is slow-cycle carbon that left the fast cycle hundreds of millions of years ago and would have stayed in rock for millions more. Burning it adds carbon the fast cycle was not previously handling, which is an addition rather than a return. Wood returns recently fixed carbon; fossil fuel injects slow-cycle carbon into the fast cycle

  7. The photosynthesis flux is twelve times the fossil fuel flux. Explain why the smaller one still changes the atmosphere.
    Show the full solution

    Because size is not what matters; balance is. Photosynthesis is matched almost exactly by respiration and decomposition returning the same carbon, so the two large fluxes cancel and leave the reservoir unchanged however big they are. The fossil fuel flux has no matching removal, since nothing is burying carbon back into rock at a comparable rate, so every unit of it accumulates. A small unmatched flux changes a reservoir while an enormous balanced pair does not. Large fluxes cancel; a small unmatched one accumulates

  8. Explain why planting trees slows atmospheric carbon increase but does not reverse fossil fuel emissions permanently.
    Show the full solution

    A growing forest genuinely removes carbon dioxide and stores it as wood, so while it is growing it is a real sink. But that carbon is now in the fast cycle, and it returns to the atmosphere when the trees die and decompose or if the forest burns, so the storage lasts decades to centuries rather than the millions of years the carbon had previously been out of circulation. The forest also stops accumulating once mature. It buys time and moves the problem, rather than restoring the slow-cycle burial that fossil fuels reversed. Tree carbon stays in the fast cycle and returns on death or fire

  9. Why does carbon escaping decomposition matter for the slow cycle?
    Show the full solution

    Decomposers normally return the carbon in dead tissue to the atmosphere within months or years, keeping it in the fast cycle. Where conditions prevent that, typically waterlogged oxygen-poor sediment, the material accumulates and can be buried, compressed and eventually incorporated into rock. That burial is the only route by which carbon leaves the fast cycle for geological time, and it is how coal, oil and gas formed. The slow cycle is therefore built entirely from decomposition's failures. Burial of undecomposed material is the only route out of the fast cycle

  10. The ocean absorbs part of the excess carbon dioxide. Explain why this is not simply good news.
    Show the full solution

    The uptake slows the rise in atmospheric concentration, which is a real benefit, but the carbon does not vanish. Dissolved carbon dioxide reacts with water to form carbonic acid, lowering ocean pH, and more acidic water makes it harder for corals, molluscs and some plankton to build calcium carbonate shells and skeletons. Since many of those organisms sit at the base of marine food webs, the cost is transferred from the atmosphere to the ocean rather than removed, which is a trade rather than a solution. It transfers the problem to ocean chemistry, harming shell-builders

Lesson 4.3 · Unit 4 · HS-LS2-5

The nitrogen cycle, and why bacteria run it

Nitrogen makes up about 78 percent of the atmosphere, and almost nothing alive can use it. Every organism needs nitrogen for amino acids and for the bases of DNA, and every one of them depends on a small group of bacteria to convert it into a form that can be absorbed. No other cycle is so completely in the hands of microorganisms.

The key ideas
  1. Atmospheric nitrogen is N2, held together by a triple bond that takes a great deal of energy to break. Plants and animals cannot break it.
  2. Nitrogen fixation converts N2 to ammonia or ammonium, carried out by nitrogen-fixing bacteria, some free living in soil and some in legume root nodules. Lightning fixes a small amount.
  3. Nitrification converts ammonium to nitrite and then to nitrate, by two groups of nitrifying bacteria. Nitrate is the form most plants absorb.
  4. Assimilation is uptake and incorporation of nitrate into amino acids, proteins and nucleic acids by plants, and then by animals eating them.
  5. Ammonification returns nitrogen from dead tissue and waste to ammonium, carried out by decomposers.
  6. Denitrification returns nitrate to N2, by denitrifying bacteria in oxygen-poor soils, completing the cycle and removing nitrogen from the soil.

Where students lose marks: writing that plants absorb nitrogen from the air. They absorb nitrate ions from soil water through their roots. The nitrogen in a leaf came from the atmosphere originally, but it arrived through bacteria and soil, not through the stomata.

Worked example

The task. Trace one nitrogen atom from the air into a protein in a cow, and back to the air, naming the process and the organism at each step.

Step one: fixation. The atom starts as part of an N2 molecule in the soil air. A nitrogen-fixing bacterium in a clover root nodule breaks the triple bond, using energy from sugars the plant supplies, and produces ammonium.

Step two: nitrification, first stage. A nitrifying bacterium oxidizes the ammonium to nitrite. This releases energy the bacterium uses, so the process is not a favor to the plant.

Step three: nitrification, second stage. A second group of nitrifying bacteria oxidizes nitrite to nitrate. Nitrate is highly soluble and is the form most plant roots take up.

Step four: assimilation. The clover absorbs the nitrate in soil water, reduces it, and builds it into an amino acid, then into a protein in a leaf cell.

Step five: consumption. A cow eats the clover, digests the protein to amino acids, absorbs them, and reassembles them into its own proteins. The atom is now in muscle.

Step six: ammonification. The cow excretes urea, or eventually dies. Decomposing bacteria and fungi convert the nitrogen in that organic matter back to ammonium in the soil, where it can be nitrified and used again.

Step seven: denitrification closes the loop. In a waterlogged patch of soil with little oxygen, denitrifying bacteria use nitrate instead of oxygen in respiration and release N2 back to the atmosphere. The atom has returned to where it began, and only bacteria can send it back.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What proportion of the atmosphere is nitrogen, and why can plants not use it?
    Show the full solution

    About 78 percent, and the triple bond in N2 is too strong for them to break

  2. Name the process that converts N2 to ammonium.
    Show the full solution

    Nitrogen fixation

  3. What does nitrification produce, and why does it matter?
    Show the full solution

    Nitrate, which is the form most plants absorb

  4. Which process returns nitrogen from dead tissue to the soil?
    Show the full solution

    Ammonification, by decomposers

  5. Which process returns nitrogen to the atmosphere?
    Show the full solution

    Denitrification, by denitrifying bacteria in oxygen-poor soil

  6. Explain why a farmer might plant clover in a field between crops.
    Show the full solution

    Clover is a legume, and its root nodules house nitrogen-fixing bacteria that convert atmospheric N2 into ammonium. Growing clover therefore adds usable nitrogen to the soil rather than depleting it, and plowing the crop in releases that nitrogen through ammonification as the tissue decomposes. Since nitrogen is usually the nutrient limiting crop yield, this restores fertility without manufactured fertilizer, which is why the practice long predates any understanding of the bacteria involved. Its root nodule bacteria fix atmospheric nitrogen, restoring soil fertility

  7. Why is waterlogging bad for soil fertility, in nitrogen terms?
    Show the full solution

    Water displaces air from the soil spaces, so oxygen becomes scarce. Denitrifying bacteria thrive in those conditions because they can respire using nitrate in place of oxygen, and doing so converts nitrate into nitrogen gas that escapes to the atmosphere. The soil therefore loses precisely the form of nitrogen plants can absorb. At the same time the low oxygen slows the nitrifying bacteria that would replace it, so losses rise while resupply falls. Low oxygen favors denitrification, which strips nitrate from the soil

  8. Explain why the nitrogen cycle depends more completely on bacteria than the carbon cycle does.
    Show the full solution

    Every step of the nitrogen cycle that changes the chemical form of nitrogen is carried out by bacteria: fixation, both stages of nitrification, and denitrification, with only ammonification shared with fungi. No plant or animal can perform any of them. The carbon cycle is quite different, since plants fix carbon themselves through photosynthesis and all organisms return it through respiration, so carbon can move through its cycle without any bacterial step at all. Remove the bacteria and the nitrogen cycle stops entirely. Bacteria perform every form-changing step, which no plant or animal can do

  9. A plant is grown in distilled water with all minerals except nitrate. Predict and explain the result.
    Show the full solution

    The plant grows poorly and turns yellow, particularly in its older leaves. Nitrogen is required to build amino acids and therefore all proteins, including enzymes, and it is a component of chlorophyll, so a shortage limits both growth and photosynthesis. The yellowing appears first in older leaves because the plant moves the limited nitrogen it has to the growing tips, where it is most needed. Photosynthesis is not directly blocked, since light, water and carbon dioxide are all present, but the machinery cannot be built. Stunted growth and yellowing, since nitrogen is needed for proteins and chlorophyll

  10. Why does the nitrogen in a leaf not enter through the leaf?
    Show the full solution

    Leaves exchange gases with the air through stomata, but the nitrogen in air is N2, which the plant has no means of breaking apart. The nitrogen in its proteins arrived as nitrate ions dissolved in soil water, absorbed by root hairs and carried upward in the xylem. The atoms did come from the atmosphere originally, but only after nitrogen-fixing and nitrifying bacteria converted them into an absorbable form in the soil, so the route is through the roots rather than the leaf surface. Leaves cannot use N2; nitrate enters through the roots

Lesson 4.4 · Unit 4 · HS-LS2-5, HS-LS2-7

The phosphorus cycle and eutrophication in sequence

Phosphorus has no gas phase worth speaking of, which makes its cycle the slowest and most local of the three. It is also the nutrient that most often limits growth in fresh water, and that combination produces eutrophication: a chain of six events that students routinely put in the wrong order.

The key ideas
  1. Phosphorus has no significant atmospheric phase. It does not circulate through the air, so it moves only through rock, soil, water and organisms.
  2. The source is weathering of rock, which releases phosphate ions slowly into soil and water. This makes phosphorus naturally scarce.
  3. Plants absorb phosphate and build it into DNA, RNA, ATP and phospholipid membranes. Animals obtain it by eating.
  4. It returns through decomposition and is eventually washed to the sea, where it settles into sediment and may be locked up for millions of years until uplift exposes the rock again.
  5. Phosphate is often the limiting nutrient in fresh water, so adding it from fertilizer runoff or sewage produces a large response.
  6. Eutrophication has a strict causal order, and the oxygen loss comes from decomposers, not from the algae themselves.

Where students lose marks: writing that the algae use up the oxygen. Algae photosynthesize and release oxygen during the day. The oxygen crash is caused by bacteria respiring the enormous quantity of dead algae, and naming the wrong organism loses the mark even when the rest is right.

Worked example

The task. A lake beside arable farmland develops a green surface film in spring, and by midsummer dead fish are found. Write the sequence in correct causal order.

Step one: the input. Rain washes phosphate fertilizer from the fields into the lake. Nitrate usually arrives with it, but in fresh water phosphate is normally the limiting nutrient, so it drives the response.

Step two: the algal bloom. Algae and cyanobacteria were previously limited by phosphate supply. With that limit removed they reproduce rapidly and form a dense layer at the surface, which is the green film.

Step three: light is blocked. The surface layer shades the water below, so submerged rooted plants and deeper algae receive too little light to photosynthesize, and they die.

Step four: a large mass of dead material accumulates. The dead submerged plants are joined by the algae themselves, which are short lived and die in vast numbers as the bloom exhausts the nutrient pulse.

Step five: decomposers respond. Bacteria feeding on this material multiply enormously. This is the step that does the damage, and it is a density-dependent response to a sudden food supply.

Step six: oxygen collapses. The bacteria respire aerobically, consuming dissolved oxygen faster than it can dissolve in from the air or be produced by the remaining photosynthesis. Concentrations fall sharply, exactly as in the sag curve from lesson 1.4.

Step seven: fish and invertebrates die. They cannot extract enough oxygen from the water. Species with high oxygen demands die first, which is why the composition of the surviving community is itself evidence about what happened.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What makes the phosphorus cycle different from the carbon and nitrogen cycles?
    Show the full solution

    It has no significant atmospheric phase

  2. What is the natural source of phosphate?
    Show the full solution

    Weathering of rock

  3. Name three biological molecules that contain phosphorus.
    Show the full solution

    DNA, RNA, ATP and phospholipids

  4. Which organisms cause the oxygen crash in eutrophication?
    Show the full solution

    Decomposing bacteria respiring the dead material

  5. Put in order: oxygen falls, algal bloom, fish die, nutrient enters, light blocked, decomposers multiply.
    Show the full solution

    Nutrient enters, algal bloom, light blocked, decomposers multiply, oxygen falls, fish die

  6. Explain why saying "the algae use up the oxygen" is wrong.
    Show the full solution

    Algae are photosynthetic, so during daylight they release oxygen rather than consuming it, and a healthy bloom raises daytime oxygen concentrations. They do respire, but their net contribution while alive is positive. The crash comes after they die, when bacteria decomposing the enormous mass of dead algae and shaded plants respire aerobically on a scale the water cannot supply. Naming the algae rather than the decomposers identifies the wrong organism at the critical step of the sequence. Living algae release oxygen; the bacteria decomposing them consume it

  7. Why is phosphorus naturally scarce in most ecosystems?
    Show the full solution

    It has no gas phase, so unlike carbon and nitrogen it cannot be drawn from a large atmospheric reservoir available everywhere. Its only natural source is the slow weathering of phosphate-bearing rock, which releases small quantities over long periods. Once washed into the sea it settles into sediment and can be locked away for millions of years until geological uplift exposes it again. Scarce supply and slow return together keep environmental concentrations low, which is why adding it produces such a dramatic response. No atmospheric reservoir, slow release by weathering, and long burial in sediment

  8. Two lakes receive the same phosphate input, but only one develops a severe bloom. Suggest reasons.
    Show the full solution

    Phosphate may not be the limiting factor in the second lake: if light, nitrate or temperature limits its algae, extra phosphate changes little. The lakes may also differ in residence time, since a lake flushed in days exports the nutrient before algae can respond while a slow-turnover lake retains it. Depth and mixing matter too, as a deep well-mixed lake dilutes the input through a large volume, and a healthy population of zooplankton grazing the algae can suppress a bloom before it forms. Phosphate may not be limiting there, or flushing, depth and grazing may differ

  9. Explain why the species of fish that survive tell you something about the cause.
    Show the full solution

    Species differ in how much dissolved oxygen they require, so a low oxygen event kills them in a predictable order rather than at random. Trout and other demanding species die first, while carp and some invertebrates tolerate low concentrations and persist. Finding a community reduced to tolerant species is therefore evidence that oxygen was the killing factor, which points to decomposition following enrichment rather than to a toxin, since a poison would not sort the community by oxygen requirement. Oxygen-demanding species die first, so the surviving community identifies oxygen as the cause

  10. Suggest two ways to reduce eutrophication, and say which step of the sequence each interrupts.
    Show the full solution

    Removing phosphate from sewage before discharge and applying fertilizer at rates crops can absorb both cut the input at step one, preventing the whole chain from starting, which is the most effective point to act. Planting uncultivated buffer strips of vegetation between fields and watercourses also acts at step one by intercepting runoff. Aerating a lake mechanically attacks step six instead, replacing the oxygen the decomposers consume, which treats the symptom and must be maintained indefinitely. Cut the nutrient input at the start, or aerate to offset the oxygen loss near the end

Lesson 4.5 · Unit 4 · HS-LS2-6, HS-ESS2-2

Feedback loops: damping and amplifying

A feedback loop exists when the output of a process comes back and changes the process. There are only two kinds, and which one a system has determines whether it is stable or runs away. The vocabulary is unfortunate: positive feedback is very often bad news.

The key ideas
  1. Negative feedback opposes the change that produced it. A rise triggers something that lowers it, so the system is pushed back toward a set point.
  2. Positive feedback reinforces the change. A rise triggers something that raises it further, so the system accelerates away from where it started.
  3. Positive does not mean beneficial and negative does not mean harmful. The words describe the direction of the effect on the original change, nothing more.
  4. Negative feedback produces stability, and it is how body temperature, blood glucose and population size near carrying capacity are all held steady.
  5. Positive feedback produces rapid change and must be stopped by something outside the loop. Childbirth contractions and blood clotting are useful examples.
  6. To identify a loop, state it as a circle and check the final arrow: does it increase or decrease the thing you started with?

Where students lose marks: describing a one-way chain and calling it feedback. Feedback requires the loop to close. If your description does not return to its starting variable, you have written a sequence, not a feedback loop.

Worked example

Part one: a negative loop. Human body temperature, which is held near 37 degrees Celsius.

Step one: state the change. Core temperature rises above the set point, perhaps through exercise.

Step two: state the response. Receptors detect the rise, the brain triggers sweating and widening of skin blood vessels, and heat loss increases.

Step three: close the loop and check the sign. Increased heat loss lowers core temperature, back toward the set point. The response opposed the original change, so this is negative feedback, and the result is stability.

Part two: a positive loop. The ice albedo effect.

Step four: state the change. Average temperature rises slightly, and some sea ice melts.

Step five: state the response. Ice is white and reflects most of the sunlight hitting it. Open ocean is dark and absorbs most of it. Replacing ice with water means more solar energy is absorbed rather than reflected.

Step six: close the loop and check the sign. More absorbed energy raises the temperature further, which melts more ice. The response reinforced the original change, so this is positive feedback, and it amplifies whatever started it.

Step seven: note what each loop implies for prediction. A system governed by negative feedback returns to its set point after a disturbance, so it can be treated as stable. A system with a strong positive loop can move rapidly and far from a small initial push, and it will not stop on its own, which is why positive feedbacks dominate discussions of climate risk.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What does negative feedback do to a change?
    Show the full solution

    It opposes it, pushing the system back toward a set point

  2. What does positive feedback do?
    Show the full solution

    It reinforces the change, amplifying it

  3. Does positive feedback mean a good outcome?
    Show the full solution

    No; it describes the direction of the effect, not whether it is beneficial

  4. Give one biological example of each kind.
    Show the full solution

    Negative: body temperature regulation. Positive: blood clotting or childbirth contractions

  5. Why is ice albedo a positive loop?
    Show the full solution

    Melting ice exposes dark water that absorbs more energy, raising temperature and melting more ice

  6. Explain why negative feedback is what makes homeostasis possible.
    Show the full solution

    Homeostasis means holding an internal condition near a constant value despite changes outside, and that requires a mechanism that detects a departure and acts to reverse it. Negative feedback does exactly this: a rise triggers a response that lowers, a fall triggers one that raises, so the variable is pushed toward the set point from either direction. Positive feedback would do the opposite, driving the variable further from the set point once it moved, which is incompatible with maintaining a stable internal state. It reverses departures from the set point from either direction

  7. Explain why a positive feedback loop must be stopped by something outside itself.
    Show the full solution

    By construction the loop makes the change larger, so nothing within it ever reduces the driver, and it contains no mechanism for stopping. Left alone it accelerates until some external limit intervenes: childbirth contractions intensify until the baby is delivered and the stretch stimulus is removed, and clotting accelerates until the damaged surface is sealed. In each case the terminating event comes from outside the loop. This is why positive feedbacks in the climate system are treated so seriously. The loop only amplifies, so termination must come from outside

  8. Thawing permafrost releases methane, a greenhouse gas. Classify the loop and explain.
    Show the full solution

    Positive feedback. Warming thaws permafrost that has been frozen for millennia, decomposition of the newly available organic matter releases methane and carbon dioxide, those gases increase the greenhouse effect, temperatures rise further, and more permafrost thaws. The loop closes on its starting variable and each step reinforces rather than opposes the original warming. Nothing within the sequence slows it down, which is why it is treated as one of the more serious amplifying mechanisms in the climate system. Positive: warming releases gases that cause more warming

  9. A student describes predator and prey cycles as positive feedback. Correct them.
    Show the full solution

    It is negative feedback with a time lag. Rising prey numbers lead to rising predator numbers, which then reduce the prey, and falling prey numbers reduce the predators, which lets the prey recover. Each half of the loop opposes the change that produced it, which is the definition of negative feedback, so the system is regulated rather than running away. The oscillation comes from the delay in the response rather than from amplification: without the lag the two populations would settle at a steady point. Negative feedback with a lag, which produces cycling rather than runaway

  10. Why does the distinction between the two kinds matter for predicting climate?
    Show the full solution

    Because it determines whether a small initial change stays small. If the dominant loops are negative, the system absorbs a disturbance and returns close to where it was, and a modest forcing produces a modest response. If strong positive loops exist, the same forcing is amplified, and effects can be far larger than the original push and can continue after the push stops. Identifying which loops operate, and how strong each is, is therefore the central problem in projecting how much warming a given emission produces. Positive loops amplify a small forcing into a large response, negative loops absorb it

Lesson 4.6 · Unit 4 · HS-ESS2-4, HS-ESS3-5

Reading a long atmospheric record

Continuous measurement of atmospheric carbon dioxide began at Mauna Loa in Hawaii in 1958 and has continued ever since, producing one of the most examined datasets in science. It shows two things at once: a sawtooth that repeats every year, and a rise that does not. Separating them is the skill this lesson builds.

The key ideas
  1. The record is a US federal government dataset, maintained by NOAA, and is therefore public information anyone may use and check.
  2. The annual sawtooth is biological. Concentration falls through the northern summer and rises through the northern winter.
  3. The northern hemisphere drives it because it holds most of the world's land and therefore most of the world's seasonal vegetation.
  4. The long-term rise is the trend, and it continues across every season, so it cannot be explained by the seasonal cycle.
  5. The rise is accelerating, so the average annual increase over recent decades is larger than over earlier ones.
  6. A trend alone does not establish a cause. Attributing it requires other evidence, including the isotopic signature of the added carbon and the falling oxygen concentration that combustion predicts.

Where students lose marks: explaining the seasonal dip by saying plants photosynthesize more in summer without saying which hemisphere or why that matters. The asymmetry of land between the hemispheres is the whole reason a global average has a seasonal signal at all.

Worked example

The data. Approximate annual mean carbon dioxide concentration at Mauna Loa, in parts per million, rounded from the NOAA record.

Year1960198020002020
Carbon dioxide (ppm)317339369414

Step one: describe before explaining. Concentration rose throughout, from 317 ppm in 1960 to 414 ppm in 2020, an increase of 97 ppm over 60 years.

Step two: find the mean annual rate. 97 divided by 60 is about 1.6 ppm per year averaged across the whole period.

Step three: test whether the rate is constant. From 1960 to 1980 the rise was 339 minus 317, which is 22 ppm over 20 years, or 1.1 ppm per year.

Step four: compare the recent period. From 2000 to 2020 the rise was 414 minus 369, which is 45 ppm over 20 years, or 2.25 ppm per year. That is roughly double the earlier rate.

Step five: state the finding precisely. The concentration is not merely rising; the rate of rise has approximately doubled between the 1960s and the 2010s. Describing it as a steady increase would miss the most important feature.

Step six: explain the seasonal sawtooth. Most of the planet's land is in the northern hemisphere, so most seasonal vegetation grows there together. Northern spring and summer growth draws carbon dioxide down; northern autumn and winter decomposition and reduced photosynthesis let it rise. The whole globe shows a northern signal.

Step seven: state what the trend alone cannot establish. It shows that concentration is rising and accelerating, not why. Attribution rests on further evidence: the added carbon has the isotopic signature of ancient plant material rather than volcanic carbon, and atmospheric oxygen is falling in the ratio that combustion predicts.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Where and when did the continuous record begin?
    Show the full solution

    Mauna Loa, Hawaii, in 1958

  2. What causes the annual sawtooth?
    Show the full solution

    Seasonal photosynthesis and decomposition, dominated by northern hemisphere vegetation

  3. Calculate the mean annual rise between 1960 and 2020 from the table.
    Show the full solution

    97 ppm over 60 years, which is about 1.6 ppm per year

  4. What was the rate between 2000 and 2020?
    Show the full solution

    45 ppm over 20 years, which is 2.25 ppm per year

  5. Why can this dataset be used and republished freely?
    Show the full solution

    It is a US federal government dataset, maintained by NOAA

  6. Explain why the seasonal cycle cannot account for the long-term rise.
    Show the full solution

    The seasonal cycle is a closed loop that returns to its starting point each year: carbon drawn down by northern summer growth is released again by autumn and winter decomposition, so its net effect over any whole year is approximately zero. The long-term trend is visible when comparing the same month across different years, which removes the seasonal component entirely, and it still rises. A repeating oscillation cannot generate a sustained increase, no matter how large its amplitude. The seasonal loop nets to zero annually, so it cannot produce a sustained rise

  7. Why does the northern hemisphere dominate the seasonal signal?
    Show the full solution

    Because the great majority of the world's land area lies north of the equator, and land is where seasonal vegetation grows. The southern hemisphere is largely ocean, whose phytoplankton do not produce a comparable synchronized annual pulse. Northern forests and croplands therefore green and senesce together, producing a drawdown and release large enough to appear in the global average. If land were distributed evenly, the two hemispheres' opposite seasons would largely cancel and the sawtooth would be much smaller. Most land, and therefore most seasonal vegetation, is in the north

  8. A student says the graph proves humans caused the rise. Explain what more is needed.
    Show the full solution

    The graph establishes that concentration is rising and accelerating, which is a description rather than an attribution, and by itself it is consistent with any source of carbon. Establishing the cause needs evidence that identifies the carbon: the isotopic composition of the added carbon dioxide matches ancient plant material rather than volcanic sources, atmospheric oxygen is declining in the ratio combustion predicts, and the measured rise is consistent with recorded fuel consumption after accounting for ocean and land uptake. Isotopic signature, falling oxygen, and consistency with recorded fuel use

  9. Why is comparing the same month across years a better method than comparing consecutive months?
    Show the full solution

    Because consecutive months differ for two reasons at once, the season and the trend, and the seasonal swing is much larger over a few months than the trend is. A fall from May to September reflects northern summer growth and says nothing about the long-term direction. Comparing every May with every previous May holds the seasonal position constant so that only the trend remains, which is the standard way of separating a cycle from an underlying change in any dataset. It holds the seasonal position constant so only the trend remains

  10. Using lesson 4.2, explain why the concentration keeps rising even though photosynthesis removes far more carbon each year than burning fuel adds.
    Show the full solution

    Photosynthesis is one arm of a balanced loop: almost all the carbon it removes is returned within years by respiration and decomposition, so however large the flux, its net effect on the reservoir is close to zero. Fossil fuel burning has no matching return, since nothing is burying carbon into rock at a comparable rate, so it is an unmatched addition. The atmosphere accumulates the difference between additions and removals rather than responding to the size of any single flux. Photosynthesis is matched by respiration, while fossil carbon is added unmatched

Unit 4 review · Matter Cycles and the Earth System

Ten questions across the whole unit

Questions 1 to 5 check that you hold the terms. Questions 6 to 10 require you to reason across the six lessons.

  1. Distinguish a reservoir from a flux.
    Show the full solution

    A reservoir is a store measured as an amount; a flux is a transfer measured as an amount per unit time

  2. A lake holds 84,000 cubic meters with an inflow of 7,000 per day. Find the residence time.
    Show the full solution

    12 days

  3. Which process converts atmospheric nitrogen into a usable form, and what carries it out?
    Show the full solution

    Nitrogen fixation, by nitrogen-fixing bacteria

  4. Put the eutrophication sequence in order: oxygen falls, decomposers multiply, nutrient enters, fish die, algal bloom, light blocked.
    Show the full solution

    Nutrient enters, algal bloom, light blocked, decomposers multiply, oxygen falls, fish die

  5. What does positive feedback do to a change?
    Show the full solution

    It reinforces and amplifies it

  6. Explain why burning fossil fuel changes the atmosphere when photosynthesis moves twelve times more carbon each year.
    Show the full solution

    Size is not what matters; balance is. Photosynthesis is matched almost exactly by respiration and decomposition returning the same carbon, so those two enormous fluxes cancel and leave the reservoir unchanged. Fossil fuel burning has no matching removal, because nothing is burying carbon back into rock at a comparable rate, so every unit of it accumulates. A small unmatched flux changes a reservoir while a vast balanced pair does not. Large fluxes cancel; a small unmatched one accumulates

  7. Explain why a long residence time makes a pollution problem harder to solve.
    Show the full solution

    Residence time measures how fast a reservoir's contents are replaced, so a long one means no substantial flux is carrying material away. A contaminant entering such a store is diluted and flushed slowly and stays available to organisms drawing on it for the whole turnover period. An aquifer with a residence time of decades will still contain the pollutant long after the source is shut off, which is why groundwater contamination is treated far more seriously than a river spill. No fast flux removes it, so it persists for the length of the turnover

  8. Explain why saying "the algae use up the oxygen" misidentifies the mechanism of eutrophication.
    Show the full solution

    Algae are photosynthetic, so in daylight they release oxygen rather than consuming it, and a healthy bloom raises daytime oxygen concentrations. The crash comes afterward, when bacteria decomposing the enormous mass of dead algae and light-starved plants respire aerobically on a scale the water cannot supply. Naming the algae rather than the decomposers identifies the wrong organism at the critical step, which is where the marks are. Living algae release oxygen; the bacteria decomposing them consume it

  9. Classify the ice albedo effect and explain why a positive loop must be stopped from outside.
    Show the full solution

    It is positive feedback: warming melts ice, exposing darker ocean that absorbs more solar energy than the ice reflected, which raises temperature further and melts more ice. Because every step reinforces the original change, nothing within the loop reduces the driver, so it contains no mechanism for stopping. Termination has to come from outside it, which is why positive feedbacks dominate assessments of climate risk. Positive feedback, and it contains no self-limiting step

  10. Explain why a rising carbon dioxide trend does not by itself establish its cause.
    Show the full solution

    A trend is a description of what the measured quantity is doing and is consistent with any source of carbon. Establishing the cause requires evidence identifying the carbon: the isotopic composition of the added carbon dioxide matches ancient plant material rather than volcanic sources, atmospheric oxygen is falling in the ratio combustion predicts, and the observed rise is consistent with recorded fuel use once ocean and land uptake are accounted for. A trend describes; attribution needs isotopic, oxygen and fuel-use evidence

Lesson 5.1 · Unit 5 · HS-LS1-1, HS-LS1-2

Cell theory, and the evidence that took two centuries

Cell theory is three short statements, and every one of them had to be established against a serious alternative. The third took longest, because the idea that living things arise spontaneously from non-living material was not stupid: it fitted everyday observation, and defeating it required an experiment of real ingenuity.

The key ideas
  1. All living things are made of one or more cells. This followed from improved microscopes and from looking at enough different organisms.
  2. The cell is the basic unit of structure and function in living things: the smallest thing that is itself alive.
  3. All cells come from pre-existing cells. This is the statement that denies spontaneous generation, and it was the hardest to establish.
  4. Hooke saw and named cells in 1665, examining cork with a compound microscope. He was looking at the empty walls of dead plant cells, not at living contents.
  5. Leeuwenhoek saw living single-celled organisms in the 1670s with simple single-lens microscopes of remarkable quality, establishing that entire organisms could consist of one cell.
  6. Pasteur's swan-neck flask experiment settled the third statement: broth in a flask whose neck admitted air but trapped dust stayed sterile indefinitely, and spoiled within days once the neck was broken.

Where students lose marks: saying Pasteur proved spontaneous generation false by boiling broth. Boiling alone had been done before and was dismissed, because critics said it destroyed a vital principle in the air. The swan neck is the whole point: it let air in and kept dust out, which is what made the result decisive.

Worked example

The source. Robert Hooke, Micrographia, 1665, describing a thin slice of cork under his microscope. Public domain.

I could exceeding plainly perceive it to be all perforated and porous, much like a Honey-comb, but that the pores of it were not regular.

Step one: notice what he actually reports. Holes. He describes a structure, compares it to something familiar, and notes where the comparison fails. There is no claim about life in the sentence at all.

Step two: identify what he was looking at. Cork is dead tissue, so the boxes he saw were cell walls with nothing inside. He named the empty spaces, which is why the word cell means a small room.

Step three: state the limit of this evidence. Hooke established that plant tissue has a repeating compartmental structure. He did not establish that those compartments are the units of life, nor that animals have them.

Step four: add Leeuwenhoek's contribution. Within a decade he was describing moving single-celled organisms in pond water and scrapings from teeth. That extended the picture from compartments in dead plant tissue to living things that are one cell in total.

Step five: set up the remaining problem. Even granting that living things are made of cells, where does a new cell come from? Broth left out grows cloudy with microorganisms, and for two centuries the natural reading was that they formed from the broth.

Step six: design the decisive experiment. Pasteur boiled broth in a flask drawn into a long curved neck. Air could pass freely, so any vital principle in the air could reach the broth, but dust and microorganisms settled in the bend and never arrived. The broth stayed clear for months.

Step seven: identify the control that closes the argument. Snapping the neck off an identical flask let dust reach the broth, and it spoiled within days. Same broth, same boiling, same air: the only variable was access for airborne particles. That is the design from lesson 1.2, and it is why the result settled the question.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. State the three parts of cell theory.
    Show the full solution

    All living things are made of cells; the cell is the basic unit of structure and function; all cells come from pre-existing cells

  2. What was Hooke looking at, and in what year?
    Show the full solution

    Cork, in 1665; the empty walls of dead plant cells

  3. What did Leeuwenhoek add?
    Show the full solution

    Observations of living single-celled organisms

  4. What idea did Pasteur's experiment defeat?
    Show the full solution

    Spontaneous generation

  5. What did the swan neck allow in, and what did it exclude?
    Show the full solution

    It allowed air in and trapped dust and microorganisms in the bend

  6. Explain why the shape of the flask neck mattered more than the boiling.
    Show the full solution

    Boiling sealed flasks had been done before and had not convinced anyone, because defenders of spontaneous generation argued that sealing excluded some vital principle in the air that living things needed to form. The swan neck removed that objection by leaving the flask open: air moved freely in and out, so any such principle had full access, while the bend trapped settling dust. The neck therefore isolated the single variable in dispute, which is exactly what the earlier experiments had failed to do. It admitted air while excluding dust, removing the vital principle objection

  7. Identify the independent variable, dependent variable and control in Pasteur's experiment.
    Show the full solution

    The independent variable is whether airborne dust can reach the broth, manipulated by leaving the swan neck intact or snapping it off. The dependent variable is whether the broth becomes cloudy with microbial growth, and how quickly. The intact-neck flask serves as the comparison condition showing what happens without dust access. Everything else is controlled: the same broth, the same boiling, the same temperature, the same flask, and free access to air in both cases. Dust access is independent, microbial growth is dependent, and the intact flask is the comparison

  8. Why did Hooke's observation not by itself establish cell theory?
    Show the full solution

    He observed a repeating compartmental structure in one dead plant tissue, which supports none of the three statements on its own. It does not show that animals are similarly built, since cork is not representative of life generally; it does not show the compartments are units of function, since what he saw were empty walls with no contents; and it says nothing about where new cells come from. Establishing a general theory required observations across many organisms and, for the third statement, a controlled experiment. One dead plant tissue supports none of the three statements generally

  9. Spontaneous generation fitted everyday observation. Explain why, and what that teaches.
    Show the full solution

    Meat left out grows maggots, broth turns cloudy, and grain stores fill with mice, all apparently from nothing, so the idea was an economical reading of what people could actually see. It was wrong because the relevant causes were too small or too quick to observe: flies laying eggs, airborne spores settling. The lesson is that a theory can fit all the available observations and still be false, which is why controlled experiments that exclude one specific cause are worth more than any quantity of casual observation. It fitted the visible evidence, showing that observation alone cannot settle causes

  10. Why is "all cells come from pre-existing cells" the most far-reaching of the three statements?
    Show the full solution

    Because it makes every living cell part of an unbroken chain of division stretching back through time, which means all life is connected by descent rather than arising repeatedly and independently. That single claim underlies the continuity of heredity, since genetic material must be copied and passed at each division, and it underlies common ancestry, which unit 10 develops. It also implies that a sterile environment stays sterile, which is the basis of food preservation, antiseptic surgery and every technique in microbiology. It makes all life a single unbroken chain of division, grounding heredity and common ancestry

Lesson 5.2 · Unit 5 · HS-LS1-2

Prokaryotic and eukaryotic cells compared

The deepest division among living things is not plant against animal. It is between cells that keep their DNA in a membrane-bound nucleus and cells that do not. That one difference comes with a cluster of others, and it separates bacteria from every plant, animal, fungus and protist on the planet.

The key ideas
  1. Prokaryotic cells have no nucleus and no membrane-bound organelles. Their DNA sits in the cytoplasm in a region called the nucleoid.
  2. Eukaryotic cells have a true nucleus enclosed by a double membrane, along with mitochondria, endoplasmic reticulum and other compartments.
  3. No nucleus does not mean no DNA. Prokaryotes have a single circular chromosome, usually with small extra rings called plasmids.
  4. Prokaryotes are much smaller, typically 1 to 2 micrometers against 10 to 100 for a eukaryotic cell, which matters for the exchange argument in lesson 5.4.
  5. Both have ribosomes, a cell membrane, cytoplasm and DNA. The shared features are as informative as the differences, because they point to common ancestry.
  6. Compartments allow specialization. Separating incompatible reactions into organelles is what permits the size and complexity of eukaryotic cells.

Where students lose marks: listing prokaryotes as "simple" and leaving it there. They are structurally simpler and metabolically far more diverse than eukaryotes: nitrogen fixation, chemosynthesis and most forms of anaerobic respiration are exclusively prokaryotic abilities.

Worked example

The task. Build the comparison systematically rather than memorizing a list, then use it.

FeatureProkaryoticEukaryotic
Nucleusabsent, DNA in nucleoidpresent, double membrane
DNA formsingle circular chromosome, plus plasmidsseveral linear chromosomes
Membrane-bound organellesabsentpresent
Ribosomespresent, smallerpresent, larger
Typical size1 to 2 micrometers10 to 100 micrometers
Cell wallusually present, peptidoglycanpresent in plants and fungi, different material

Step one: find the one difference that explains the others. Internal membranes. A cell that can enclose regions can separate incompatible chemistry, concentrate enzymes, and protect DNA from the cytoplasm.

Step two: follow that to size. Without compartments a cell must run all its chemistry in one shared space, and it depends on diffusion across its whole volume. That works only if the cell stays small.

Step three: follow it to the DNA arrangement. A single circular chromosome in the cytoplasm can be copied and separated quickly, which is part of why bacteria divide in minutes while eukaryotic cells take hours.

Step four: use the shared features. Both types have a membrane, cytoplasm, ribosomes and DNA using the same genetic code. Those shared features are evidence of common ancestry, which is unit 10's argument.

Step five: apply the comparison to a real question. An antibiotic that targets peptidoglycan cell walls damages bacteria and not human cells, because human cells have no wall of that material. The comparison table predicts which drugs can be selective.

Step six: apply it to ribosomes. Prokaryotic ribosomes differ enough from eukaryotic ones that some antibiotics bind one and not the other, which is a second route to selective toxicity.

Step seven: correct the simplicity error. Prokaryotes are structurally simpler and metabolically richer. Nitrogen fixation from lesson 4.3, chemosynthesis from lesson 2.1 and denitrification are all things no eukaryote can do.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What is the defining difference between the two cell types?
    Show the full solution

    Eukaryotic cells have a membrane-bound nucleus; prokaryotic cells do not

  2. Where is prokaryotic DNA found, and in what form?
    Show the full solution

    In the nucleoid region of the cytoplasm, as a single circular chromosome

  3. Name four features both cell types share.
    Show the full solution

    Cell membrane, cytoplasm, ribosomes and DNA

  4. Give typical sizes for each.
    Show the full solution

    Prokaryotic 1 to 2 micrometers, eukaryotic 10 to 100 micrometers

  5. What is a plasmid?
    Show the full solution

    A small circular piece of DNA separate from the main chromosome in a prokaryote

  6. Explain how internal membranes allow a cell to be larger and more complex.
    Show the full solution

    Membranes let a cell run incompatible processes at once by keeping them in separate compartments, so digestive enzymes can be concentrated inside a lysosome without destroying the cytoplasm, and conditions such as pH can differ between regions. Compartments also concentrate enzymes with their substrates instead of relying on chance encounters in one large space, which keeps reaction rates workable as volume grows. Without them, every reaction would share one environment, and the compromises required would limit both size and the number of processes possible. Compartments separate incompatible chemistry and concentrate reactions locally

  7. Why does an antibiotic that disrupts peptidoglycan harm bacteria but not human cells?
    Show the full solution

    Peptidoglycan is the material of the bacterial cell wall and occurs nowhere in human cells, which have a membrane but no wall at all. A drug that blocks its synthesis therefore has a target present in one organism and absent in the other, so the bacterial cell cannot maintain its wall and bursts while human cells are unaffected. This is selective toxicity, and it is why structural differences between the two cell types are of direct medical importance rather than merely classificatory. Human cells contain no peptidoglycan, so the drug has no target in them

  8. Explain why "prokaryotes are simple organisms" is misleading.
    Show the full solution

    It is accurate about structure and badly wrong about capability. Prokaryotes lack compartments and are smaller, so their architecture is simpler, but their metabolic range far exceeds that of eukaryotes. Only prokaryotes fix atmospheric nitrogen, only they carry out chemosynthesis at vents, and they perform forms of anaerobic respiration no eukaryote can manage. They also occupy environments lethal to everything else. Calling them simple invites the assumption that they are primitive or unimportant, when the nitrogen cycle depends entirely on them. Structurally simpler but metabolically far more capable

  9. What do the shared features of the two cell types suggest, and why?
    Show the full solution

    They suggest descent from a common ancestor. Both use a phospholipid membrane, both store information in DNA, both translate it using ribosomes, and both read essentially the same genetic code. There is no functional reason the code had to be the same in two independently arising lineages, since many alternative codes would work equally well, so the shared arbitrary details are far better explained by inheritance from a single ancestral cell than by coincidence. This is the molecular evidence of lesson 10.7 in miniature. Common ancestry, since the shared genetic code is arbitrary and need not have matched

  10. Bacteria divide in minutes while eukaryotic cells take hours. Suggest why.
    Show the full solution

    A prokaryote copies a single circular chromosome sitting free in the cytoplasm and separates the two copies as the cell elongates, a short and direct process. A eukaryote must replicate several much longer linear chromosomes, break down and rebuild the nuclear envelope, assemble a spindle, align the chromosomes and separate them precisely, then divide the cytoplasm and distribute organelles. More DNA, more structures to reorganize and more checkpoints to pass all add time, and the smaller prokaryotic cell also has less material to duplicate. Less DNA and no nucleus, spindle or organelles to reorganize

Lesson 5.3 · Unit 5 · HS-LS1-2

Organelles, learned by the job they do

A list of organelles with definitions is almost impossible to remember and almost useless in an exam. The same information organized as a production line is neither. Follow one protein from the gene that specifies it to the outside of the cell, and most of the organelles appear in order, each doing one identifiable thing.

The key ideas
  1. The nucleus stores DNA and controls the cell by determining which proteins are made. Its envelope has pores through which mRNA leaves.
  2. Ribosomes build proteins from the instructions in mRNA. Some float free in the cytoplasm; others are attached to the endoplasmic reticulum.
  3. Rough endoplasmic reticulum is studded with ribosomes and handles proteins destined for export or for membranes. Smooth ER makes lipids and detoxifies.
  4. The Golgi apparatus modifies, sorts and packages proteins arriving from the ER, then dispatches them in vesicles.
  5. Mitochondria carry out aerobic respiration, releasing energy as ATP. Chloroplasts carry out photosynthesis in plant and algal cells.
  6. Lysosomes contain digestive enzymes, breaking down waste and worn organelles. Vacuoles store material; the large central vacuole of a plant cell maintains turgor.

Where students lose marks: saying mitochondria "produce energy" or "make energy". Energy is not made. They transfer energy from glucose to ATP, releasing some as heat. Write transfer, not produce, and the point is secure.

Worked example

The task. Follow a digestive enzyme from gene to secretion in a pancreatic cell, naming each organelle and what it contributes.

Step one: the nucleus. The gene for the enzyme is transcribed into mRNA. The DNA itself never leaves; a copy does, passing out through a nuclear pore.

Step two: the ribosome. The mRNA is read by a ribosome, which assembles amino acids into the polypeptide chain in the order the mRNA specifies. This is where the protein first exists.

Step three: the rough endoplasmic reticulum. Because this protein is for export, the ribosome making it is bound to the rough ER, and the growing chain is fed into the ER's interior, where it begins to fold.

Step four: transport vesicle. A piece of ER membrane buds off enclosing the protein and carries it to the Golgi. The protein never travels loose in the cytoplasm.

Step five: the Golgi apparatus. The protein is chemically modified, checked, labeled for its destination, and packaged into a new vesicle. This is the sorting office of the cell.

Step six: the secretory vesicle and the membrane. The vesicle moves to the cell membrane, fuses with it, and releases the enzyme outside by exocytosis. The vesicle's membrane becomes part of the cell membrane.

Step seven: the mitochondria, running throughout. Every step above costs ATP: transcription, translation, vesicle movement and fusion. A cell that secretes heavily is packed with mitochondria, which is a prediction you can check under a microscope and a standard exam question.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What is the function of the nucleus?
    Show the full solution

    It stores DNA and controls the cell by determining which proteins are made

  2. What do ribosomes do?
    Show the full solution

    Assemble proteins from amino acids using the instructions in mRNA

  3. What is the difference between rough and smooth ER?
    Show the full solution

    Rough ER has ribosomes and handles proteins; smooth ER makes lipids and detoxifies

  4. What does the Golgi apparatus do?
    Show the full solution

    Modifies, sorts and packages proteins into vesicles for dispatch

  5. Name the organelle that carries out aerobic respiration.
    Show the full solution

    The mitochondrion

  6. Explain why saying mitochondria "produce energy" loses a mark.
    Show the full solution

    Energy cannot be created, so nothing produces it. Mitochondria transfer energy that is already present in the bonds of glucose into the more usable form of ATP, and a substantial fraction is released as heat in the process rather than captured. Writing that they produce energy contradicts the conservation principle the whole of unit 2 rests on, and it also obscures what the mitochondrion actually does, which is convert a store the cell cannot spend directly into one it can. They transfer energy from glucose to ATP; energy is never made

  7. A cell is found to be packed with rough ER and Golgi. Predict its job and justify it.
    Show the full solution

    It is almost certainly a secretory cell, producing proteins for export, such as a pancreatic cell making digestive enzymes or a plasma cell making antibodies. Rough ER is where proteins destined for export are fed and folded, and the Golgi modifies and packages them, so large amounts of both indicate a high throughput along that particular route. A cell making proteins only for its own cytoplasm would rely on free ribosomes and need neither organelle in quantity. A secretory cell, since that pathway handles proteins for export

  8. Why does a muscle cell contain many mitochondria?
    Show the full solution

    Contraction requires ATP continuously, both to drive the sliding of the filaments and to reset the cell afterward, and a muscle cell can demand that energy at very high rates during activity. Since cells store only small amounts of ATP, supply must match demand almost moment to moment, which requires a large capacity for aerobic respiration. Numerous mitochondria provide it, and the pattern is general: mitochondrial density across cell types tracks how much ATP each type uses. Contraction demands ATP continuously, and ATP cannot be stored in quantity

  9. Why must a lysosome's enzymes be enclosed in a membrane?
    Show the full solution

    They are digestive enzymes capable of breaking down proteins, lipids and nucleic acids, which is to say the materials the cell itself is built from. Released into the cytoplasm they would destroy the cell's own structures indiscriminately. The membrane confines them to a compartment where the pH is also kept low enough for them to work, which the cytoplasm is not, so even leakage is partly self-limiting. This is the clearest single illustration of why compartmentalization matters. They would digest the cell's own structures if released

  10. Explain why the protein in the worked example never travels loose through the cytoplasm.
    Show the full solution

    Keeping it inside membrane-bound compartments at every stage serves several purposes at once. It prevents a digestive enzyme from acting on the cell's own contents, it keeps the protein with the modifying enzymes it needs to meet in sequence, and it allows the cell to direct the product to a specific destination by labeling the vesicle rather than relying on diffusion. Vesicle transport also lets the cell move large quantities in one operation and control the timing of release. Enclosure protects the cell, keeps the sequence ordered, and allows targeted delivery

Lesson 5.4 · Unit 5 · HS-LS1-2, HS-LS1-3

Surface area to volume, and the limit on cell size

Lesson 1.7 established the arithmetic: doubling an object's size halves its surface to volume ratio. Here that fact becomes a biological constraint. Everything a cell needs crosses its surface, everything that needs supplying is in its volume, and diffusion over distance is slow. Together these set a ceiling on how large a cell can be.

The key ideas
  1. Exchange happens at the surface. Oxygen, glucose, ions and waste all cross the membrane, so supply capacity scales with area.
  2. Demand comes from the volume. The quantity of living material needing supply scales with the cube of the linear size, while area scales with the square.
  3. Diffusion is slow over distance. Time taken rises with the square of the distance, so doubling the distance to the center quadruples the time.
  4. Cells therefore divide rather than enlarge, keeping each unit small enough to serve its interior.
  5. Specialized cells beat the limit by changing shape, with microvilli, flattened profiles or long thin extensions raising area without adding much volume.
  6. Large organisms need transport systems for the same reason: diffusion across an outer surface cannot serve a body measured in centimeters.

Where students lose marks: saying big cells cannot get enough oxygen "because they are too big". State the mechanism: area grows with the square of the linear dimension while volume grows with the cube, so the ratio falls, and the diffusion distance to the center also rises.

Worked example

The model. Cubes of agar containing an indicator are placed in dye. The dye diffuses inward at the same rate in every block, penetrating 0.5 cm during the experiment. This is a standard laboratory model for a cell.

Step one: the 1 cm cube. Dye enters 0.5 cm from every face. Since the cube is only 1 cm across, the fronts meet in the middle and the whole block is colored. Fraction reached: 100 percent.

Step two: the 2 cm cube, outer layer. Dye penetrates 0.5 cm from each face, so an unreached core remains, measuring 2 minus 0.5 minus 0.5, which is 1 cm on each side.

Step three: compute the fraction reached. Total volume is 2 cubed, which is 8 cubic centimeters. The unreached core is 1 cubed, which is 1. So 7 of 8 is colored, which is 87.5 percent.

Step four: the 3 cm cube. The unreached core measures 3 minus 1, which is 2 cm on each side. Total volume is 27 and the core is 8, so 19 of 27 is colored, which is about 70 percent.

Step five: read the pattern. 100 percent, then 87.5, then 70. As the block grows, a steadily larger share of its interior is never reached in the time available, even though the dye moves at exactly the same speed in all three.

Step six: check the ratios from lesson 1.7. The three cubes have surface to volume ratios of 6, 3 and 2. The decline in the ratio and the decline in the fraction supplied are the same phenomenon measured two ways.

Step seven: state the biological conclusion. A cell that grew to the size of the 3 cm block would have a large central region that oxygen could not reach in useful time. Dividing into smaller units restores a high ratio and a short diffusion distance, which is why growth in organisms happens by making more cells rather than bigger ones.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What scales with area, and what with volume?
    Show the full solution

    Exchange capacity scales with surface area; demand scales with volume

  2. Give the surface to volume ratios of cubes of side 1, 2 and 3 cm.
    Show the full solution

    6, 3 and 2

  3. In the worked example, what fraction of the 2 cm cube is reached?
    Show the full solution

    7 of 8, which is 87.5 percent

  4. How does the time for diffusion change if the distance doubles?
    Show the full solution

    It quadruples, since time rises with the square of the distance

  5. Name two ways a cell can raise its surface area.
    Show the full solution

    Microvilli or other folds, and a flattened or elongated shape

  6. Calculate the fraction of a 4 cm cube reached by dye penetrating 0.5 cm, and comment.
    Show the full solution

    The unreached core measures 4 minus 1, which is 3 cm on each side, so its volume is 27 cubic centimeters. The total volume is 4 cubed, which is 64, so the colored portion is 64 minus 27, which is 37, and 37 divided by 64 is about 58 percent. The sequence across the four blocks is 100, 87.5, 70 and 58 percent, falling steadily as size rises even though the dye's speed never changes. Size alone determines how much of the interior is served. About 58 percent, continuing the decline from 100, 87.5 and 70

  7. Explain why a cell divides rather than continuing to grow.
    Show the full solution

    As a cell enlarges, its volume and therefore its demand for oxygen, glucose and waste removal grow with the cube of its linear size, while the membrane area that must handle all that exchange grows only with the square. The distance from the membrane to the center also increases, and diffusion time rises with the square of distance, so the interior is served ever more slowly. Division restores both a high surface to volume ratio and a short diffusion path, which is why growth proceeds by increasing cell number. Demand outgrows exchange capacity and diffusion distances lengthen

  8. Red blood cells are flattened discs with a dip in the middle. Explain the advantage.
    Show the full solution

    The shape increases surface area relative to volume compared with a sphere of the same content, so more membrane is available for oxygen to cross, and it reduces the maximum distance from the membrane to any point inside, so oxygen reaches all of the interior quickly. Since the cell's entire function is rapid uptake and release of oxygen, both effects matter directly. The flexible flattened shape also allows the cell to deform and pass through capillaries narrower than itself. More membrane per unit volume and a shorter internal diffusion distance

  9. Why can a very large single-celled organism exist at all, given this argument?
    Show the full solution

    Because the constraint can be evaded by shape and by internal movement rather than by size alone. A large single-celled organism is typically long and thin or highly branched rather than spherical, which keeps every point close to the membrane despite a large total volume. Some also stream their cytoplasm actively, moving material by bulk flow rather than waiting for diffusion, and some contain many nuclei so that no single nucleus has to serve an impossible volume. Elongated shapes, cytoplasmic streaming and multiple nuclei evade the limit

  10. Connect this lesson to why humans have lungs and a circulatory system.
    Show the full solution

    A human body has an extremely low surface to volume ratio and interior tissues centimeters from any outer surface, so diffusion across the skin could never supply them: the distances involved would take days. Lungs solve the area problem by folding an enormous exchange surface into a small space, the same trick as microvilli on a larger scale. The circulatory system solves the distance problem by carrying blood in bulk to within diffusion range of every cell, so the final step is always short. Lungs supply the area and circulation removes the distance, since diffusion alone cannot

Lesson 5.5 · Unit 5 · HS-LS1-3

The membrane: structure explains selective permeability

The cell membrane is not a bag. It is a highly selective barrier whose behavior follows directly from the shape of the molecules that build it, and if you understand why a phospholipid arranges itself the way it does, you can predict which substances cross freely and which need help.

The key ideas
  1. A phospholipid has two ends with opposite properties: a phosphate head that is attracted to water, and two fatty acid tails that are repelled by it.
  2. In water they form a bilayer automatically, heads facing outward to the water on both sides and tails facing inward, shielded. No energy or instruction is required; the arrangement is the most stable one.
  3. The interior is a region of fatty tails, so substances that dissolve in fat pass through easily while charged or water-loving substances do not.
  4. Proteins are embedded in the bilayer, some spanning it completely. These provide channels, carriers, receptors and enzymes.
  5. The model is called fluid mosaic: fluid because the components drift laterally rather than being fixed, mosaic because of the scattered proteins set in the lipid.
  6. Selective permeability follows from all of this. Small non-polar molecules such as oxygen and carbon dioxide cross directly; ions and glucose require protein routes.

Where students lose marks: describing the tails as "water hating" as though repulsion were a force they exert. They are non-polar, so they cannot form the attractions water molecules form with each other, and water excludes them. The bilayer forms because that arrangement is most stable, not because anything is pushing.

Worked example

The task. Predict, from structure alone, whether each substance crosses a membrane unaided. Work from the properties, not from memory.

SubstancePropertiesCrosses unaided?
Oxygensmall, non-polaryes, freely
Carbon dioxidesmall, non-polaryes, freely
Watersmall but polarslowly; mostly via channels
Sodium ionchargedno, needs a protein
Glucoselarge and polarno, needs a carrier

Step one: establish the rule from the structure. The middle of the membrane is a layer of fatty acid tails, which are non-polar. Anything that mixes well with fat passes through it; anything that does not is blocked.

Step two: apply it to oxygen. Small and non-polar, so it dissolves in the tail region and diffuses straight through. This is why gas exchange needs no transport proteins at all.

Step three: apply it to a sodium ion. It carries a full charge, so entering the non-polar interior is energetically very unfavorable. It cannot cross the lipid and must use a channel or pump protein.

Step four: handle the water exception carefully. Water is polar, so by the rule it should be blocked, and in fact it crosses only slowly through the lipid. Most water movement in cells that need speed goes through dedicated channel proteins, which is why the rule and the observation can both be right.

Step five: apply it to glucose. Both large and polar, so it fails the test twice and requires a specific carrier protein, which is why cells can control their glucose uptake.

Step six: draw out the consequence for control. Substances that cross freely cannot be regulated by the cell; substances that need proteins can be, because the cell decides how many transporters to make and whether they are open.

Step seven: note why fluidity matters. Because the components drift, membranes can fuse, bud off vesicles, and reseal after damage. A rigid sheet could not carry out the vesicle transport of lesson 5.3 at all.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Describe the two ends of a phospholipid.
    Show the full solution

    A phosphate head attracted to water, and two non-polar fatty acid tails that are not

  2. Why is the model called fluid mosaic?
    Show the full solution

    Fluid because components drift laterally; mosaic because of the scattered embedded proteins

  3. Name two substances that cross the bilayer freely.
    Show the full solution

    Oxygen and carbon dioxide

  4. Why can a sodium ion not cross unaided?
    Show the full solution

    It is charged, so it cannot enter the non-polar interior of the bilayer

  5. Name three jobs done by membrane proteins.
    Show the full solution

    Channels or carriers for transport, receptors for signals, and enzymes

  6. Explain why a bilayer forms spontaneously in water.
    Show the full solution

    Phospholipids have heads that interact favorably with water and tails that cannot, so any arrangement leaving tails exposed to water is unstable. Two sheets placed tail to tail solve the problem completely: every head faces water on one side or the other, and every tail is shielded in the interior. The structure assembles because it is the lowest energy arrangement available, with no instruction, template or energy input required, which is why artificial membranes form as soon as phospholipids are added to water. It is the most stable arrangement, shielding all tails while exposing all heads

  7. Explain how membrane structure produces selective permeability.
    Show the full solution

    The core of the membrane is a layer of non-polar fatty acid tails, so substances that dissolve in fat can pass through it directly while charged or strongly polar substances cannot enter that region at all. Permeability therefore depends on a molecule's size and polarity rather than being uniform. Proteins spanning the bilayer provide specific routes for the substances the lipid excludes, so the cell ends up with a barrier that is open to some things, closed to others, and controllable for a third group. A non-polar core admits fat-soluble molecules and blocks charged ones, with proteins supplying exceptions

  8. Why is it an advantage that some substances cannot cross without proteins?
    Show the full solution

    Because it gives the cell control. A substance that diffuses freely enters and leaves according to concentration alone, and the cell can do nothing about it, which is why cells cannot regulate their oxygen uptake. A substance that requires a transport protein can be controlled by how many transporters the cell makes, whether they are open, and how much ATP is spent pumping. Glucose uptake, ion balance and nerve signaling all depend on exactly this, and none would be possible through a freely permeable membrane. Protein-dependent entry allows the cell to regulate what comes in and out

  9. Predict whether a small fat-soluble drug or a small charged one crosses more easily, and explain.
    Show the full solution

    The fat-soluble one, by a wide margin. It dissolves into the non-polar tail region and diffuses straight through the bilayer without needing any protein, so it can enter essentially any cell in the body. The charged drug cannot enter that region and must find a suitable transport protein, which most cells may not have, so its distribution is limited to tissues carrying the right transporter. This is a central consideration in drug design, and it explains why fat-soluble substances also cross into the brain more readily. The fat-soluble drug, since it dissolves in the non-polar interior

  10. Why does membrane fluidity matter for the vesicle transport of lesson 5.3?
    Show the full solution

    Vesicle transport requires membranes to bend, pinch off, travel and then fuse seamlessly with another membrane, and every one of those operations needs the phospholipids to move relative to one another. In a rigid sheet a vesicle could not bud from the endoplasmic reticulum, could not fuse with the Golgi, and could not merge with the cell membrane during exocytosis. Fluidity also allows a membrane to reseal after minor damage rather than leaking, which is what makes the whole compartmental system viable. Budding, fusion and resealing all require the lipids to move

Lesson 5.6 · Unit 5 · HS-LS1-3

Passive transport: diffusion, facilitated diffusion and osmosis

Passive means the cell spends no ATP. Substances move because random molecular motion spreads them from where they are concentrated to where they are not, and the cell simply permits or blocks the route. Osmosis is a special case of this that causes more confusion than any other topic in the unit, because it is about the water rather than the solute.

The key ideas
  1. Diffusion is net movement from higher to lower concentration, driven by the random motion of particles, requiring no energy from the cell.
  2. The concentration gradient is the difference between the two regions. A steeper gradient gives a faster net rate.
  3. Rate also depends on temperature, surface area and distance, all of which follow from what diffusion physically is.
  4. Facilitated diffusion is still passive but uses a channel or carrier protein for substances the lipid blocks. Down the gradient, no ATP.
  5. Osmosis is the diffusion of water across a partially permeable membrane, from a region of higher water potential to one of lower water potential.
  6. Water moves toward the more concentrated solution, because a solution with more solute has proportionally less free water.

Where students lose marks: saying water moves "from low concentration to high concentration". Concentration of what? Water moves from higher water concentration to lower water concentration, which is toward the more concentrated solute. Always say which substance the word concentration refers to.

Worked example

The setup. A partially permeable membrane separates two solutions. It allows water through but not sucrose. Side A holds 0.1 molar sucrose; side B holds 0.5 molar sucrose. Both sides start with equal volumes.

Step one: identify what can move. Water can cross; sucrose cannot. So whatever happens must happen by water movement, and the sucrose amounts on each side are fixed.

Step two: compare the water. Side B has five times the sucrose, so a smaller proportion of side B is water. Side A has the higher water concentration.

Step three: apply the rule. Water diffuses from higher water concentration to lower, so net movement is from A to B. It moves toward the more concentrated sucrose solution.

Step four: predict the volumes. Side B gains volume and side A loses it. If the tube allows, the level on side B rises.

Step five: predict the concentrations. Side B is being diluted by incoming water, so its sucrose concentration falls. Side A is losing water with its sucrose staying put, so its concentration rises. The two approach each other.

Step six: state the end point precisely. Net movement stops when the concentrations are equal, or when pressure from the raised column on side B opposes further entry. Individual water molecules keep crossing in both directions; the net flow is zero.

Step seven: check the common error. Nothing moved the sucrose, and nothing was trying to equalize anything. Water molecules moved randomly in both directions, and more happened to cross from the side that had more of them. Osmosis is a statistical outcome, not a purpose.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Define diffusion.
    Show the full solution

    Net movement of particles from higher to lower concentration by random motion

  2. Name three factors that affect the rate of diffusion.
    Show the full solution

    Steepness of the gradient, temperature, surface area, and distance to travel

  3. What makes facilitated diffusion passive?
    Show the full solution

    It moves substances down their gradient and uses no ATP

  4. Define osmosis.
    Show the full solution

    Diffusion of water across a partially permeable membrane from higher to lower water potential

  5. In the worked example, which way does water move and why?
    Show the full solution

    From A to B, because A has the higher water concentration

  6. Explain why "water moves from low to high concentration" is a dangerous way to state osmosis.
    Show the full solution

    Because it omits the substance the word concentration refers to, and the two possible readings give opposite answers. Water moves from high water concentration to low water concentration, which is the same thing as moving toward the higher solute concentration. A student who writes the phrase without specifying gets no credit, and a student who is thinking of solute while writing water will predict the direction backwards. Naming the substance every time removes the ambiguity entirely. It omits which substance, and the two readings give opposite directions

  7. Explain why facilitated diffusion has a maximum rate that simple diffusion does not.
    Show the full solution

    Simple diffusion can use any part of the membrane, so raising the gradient keeps raising the rate. Facilitated diffusion depends on a limited number of protein channels or carriers, each of which handles one molecule at a time. As the gradient steepens, more of those proteins are occupied, and once all are working continuously the rate cannot rise further no matter how steep the gradient becomes. The transporters are saturated, which is the same saturation behavior enzymes show in lesson 6.3. A limited number of transport proteins can saturate; the lipid cannot

  8. Why does net movement stop at equilibrium even though molecules keep moving?
    Show the full solution

    Diffusion is the statistical result of random individual motion, and individual particles never stop moving or check where they are going. When concentrations are equal, the number crossing in each direction per second is also equal, so the two flows cancel and no net change occurs. Equilibrium is therefore a balance of two continuing processes rather than a halt, which is why it is described as dynamic and why an isolated system can sit at equilibrium indefinitely without anything being still. Equal numbers cross each way, so the flows cancel: it is a dynamic balance

  9. A cell is placed in pure water. Predict the direction of water movement and explain.
    Show the full solution

    Water enters the cell. Pure water has the highest possible water concentration, while the cytoplasm contains dissolved salts, sugars and proteins and therefore has a lower one. Water diffuses down that gradient across the partially permeable membrane into the cell, which swells. What happens next depends on whether the cell has a wall: a plant cell becomes turgid and stops, while an animal cell may burst, which is the subject of the next lesson. Into the cell, since pure water has the higher water concentration

  10. Why is a large surface area with a short diffusion distance the standard design for an exchange surface?
    Show the full solution

    Rate of diffusion rises with the area available for crossing and falls sharply as the distance to be crossed increases, since diffusion time grows with the square of distance. An exchange surface therefore maximizes the first and minimizes the second, which is why lungs, gills, root hairs and intestinal villi all combine extensive folded surfaces with walls only one cell thick. Maintaining a steep concentration gradient, usually by a blood supply carrying material away, completes the design. Rate rises with area and falls steeply with distance, so both are optimized

Lesson 5.7 · Unit 5 · HS-LS1-3

Tonicity and active transport

Put an animal cell in pure water and it bursts. Put a plant cell in the same water and it becomes firm and healthy. The difference is the cell wall, and predicting outcomes like these is a standard task that rewards careful vocabulary. Then there is the question of moving something the wrong way, which costs ATP.

The key ideas
  1. Hypertonic means the solution outside has more solute than the cell, so water leaves the cell.
  2. Hypotonic means the solution outside has less solute, so water enters the cell.
  3. Isotonic means the concentrations match, so there is no net movement.
  4. Animal cells have no wall. In a hypotonic solution they swell and may burst; in a hypertonic one they shrink and become crenated.
  5. Plant cells have a rigid wall. In a hypotonic solution they become turgid, which is their healthy state; in a hypertonic one the membrane pulls away from the wall, which is plasmolysis.
  6. Active transport moves substances against the gradient using carrier proteins and ATP. The sodium potassium pump is the standard example, and bulk transport by endocytosis and exocytosis also costs energy.

Where students lose marks: using hypertonic and hypotonic without saying what is being compared with what. Always write "the solution is hypertonic to the cell" rather than "the cell is hypertonic". The terms are comparative and mean nothing on their own.

Worked example

The task. Predict what happens to a red blood cell and to a plant cell in each of three solutions, then explain why the two differ.

SolutionRed blood cellPlant cell
Hypotonic (pure water)swells and burstsbecomes turgid
Isotonicno changeflaccid
Hypertonic (strong salt)shrinks, crenatedplasmolyzed

Step one: establish the direction of water movement. It is the same for both cell types and depends only on the solutions: into the cell in hypotonic, out in hypertonic, no net movement in isotonic.

Step two: apply it to the animal cell in hypotonic solution. Water enters, the cell swells, and since only the membrane resists, it stretches until it ruptures. The cell is destroyed.

Step three: apply it to the plant cell in the same solution. Water enters and the contents press outward against the rigid cellulose wall. The wall pushes back, pressure builds, and water entry stops before anything ruptures. The cell is turgid, which is how plants stay upright.

Step four: note the reversal of what counts as healthy. Pure water kills an animal cell and is ideal for a plant cell. The same physics produces opposite outcomes because of one structural difference.

Step five: apply the hypertonic case. Water leaves both. The animal cell shrinks and its surface wrinkles. In the plant cell the membrane and contents shrink away from the wall, which stays where it is, and the cell is plasmolyzed.

Step six: explain wilting. A plant short of water has flaccid or plasmolyzed cells that no longer press against their walls, so the tissue loses its rigidity and the plant droops. Turgor is a structural support system that depends entirely on osmosis.

Step seven: bring in active transport. A root cell may need to take up nitrate when soil nitrate is already lower than the concentration inside. That is against the gradient, so diffusion cannot do it, and the cell uses carrier proteins powered by ATP. This is also why root cells are rich in mitochondria and why waterlogged soil, which starves roots of oxygen, causes mineral deficiency.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Define hypertonic, hypotonic and isotonic.
    Show the full solution

    Hypertonic has more solute than the cell, hypotonic less, isotonic the same

  2. What happens to an animal cell in a hypotonic solution?
    Show the full solution

    It swells and may burst

  3. What is plasmolysis?
    Show the full solution

    The membrane and contents of a plant cell pulling away from the wall as water leaves

  4. How does active transport differ from facilitated diffusion?
    Show the full solution

    It moves substances against the gradient and requires ATP

  5. Why is a turgid plant cell the healthy state?
    Show the full solution

    Turgor pressure against the wall supports the tissue and keeps the plant upright

  6. Explain why pure water kills an animal cell but suits a plant cell.
    Show the full solution

    Water enters both cells for the same reason, since pure water is hypotonic to both, but the consequences differ because of the wall. An animal cell has only its membrane to resist the increasing volume, so it stretches and eventually ruptures. A plant cell's contents press against a rigid cellulose wall that pushes back, and once that pressure balances the tendency of water to enter, net entry stops before any damage occurs. The wall converts a fatal influx into a useful support mechanism. The rigid wall builds counter-pressure that stops water entry before rupture

  7. Why must a root cell absorbing nitrate from dilute soil use active transport?
    Show the full solution

    Because the nitrate concentration inside the root cell is often already higher than in the surrounding soil water, so the gradient runs the wrong way for diffusion. Passive transport can only move substances down a gradient, and would carry nitrate out of the cell rather than in. Taking up more requires carrier proteins that use energy from ATP to move the ions against the gradient, which is why root cells contain many mitochondria and why absorption stops when oxygen is unavailable. The gradient runs the wrong way, so movement against it needs ATP

  8. Explain why waterlogged soil causes mineral deficiency in plants even though water is abundant.
    Show the full solution

    Water fills the air spaces in the soil, so oxygen cannot reach the roots. Root cells depend on aerobic respiration to supply the ATP that active transport requires, and without oxygen that supply collapses. Mineral ions such as nitrate can then no longer be taken up against their gradients, so the plant becomes deficient despite being surrounded by soil water containing them. The denitrification of lesson 4.3 makes the situation worse by removing nitrate from the soil at the same time. No oxygen means no ATP, so active uptake of ions stops

  9. Why are intravenous drips isotonic rather than pure water?
    Show the full solution

    Because pure water would be strongly hypotonic to the patient's red blood cells, so water would move rapidly into them and they would swell and burst, which is both dangerous and useless for delivering fluid. An isotonic solution has the same solute concentration as the cells, so there is no net water movement across their membranes, and the fluid can be added to the circulation without damaging the cells suspended in it. The same reasoning applies to solutions used to store organs. Pure water would be hypotonic and burst the red blood cells

  10. A plant is watered with salty water and wilts. Explain the mechanism.
    Show the full solution

    The salt makes the soil solution hypertonic to the root cells, so water moves out of the roots into the soil rather than in, and the plant loses water it cannot replace. Its cells become flaccid and then plasmolyzed, so they no longer press against their walls and the turgor supporting the tissue is lost, which is what wilting is. The plant is dying of water shortage while standing in wet soil, which is why salinity damages farmland so severely. Salty soil is hypertonic, so water leaves the roots and turgor is lost

Unit 5 review · Cells, Membranes and Transport

Ten questions across the whole unit

Questions 1 to 5 check that you hold the terms. Questions 6 to 10 require you to reason across the seven lessons.

  1. State the three parts of cell theory.
    Show the full solution

    All living things are made of cells; the cell is the basic unit of structure and function; all cells come from pre-existing cells

  2. Name four features shared by prokaryotic and eukaryotic cells.
    Show the full solution

    Cell membrane, cytoplasm, ribosomes and DNA

  3. Trace a secreted protein through the organelles in order.
    Show the full solution

    Nucleus, ribosome on rough ER, transport vesicle, Golgi, secretory vesicle, cell membrane

  4. A cube of side 6 cm: give surface area, volume and ratio.
    Show the full solution

    Surface area 216 square centimeters, volume 216 cubic centimeters, ratio 1.0

  5. Why can oxygen cross a membrane unaided when a sodium ion cannot?
    Show the full solution

    Oxygen is small and non-polar so it dissolves in the fatty interior; a sodium ion is charged and cannot enter it

  6. Explain why the shape of Pasteur's flask mattered more than the boiling.
    Show the full solution

    Boiling sealed flasks had been done before and convinced nobody, because defenders of spontaneous generation argued that sealing excluded a vital principle in the air. The swan neck removed that objection by leaving the flask open, so air moved freely while the bend trapped settling dust. It therefore isolated the single variable in dispute, which is exactly what the earlier experiments had failed to do and why this one was decisive. It admitted air while excluding dust, removing the vital principle objection

  7. Explain why a cell divides rather than continuing to grow, naming the mechanism.
    Show the full solution

    As a cell enlarges its volume and therefore its demand for oxygen, glucose and waste removal grow with the cube of its linear size, while the membrane area handling all that exchange grows only with the square, so the surface to volume ratio falls. The distance from membrane to center also increases, and diffusion time rises with the square of distance, so the interior is served ever more slowly. Division restores both. Demand outgrows exchange capacity and diffusion distances lengthen

  8. Explain why it is an advantage that some substances require transport proteins.
    Show the full solution

    It gives the cell control. A substance that diffuses freely enters and leaves according to concentration alone and the cell can do nothing about it, which is why cells cannot regulate oxygen uptake. A substance requiring a transport protein can be controlled through how many transporters are made, whether they are open, and how much ATP is spent pumping. Glucose uptake, ion balance and nerve signaling all depend on exactly this. Protein-dependent entry lets the cell regulate what crosses

  9. Explain why pure water bursts an animal cell but suits a plant cell.
    Show the full solution

    Water enters both for the same reason, since pure water is hypotonic to both, but the consequences differ because of the wall. An animal cell has only its membrane to resist the increasing volume, so it stretches and ruptures. A plant cell's contents press against a rigid cellulose wall that pushes back, and once that pressure balances the tendency of water to enter, net entry stops before damage occurs. The wall converts a fatal influx into a support mechanism. The rigid wall builds counter-pressure that halts water entry before rupture

  10. Explain why waterlogged soil causes mineral deficiency despite abundant water.
    Show the full solution

    Water fills the soil air spaces, so oxygen cannot reach the roots. Root cells depend on aerobic respiration to supply the ATP that active transport requires, and without oxygen that supply collapses, so ions such as nitrate can no longer be taken up against their concentration gradients. The plant becomes deficient while surrounded by soil water containing the ions, and denitrification in the same oxygen-poor conditions removes nitrate as well. No oxygen means no ATP, so active uptake of ions stops

Lesson 6.1 · Unit 6 · HS-LS1-5, HS-LS1-7

ATP: why cells do not spend glucose directly

A cell cannot pay for a single protein with a glucose molecule, for the same reason you cannot buy a coffee with a gold bar. Glucose holds far too much energy to release in one place at one time, and cells need a small denomination they can spend anywhere. That currency is ATP.

The key ideas
  1. ATP is adenosine triphosphate: an adenine base, a ribose sugar, and a chain of three phosphate groups.
  2. Energy is released by removing the third phosphate, converting ATP to ADP plus a free phosphate. This is a hydrolysis reaction.
  3. The cycle runs constantly in both directions. Respiration uses energy from glucose to reattach a phosphate to ADP, rebuilding ATP.
  4. ATP is an immediate store, not a long-term one. A cell holds only a few seconds' supply and must continually regenerate it.
  5. It powers three broad classes of work: synthesis of molecules, active transport against gradients, and movement such as muscle contraction.
  6. One glucose molecule yields many ATP, which is what makes the arrangement useful: a large store is broken into many small, spendable units.

Where students lose marks: calling ATP "energy" or saying the cell "stores energy as ATP" for later use. ATP is a molecule, not energy, and it is the cell's working change rather than its savings. Glycogen and fat are the stores.

Worked example

The question. Why break glucose into many ATP rather than using it directly? Work it out from the numbers, using figures that are constructed but in the right proportions.

Step one: state the two stores. Complete aerobic breakdown of one glucose molecule yields roughly 30 ATP. So the energy in one glucose is approximately thirty times the energy in one ATP.

Step two: consider a single small job. Moving one sodium ion against its gradient costs a fraction of one ATP's worth of energy. Releasing a whole glucose to do it would waste almost all of the energy as heat.

Step three: work an example. Suppose a cell needs 300 ATP worth of work in a second. Using aerobic respiration at 30 ATP per glucose, it consumes 300 divided by 30, which is 10 glucose molecules.

Step four: consider the alternative. If the cell had to spend glucose directly on each task, each task would consume one whole glucose regardless of how small it was, and the same work would cost far more fuel.

Step five: state the second advantage, universality. Every energy-requiring process in every cell uses the same molecule, so one respiratory pathway supplies all of them. A separate fuel for each process would require a separate production system for each.

Step six: state the third advantage, control. Because ATP is consumed and regenerated continuously, the rate of respiration can be matched to demand almost instantly. A rising level of ADP signals that work is being done and more ATP is needed.

Step seven: note the consequence of holding so little. A cell carries only seconds' worth of ATP, so any interruption to respiration is felt immediately. This is why a few minutes without oxygen damages brain tissue permanently while food reserves remain untouched.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What do the letters ATP stand for, and what are its three parts?
    Show the full solution

    Adenosine triphosphate: an adenine base, a ribose sugar and three phosphate groups

  2. How is energy released from ATP?
    Show the full solution

    By hydrolysis, removing the third phosphate to give ADP and a free phosphate

  3. Name three kinds of work ATP powers.
    Show the full solution

    Synthesis of molecules, active transport, and movement such as muscle contraction

  4. Roughly how many ATP does aerobic respiration of one glucose yield?
    Show the full solution

    About 30, though older textbooks give figures nearer 36 to 38

  5. Why is ATP not a long-term energy store?
    Show the full solution

    Cells hold only a few seconds' supply and regenerate it continuously

  6. Explain why a cell uses ATP rather than spending glucose directly.
    Show the full solution

    Glucose holds far more energy than any single cellular task requires, so releasing a whole molecule for a small job would waste most of it as heat. ATP divides that store into small units the cell can spend precisely, matching supply to the size of each task. Using one universal currency also means a single respiratory pathway can power every process in the cell, and because ATP is consumed and rebuilt continuously, the rate of respiration can track demand from moment to moment. It breaks a large store into spendable units usable by every process

  7. A cell needs 600 ATP of work. Calculate the glucose required aerobically, and explain what the figure assumes.
    Show the full solution

    At about 30 ATP per glucose, 600 divided by 30 gives 20 glucose molecules. The figure assumes complete aerobic breakdown with oxygen freely available, since without oxygen the yield collapses to about 2 ATP per glucose and the same work would need 300 molecules. It also treats 30 as exact when the real yield varies with conditions and with how efficiently the electron transport chain is coupled, so the answer is an estimate rather than a precise count. 20 glucose molecules, assuming complete aerobic respiration

  8. Why does a shortage of oxygen affect a cell within seconds rather than hours?
    Show the full solution

    Because the cell's stock of ATP is tiny, amounting to only a few seconds of work, and it is maintained by continuous regeneration rather than held in reserve. Oxygen is required at the final step of aerobic respiration, so removing it halts ATP production almost immediately while consumption continues. Food reserves such as glycogen and fat are untouched by the problem but cannot be used quickly without oxygen, which is why tissues fail long before they run out of fuel. ATP stocks last seconds, and regeneration stops when oxygen does

  9. Explain why the ATP to ADP conversion is described as a cycle.
    Show the full solution

    Because the molecule is not consumed, only converted back and forth. Hydrolysis removes the third phosphate, releasing energy for work and leaving ADP; energy released from glucose during respiration then reattaches a phosphate to the ADP, regenerating ATP. The same adenosine unit is reused many thousands of times a day rather than being made afresh, so what flows through the system is energy while the carrier circulates, which is the pattern of lesson 2.7 at the scale of a single molecule. The same molecule is repeatedly broken down and rebuilt rather than consumed

  10. Why might a rising concentration of ADP in a cell increase the rate of respiration?
    Show the full solution

    ADP accumulates when ATP is being used quickly, so its concentration is a direct signal of how much work the cell is doing. Respiration requires ADP as a raw material for rebuilding ATP, so more ADP available means the process can run faster, and ADP also acts as a regulator stimulating the pathway. The result is automatic matching of supply to demand without any external instruction, which is a negative feedback loop of the kind described in lesson 4.5. ADP is both the raw material and the signal that ATP is being spent

Lesson 6.2 · Unit 6 · HS-LS1-3, HS-LS1-6

Enzymes: specificity and the active site

Almost every reaction in a cell would happen eventually without help, and eventually is no use to something that has to stay alive. Enzymes make reactions fast enough to matter, and they do it selectively, so a cell can run one reaction at high speed while leaving a chemically similar one untouched.

The key ideas
  1. An enzyme is a biological catalyst, almost always a protein. It speeds a reaction and is unchanged by it, so one enzyme molecule works over and over.
  2. The active site is a region of the enzyme's surface whose shape and chemistry fit one substrate. Specificity comes from that fit.
  3. The enzyme-substrate complex forms when substrate binds. The reaction occurs, products leave, and the active site is free again.
  4. Induced fit is the better model: the active site is not a rigid keyhole but adjusts slightly as the substrate binds, tightening the fit and straining the bonds.
  5. Enzymes lower activation energy, the energy barrier a reaction must cross. They do not change how much energy the reaction releases overall.
  6. The enzyme's shape comes from its amino acid sequence, so it is specified by a gene, which is how DNA controls metabolism.

Where students lose marks: saying enzymes "make reactions happen" or "give energy to the reaction". They do neither. They lower the barrier so that a reaction which was already possible happens far more often at ordinary temperatures.

Worked example

The case. Catalase breaks down hydrogen peroxide, a toxic waste product of metabolism, into water and oxygen. Work through what the enzyme does and does not do.

Step one: establish that the reaction happens anyway. Hydrogen peroxide decomposes slowly on its own. The products are the same with or without catalase, and so is the energy released.

Step two: identify what changes. The rate. With catalase the reaction proceeds enormously faster, which is why a piece of liver added to hydrogen peroxide froths immediately.

Step three: explain the mechanism in terms of the barrier. The reaction needs an input of energy to get started, the activation energy. The active site holds the substrate in a position that strains its bonds, so less energy is needed to break them.

Step four: follow the cycle. Hydrogen peroxide binds to the active site, forming the enzyme-substrate complex. The bonds break, water and oxygen are released, and the active site is empty and unchanged, ready for the next molecule.

Step five: note the turnover. Because the enzyme is not consumed, a single molecule processes many substrate molecules per second. This is why cells need only small quantities of each enzyme.

Step six: test the specificity. Catalase acts on hydrogen peroxide and not on other molecules in the cell, because only hydrogen peroxide fits its active site. The cell can therefore destroy one compound without disturbing anything else.

Step seven: connect it back to DNA. The shape of that active site is determined by the sequence of amino acids in catalase, which is determined by the sequence of bases in the catalase gene. Change the gene and you change the shape, which is the link unit 7 will make explicit.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What is an enzyme, and what class of molecule is it usually?
    Show the full solution

    A biological catalyst, almost always a protein

  2. What is the active site?
    Show the full solution

    The region of the enzyme whose shape and chemistry fit a specific substrate

  3. What does an enzyme do to activation energy?
    Show the full solution

    It lowers it

  4. What is the induced fit model?
    Show the full solution

    The active site adjusts its shape slightly as the substrate binds, tightening the fit

  5. What determines an enzyme's shape?
    Show the full solution

    Its amino acid sequence, which is specified by a gene

  6. Explain why saying an enzyme "makes a reaction happen" is wrong.
    Show the full solution

    The reaction is already possible and already occurs without the enzyme, just very slowly, and the products and the overall energy change are identical either way. What the enzyme alters is the height of the energy barrier that must be crossed before the reaction can proceed, so a much larger proportion of molecules have enough energy to react at ordinary temperatures. Saying the enzyme makes it happen implies it supplies something the reaction lacked, which would violate the conservation of energy. The reaction already occurs; the enzyme only lowers the barrier and raises the rate

  7. Why does induced fit explain specificity better than a rigid lock and key?
    Show the full solution

    A rigid keyhole explains why the wrong substrate does not fit, but not why binding helps the reaction proceed. Induced fit adds that the active site changes shape as the correct substrate enters, and in closing around it places strain on particular bonds, which is a direct mechanism for lowering activation energy. It also explains why some enzymes accept a small range of closely related substrates, and why binding at one site can change the shape and activity of another part of the molecule. It explains how binding lowers activation energy, not just why the wrong substrate is rejected

  8. Why do cells need only small amounts of each enzyme?
    Show the full solution

    Because an enzyme is not consumed by the reaction it catalyzes. Substrate binds, the reaction occurs, products leave, and the active site is left unchanged and immediately available, so a single molecule can process thousands of substrate molecules each second. The quantity needed therefore depends on the rate of turnover required rather than on the amount of substrate present, which is why an enzyme concentration far lower than its substrate concentration is usually sufficient. Enzymes are unchanged by the reaction and turn over repeatedly

  9. A mutation changes one amino acid in an enzyme's active site. Predict the effect and explain.
    Show the full solution

    The active site's shape or chemistry would change, so the substrate may no longer bind properly or at all, and the reaction rate would fall sharply or stop. The effect depends on which amino acid and where: a change at a position critical to binding can abolish activity entirely, while one at the periphery may barely matter. This is the mechanism connecting a single base change in DNA to a metabolic disorder, and lesson 7.6 develops it. Altered active site shape, so the substrate binds poorly and the rate falls

  10. Explain how genes control metabolism, using this lesson.
    Show the full solution

    Each metabolic reaction in a cell is catalyzed by a specific enzyme, and each enzyme is a protein whose amino acid sequence is specified by a gene. The sequence determines how the protein folds, the folding determines the shape of the active site, and the active site determines which reaction is catalyzed and how fast. Controlling which genes are expressed therefore controls which enzymes exist, which controls which reactions can proceed, so the genome sets the cell's entire chemistry indirectly. Genes specify enzymes, enzymes determine which reactions run and how fast

Lesson 6.3 · Unit 6 · HS-LS1-3, HS-LS1-6

Enzyme rate: temperature, pH, saturation and inhibition

Enzyme rate curves are among the most common graphs in biology, and they are almost always explained sloppily. The rising part and the falling part of a temperature curve have completely different causes, and saying "heat kills enzymes" throws away both of them.

The key ideas
  1. Rate rises with temperature at first because molecules move faster, so enzyme and substrate collide more often and with more energy.
  2. Above the optimum the rate falls sharply because the enzyme denatures: the bonds holding its three-dimensional shape break, and the active site loses its shape.
  3. Denaturation is a change of shape, not death. Enzymes are molecules and were never alive, and the damage is usually permanent because the protein cannot refold correctly.
  4. pH has an optimum too, and moving away from it in either direction disrupts the bonds maintaining the active site's shape.
  5. Substrate concentration raises the rate until saturation, at which point every active site is occupied and adding more substrate changes nothing.
  6. Competitive inhibitors resemble the substrate and block the active site; non-competitive inhibitors bind elsewhere and change the active site's shape.

Where students lose marks: writing that high temperature "kills" an enzyme, and writing that low temperature denatures it. Cold slows enzymes by reducing collisions and is reversible: warm the enzyme and activity returns. Heat denatures, and generally does not reverse.

Worked example

The data. Rate of an enzyme-controlled reaction against temperature, constructed to show the standard shape.

Temperature (°C)0102030405060
Rate (arbitrary units)25112240120

Step one: describe before explaining. The rate rises steadily from 2 at 0 degrees to a maximum of 40 at 40 degrees, then falls steeply to 12 at 50 and to zero at 60.

Step two: quantify the rise. Between 30 and 40 degrees the rate goes from 22 to 40, an increase of 18. Between 0 and 10 it rises only from 2 to 5. The rise is accelerating, not linear.

Step three: explain the rising section. Higher temperature gives molecules more kinetic energy, so enzyme and substrate collide more frequently and more of those collisions carry enough energy to react. Nothing is damaged in this region.

Step four: identify the optimum. 40 degrees, the temperature at which rate is greatest. It is a balance point, not a property of the reaction itself.

Step five: explain the falling section, which is a different mechanism. Above the optimum the increased vibration breaks the weak bonds holding the enzyme's tertiary structure. The active site loses its shape, substrate can no longer bind, and rate collapses.

Step six: explain why the fall is so much steeper than the rise. The rise reflects a gradual increase in collision energy, while the fall reflects molecules being progressively destroyed. Once an enzyme molecule denatures it stops contributing entirely, so the loss compounds.

Step seven: test the reversibility. Cool the sample from 20 degrees to 0 and back, and activity returns, because nothing was damaged. Cool it from 60 back to 40 and the rate stays near zero, because the enzymes have denatured. That difference is the evidence that the two halves of the curve have different causes.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Why does rate rise as temperature increases below the optimum?
    Show the full solution

    Molecules move faster, so collisions are more frequent and more energetic

  2. What happens above the optimum temperature?
    Show the full solution

    The enzyme denatures: bonds holding its shape break and the active site is lost

  3. Define denaturation.
    Show the full solution

    Loss of an enzyme's three-dimensional shape, destroying the active site

  4. What is saturation?
    Show the full solution

    The point at which all active sites are occupied, so more substrate does not raise the rate

  5. How does a competitive inhibitor differ from a non-competitive one?
    Show the full solution

    A competitive inhibitor resembles the substrate and blocks the active site; a non-competitive one binds elsewhere and changes its shape

  6. Explain why "heat kills enzymes" is marked wrong.
    Show the full solution

    Enzymes are protein molecules and have never been alive, so they cannot be killed. What heat does is break the relatively weak bonds maintaining the protein's folded shape, so the active site loses the geometry the substrate depends on and the enzyme can no longer catalyze. The correct word is denatured, and using it signals that you know the mechanism is a change of shape rather than a vague destruction, which is what the question is testing. Enzymes were never alive; heat denatures them by destroying their shape

  7. Explain why the effect of cold is reversible and the effect of heat usually is not.
    Show the full solution

    Cold reduces the kinetic energy of the molecules, so collisions between enzyme and substrate become less frequent and less energetic and the rate falls. The enzyme's structure is untouched, so warming restores the collision rate and activity returns. Heat above the optimum breaks the bonds holding the folded shape, and once the protein has unfolded it does not generally refold into the same precise arrangement, so the active site is permanently lost and cooling changes nothing. Cold only slows collisions; heat destroys the structure permanently

  8. Explain the shape of a graph of rate against substrate concentration.
    Show the full solution

    The rate rises steeply at first because most active sites are free, so adding substrate increases the frequency with which sites are occupied. As concentration rises the sites spend more of their time occupied, so each additional increment of substrate produces a smaller gain and the curve bends. Eventually every active site is working continuously and the enzyme is saturated, at which point the rate plateaus and further substrate has no effect. Raising the rate then requires more enzyme, not more substrate. A steep rise flattening to a plateau as active sites become saturated

  9. Why can adding more substrate overcome a competitive inhibitor but not a non-competitive one?
    Show the full solution

    A competitive inhibitor occupies the same active site the substrate uses, so the two are in direct contest for it, and raising the substrate concentration increases the proportion of encounters won by the substrate until the inhibition is effectively swamped. A non-competitive inhibitor binds at a different location and alters the active site's shape, so the site no longer fits the substrate at all. No amount of substrate helps, because the problem is that the site has changed rather than that it is occupied. Competitive inhibitors contest the site; non-competitive ones change its shape

  10. Human enzymes have an optimum near 37 degrees. Explain why a fever of 40 degrees is dangerous but a fever of 38 is not.
    Show the full solution

    At 38 degrees most enzymes are still close to their optimum and are working slightly faster, which is part of why a modest fever helps fight infection. By 40 degrees the temperature is approaching the point at which the weak bonds holding protein structure begin to fail, and denaturation is not gradual once it starts, since each denatured molecule is lost entirely. A small further rise therefore causes a disproportionate loss of enzyme activity across many systems at once, which is why high fever is treated urgently. Denaturation begins near 40 and, once started, removes enzymes permanently

Lesson 6.4 · Unit 6 · HS-LS1-5

Photosynthesis: the equation, the place, and the pigment

Unit 2 treated photosynthesis as the door through which energy enters an ecosystem. This lesson opens the door and looks inside. The overall equation is short, and every term in it answers a question that unit 4 raised about where the carbon in a tree comes from.

The key ideas
  1. The overall equation: 6CO2 + 6H2O, using light energy, gives C6H12O6 + 6O2.
  2. The carbon comes from the air, not the soil. A tree's mass is built largely from carbon dioxide taken in through the leaves.
  3. The oxygen released comes from water, not from carbon dioxide. Water is split, and this was established by tracing isotopes.
  4. It happens in chloroplasts, which contain stacked membranes called thylakoids surrounded by a fluid stroma.
  5. Chlorophyll absorbs red and blue light strongly and reflects green, which is why leaves look green: the green is the part not used.
  6. Rate is limited by light intensity, carbon dioxide concentration and temperature, and at any moment one of them is the limiting factor.

Where students lose marks: saying plants take in carbon dioxide and "give out oxygen" as though the two were the same atoms rearranged. The oxygen released comes from splitting water. The oxygen in carbon dioxide ends up in the glucose and in water.

Worked example

The question. A tree gains 500 kg of dry mass over twenty years. Where did the mass come from? This question was first asked experimentally in the seventeenth century and the intuitive answer is wrong.

Step one: state the intuitive answer. From the soil. A tree stands in soil, roots take things from soil, so the mass presumably came out of the ground.

Step two: state the historical test. Weigh the soil at the start, grow the tree for years adding only water, then weigh the soil again. The soil loses only a tiny fraction of the mass the tree gained.

Step three: read the equation for the carbon. The only carbon entering the plant is in carbon dioxide from the air, taken in through stomata. Dry plant mass is largely carbohydrate, which is mostly carbon, hydrogen and oxygen.

Step four: account for the hydrogen. That comes from water taken up by the roots, so the soil does contribute, but through water rather than through dissolved solids.

Step five: account for the small soil loss. The mineral ions of lesson 4.3, nitrogen for proteins and magnesium for chlorophyll, do come from soil, and they are a small fraction of total dry mass.

Step six: state the conclusion. Most of a tree is built from air and water. A log is, in effect, solidified atmospheric carbon dioxide, which is what makes forests a carbon reservoir in lesson 4.2.

Step seven: settle the oxygen question separately. The oxygen released is not left over from carbon dioxide. Experiments using water containing a heavier isotope of oxygen showed the released gas carried that label, proving water is the source.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Write the overall equation for photosynthesis in words.
    Show the full solution

    Carbon dioxide plus water, using light energy, gives glucose plus oxygen

  2. Where in the cell does photosynthesis take place?
    Show the full solution

    In the chloroplast, in the thylakoid membranes and the stroma

  3. Which molecule is the source of the oxygen released?
    Show the full solution

    Water

  4. Why do leaves appear green?
    Show the full solution

    Chlorophyll absorbs red and blue light and reflects green

  5. Name the three main limiting factors.
    Show the full solution

    Light intensity, carbon dioxide concentration and temperature

  6. Explain where the mass of a large tree comes from.
    Show the full solution

    Mostly from the air. The carbon that makes up the bulk of a tree's dry mass enters as carbon dioxide through the stomata and is fixed into carbohydrate by photosynthesis, while the hydrogen comes from water absorbed by the roots. Soil contributes mineral ions such as nitrate and magnesium, which are essential but form only a small fraction of the total. This is why the soil in a pot loses almost no mass while the plant growing in it gains a great deal. Carbon from atmospheric carbon dioxide and hydrogen from water, with minerals a small fraction

  7. Explain how isotope experiments showed the oxygen comes from water.
    Show the full solution

    Water was supplied containing a heavier isotope of oxygen while the carbon dioxide contained the ordinary isotope, and the oxygen gas released carried the heavy label. Repeating the experiment with the labels reversed, so that the carbon dioxide was heavy, produced ordinary oxygen gas. Since the label tracked the water in both cases, the released oxygen must originate there. This is a clean example of an experiment with a single variable and a clear falsifying outcome, as lesson 1.2 describes. Labeled heavy oxygen in the water appeared in the gas released, and the reverse did not

  8. A greenhouse grower raises light intensity and sees no increase in growth. Suggest why and what to do.
    Show the full solution

    Light is evidently no longer the limiting factor, so raising it further cannot help: something else has become the constraint, most likely carbon dioxide concentration or temperature. The grower should raise carbon dioxide, which is why commercial greenhouses often enrich the air, or check whether temperature is below the optimum for the plant's enzymes. The general principle is that the rate is set by whichever factor is in shortest supply, so increasing any other one has no effect until that one is relieved. Another factor is now limiting; raise carbon dioxide or temperature

  9. Why would a plant given green light only grow poorly?
    Show the full solution

    Because chlorophyll absorbs light most strongly in the red and blue regions and reflects or transmits green, which is precisely why leaves look green. Under green light very little of the energy arriving is absorbed by the pigment, so little is available to drive the light-dependent reactions, and photosynthesis runs slowly regardless of how bright the light appears to a human eye. Brightness as we perceive it is not the same as usable energy for the plant. Chlorophyll reflects green, so little of that light is absorbed

  10. Explain how this lesson connects to the carbon cycle of lesson 4.2.
    Show the full solution

    Photosynthesis is the flux that removes carbon dioxide from the atmosphere and fixes it into organic molecules, so it is the entry point of the fast carbon cycle. The mass of a tree is atmospheric carbon that has been converted into wood, which is why growing forests act as a carbon sink. That carbon returns when respiration or decomposition breaks the molecules down, closing the loop, and only the small fraction that escapes decomposition and is buried leaves for the slow cycle. It is the flux that fixes atmospheric carbon into the fast cycle

Lesson 6.5 · Unit 6 · HS-LS1-5

The two stages: light reactions and the Calvin cycle

Photosynthesis is two linked processes in two different parts of the chloroplast. The first captures light and makes a short-lived energy supply. The second spends that supply building sugar from carbon dioxide, and it can run for a while in darkness, which is why calling it the dark reaction causes so much trouble.

The key ideas
  1. The light-dependent reactions occur in the thylakoid membranes. They absorb light, split water, release oxygen, and produce ATP and a carrier called NADPH.
  2. Splitting water is where the oxygen comes from, and it also supplies the hydrogen that NADPH carries.
  3. The Calvin cycle occurs in the stroma, the fluid around the thylakoids. It uses ATP and NADPH to fix carbon dioxide into sugar.
  4. The Calvin cycle needs no light directly, but it depends entirely on the ATP and NADPH the light reactions supply, so it stops soon after darkness falls.
  5. Carbon fixation means attaching carbon dioxide to an existing molecule, converting inorganic carbon into an organic form.
  6. The two stages exchange materials both ways: ATP and NADPH go to the stroma, and ADP and the empty carrier return to the thylakoid.

Where students lose marks: calling the Calvin cycle the "dark reaction" and concluding that it happens at night. It happens whenever ATP and NADPH are available, which in practice means during and shortly after illumination. Light independent is the accurate term.

Worked example

The task. Track the inputs and outputs of each stage, then use the result to predict what happens when the light goes out.

StageLocationTakes inGives out
Light-dependentthylakoid membranelight, water, ADP, carrieroxygen, ATP, NADPH
Calvin cyclestromacarbon dioxide, ATP, NADPHsugar, ADP, empty carrier

Step one: notice the outputs of one are the inputs of the other. ATP and NADPH made in the thylakoid are consumed in the stroma, and the ADP and empty carrier returned are reused in the thylakoid. The two stages are coupled.

Step two: locate the oxygen. It is an output of the first stage only, produced when water is split. It is a by-product: the plant needs the hydrogen and the electrons, not the oxygen.

Step three: locate the carbon dioxide. It enters only at the second stage. The light reactions never touch carbon dioxide, which is why the two stages answer different questions.

Step four: predict the effect of darkness. The light reactions stop at once. The Calvin cycle continues briefly on the ATP and NADPH already present, then stops when they run out.

Step five: predict the effect of removing carbon dioxide in bright light. The Calvin cycle stops for lack of substrate. ATP and NADPH accumulate because nothing is spending them, and the light reactions then slow because ADP and the empty carrier are no longer being returned.

Step six: read what that prediction shows. The coupling runs both ways. Blocking the second stage slows the first, even though the first does not use carbon dioxide at all, and this is testable.

Step seven: state the correct name and why it matters. Light independent, not dark. The reaction does not require light itself but does require the products of light capture, so it neither needs darkness nor survives it for long.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Where do the light-dependent reactions occur?
    Show the full solution

    In the thylakoid membranes of the chloroplast

  2. Name the three products of the light-dependent reactions.
    Show the full solution

    Oxygen, ATP and NADPH

  3. Where does the Calvin cycle occur and what does it take in?
    Show the full solution

    In the stroma; it takes in carbon dioxide, ATP and NADPH

  4. What does carbon fixation mean?
    Show the full solution

    Attaching carbon dioxide to an existing molecule, converting inorganic carbon to organic

  5. Why is "light independent" better than "dark reaction"?
    Show the full solution

    It does not need light directly but needs the products of the light reactions, so it does not run in prolonged darkness

  6. Explain why the Calvin cycle stops shortly after nightfall.
    Show the full solution

    The cycle does not use light itself, but it consumes ATP and NADPH, and both are produced only by the light-dependent reactions. When light stops, that supply ends immediately while the cycle continues spending the small quantity already present in the stroma. Within a short time both are exhausted and the cycle halts for lack of energy and reducing power, not for lack of carbon dioxide. This is exactly why the name dark reaction misleads students into predicting the opposite. It runs on ATP and NADPH, which only the light reactions supply

  7. Predict what happens to oxygen output if carbon dioxide is removed in bright light, and explain.
    Show the full solution

    Oxygen output falls, even though the reaction producing oxygen does not use carbon dioxide. Without carbon dioxide the Calvin cycle stops, so it no longer consumes ATP and NADPH and no longer returns ADP and the empty carrier to the thylakoid. The light-dependent reactions need those returning molecules as raw materials, so they slow once the supply dries up, and water splitting slows with them. The coupling between the stages makes the second stage able to limit the first. The Calvin cycle stops returning ADP and carrier, so the light reactions slow

  8. Why is the oxygen released described as a by-product?
    Show the full solution

    Because the plant splits water for the hydrogen and the electrons it needs to make NADPH and drive ATP synthesis, and the oxygen atoms are simply what is left over. Nothing in photosynthesis requires oxygen, and the plant makes no further use of it, so it diffuses out through the stomata. It is essential to nearly all other life and irrelevant to the process producing it, which is why the history of Earth's atmosphere in lesson 11.7 turns on an accident of plant chemistry. The plant needs the hydrogen and electrons from water; oxygen is left over

  9. Why must the two stages occur in different parts of the chloroplast?
    Show the full solution

    The light-dependent reactions need an organized membrane to hold the pigments and electron carriers in the correct order and to maintain a difference in hydrogen ion concentration across it, which is only possible in a sealed membrane system such as the thylakoid. The Calvin cycle is a series of enzyme-controlled reactions in solution and needs a fluid compartment where enzymes and substrates can mix freely, which the stroma provides. This is the compartmentalization argument of lesson 5.2 applied inside one organelle. One needs an organized membrane, the other a fluid compartment for enzymes

  10. A plant is kept in constant light. Predict whether it grows faster indefinitely, and explain.
    Show the full solution

    No. Once light is no longer the limiting factor, further illumination cannot raise the rate, and carbon dioxide concentration or temperature will constrain it instead. Very high light intensities can also damage the photosynthetic machinery. Beyond that, plants have internal rhythms and many processes, including some aspects of growth and flowering, depend on a period of darkness, so constant light can disrupt development even where photosynthesis itself is unaffected. No: another factor becomes limiting, and many plants need a dark period

Lesson 6.6 · Unit 6 · HS-LS1-7

Cellular respiration, stage by stage

Respiration is the controlled release of energy from glucose, and the word controlled is doing the work. Burning glucose releases the same energy in one uncontrolled burst of heat. A cell takes it apart in small steps, capturing energy as ATP at each one, and the three stages happen in three different places.

The key ideas
  1. The overall equation: C6H12O6 + 6O2 gives 6CO2 + 6H2O, releasing energy transferred to ATP.
  2. Glycolysis occurs in the cytoplasm. Glucose is split into two three-carbon molecules of pyruvate, with a net gain of 2 ATP. No oxygen is required.
  3. The Krebs cycle occurs in the mitochondrial matrix. Pyruvate is broken down completely, releasing carbon dioxide and loading electron carriers.
  4. The electron transport chain is in the inner mitochondrial membrane, and produces most of the ATP.
  5. Oxygen's role is at the very end: it is the final electron acceptor, combining with electrons and hydrogen to form water.
  6. Total yield is about 30 to 32 ATP per glucose, the great majority of it from the electron transport chain.

Where students lose marks: saying oxygen is needed "to break down glucose". Glucose is broken down in glycolysis and the Krebs cycle without oxygen being involved. Oxygen accepts electrons at the end of the chain, and without it the chain backs up and everything upstream stops.

Worked example

The task. Follow one glucose molecule through all three stages, tracking location, carbon and ATP.

Step one: glycolysis, in the cytoplasm. Glucose, with six carbons, is split into two molecules of pyruvate with three carbons each. Two ATP are invested and four produced, a net gain of 2. Electron carriers are loaded.

Step two: note what has not happened. No carbon dioxide has been released and no oxygen has been used. All six carbons are still in the two pyruvate molecules.

Step three: pyruvate enters the mitochondrion. It is converted to a two-carbon compound, releasing one carbon dioxide per pyruvate, so two of the six carbons leave here.

Step four: the Krebs cycle, in the matrix. The remaining carbons are released as carbon dioxide, accounting for all six. A small amount of ATP is made directly, and many electron carriers are loaded.

Step five: the electron transport chain, in the inner membrane. The loaded carriers deliver electrons to a series of proteins. The energy released as electrons pass along is used to pump hydrogen ions across the membrane, and their return flow drives ATP synthesis.

Step six: oxygen at the end. Electrons must go somewhere once they reach the end of the chain. Oxygen accepts them, combining with hydrogen ions to form water. Without an acceptor the chain fills and stops.

Step seven: add up and locate the yield. About 30 ATP in total, with only 2 from glycolysis and a small number from the Krebs cycle. The overwhelming majority comes from the electron transport chain, which is why the absence of oxygen is so costly.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Write the overall equation for aerobic respiration in words.
    Show the full solution

    Glucose plus oxygen gives carbon dioxide plus water, releasing energy for ATP

  2. Where does glycolysis occur and what is the net ATP gain?
    Show the full solution

    In the cytoplasm, with a net gain of 2 ATP

  3. Where does the Krebs cycle occur?
    Show the full solution

    In the mitochondrial matrix

  4. What is the role of oxygen?
    Show the full solution

    It is the final electron acceptor at the end of the electron transport chain

  5. Which stage produces most of the ATP?
    Show the full solution

    The electron transport chain

  6. Explain why "oxygen is needed to break down glucose" is inaccurate.
    Show the full solution

    Glucose is broken apart in glycolysis and the Krebs cycle, and neither uses oxygen: all six carbons have been released as carbon dioxide before oxygen appears anywhere in the process. Oxygen acts only at the end of the electron transport chain, accepting the electrons that have been passed along it. Its absence matters enormously, because the chain then backs up and the earlier stages stop, but describing it as the agent of breakdown misplaces it by two stages and obscures why anaerobic respiration is possible at all. Glucose is broken down without oxygen; oxygen only accepts electrons at the end

  7. Explain what happens to the whole process if the electron transport chain is blocked.
    Show the full solution

    ATP production collapses almost entirely, since the chain supplies the great majority of it. The electron carriers loaded during glycolysis and the Krebs cycle cannot unload, so they remain full and are unavailable to accept more electrons, which halts the Krebs cycle for lack of empty carriers. Glycolysis can continue only if the cell has another way of regenerating those carriers, which fermentation provides, and that yields just 2 ATP per glucose. This is why cyanide, which blocks the chain, is so rapidly fatal. Carriers stay loaded, the Krebs cycle halts, and yield falls to glycolysis alone

  8. Why is respiration described as controlled release rather than burning?
    Show the full solution

    Burning releases all the energy in glucose at once as heat, which a cell could neither capture nor survive. Respiration dismantles the molecule through many small enzyme-controlled steps, each releasing a modest amount of energy, much of which is captured as ATP rather than lost. The stepwise design is what makes capture possible: a single large release would exceed anything the cell could store, and the heat would denature its proteins. The products are identical, which shows the difference is entirely in the pathway. Many small steps allow energy capture, while one burst would be lost as heat

  9. All six carbons leave as carbon dioxide. Trace where each pair is released.
    Show the full solution

    Glucose has six carbons, and glycolysis splits it into two pyruvate molecules of three carbons each, releasing none. When each pyruvate enters the mitochondrion it is converted to a two-carbon compound, releasing one carbon dioxide each, so two of the six leave at this step. The remaining two carbons in each of the two compounds are then released during the Krebs cycle, accounting for the final four. Every carbon that entered as glucose leaves as carbon dioxide. Two on entry to the mitochondrion, four in the Krebs cycle, none in glycolysis

  10. Why do cells with high energy demands have mitochondria with extensively folded inner membranes?
    Show the full solution

    The electron transport chain, which makes most of the ATP, is embedded in the inner mitochondrial membrane, so the quantity of ATP a mitochondrion can produce depends on how much of that membrane it has. Folding it into cristae packs a much larger area into the same volume, exactly the surface area strategy of lesson 5.4, allowing many more chains to operate at once. Cells such as muscle and liver cells that demand ATP continuously show the most extensive folding. Folding packs more electron transport chain membrane into the same volume

Lesson 6.7 · Unit 6 · HS-LS1-5, HS-LS1-7

Aerobic against anaerobic, and the two processes as a matched pair

Without oxygen a cell can still extract a little energy from glucose, and the difference in yield is startling: roughly fifteen times less. This lesson settles that comparison and then does something the course has been building toward since unit 2, setting photosynthesis and respiration side by side properly.

The key ideas
  1. Anaerobic respiration runs without oxygen and consists of glycolysis plus a step that regenerates the electron carriers so glycolysis can continue.
  2. In animals the product is lactate, which accumulates in muscle during hard exercise and is later processed by the liver.
  3. In yeast and plants the products are ethanol and carbon dioxide, which is the basis of brewing and of bread rising.
  4. The yield is about 2 ATP per glucose against about 30 aerobically, so anaerobic respiration is roughly fifteen times less efficient.
  5. The energy is not destroyed, it remains locked in lactate or ethanol, which is why those products still burn and why yeast can be used to make fuel.
  6. Photosynthesis and respiration are near reverses, but they are not the same reaction run backwards: different locations, different enzymes, different intermediate steps, and photosynthesis stores energy while respiration releases it.

Where students lose marks: saying plants photosynthesize and animals respire. Plants respire constantly, day and night, in every living cell. During daylight photosynthesis usually exceeds respiration, which is why the net exchange looks one way.

Worked example

Part one: the cost of running without oxygen. A muscle cell needs 300 ATP worth of work.

Step one: the aerobic requirement. At about 30 ATP per glucose, 300 divided by 30 is 10 glucose molecules.

Step two: the anaerobic requirement. At 2 ATP per glucose, 300 divided by 2 is 150 glucose molecules, fifteen times as many for the same work.

Step three: explain where the rest of the energy went. It did not disappear. It remains in the lactate, which is still an energy-rich molecule. Anaerobic respiration extracts only the small portion released during glycolysis.

Step four: state why cells use it anyway. It is much faster per unit time and needs no oxygen, so a sprinting muscle can draw on it when the blood supply cannot deliver oxygen quickly enough. It buys power at the cost of efficiency.

Part two: the matched pair. Set the two equations against each other.

Step five: write them out. Photosynthesis: carbon dioxide plus water, using light, gives glucose plus oxygen. Respiration: glucose plus oxygen gives carbon dioxide plus water, releasing energy. The reactants of each are the products of the other.

Step six: state the crucial difference. Photosynthesis converts light energy into chemical energy, storing it. Respiration converts chemical energy into a usable form, releasing it. One fills the store and one empties it, so they cannot be the same reaction running in two directions.

Step seven: list the other differences that matter. Different organelles, different enzymes, different intermediate compounds, and different organisms capable of each: every living thing respires, while only autotrophs photosynthesize. A plant does both at once, all day.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What is the ATP yield of anaerobic respiration per glucose?
    Show the full solution

    About 2

  2. Name the products of anaerobic respiration in animals and in yeast.
    Show the full solution

    Lactate in animals; ethanol and carbon dioxide in yeast

  3. Roughly how many times more efficient is aerobic respiration?
    Show the full solution

    About fifteen times

  4. A cell needs 900 ATP. How much glucose aerobically, and how much anaerobically?
    Show the full solution

    30 molecules aerobically and 450 anaerobically

  5. Do plants respire at night?
    Show the full solution

    Yes, constantly, in every living cell, day and night

  6. Explain where the missing energy goes in anaerobic respiration.
    Show the full solution

    It stays in the products. Anaerobic respiration only completes glycolysis, which splits glucose into two three-carbon molecules, so the great majority of the chemical energy originally in the glucose remains locked in the bonds of lactate or ethanol. Nothing has been destroyed and little has been lost as heat; the pathway simply stops early. This is why ethanol is a usable fuel and why the liver can later process lactate to recover energy from it when oxygen becomes available. It remains in the bonds of lactate or ethanol, which are still energy-rich

  7. Why does a sprinter use anaerobic respiration even though it wastes glucose?
    Show the full solution

    Because the limiting factor during a sprint is not fuel but the rate at which ATP can be supplied. Aerobic respiration depends on oxygen reaching the muscle through the blood, and that delivery cannot rise fast enough to meet the demand of maximal effort. Anaerobic respiration produces ATP quickly and without oxygen, so it can bridge the gap. The cost is inefficient use of glucose and the accumulation of lactate, which is acceptable for a short burst. It supplies ATP quickly without oxygen, which delivery cannot match in a sprint

  8. Explain why calling photosynthesis and respiration opposites is only partly right.
    Show the full solution

    The overall equations are near reverses, so the reactants of one are the products of the other, and in that limited sense they are opposites. But they are not one reaction run in two directions: they occur in different organelles, use different enzymes, proceed through entirely different intermediates, and differ in what happens to energy, since photosynthesis converts light into stored chemical energy while respiration releases stored chemical energy into a usable form. Treating them as a single reversible process leads to wrong predictions about both. The equations reverse, but the locations, enzymes, intermediates and energy direction all differ

  9. Why does bread rise, and why does the alcohol not remain?
    Show the full solution

    Yeast respires anaerobically in the dough, producing carbon dioxide and ethanol. The carbon dioxide forms bubbles trapped by the gluten network, which expands the dough and gives bread its texture. The ethanol is also present but boils at a much lower temperature than water, so it evaporates during baking and almost none remains in the finished loaf. The same process in a sealed vessel, where the gas cannot escape and the liquid is not heated, produces beer instead. Carbon dioxide from yeast fermentation raises it; the ethanol evaporates in the oven

  10. A sealed jar containing a green plant is kept in darkness. Predict what happens to the oxygen and carbon dioxide, and explain.
    Show the full solution

    Oxygen falls and carbon dioxide rises. In darkness photosynthesis stops entirely, but respiration continues in every living cell of the plant, consuming oxygen and releasing carbon dioxide, so the exchange runs one way only. In the light the same jar would show the reverse, because photosynthesis normally exceeds respiration during the day, but the plant would still be respiring throughout. This is the experiment that disproves the idea that plants only photosynthesize. Oxygen falls and carbon dioxide rises, since respiration continues without photosynthesis

Unit 6 review · Energy in the Cell

Ten questions across the whole unit

Questions 1 to 5 check that you hold the terms. Questions 6 to 10 require you to reason across the seven lessons.

  1. What are the three parts of an ATP molecule?
    Show the full solution

    An adenine base, a ribose sugar and three phosphate groups

  2. What does an enzyme do to activation energy, and what does it not change?
    Show the full solution

    It lowers activation energy; it does not change the overall energy released

  3. Write the photosynthesis equation in words and name the source of the released oxygen.
    Show the full solution

    Carbon dioxide plus water, using light, gives glucose plus oxygen; the oxygen comes from water

  4. Give the location and ATP yield of each stage of aerobic respiration.
    Show the full solution

    Glycolysis in the cytoplasm, net 2 ATP; Krebs cycle in the matrix, a small amount; electron transport chain in the inner membrane, most of the total

  5. A cell needs 450 ATP. How much glucose aerobically and anaerobically?
    Show the full solution

    15 molecules aerobically at about 30 each, and 225 anaerobically at 2 each

  6. Explain why "heat kills enzymes" loses a mark and what the accurate statement is.
    Show the full solution

    Enzymes are protein molecules and have never been alive, so they cannot be killed. Heat above the optimum breaks the relatively weak bonds maintaining the protein's folded shape, so the active site loses the geometry the substrate depends on and catalysis stops. The correct word is denatured, and using it signals that the mechanism is understood as a change of shape rather than a vague destruction, which is what the question tests. Enzymes were never alive; heat denatures them by destroying their shape

  7. Explain why the falling half of a temperature curve is steeper than the rising half.
    Show the full solution

    The rise reflects a gradual increase in the frequency and energy of collisions between enzyme and substrate, which raises the rate smoothly while leaving the enzyme intact. The fall reflects molecules being progressively destroyed: once an enzyme molecule denatures it stops contributing entirely and does not recover, so the loss compounds as more molecules are affected. Two different mechanisms produce the two halves, which is why their shapes differ. Rising reflects more collisions; falling reflects permanent destruction, which compounds

  8. Predict what happens to oxygen output if carbon dioxide is removed in bright light, and explain.
    Show the full solution

    Oxygen output falls, even though the reaction producing oxygen does not use carbon dioxide. Without carbon dioxide the Calvin cycle stops, so it no longer consumes ATP and NADPH and no longer returns ADP and the empty carrier to the thylakoid. The light-dependent reactions need those returning molecules as raw materials, so they slow and water splitting slows with them. The coupling lets the second stage limit the first. The Calvin cycle stops returning ADP and carrier, so the light reactions slow

  9. Explain why "oxygen is needed to break down glucose" is inaccurate.
    Show the full solution

    Glucose is broken apart in glycolysis and the Krebs cycle, neither of which uses oxygen, and all six carbons have been released as carbon dioxide before oxygen appears anywhere. Oxygen acts only at the end of the electron transport chain, accepting the electrons passed along it. Its absence matters enormously, because the chain then backs up and the earlier stages halt, but describing it as the agent of breakdown misplaces it by two stages. Glucose is broken down without oxygen; oxygen only accepts electrons at the end

  10. Explain why photosynthesis and respiration are not simply one reaction run in two directions.
    Show the full solution

    The overall equations are near reverses, but the processes occur in different organelles, use different enzymes and proceed through entirely different intermediates. They also differ in what happens to energy: photosynthesis converts light into stored chemical energy while respiration releases stored chemical energy into a usable form. One fills the store and one empties it, so treating them as a single reversible process produces wrong predictions about both. Different locations, enzymes, intermediates and energy direction

Lesson 7.1 · Unit 7 · HS-LS1-1, HS-LS3-1

Finding the genetic material: three experiments

That DNA carries genetic information is now so familiar it seems obvious. It was not. For decades the reasonable bet was protein, because proteins are built from twenty different amino acids and DNA from only four bases, and four symbols looked far too few to specify an organism. Three experiments changed the answer.

The key ideas
  1. The problem: chromosomes contain both DNA and protein, so finding them in the right place did not identify which molecule carried the information.
  2. Griffith, 1928, showed that something from dead bacteria could permanently change living bacteria of a different strain. He called it the transforming principle and did not know what it was.
  3. The transformation was heritable, which is the crucial detail: the changed bacteria bred true, so whatever had been transferred was genetic material rather than a temporary effect.
  4. Avery and colleagues, in the 1940s, purified the transforming principle and destroyed each candidate molecule in turn with enzymes. Transformation failed only when DNA was destroyed.
  5. Hershey and Chase, in 1952, labeled viral DNA and viral protein separately and showed that only the DNA entered the bacterial cell it infected.
  6. The argument is cumulative. No single experiment was decisive; three independent approaches agreeing is what settled it, which is the pattern lesson 10.7 will meet again.

Where students lose marks: saying Griffith discovered DNA is the genetic material. He discovered that something transferable existed. Identifying it took another sixteen years, and the distinction between observing an effect and identifying its cause is exactly what these questions test.

Worked example

Description of: Griffith's 1928 transformation experiment. Published in 1928 and therefore public domain; described here rather than quoted.

Step one: the two strains. Griffith worked with two forms of a bacterium that causes pneumonia. The S strain has a smooth capsule and is lethal to mice. The R strain is rough, lacking the capsule, and is harmless.

Step two: the two simple controls. Mice injected with living S bacteria died. Mice injected with living R bacteria survived. This establishes what each strain does on its own.

Step three: the third control. Mice injected with heat-killed S bacteria survived. Heat destroys the bacteria's ability to cause disease, as expected.

Step four: the experimental group. Mice injected with heat-killed S bacteria together with living R bacteria died. Neither component killed a mouse on its own, so something about the combination did.

Step five: the observation that makes it genetic. Living S bacteria were recovered from the dead mice. The harmless R bacteria had not merely been made dangerous; they had been converted into the S form.

Step six: the detail that rules out contamination. Those S bacteria bred true, producing more S bacteria in later generations. A temporary chemical effect would not be inherited, so material carrying heritable information had passed from the dead cells to the living ones.

Step seven: state precisely what was and was not shown. Shown: heritable information can be transferred between bacteria, and it survives heat that kills the cell. Not shown: which molecule carries it. Griffith's four groups are a model of controlled design, and they still leave the chemical question open.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Why did many scientists expect protein to be the genetic material?
    Show the full solution

    Proteins are built from twenty amino acids and DNA from only four bases, so protein looked capable of carrying more information

  2. Describe the two bacterial strains Griffith used.
    Show the full solution

    S with a smooth capsule and lethal; R rough, without a capsule, and harmless

  3. What happened when heat-killed S was injected with living R?
    Show the full solution

    The mice died, and living S bacteria were recovered from them

  4. What did Avery's group do to identify the transforming principle?
    Show the full solution

    Destroyed each candidate molecule in turn with enzymes; transformation failed only when DNA was destroyed

  5. What did Hershey and Chase show?
    Show the full solution

    That only viral DNA, not viral protein, entered the infected bacterial cell

  6. Explain why the recovery of living S bacteria mattered more than the death of the mice.
    Show the full solution

    The deaths alone could have had several explanations, including a toxin surviving the heat treatment or some chemical from the dead cells making the R bacteria temporarily dangerous. Recovering living S bacteria showed that the R cells themselves had been converted into a different strain, and because those bacteria bred true in later generations the change was inherited. Only a transfer of genetic material explains a permanent heritable conversion, so that observation is what makes the experiment about heredity rather than about toxicity. It showed a permanent heritable conversion rather than a temporary toxic effect

  7. Identify the variables and controls in Griffith's design.
    Show the full solution

    The independent variable is what is injected, with four levels: living S, living R, heat-killed S, and heat-killed S combined with living R. The dependent variable is whether the mouse survives, with recovery of bacteria from the body as a second measurement. The first three groups act as controls establishing what each component does alone, which is what makes the fourth interpretable: since neither heat-killed S nor living R kills by itself, the deaths in the combined group must come from their interaction. Injection contents is independent, survival is dependent, and the three single-component groups are controls

  8. Why was Avery's enzyme approach more decisive than Griffith's?
    Show the full solution

    Griffith showed that some material transferred information but had no way to say which molecule. Avery's group took the purified extract and destroyed one candidate at a time, using enzymes that break down protein, RNA or DNA specifically, then tested whether transformation still occurred. Transformation survived the destruction of protein and RNA and failed only when DNA was destroyed, which isolates a single variable and points at one molecule. It moves from detecting an effect to identifying its cause. Destroying one candidate at a time isolated DNA as the necessary molecule

  9. Why does the agreement of three independent experiments matter more than any one of them?
    Show the full solution

    Each experiment has its own possible weaknesses: Griffith's could be explained by an unknown transferable substance, Avery's by traces of contaminating protein in a supposedly pure DNA preparation, and Hershey and Chase's by imperfect labeling or incomplete separation. Those weaknesses are unrelated to one another, so a single explanation that accounts for all three results while leaving DNA out becomes very hard to construct. Independent lines converging on the same answer is the strongest form of evidence in biology. Their weaknesses are unrelated, so an alternative explanation would have to defeat all three

  10. The four-base objection turned out to be wrong. Suggest why four symbols are enough.
    Show the full solution

    Because information capacity depends on sequence length as well as on the number of symbols available, and long sequences of few symbols carry enormous amounts of information. Four bases read in groups of three give sixty four combinations, comfortably more than the twenty amino acids that need specifying, and a chromosome contains millions of bases in a defined order. The same principle lets two symbols encode anything in a computer. The objection confused the size of the alphabet with the length of the message. Sequence length carries the information; four symbols in long strings are ample

Lesson 7.2 · Unit 7 · HS-LS1-1, HS-LS3-1

DNA structure: the shape that explains the function

The structure of DNA is famous partly because it answered a question nobody had been able to approach: how a molecule can be copied exactly. The answer is visible in the structure itself, which is unusual and is why the model was accepted so quickly once it was proposed.

The key ideas
  1. A nucleotide has three parts: a phosphate group, a deoxyribose sugar, and one of four nitrogen-containing bases.
  2. The four bases are adenine, thymine, cytosine and guanine, written A, T, C and G.
  3. The backbone is sugar and phosphate alternating, with the bases projecting inward. The backbone is the same all the way along, so it carries no information.
  4. Base pairing is specific: A pairs only with T, and C only with G, held by hydrogen bonds. This is complementary base pairing.
  5. The two strands run in opposite directions, which is described as antiparallel, and the whole structure twists into a double helix.
  6. Chargaff's ratios were the clue. In any organism's DNA the amount of A equals the amount of T, and C equals G, which is exactly what specific pairing predicts.

Where students lose marks: saying the bases are joined by strong bonds. Hydrogen bonds between bases are individually weak, which is essential: the strands must separate easily for replication and transcription. It is their number, not their strength, that holds the molecule together.

Worked example

Part one: using Chargaff's ratios. A sample of DNA is found to contain 30 percent adenine. Work out the other three percentages.

Step one: apply the pairing rule to A. Every adenine is paired with a thymine, so thymine must also be 30 percent.

Step two: find what remains. A and T together account for 60 percent, so C and G together account for 100 minus 60, which is 40 percent.

Step three: split the remainder. C pairs only with G, so they are present in equal amounts. 40 divided by 2 is 20, so cytosine is 20 percent and guanine is 20 percent.

Step four: check the total. 30 plus 30 plus 20 plus 20 is 100. The arithmetic is consistent, and the method works from any single value.

Part two: why the structure explains copying.

Step five: state what each strand contains. Because pairing is specific, the sequence of one strand completely determines the sequence of the other. A stretch reading ATCG must face TAGC.

Step six: draw the consequence. Separate the strands and each one carries the full information needed to rebuild its partner. The molecule contains two copies of the same message, written in complementary form.

Step seven: note why this was so persuasive. A structure proposed to explain X-ray data turned out to contain, in its own geometry, a mechanism for the central unsolved problem of heredity. That is rare, and it is why the model was accepted before the copying mechanism had been demonstrated.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Name the three parts of a nucleotide.
    Show the full solution

    A phosphate group, a deoxyribose sugar, and a nitrogenous base

  2. Which bases pair with which?
    Show the full solution

    A with T, and C with G

  3. What holds the two strands together?
    Show the full solution

    Hydrogen bonds between the paired bases

  4. A sample contains 22 percent guanine. Find the other three percentages.
    Show the full solution

    C is 22 percent; A and T are 28 percent each

  5. What does antiparallel mean?
    Show the full solution

    The two strands run in opposite directions

  6. Explain why it is an advantage that the base pair bonds are weak.
    Show the full solution

    The strands must be separated every time the molecule is copied or a gene is transcribed, and that has to be possible at body temperature using enzymes rather than extreme conditions. Individually weak hydrogen bonds can be broken locally with little energy, so a region can be opened without disturbing the rest. The molecule stays stable overall because there are so many of these bonds along its length, so strength comes from number rather than from each bond being strong. Strands must separate easily for copying; stability comes from the number of bonds

  7. Explain why the sugar-phosphate backbone carries no information.
    Show the full solution

    The backbone is identical everywhere along the molecule, an unvarying alternation of the same sugar and the same phosphate group, so reading it at one position tells you nothing that reading it at any other would not. Information requires something that can differ from place to place, and in DNA only the bases do. This is the reason a four-letter sequence of bases, rather than the structure holding them, is what a gene consists of. It is identical along its length, and information requires variation

  8. Explain how the structure itself suggests a copying mechanism.
    Show the full solution

    Because pairing is specific, each strand's sequence dictates its partner's exactly, so the molecule effectively carries the same message twice in complementary form. Separating the two strands therefore yields two complete templates, each able to direct the assembly of a new partner by the same pairing rules. No additional information is needed and no separate copying machinery has to store the sequence, which is why the structure was regarded as solving the problem of heredity as soon as it was proposed. Specific pairing means each strand is a complete template for its partner

  9. Chargaff's ratios were known before the structure was proposed. Explain their significance.
    Show the full solution

    They were an unexplained regularity: across very different organisms the amount of adenine always matched thymine and cytosine always matched guanine, even though the overall proportions varied between species. Any correct structure had to account for that, and specific pairing explains it exactly, since pairing A with T necessarily makes their quantities equal. The ratios therefore acted as a strong constraint that ruled out proposed structures and supported the one that predicted them. They were a regularity any correct structure had to explain, and specific pairing does

  10. Two species have DNA with very different proportions of A and C. Does this conflict with Chargaff? Explain.
    Show the full solution

    No. Chargaff's rules state that within any one sample the amount of A equals the amount of T and C equals G, which follows from pairing. They say nothing about the ratio of A to C, which varies considerably between species and is a genuine difference in DNA composition. Confusing the two is a standard error: the rules constrain each pair to be balanced, not the two pairs to be equal to each other. The rules equate A with T and C with G, not A with C

Lesson 7.3 · Unit 7 · HS-LS1-1, HS-LS3-1

Replication: semi-conservative, and why that was testable

Before a cell divides it must copy its entire genome, and the copy has to be accurate or the daughter cells inherit errors. The structure of DNA suggested how, but three different mechanisms were consistent with it, and choosing between them required an experiment of unusual elegance.

The key ideas
  1. Replication is semi-conservative: each new double helix consists of one original strand and one newly built strand.
  2. Helicase unwinds and separates the strands, breaking the hydrogen bonds between the paired bases.
  3. DNA polymerase builds the new strands, adding free nucleotides that pair with the exposed bases according to the pairing rules.
  4. The original strands act as templates, which is why the copy is accurate: the sequence is dictated rather than remembered.
  5. Proofreading reduces errors because DNA polymerase checks each added base, giving an extremely low but non-zero error rate.
  6. The remaining errors are mutations, and they are the ultimate source of all genetic variation, which is the link to units 8 and 10.

Where students lose marks: saying DNA "splits in half and makes a new half". Say which bonds break: the hydrogen bonds between the bases, not the covalent bonds of the backbone. The backbone of each original strand stays intact throughout, which is precisely what semi-conservative means.

Worked example

The problem. Three mechanisms fit the structure. Distinguish them by predicting what each says about where the original atoms end up.

ModelAfter one roundAfter two rounds
Conservativeone all-old helix, one all-newone all-old, three all-new
Semi-conservativetwo helices, each half oldtwo half-old, two all-new
Dispersivetwo helices of mixed fragmentsfour helices, all mixed

Step one: see why the structure does not settle it. All three produce accurate copies using base pairing. The disagreement is only about what happens to the original strands, which the structure does not specify.

Step two: find a measurable difference. The models differ in how old and new material is distributed. If old and new could be made to differ in weight, the resulting molecules could be separated and counted.

Step three: set up the labeling. Grow bacteria for many generations on a nitrogen source containing a heavy isotope, so all their DNA is heavy. Then move them to a normal light nitrogen source, so all new DNA is light.

Step four: predict the first round. Conservative predicts two distinct bands, one heavy and one light. Semi-conservative predicts a single intermediate band, since every molecule is half heavy and half light. Dispersive also predicts a single intermediate band.

Step five: predict the second round. This is where the remaining two models separate. Semi-conservative predicts two bands, one intermediate and one light, in equal amounts. Dispersive predicts a single band, lighter than before but still uniform.

Step six: state the result. One intermediate band after the first round and two bands after the second, which matches semi-conservative and rules out both alternatives.

Step seven: note the design principle. The experiment is powerful because each model made a different prediction before the data were collected, and every outcome would have eliminated at least one. That is falsifiability from lesson 1.1 used deliberately as a design tool.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What does semi-conservative mean?
    Show the full solution

    Each new double helix has one original strand and one new strand

  2. What does helicase do?
    Show the full solution

    Unwinds the helix and separates the strands by breaking hydrogen bonds

  3. What does DNA polymerase do?
    Show the full solution

    Builds new strands by adding nucleotides that pair with the template bases

  4. Which bonds break during replication?
    Show the full solution

    The hydrogen bonds between paired bases, not the backbone

  5. Why is replication accurate?
    Show the full solution

    The original strand acts as a template and polymerase proofreads

  6. Explain why the first round of the labeling experiment could not distinguish semi-conservative from dispersive.
    Show the full solution

    Both models predict that after one round every molecule contains equal amounts of old heavy material and new light material, so every molecule has the same intermediate density and all of them form one band in the same position. The models disagree about how that material is arranged, with semi-conservative putting it in two intact strands and dispersive scattering it in fragments, but density measures only the proportions. A second round is needed because only then do the two arrangements produce different distributions. Both give molecules of identical intermediate density after one round

  7. Explain how the second round separates the two.
    Show the full solution

    Under semi-conservative replication each intermediate molecule separates into one heavy strand and one light strand, and each acquires a new light partner, producing half intermediate molecules and half entirely light ones, which form two distinct bands. Under dispersive replication the old material is broken up and distributed among all the products, so every molecule is again uniform in composition, merely lighter than before, and a single band appears. Two bands against one is a clean qualitative difference. Semi-conservative gives two bands; dispersive gives one uniformly lighter band

  8. Why does it matter that the original strands survive intact?
    Show the full solution

    It means the information is never reconstructed from a copy of a copy within a single round, since each new molecule retains an original strand as its reference. Errors therefore cannot compound in the way they would if each generation were built entirely from the previous generation's copy. It also means a cell's DNA contains physically old material inherited across many divisions, and it is what makes the labeling experiment possible at all, since the label stays in identifiable strands instead of being scattered. An original template is retained each round, so copying errors cannot compound

  9. DNA polymerase proofreads but the error rate is not zero. Explain why that matters for unit 10.
    Show the full solution

    Uncorrected errors are mutations, and mutation is the only original source of new genetic variation. Crossing over and independent assortment in meiosis rearrange existing alleles but cannot create one that never existed, so without replication errors there would be nothing for natural selection to act on and no evolution. A perfect copying system would therefore be an evolutionary dead end. The error rate is low enough to protect the individual and high enough to supply variation to the population. Uncorrected errors are mutations, the only original source of new variation

  10. A student says replication is how organisms reproduce. Correct them.
    Show the full solution

    Replication is the copying of a DNA molecule, which happens inside a cell before it divides. Reproduction is the production of new organisms, and it requires cell division, and in sexually reproducing species also meiosis, fertilization and development. Replication is a necessary step within those processes rather than the process itself, and confusing the two loses the distinction between copying information and building an organism, which is the subject of the next four lessons. Replication copies DNA within a cell; reproduction produces new organisms

Lesson 7.4 · Unit 7 · HS-LS1-1

Transcription: getting the message out of the nucleus

In a eukaryotic cell the DNA stays in the nucleus and the ribosomes that build proteins are outside it. Something has to carry the instructions across, and it cannot be the DNA itself, which is far too valuable to send out into the cytoplasm. The solution is a disposable copy.

The key ideas
  1. Transcription copies one gene into messenger RNA, which then leaves the nucleus through a pore.
  2. RNA differs from DNA in three ways: it uses ribose rather than deoxyribose, uracil in place of thymine, and it is single stranded.
  3. Only one strand is copied, the template strand. The other carries the same sequence as the mRNA, with uracil replacing thymine.
  4. RNA polymerase does the work, binding at a promoter region that marks where the gene begins and which strand to read.
  5. Base pairing directs it, as in replication, except that adenine on the template pairs with uracil in the RNA.
  6. Only the genes currently needed are transcribed, which is how a cell with a complete genome produces only the proteins its job requires.

Where students lose marks: forgetting that RNA has no thymine. If your mRNA sequence contains a T, you have made an error. Adenine in the DNA template pairs with uracil in the RNA.

Worked example

The task. Transcribe a short DNA template strand, then check the result against the coding strand.

Step one: write the template. The template strand reads TAC GGA TTA ACT. The grouping into threes is only for readability; the cell reads it as a continuous sequence.

Step two: apply the pairing rules base by base. T pairs with A, A pairs with U, C pairs with G, G pairs with C. Work along the sequence rather than trying to do it in blocks.

Step three: transcribe the first group. T gives A, A gives U, C gives G. So TAC becomes AUG.

Step four: complete the sequence. GGA becomes CCU, TTA becomes AAU, and ACT becomes UGA. The full mRNA is AUG CCU AAU UGA.

Step five: check for thymine. The mRNA contains A, U, G and C and no T anywhere. If a T had appeared, the pairing would have been done wrongly.

Step six: write the coding strand for comparison. The other DNA strand is ATG CCT AAT TGA. Compare it with the mRNA: identical except that every T has become U. This is why it is called the coding strand.

Step seven: note what has been achieved. The information in one gene now exists as a short, mobile, disposable molecule that can leave the nucleus, be translated, and then be broken down. The original DNA has not left or been altered, which is the entire point of the arrangement.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Name three differences between RNA and DNA.
    Show the full solution

    Ribose instead of deoxyribose, uracil instead of thymine, and single stranded

  2. Which enzyme carries out transcription?
    Show the full solution

    RNA polymerase

  3. What is a promoter?
    Show the full solution

    A region marking where a gene begins and which strand to read

  4. Transcribe the template strand TAC CGA GTA ATT.
    Show the full solution

    AUG GCU CAU UAA

  5. Where does transcription occur in a eukaryotic cell?
    Show the full solution

    In the nucleus

  6. Explain why the cell makes a disposable RNA copy rather than sending the DNA.
    Show the full solution

    The DNA is the cell's only master copy of its entire genetic information, and the cytoplasm contains enzymes and chemical conditions that could damage it, so sending it out would risk the permanent loss of information that cannot be recovered. A short mRNA copy carries only the one gene needed, can be made in large numbers when a protein is required in quantity, and is broken down afterward, which also gives the cell a way of switching production off. The original stays protected in the nucleus throughout. The master copy stays protected, and disposable copies allow control of output

  7. Why is only one DNA strand transcribed?
    Show the full solution

    The two strands are complementary rather than identical, so they carry different base sequences and would specify different and mostly meaningless amino acid sequences. Only one of them corresponds to the protein the gene encodes, so transcribing the other would produce a useless or harmful product. The promoter region determines which strand RNA polymerase reads for a given gene, and different genes along the same chromosome can use either strand as their template. The strands are complementary, so only one carries the correct sequence

  8. Explain why the mRNA matches the coding strand rather than the template.
    Show the full solution

    The mRNA is built by pairing with the template strand, and the coding strand is also the complement of that same template. Two sequences complementary to the same third sequence must match each other, so the mRNA reproduces the coding strand exactly, with uracil in every position where the DNA has thymine. This is a useful check when working a question: if the mRNA does not read like the coding strand with T replaced by U, a pairing error has been made somewhere. Both are complementary to the template, so they match each other

  9. How does transcription allow cells with identical DNA to be different?
    Show the full solution

    Every cell carries the same genes, but transcription is selective: only the genes a particular cell needs are copied into mRNA, so only those proteins are made. A muscle cell transcribes the genes for contractile proteins and leaves the insulin gene untouched, while a pancreatic cell does the reverse. The difference between cell types is therefore a difference in which genes are being read rather than in which genes are present, which is the subject of lesson 7.7. Only the genes a cell needs are transcribed, so different proteins are made from the same genome

  10. A student writes an mRNA sequence containing thymine. Explain the error and its consequence.
    Show the full solution

    RNA does not contain thymine at all; it uses uracil in that role, so a T in an mRNA sequence means adenine on the template was paired incorrectly. The consequence in an exam is that the sequence is wrong from that point and any amino acids read from it afterward may also be wrong, so a single slip can cost the whole answer. Checking a finished mRNA sequence for the letter T takes a moment and catches the error reliably. RNA uses uracil, so a T means adenine was paired wrongly

Lesson 7.5 · Unit 7 · HS-LS1-1

Translation: reading the code three letters at a time

Translation is where a sequence of bases becomes a sequence of amino acids, and where the word code stops being a metaphor. The rule that connects them is fixed, nearly universal across all living things, and short enough to print on one page.

The key ideas
  1. A codon is three bases of mRNA specifying one amino acid. Three is the smallest group that works, since four bases in pairs give only sixteen combinations and twenty amino acids must be specified.
  2. There are 64 codons for 20 amino acids, so the code is redundant: most amino acids have more than one codon.
  3. AUG is the start codon and also codes for methionine. Three codons are stop signals and code for no amino acid.
  4. The ribosome holds the mRNA and moves along it one codon at a time, building the polypeptide.
  5. Transfer RNA brings the amino acids. Each tRNA has an anticodon that pairs with a specific codon, and carries the matching amino acid.
  6. The code is nearly universal, reading the same in bacteria, plants and animals, which is powerful evidence of common ancestry.

Where students lose marks: confusing codon and anticodon. The codon is on the mRNA; the anticodon is on the tRNA and is complementary to it. Say which molecule you are describing before giving a sequence.

Worked example

The task. Translate the mRNA produced in lesson 7.4, using the extract from the genetic code below.

CodonAUGCCUAAUUGAGCUCAUUAA
Amino acidMet (start)ProAsnSTOPAlaHisSTOP

Step one: take the mRNA. From lesson 7.4 it reads AUG CCU AAU UGA. The grouping into threes is not arbitrary here: it is the reading frame.

Step two: find the start. The ribosome begins at AUG, which both signals the start and codes for methionine. Everything is read in threes from that point.

Step three: read the second codon. CCU is proline. A tRNA carrying proline, with the anticodon GGA, pairs with this codon and delivers its amino acid.

Step four: read the third. AAU is asparagine, delivered by a tRNA with the anticodon UUA.

Step five: read the fourth. UGA is a stop codon. No tRNA corresponds to it and no amino acid is added; the ribosome releases the completed chain.

Step six: state the product. The polypeptide is methionine, proline, asparagine: three amino acids from twelve DNA bases. The stop codon contributes nothing to the chain but is essential for ending it correctly.

Step seven: check the anticodons against the codons. Codon CCU pairs with anticodon GGA, following the same rules with U replacing T. The anticodon is complementary to the codon, never identical, which is the distinction most often muddled.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. How many bases make a codon, and how many codons are there?
    Show the full solution

    Three bases, giving 64 codons

  2. What is the start codon and which amino acid does it specify?
    Show the full solution

    AUG, which specifies methionine

  3. What does a stop codon do?
    Show the full solution

    Ends translation; it codes for no amino acid

  4. What is an anticodon, and where is it found?
    Show the full solution

    A sequence of three bases on a tRNA, complementary to a codon on the mRNA

  5. Using the table, translate AUG GCU CAU UAA.
    Show the full solution

    Methionine, alanine, histidine, then stop

  6. Explain why codons must be three bases rather than two.
    Show the full solution

    Four different bases read in groups of two give four times four, which is sixteen possible combinations, and twenty amino acids must be specified, so a two-base code is simply too small. Groups of three give four times four times four, which is sixty four, comfortably enough. Three is therefore the smallest group size that can work, and the surplus explains the redundancy in the code, since sixty four codons must cover twenty amino acids plus a stop signal. Two bases give only 16 combinations for 20 amino acids; three give 64

  7. Explain what redundancy in the genetic code means and why it is useful.
    Show the full solution

    Redundancy means most amino acids are specified by more than one codon, since sixty four codons cover twenty amino acids. It is useful because it buffers against mutation: a base change that converts one codon into another for the same amino acid leaves the protein completely unaltered. Such silent mutations are common, and the redundancy is concentrated in the third base of many codons, so changes there are especially likely to be harmless. The code has a degree of built-in error tolerance. Several codons per amino acid, so many base changes leave the protein unchanged

  8. Why is the near-universality of the code strong evidence for common ancestry?
    Show the full solution

    The assignment of particular codons to particular amino acids is arbitrary in the sense that a different assignment would work just as well, so there is no chemical necessity making AUG mean methionine. If life had arisen independently several times, those separate origins would have had no reason to settle on the same arbitrary scheme. Finding essentially the same code in bacteria, plants, fungi and animals is therefore best explained by inheritance from a single ancestral population that already used it. The assignments are arbitrary, so shared ones point to a single origin

  9. A tRNA has the anticodon UUA. Which codon does it read and which amino acid does it carry?
    Show the full solution

    The anticodon pairs with its complementary codon, so UUA pairs with AAU, using the pairing rules with uracil in place of thymine: U pairs with A, U with A, and A with U. From the table AAU specifies asparagine, so this tRNA carries asparagine and delivers it whenever the ribosome reaches an AAU codon. Working from anticodon to codon requires taking the complement, which is why keeping the two terms distinct matters. It reads the codon AAU and carries asparagine

  10. Explain why the reading frame matters, using the worked example.
    Show the full solution

    The ribosome reads in consecutive groups of three from the start codon, so where it starts determines how every subsequent base is grouped. Reading AUG CCU AAU gives methionine, proline, asparagine, but starting one base later would group the same sequence as UGC CUA AUU and give entirely different amino acids. The bases have not changed; only the grouping has. This is why an insertion or deletion, which shifts the frame, is so much more damaging than a substitution, as the next lesson shows. The same bases grouped differently specify entirely different amino acids

Lesson 7.6 · Unit 7 · HS-LS3-2

Mutations: substitutions, frameshifts, and why one is worse

A mutation is a change in the base sequence of DNA. Most have no effect at all, some are harmful, and a very small number are useful, which is the entire raw material of evolution. Predicting which is which requires only the reading frame idea from the last lesson.

The key ideas
  1. A substitution replaces one base with another and affects at most one codon.
  2. A silent substitution changes the codon but not the amino acid, thanks to the redundancy of the code. The protein is unaffected.
  3. A missense substitution changes one amino acid. The effect ranges from nothing to severe depending on where in the protein it falls.
  4. A nonsense substitution creates a stop codon early, truncating the protein, which is usually severe.
  5. Insertions and deletions shift the reading frame unless they involve a multiple of three bases, so every codon downstream is regrouped.
  6. Mutations occur in two contexts: body cells, where the effect is limited to that individual, and gametes, where it can be inherited.

Where students lose marks: saying mutations are always harmful. Most are neutral, many are silent, and the rare beneficial ones are the reason adaptation is possible. Saying they are harmful also encourages the teleology error of lesson 10.2.

Worked example

The starting sequence. Take the mRNA AUG CCU AAU UGA from lesson 7.5, giving methionine, proline, asparagine, stop. Apply three mutations and compare the damage.

Step one: a substitution in the third base of codon two. CCU becomes CCA. Both specify proline, because the code is redundant in the third position for this amino acid. The protein is unchanged, and this is a silent mutation.

Step two: a substitution in the first base of codon three. AAU becomes GAU, which specifies a different amino acid. One amino acid in three has changed, and this is a missense mutation.

Step three: judge the missense case honestly. If that amino acid sits in the active site of an enzyme, the protein may fail completely. If it sits on an outer loop, the protein may work normally. The mutation type alone does not determine severity.

Step four: delete one base from codon two. Remove the first C, and the remaining sequence is AUG CUA AUU GA. Every base after the deletion has moved one place to the left.

Step five: read the regrouped sequence. Codon two is now CUA rather than CCU, codon three is AUU rather than AAU, and the original stop codon UGA no longer exists as a group. Every codon downstream is different.

Step six: state why this is far worse. A substitution alters at most one amino acid. A frameshift alters every amino acid from the mutation to the end of the gene, and usually destroys or relocates the stop codon as well, so the protein is entirely wrong rather than slightly wrong.

Step seven: note the exception. An insertion or deletion of three bases, or any multiple of three, adds or removes whole codons without shifting the frame. The protein gains or loses an amino acid and the rest is unaffected, which can be far milder than a single-base deletion.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Define a mutation.
    Show the full solution

    A change in the base sequence of DNA

  2. Name the three kinds of substitution.
    Show the full solution

    Silent, missense and nonsense

  3. What is a frameshift?
    Show the full solution

    A shift in the reading frame caused by an insertion or deletion not a multiple of three

  4. Why can a substitution be silent?
    Show the full solution

    Because the code is redundant, so the new codon may specify the same amino acid

  5. Which mutations can be inherited?
    Show the full solution

    Those occurring in gametes or the cells that produce them

  6. Explain why a frameshift is usually more damaging than a substitution.
    Show the full solution

    A substitution alters a single base and therefore at most one codon, so at worst one amino acid in the protein changes. An insertion or deletion shifts every base after it into a different grouping, so every codon from that point to the end of the gene is read differently and specifies a different amino acid. The original stop codon is usually destroyed as well, so the protein may also be the wrong length. The result is a protein that is entirely wrong downstream rather than slightly altered. It changes every codon after it, while a substitution changes at most one

  7. Explain why a deletion of three bases is often much milder than a deletion of one.
    Show the full solution

    Codons are groups of three, so removing three bases removes exactly one whole codon and leaves the grouping of everything after it unchanged. The protein is produced with one amino acid missing but is otherwise correct, and depending on which amino acid it was, it may still function reasonably well. Removing one base leaves the remaining bases regrouped from that point onward, so the entire downstream sequence is wrong. The multiple of three is what preserves the reading frame. Three bases remove a whole codon without shifting the frame

  8. Two missense mutations in the same gene have very different effects. Suggest why.
    Show the full solution

    Because a protein's function depends far more on some positions than others. An amino acid change within the active site of an enzyme alters the shape or chemistry that binds the substrate, and can abolish activity entirely, as lesson 6.2 describes. A change on an outer surface loop far from the active site may leave the folding and the binding unaffected, so the protein works normally. The severity depends on the position and on how chemically different the substituted amino acid is. The effect depends on whether the position is critical to folding or the active site

  9. Explain why "mutations are harmful" is a poor summary.
    Show the full solution

    Most mutations have no detectable effect at all, either because they fall in non-coding DNA or because they are silent substitutions that leave the protein unchanged. Of those that do change a protein, many are tolerated. Harmful ones exist and are important, but a rare few improve function or fitness in a particular environment, and those are the only original source of the variation natural selection acts on. Describing mutation as harmful also invites the idea that organisms mutate in response to need, which is false. Most are neutral, and the rare beneficial ones are the raw material of evolution

  10. A mutation occurs in a skin cell and another in a sperm cell. Compare the consequences.
    Show the full solution

    The skin cell mutation affects only that cell and the cells it divides to produce, so its consequences are confined to the individual and disappear when they die. It can matter greatly to that person if it disrupts the control of cell division, which is how cancers begin. The sperm cell mutation is not present in the parent's body tissues at all, but if that sperm fertilizes an egg it will be present in every cell of the offspring and can be passed to further generations. The skin mutation affects one individual; the gamete mutation can be inherited by every cell of offspring

Lesson 7.7 · Unit 7 · HS-LS1-4, HS-LS3-1

Why cells with identical DNA do different jobs

A nerve cell and a liver cell in the same person contain exactly the same genome. Every gene for every protein the body can make is present in both. The difference between them is entirely a difference in which of those genes is being read, and that raises the question of what does the deciding.

The key ideas
  1. Almost every cell in an organism carries the complete genome, inherited by repeated mitosis from the original fertilized egg.
  2. Differentiation is the process of specialization, in which a cell switches on some genes and silences others, becoming a particular cell type.
  3. Gene expression is regulated at transcription above all: a gene that is not transcribed produces no mRNA and therefore no protein.
  4. Regulatory proteins bind to DNA near a gene and either promote or block the attachment of RNA polymerase.
  5. Bacteria regulate genes in response to conditions. A cluster of genes for digesting a particular sugar is transcribed only when that sugar is present and a better fuel is not.
  6. Stem cells are undifferentiated and retain the ability to become other cell types, which is why they are of medical interest.

Where students lose marks: saying specialized cells "lose the genes they do not need". They keep them. The genes are present and silent, which is why a nucleus from a specialized cell can, under the right conditions, direct the development of a whole organism.

Worked example

Part one: a bacterial switch. A bacterium can digest lactose, but only if it makes the necessary enzymes. Making them when no lactose is present would waste resources.

Step one: state the problem the cell must solve. The enzymes are needed sometimes and useless at other times. A cell that always made them would be outcompeted by one that made them only when required.

Step two: describe the default state. A regulatory protein binds to the DNA near the enzyme genes and physically blocks RNA polymerase, so the genes are not transcribed and no enzymes are made.

Step three: describe what lactose does. When lactose is present it binds to the regulatory protein, changing its shape so that it can no longer attach to the DNA. The block is removed.

Step four: state the result. RNA polymerase transcribes the genes, the enzymes are made, and the lactose is digested. As the lactose runs out the regulatory protein resumes blocking, and production stops.

Step five: identify the loop. The substrate switches on the enzymes that destroy it, and their success switches them off again. That is negative feedback from lesson 4.5, operating at the level of a gene.

Part two: the same principle in a multicellular body.

Step six: apply it to differentiation. A developing cell receives chemical signals from its position and its neighbors. Those signals activate regulatory proteins that switch on a particular set of genes and silence others, and the pattern becomes self-maintaining.

Step seven: state the evidence that nothing is lost. A nucleus taken from a specialized adult cell and placed in an egg cell can direct the development of a complete organism. That would be impossible if differentiation involved discarding genes, which is why the result matters.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Do specialized cells contain the whole genome?
    Show the full solution

    Yes, almost all of them do

  2. Define differentiation.
    Show the full solution

    Specialization of a cell by switching on some genes and silencing others

  3. At which stage is gene expression mainly regulated?
    Show the full solution

    At transcription

  4. How does a regulatory protein control a gene?
    Show the full solution

    By binding to DNA near the gene and blocking or promoting RNA polymerase

  5. What is a stem cell?
    Show the full solution

    An undifferentiated cell that retains the ability to become other cell types

  6. Explain why a bacterium benefits from switching the lactose enzymes off.
    Show the full solution

    Making a protein costs amino acids and ATP, and enzymes that are never used return nothing for that investment. A cell that produced them constantly would divert resources from growth and reproduction and would be outcompeted by cells that did not, so selection favors regulation. Switching the genes on only when lactose is present means the cost is paid only when there is a benefit, which is why regulated genes are the rule rather than the exception even in organisms with small genomes. Making unused proteins wastes amino acids and ATP that competitors spend on growth

  7. Explain why "specialized cells lose the genes they do not need" is wrong, and give the evidence.
    Show the full solution

    The genes are retained and silenced rather than removed, so a liver cell still contains the genes for making nerve or muscle proteins but does not transcribe them. The decisive evidence is that a nucleus taken from a fully specialized adult cell and transferred into an egg cell can direct the development of a complete organism with every tissue type. That is only possible if the nucleus still carries the complete genome, so differentiation must be a change in expression rather than in content. Genes are silenced, not deleted, as nuclear transfer producing a whole organism shows

  8. How does the lactose switch illustrate negative feedback?
    Show the full solution

    The presence of lactose removes the block on the genes, so the enzymes that digest lactose are produced. Those enzymes then break the lactose down, and as its concentration falls the regulatory protein is no longer prevented from binding, so it blocks the genes again and production ceases. The output of the process reduces the signal that triggered it, which is the definition of negative feedback, and the result is that enzyme levels track the need for them automatically. The enzymes destroy the substance that switched them on, so the signal is self-limiting

  9. Why are stem cells medically interesting?
    Show the full solution

    Because they have not yet committed to a single fate and can be directed to become particular cell types, which raises the possibility of replacing tissue that the body cannot regenerate, such as damaged nerve or heart muscle. They are also valuable for studying how differentiation is controlled and for testing drugs on human cells of a specific type. The difficulties are practical and ethical rather than conceptual, including controlling what the cells become and the source from which they are obtained. They can be directed to become tissue types the body cannot regenerate

  10. Connect this lesson to lesson 6.2 on enzymes.
    Show the full solution

    Lesson 6.2 established that each metabolic reaction is catalyzed by a specific enzyme whose shape is determined by its gene, so genes control chemistry through the enzymes they specify. This lesson adds the layer above: which genes are transcribed determines which enzymes exist in a given cell at a given moment. A cell's chemistry is therefore set by regulation as much as by the genome, which is how two cells with identical genes carry out entirely different reactions. Genes specify enzymes, and regulation decides which enzymes a cell actually has

Unit 7 review · DNA, Genes and Proteins

Ten questions across the whole unit

Questions 1 to 5 check that you hold the terms. Questions 6 to 10 require you to reason across the seven lessons.

  1. What did Griffith's experiment show, and what did it not show?
    Show the full solution

    That heritable information can transfer between bacteria; not which molecule carries it

  2. A DNA sample is 18 percent cytosine. Give the other three percentages.
    Show the full solution

    G is 18 percent; A and T are 32 percent each

  3. Which bonds break during replication, and which enzyme builds the new strands?
    Show the full solution

    Hydrogen bonds between paired bases; DNA polymerase builds the new strands

  4. Transcribe the template strand TAC GCA TTG ACT.
    Show the full solution

    AUG CGU AAC UGA

  5. How many codons exist, and why must a codon be three bases?
    Show the full solution

    64; two bases would give only 16 combinations for 20 amino acids

  6. Explain why the agreement of three separate experiments identified DNA more securely than any one of them.
    Show the full solution

    Each experiment has its own possible weaknesses: Griffith's could be explained by an unknown transferable substance, Avery's by traces of contaminating protein in a supposedly pure preparation, and Hershey and Chase's by imperfect labeling. Those weaknesses are unrelated to one another, so any alternative explanation would have to defeat all three separately while leaving DNA out, which is very hard to construct. Their weaknesses are unrelated, so one alternative cannot account for all three

  7. Explain why it is an advantage that base pair bonds are individually weak.
    Show the full solution

    The strands must separate every time the molecule is copied or a gene is transcribed, and that has to happen at body temperature using enzymes rather than extreme conditions. Individually weak hydrogen bonds can be broken locally with little energy, so a region can be opened without disturbing the rest, while the molecule remains stable overall because there are so many of them along its length. Strength comes from number rather than from each bond. Strands must separate easily; stability comes from the number of bonds

  8. Explain why a frameshift is usually more damaging than a substitution.
    Show the full solution

    A substitution alters a single base and therefore at most one codon, so at worst one amino acid changes. An insertion or deletion shifts every base after it into a different grouping, so every codon from that point to the end of the gene is read differently and specifies a different amino acid, and the original stop codon is usually destroyed as well. The protein is entirely wrong downstream rather than slightly altered. It changes every codon after it, while a substitution changes at most one

  9. Explain why the near-universality of the genetic code is evidence for common ancestry.
    Show the full solution

    The assignment of particular codons to particular amino acids is arbitrary, since a different assignment would work equally well and no chemistry requires AUG to mean methionine. If life had arisen independently more than once, those separate origins would have had no reason to settle on the same arbitrary scheme. Finding essentially the same code in bacteria, plants, fungi and animals is therefore best explained by inheritance from one ancestral population. The assignments are arbitrary, so shared ones point to a single origin

  10. Explain why specialized cells do not lose the genes they do not use, and give the evidence.
    Show the full solution

    The genes are retained and silenced rather than removed, so a liver cell still contains the genes for nerve and muscle proteins but does not transcribe them. The decisive evidence is that a nucleus taken from a fully specialized adult cell and transferred into an egg cell can direct the development of a complete organism with every tissue type, which is only possible if the complete genome is still present. Differentiation is a change in expression, not in content. Genes are silenced, not deleted, as nuclear transfer demonstrates

Lesson 8.1 · Unit 8 · HS-LS1-4

The cell cycle: what a cell does before it divides

Division is the short, dramatic part of a cell's life and the part textbooks illustrate. Most of the cycle is spent doing something less photogenic and more important: growing, copying the genome, and checking that the copy is sound before committing to divide.

The key ideas
  1. Interphase is the long preparatory stage, occupying the great majority of the cycle. It has three parts.
  2. G1 is growth: the cell increases in size, makes proteins and organelles, and carries out its ordinary function.
  3. S is synthesis: the entire genome is replicated, by the semi-conservative mechanism of lesson 7.3. After S the cell has two copies of every chromosome.
  4. G2 is final preparation: further growth, and the manufacture of the structures division will need.
  5. M phase is division itself, comprising mitosis, which separates the chromosomes, and cytokinesis, which divides the cytoplasm.
  6. Checkpoints control progress. The cell verifies that conditions are suitable, that DNA replication is complete and undamaged, and that chromosomes are correctly attached before separation.

Where students lose marks: describing interphase as a resting phase. It is the most metabolically active part of the cycle and the stage in which the genome is copied. Nothing rests.

Worked example

The data. A population of cells is examined and the number in each stage counted. The figures are constructed so the proportions are easy to read.

StageG1SG2MTotal
Cells counted440280200801000

Step one: check the total. 440 plus 280 plus 200 plus 80 is 1000, so every cell has been assigned to a stage.

Step two: convert to percentages. G1 is 44 percent, S is 28 percent, G2 is 20 percent and M is 8 percent.

Step three: state the principle linking count to time. In a large unsynchronized population, the proportion of cells in a stage is proportional to how long that stage lasts. A stage occupying a quarter of the cycle will contain about a quarter of the cells.

Step four: apply it to a 20 hour cycle. G1 takes 44 percent of 20 hours, which is 8.8 hours. S takes 28 percent, which is 5.6 hours. G2 takes 20 percent, which is 4 hours.

Step five: find the length of M phase. 8 percent of 20 hours is 1.6 hours, which is 96 minutes. The stage that fills the textbook diagrams occupies under two hours of a twenty hour cycle.

Step six: state what interphase totals. 44 plus 28 plus 20 is 92 percent, which is 18.4 hours. Interphase is not a gap between divisions; it is almost the whole of the cell's life.

Step seven: note what the method assumes. The population must be unsynchronized and growing steadily, and every cell must be dividing. If a substantial fraction had left the cycle permanently, they would all appear in G1 and would exaggerate its apparent length.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Name the three parts of interphase and what happens in each.
    Show the full solution

    G1 growth, S DNA replication, G2 final preparation

  2. What are the two components of M phase?
    Show the full solution

    Mitosis, which separates chromosomes, and cytokinesis, which divides the cytoplasm

  3. What happens to the amount of DNA during S phase?
    Show the full solution

    It doubles

  4. Name two things a checkpoint verifies.
    Show the full solution

    That DNA replication is complete and undamaged, and that chromosomes are correctly attached

  5. In the worked example, how long is M phase if the cycle is 20 hours?
    Show the full solution

    8 percent of 20 hours, which is 1.6 hours or 96 minutes

  6. Explain why calling interphase a resting phase is wrong.
    Show the full solution

    Interphase is when the cell does almost everything: it grows, manufactures proteins and organelles, carries out whatever specialized function it has, and replicates its entire genome during S phase. Replication alone is an enormous undertaking involving millions of base pairs copied accurately. The impression of rest comes from microscope images, in which interphase nuclei look uniform while mitotic chromosomes are dramatic, so the visually quiet stage is mistaken for an inactive one. It is the most active stage, including replication of the entire genome

  7. Explain why the proportion of cells in a stage indicates its duration.
    Show the full solution

    In a large population of cells dividing independently, each cell is at a random point in the cycle at any moment. The chance of finding a given cell in a particular stage is therefore proportional to the fraction of the cycle that stage occupies, so counting many cells estimates those fractions directly. It is the same logic as photographing a busy road and inferring how long traffic lights stay red from the proportion of images showing red. It requires the population to be unsynchronized. Cells are at random points, so the fraction seen in a stage estimates its share of the cycle

  8. Why must the checkpoint before division confirm that DNA replication is complete?
    Show the full solution

    Dividing with incompletely copied DNA would give at least one daughter cell a partial genome, missing genes it cannot recover since there is no other copy to restore from. That cell would lack proteins essential to its function and would usually die, and if it survived and divided the defect would be inherited by every descendant. Checking before the irreversible step of separation is far cheaper than dealing with the consequences, which is the general logic of every checkpoint. A daughter cell would inherit a partial genome with no way to recover the missing genes

  9. A cell is found to have twice the normal DNA content. Which stages could it be in?
    Show the full solution

    It has completed S phase, so it could be in G2 or in M phase up to the point where the chromosomes are separated. It cannot be in G1, which precedes replication, and it cannot be a cell that has finished dividing, since separation halves the DNA content again. If it were partway through S phase the content would be between the two values rather than exactly double, so the measurement places it fairly precisely. G2, or M phase before the chromosomes separate

  10. Why might a cell that has permanently stopped dividing distort the worked-example method?
    Show the full solution

    Cells that exit the cycle permanently, such as mature nerve cells, remain in a G1-like state indefinitely and never progress. Counting them alongside actively cycling cells adds a large number to the G1 tally that has nothing to do with how long G1 takes, so G1 appears far longer than it is and every other stage appears correspondingly shorter. The method assumes every cell counted is moving through the cycle, and a tissue containing many permanently arrested cells breaks that assumption. They accumulate in G1 without cycling, inflating its apparent duration

Lesson 8.2 · Unit 8 · HS-LS1-4

Mitosis: producing two identical cells

Mitosis solves a specific problem. A cell about to divide has two copies of every chromosome, and it must distribute them so that each daughter receives exactly one copy of each, with no duplicates and nothing missing. The stages are the choreography that makes that reliable.

The key ideas
  1. Mitosis produces two genetically identical diploid cells from one, and is used for growth, repair and asexual reproduction.
  2. Prophase: chromosomes condense and become visible, each as two identical sister chromatids joined at a centromere. The nuclear envelope breaks down and a spindle forms.
  3. Metaphase: chromosomes line up along the equator of the cell, attached to spindle fibers from both poles.
  4. Anaphase: sister chromatids are pulled apart to opposite poles. This is the moment the two future nuclei become separate sets.
  5. Telophase: chromosomes decondense at the poles and new nuclear envelopes form around each set.
  6. Cytokinesis divides the cytoplasm, by a pinching furrow in animal cells and by building a new cell plate in plant cells, which have a wall.

Where students lose marks: saying chromosomes are "made" in prophase. They are present throughout and were copied during S phase. Prophase condenses them so they can be moved without tangling, which is why they become visible.

Worked example

The task. Identify the stage from a description, which is the standard form of this question, and explain what makes each recognizable.

Step one: "the nuclear envelope has gone and thick threads are scattered through the cell." Chromosomes are condensed and visible but not yet aligned, and the envelope has broken down. This is prophase, or its end.

Step two: "chromosomes form a single line across the middle." A single row at the equator is unique to metaphase. This is the easiest stage to identify and the most commonly asked.

Step three: "two groups of chromosomes are moving toward opposite ends, forming V shapes." Separation is under way, so this is anaphase. The V shape comes from the centromere leading and the arms trailing.

Step four: "two clusters at the poles, each acquiring a membrane." Chromosomes have arrived and nuclei are reforming, so this is telophase.

Step five: apply the distinguishing test between metaphase and anaphase. Count the lines of chromosomes. One line means metaphase; two groups moving apart means anaphase. The distinction is separation, not position.

Step six: check the chromosome number. A cell entering mitosis with 8 chromosomes, each of two chromatids, ends with two cells of 8 chromosomes each. The number per cell is unchanged, because what separated were chromatids rather than chromosomes.

Step seven: state why identical daughters are the point. Growth and repair require new cells that do the same job as the ones around them. A skin cell must produce skin cells, and any genetic difference would be an error rather than an advantage.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. List the four stages of mitosis in order.
    Show the full solution

    Prophase, metaphase, anaphase, telophase

  2. What happens in metaphase?
    Show the full solution

    Chromosomes line up along the equator of the cell

  3. What separates during anaphase?
    Show the full solution

    Sister chromatids

  4. Name three purposes of mitosis.
    Show the full solution

    Growth, repair and asexual reproduction

  5. How does cytokinesis differ between plant and animal cells?
    Show the full solution

    Animal cells pinch inward; plant cells build a new cell plate because of the wall

  6. Explain how to tell metaphase from anaphase in a photograph.
    Show the full solution

    Count the groups of chromosomes. Metaphase shows a single line across the middle of the cell with every chromosome aligned on it, and nothing has yet separated. Anaphase shows two distinct groups moving apart toward opposite poles, often with the chromosomes forming V shapes because the centromere leads and the arms trail behind. The key difference is whether separation has begun, not exactly where the chromosomes sit, since early anaphase chromosomes are still near the middle. One aligned row is metaphase; two separating groups is anaphase

  7. Explain why chromosomes condense before being moved.
    Show the full solution

    Uncondensed DNA is extremely long and fine, and a human cell contains around two meters of it. Attempting to drag threads of that length to opposite poles would tangle and break them, losing or damaging genes. Condensing each chromosome into a short, compact structure makes it a manageable object that can be attached to a spindle fiber and pulled cleanly. The visibility that makes prophase recognizable under a microscope is a side effect of that packaging. Long fine DNA would tangle and break; condensing makes it movable

  8. A cell with 12 chromosomes undergoes mitosis. State the number in each daughter cell and explain.
    Show the full solution

    Each daughter cell has 12 chromosomes. Before division the cell replicated its DNA, so each of the 12 chromosomes consisted of two identical sister chromatids, giving 24 chromatids in total. Anaphase separates the chromatids rather than the chromosomes, sending one of each pair to each pole, so each daughter receives 12 single-chromatid chromosomes. The chromosome number per cell is therefore unchanged, which is what makes mitosis suitable for growth. 12, because chromatids separate rather than chromosomes

  9. Why is it important that mitosis produces identical cells?
    Show the full solution

    Because its purposes require sameness. Growth adds more cells of the existing types, repair replaces damaged cells with functional equivalents, and asexual reproduction produces an offspring suited to the same environment as the parent. A skin cell dividing to give something other than skin cells would be a failure, and in a multicellular body genetic differences between cells are usually the beginning of a tumor rather than a source of useful variety. Growth and repair need replacements that do the same job

  10. Explain why a drug that prevents spindle formation stops cell division.
    Show the full solution

    The spindle is the apparatus that attaches to chromosomes at the centromere and pulls the sister chromatids to opposite poles. Without it the chromosomes can condense and the nuclear envelope can break down, but they cannot be aligned at metaphase or separated at anaphase, so the cell arrests at the checkpoint that verifies correct attachment. Since rapidly dividing cells are the most affected, such drugs are used against cancers, which also explains why they damage hair follicles and gut lining. Without a spindle, chromosomes cannot align or separate, so the cell arrests

Lesson 8.3 · Unit 8 · HS-LS1-4, HS-LS3-2

Meiosis: halving the number and shuffling the deck

Sexual reproduction has an arithmetic problem. If two cells fuse, the offspring has twice the chromosomes of each parent, and the number would double every generation. Meiosis solves it by producing cells with half the usual number, and while solving it also does something else that turns out to matter more: it generates variation.

The key ideas
  1. Meiosis produces four genetically different haploid cells from one diploid cell, through two divisions rather than one.
  2. Diploid means two sets of chromosomes, one from each parent. Haploid means one set. Human body cells have 46 chromosomes; gametes have 23.
  3. Homologous chromosomes are matching pairs, one from each parent, carrying the same genes in the same order but possibly different alleles.
  4. Meiosis I separates homologous pairs, which is the division that halves the number. This is the step with no equivalent in mitosis.
  5. Meiosis II separates sister chromatids, and resembles mitosis, except that it begins with a haploid cell.
  6. Fertilization restores the diploid number, so the cycle of halving and doubling keeps chromosome number constant across generations.

Where students lose marks: saying meiosis I separates chromatids. It separates whole homologous chromosomes; chromatids separate in meiosis II. Getting this the wrong way round makes every subsequent answer about variation wrong too.

Worked example

The comparison. Build the contrast systematically for a cell with 4 chromosomes, which is 2 homologous pairs.

FeatureMitosisMeiosis
Divisionsonetwo
Daughter cellstwofour
Chromosome number4, unchanged2, halved
Genetic identityidentical to parentall different
Homologues pair upnoyes, in meiosis I
Purposegrowth and repairgamete production

Step one: start both from the same point. After S phase the cell has 4 chromosomes, each of two sister chromatids, so 8 chromatids in total. Both processes begin here.

Step two: follow mitosis. The 4 chromosomes line up individually, chromatids separate, and two cells result with 4 chromosomes each. The number is maintained.

Step three: follow meiosis I. The chromosomes pair with their homologues, giving 2 pairs. Each pair lines up together, and whole chromosomes are pulled apart, giving two cells of 2 chromosomes each, still with two chromatids apiece.

Step four: identify what has just happened. The number has halved, and it halved by separating homologues rather than chromatids. This is the reduction division and it has no counterpart in mitosis.

Step five: follow meiosis II. Each of the two cells divides again, separating sister chromatids exactly as in mitosis. The result is four cells, each with 2 single-chromatid chromosomes.

Step six: check the arithmetic. One cell with 4 chromosomes gives four cells with 2 each. The original 8 chromatids have been distributed two to each of four cells.

Step seven: state why the daughters differ. Which homologue of each pair goes to which cell is decided independently for every pair, and crossing over has exchanged material between them beforehand. Both are the subject of the next lesson.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. How many cells does meiosis produce, and are they haploid or diploid?
    Show the full solution

    Four, and they are haploid

  2. What are homologous chromosomes?
    Show the full solution

    Matching pairs, one from each parent, carrying the same genes in the same order

  3. What separates in meiosis I, and what in meiosis II?
    Show the full solution

    Homologous chromosomes in meiosis I; sister chromatids in meiosis II

  4. How many chromosomes are in a human body cell and in a human gamete?
    Show the full solution

    46 in a body cell, 23 in a gamete

  5. What restores the diploid number?
    Show the full solution

    Fertilization

  6. Explain why chromosome number would double each generation without meiosis.
    Show the full solution

    Fertilization combines the nuclei of two cells, so the offspring receives the sum of the chromosomes in each gamete. If gametes were produced by mitosis they would carry the full diploid number, and fusing two of them would give an offspring with twice the parental number, which would double again in the next generation and continue indefinitely. Meiosis halves the number before fertilization doubles it, so the two processes cancel and the species number stays constant. Fertilization adds two sets, so gametes must carry half

  7. Explain why meiosis II resembles mitosis but is not the same.
    Show the full solution

    Both separate sister chromatids and both produce two cells from one, so the mechanics look alike. The difference is the starting material: meiosis II begins with a haploid cell that has already lost one member of each homologous pair, so the products are haploid rather than diploid. The chromatids being separated are also no longer identical, because crossing over in meiosis I exchanged segments between homologues, so the resulting cells differ genetically. It starts from a haploid cell whose chromatids are no longer identical

  8. A cell with 8 chromosomes undergoes meiosis. Describe the products.
    Show the full solution

    Four cells, each containing 4 chromosomes, and all four genetically different from each other and from the parent cell. The 8 chromosomes form 4 homologous pairs, meiosis I separates the members of each pair to give two cells of 4 chromosomes each, and meiosis II separates the sister chromatids to give four cells of 4 single-chromatid chromosomes. The number has halved from 8 to 4, which is the definition of a reduction division. Four genetically different haploid cells with 4 chromosomes each

  9. Why is the pairing of homologues in meiosis I essential?
    Show the full solution

    Pairing is what allows the two members of each homologous pair to be directed to opposite cells, which is how the chromosome number is halved while ensuring each daughter gets one complete set rather than a random selection. If chromosomes lined up individually, as in mitosis, separation would be arbitrary and a cell might receive both copies of one chromosome and neither of another. Pairing also brings homologues into contact so that crossing over can occur. It ensures each cell gets one complete set, and enables crossing over

  10. Explain why meiosis is described as a reduction division but mitosis is not.
    Show the full solution

    Meiosis reduces the chromosome number per cell from diploid to haploid, because meiosis I separates whole homologous chromosomes so each daughter receives only one member of each pair. Mitosis separates sister chromatids instead, and since each chromatid becomes a full chromosome, each daughter ends with the same number the parent had. The distinction lies entirely in what is pulled apart, which is why confusing meiosis I with meiosis II makes the whole account incoherent. Meiosis I separates homologues and halves the number; mitosis separates chromatids and maintains it

Lesson 8.4 · Unit 8 · HS-LS3-2

Crossing over and independent assortment

Meiosis could have been designed simply to halve the chromosome number, handing each gamete one intact set inherited from one parent. It does something considerably more interesting, and the result is that no two gametes a person produces are alike.

The key ideas
  1. Crossing over happens in meiosis I, when paired homologues lie alongside each other and exchange corresponding segments at points called chiasmata.
  2. It produces recombinant chromosomes carrying a mixture of alleles from both parents, which no chromosome in either parent had.
  3. Independent assortment is the second source. Which member of each homologous pair goes to which pole is decided independently for every pair.
  4. The number of combinations is 2 raised to the number of pairs. For a haploid number of 23, that is 2 to the power 23, which is 8,388,608.
  5. Random fertilization multiplies the total again, since any one of those gametes may meet any one from the other parent.
  6. All three shuffle existing alleles; none creates a new one. Only mutation does that, which is why lesson 7.6 matters for evolution.

Where students lose marks: saying crossing over happens between sister chromatids. Sister chromatids are identical, so exchanging material between them changes nothing. Crossing over occurs between non-sister chromatids of homologous chromosomes, which carry different alleles.

Worked example

The task. Count the possible gametes from independent assortment, then add the other sources.

Step one: take a simple case. An organism with 2 homologous pairs, so 4 chromosomes. Call the pairs A with a, and B with b, where capitals came from one parent and lower case from the other.

Step two: list the possibilities. A gamete gets one from each pair, so the options are AB, Ab, aB and ab. That is 4 combinations.

Step three: find the rule. Each pair contributes a choice of 2, and the choices are independent, so the total is 2 multiplied by itself once for each pair. With 2 pairs that is 2 times 2, which is 4, matching the list.

Step four: apply it to a larger number. An organism with 4 pairs gives 2 to the power 4, which is 16 combinations. The total grows very quickly as pairs are added.

Step five: apply it to humans. With 23 pairs, 2 to the power 23 is 8,388,608 possible combinations from independent assortment alone, before any crossing over.

Step six: add random fertilization. Any of those 8,388,608 possible eggs may be fertilized by any of 8,388,608 possible sperm, giving 2 to the power 46 combinations, which is more than 70 million million.

Step seven: add crossing over and state the conclusion. Crossing over occurs at varying positions along the chromosomes, so the chromosomes themselves are not the fixed units the calculation assumed, and the real number is far larger still. The figure is effectively unlimited, which is why siblings differ.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. When and where does crossing over occur?
    Show the full solution

    In meiosis I, between non-sister chromatids of paired homologous chromosomes

  2. What is a chiasma?
    Show the full solution

    A point at which paired homologues are joined and exchange segments

  3. State the formula for combinations from independent assortment.
    Show the full solution

    2 raised to the power of the number of homologous pairs

  4. How many combinations does an organism with 5 pairs produce?
    Show the full solution

    2 to the power 5, which is 32

  5. Which process creates genuinely new alleles?
    Show the full solution

    Mutation only

  6. Explain why crossing over between sister chromatids would achieve nothing.
    Show the full solution

    Sister chromatids are the two identical copies produced when a chromosome was replicated in S phase, so they carry exactly the same alleles at every position. Exchanging a segment between them swaps material that is identical to the material it replaces, leaving both chromatids unchanged. Variation requires exchange between chromosomes that differ, which is why crossing over occurs between non-sister chromatids of homologous pairs, where one came from each parent and the alleles may differ. Sister chromatids are identical, so exchanging segments changes nothing

  7. Explain why independent assortment gives 2 to the power n rather than 2 times n.
    Show the full solution

    Each homologous pair contributes an independent two-way choice, and independent choices combine by multiplication rather than addition. With two pairs, each of the two options for the first pair can be combined with either option for the second, giving two times two rather than two plus two. Adding a third pair doubles the total again. Repeated doubling is a power, which is why the count rises so steeply and why 23 pairs give over eight million rather than forty six. Independent choices multiply, and repeated doubling is a power

  8. Why do siblings resemble each other more than unrelated people, yet differ?
    Show the full solution

    They draw their alleles from the same two parents, so the pool available to each is the same and many alleles are shared, which produces the resemblance. But each sibling received a different combination, because independent assortment sent a different selection of homologues into each gamete, crossing over rearranged the alleles within chromosomes differently each time, and fertilization paired a different sperm with a different egg. The pool is shared and the sample from it is not. Same parental allele pool, different combination in each gamete

  9. Explain why shuffling alleles is useful even though it creates nothing new.
    Show the full solution

    Because a population's capacity to respond to change depends on the range of combinations present, not only on the range of individual alleles. Two alleles that are individually advantageous may never have occurred together in one organism, and recombination can bring them into the same individual, or separate a beneficial allele from a harmful one it was linked to. Mutation supplies new variants slowly and rarely, so shuffling is what turns a small number of new alleles into a large number of tested combinations. It creates new combinations of existing alleles for selection to act on

  10. Two genes are very close together on the same chromosome. Predict how often they are separated by crossing over, and explain.
    Show the full solution

    Rarely. Crossing over occurs at positions scattered along the chromosome, so the chance that a crossover point falls between two particular genes depends on the distance separating them. Genes close together are nearly always inherited as a unit because few crossovers occur in the short stretch between them, while genes far apart are separated often. This relationship between distance and recombination frequency is what allowed the first genetic maps to be built from breeding data alone. Rarely, since few crossover points fall in the short distance between them

Lesson 8.5 · Unit 8 · HS-LS3-2

Where genetic variation comes from

Unit 10 will argue that natural selection requires variation to act on, and that without it nothing can evolve. This lesson assembles the complete list of where that variation originates, and ranks the entries by what each actually contributes.

The key ideas
  1. Mutation is the only original source. Every allele that exists began as a copying error or damage to DNA at some point in the past.
  2. Crossing over recombines alleles within chromosomes, producing chromosomes that carry combinations neither parent had.
  3. Independent assortment recombines whole chromosomes, giving 2 to the power of the pair number possible gametes.
  4. Random fertilization combines two of those gametes, multiplying the possibilities again.
  5. Only the first creates; the other three shuffle. This is the distinction that matters most and the one most often blurred.
  6. Environment affects phenotype but is not inherited through the genome, so a characteristic acquired during life is not passed to offspring.

Where students lose marks: listing crossing over as a source of new alleles. It rearranges existing ones. If an allele did not exist in either parent, no amount of recombination will produce it, and saying otherwise usually signals the misconception that organisms generate variation on demand.

Worked example

The task. An isolated population of beetles has no allele for a dark shell. A new predator arrives that hunts by sight on dark bark. Work out what each source of variation can and cannot do.

Step one: check what recombination offers. Crossing over and independent assortment can only rearrange alleles already present. If no dark allele exists anywhere in the population, no combination of existing alleles will produce a dark beetle.

Step two: check random fertilization. The same limitation applies, since it only pairs existing gametes. It multiplies combinations without adding ingredients.

Step three: identify the only possible route. A mutation in a gene affecting shell pigment, occurring in a cell that produces gametes. Nothing else can introduce the variant.

Step four: state when it must occur. The mutation is random with respect to need, so it may already have occurred and be present at low frequency, or it may occur after the predator arrives, or it may never occur at all. The predator does not make it more likely.

Step five: state the consequence if it does not occur. The population has no raw material for this particular adaptation, and selection cannot produce what is not there. Extinction is a genuine possible outcome, and it is common.

Step six: state what recombination does contribute. If a dark allele does exist at low frequency, recombination spreads it into many different genetic backgrounds, so it can be combined with other useful alleles and tested in many contexts rather than being tied to whatever else its original carrier had.

Step seven: draw the general conclusion. Mutation supplies the vocabulary and recombination writes the sentences. Neither is sufficient alone, and neither responds to what the population needs.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. List the four sources of genetic variation.
    Show the full solution

    Mutation, crossing over, independent assortment and random fertilization

  2. Which of them creates new alleles?
    Show the full solution

    Mutation only

  3. Which three only rearrange existing alleles?
    Show the full solution

    Crossing over, independent assortment and random fertilization

  4. Is an acquired characteristic inherited?
    Show the full solution

    No, because it does not change the alleles in the gametes

  5. In which type of cell must a mutation occur to be inherited?
    Show the full solution

    A gamete, or a cell that produces gametes

  6. Explain why a population with no suitable allele cannot adapt, however strong the selection.
    Show the full solution

    Natural selection acts by favoring individuals that already differ, so it can only increase the frequency of variants that exist. Recombination rearranges existing alleles and cannot invent one, so if the allele is absent from the entire population there is nothing for selection to favor no matter how severe the pressure. The population is limited by its variation rather than by the strength of the selection, and extinction is a realistic outcome, which is why small isolated populations are so vulnerable. Selection can only favor variants that already exist

  7. Explain why the arrival of a predator does not make a useful mutation more likely.
    Show the full solution

    Mutations arise from copying errors and chemical damage to DNA, processes that have no connection to what an organism is experiencing or needs. A predator changes which existing variants survive to reproduce, but it cannot reach into a gamete and alter a base sequence in a helpful direction. This is the central correction of the course: variation arises first and independently, and the environment then filters it. Reversing that order is the teleology error of lesson 10.2. Mutation is random with respect to need; the environment only filters

  8. A weightlifter develops large muscles. Explain why their children do not inherit them.
    Show the full solution

    Training changes the muscle cells of the body, but inheritance passes through the alleles carried in gametes, and nothing about lifting weights alters the DNA sequence in those cells. The children inherit whatever alleles the parent already carried, including any tendency toward a particular build, but not the developed muscle itself. They would need to train to achieve the same result, which is the distinction between an acquired characteristic and an inherited one. Body cells changed, but the alleles in the gametes did not

  9. Explain what recombination contributes if a rare beneficial allele already exists.
    Show the full solution

    It separates that allele from the particular genetic background it arose in and spreads it into many different combinations. The individual who first carried it also carried thousands of other alleles, some of which may be harmful, and without recombination the beneficial allele would be inherited together with them as a package. Recombination allows it to be tested on its own merits and to be combined with other favorable alleles arising elsewhere in the population, which speeds adaptation considerably. It frees the allele from its original background and combines it with others

  10. Why is sexual reproduction common despite costing more than asexual reproduction?
    Show the full solution

    Sexual reproduction requires finding a mate, produces offspring carrying only half of each parent's alleles, and takes longer, all of which are real costs relative to simply copying oneself. The compensating benefit is variation: it generates offspring with combinations never tested before, so a population can respond to a changing environment, to new diseases and to new competitors. Asexual populations are efficient while conditions hold steady and vulnerable when they change, since every individual is susceptible to the same threats. The variation it generates lets populations respond to changing conditions

Lesson 8.6 · Unit 8 · HS-LS1-4, HS-LS3-2

When division goes wrong: nondisjunction and cancer

Two things can fail. Chromosomes can be distributed unevenly, giving a cell the wrong number, or the controls on when a cell divides can break, giving division that never stops. Both are consequences of processes examined earlier in this unit, which makes them predictable rather than mysterious.

The key ideas
  1. Nondisjunction is the failure of chromosomes to separate properly during meiosis, so one gamete receives an extra chromosome and another receives none.
  2. Aneuploidy is the resulting condition, a cell with an abnormal number of chromosomes. Trisomy means three copies of one chromosome instead of two.
  3. A karyotype displays an individual's chromosomes arranged in pairs by size, which makes an abnormal number immediately visible.
  4. Most aneuploidies are not survivable, because the dosage of hundreds of genes is wrong at once. The survivable ones involve the smallest chromosomes or the sex chromosomes.
  5. Cancer is uncontrolled cell division, arising when the checkpoint controls of lesson 8.1 fail through mutations in the genes that operate them.
  6. Cancer usually requires several mutations, which is why risk rises with age and why exposure to mutagens over time matters.

Where students lose marks: describing cancer as cells "growing too fast". The problem is not speed but control: cells divide when they should not, ignore signals to stop, and fail to undergo the programmed death that would normally remove them.

Worked example

Part one: tracing nondisjunction. Follow a pair of chromosomes through a meiosis in which separation fails.

Step one: the normal outcome. A pair of homologues separates in meiosis I, one to each cell, and each chromatid pair separates in meiosis II. Four gametes result, each with exactly one copy of that chromosome.

Step two: failure in meiosis I. Both homologues go to the same pole. One cell has both copies and the other has none, and after meiosis II there are two gametes with two copies and two with none.

Step three: the consequence at fertilization. A gamete carrying two copies fused with a normal gamete gives a zygote with three, which is trisomy. A gamete carrying none gives a zygote with one, which is monosomy.

Step four: explain the severity. A chromosome carries hundreds of genes, and an extra or missing copy changes the dosage of all of them at once. Development depends on balanced expression, so most such zygotes do not survive.

Step five: explain the survivable cases. Trisomy of chromosome 21, which causes Down syndrome, is survivable partly because chromosome 21 is one of the smallest and carries relatively few genes, so the imbalance is smaller.

Part two: the failure of control.

Step six: connect to the checkpoints. Lesson 8.1 described checkpoints verifying that conditions are right before division proceeds. Those checks are carried out by proteins, which are specified by genes, and genes can mutate.

Step seven: explain why several mutations are usually needed. The controls are redundant: one damaged checkpoint is usually caught by another, and damaged cells are normally destroyed. A tumor generally requires mutations in several controlling genes in the same cell lineage, which is why the probability accumulates with age and with exposure to mutagens.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Define nondisjunction.
    Show the full solution

    Failure of chromosomes to separate properly during meiosis

  2. What is trisomy?
    Show the full solution

    Having three copies of a chromosome instead of two

  3. What is a karyotype?
    Show the full solution

    A display of an individual's chromosomes arranged in pairs by size

  4. What is the underlying problem in cancer?
    Show the full solution

    Loss of control over cell division, through mutations in the genes that regulate it

  5. Why does cancer risk rise with age?
    Show the full solution

    Several mutations are usually needed, and they accumulate over time

  6. Explain why an extra chromosome is usually more serious than a single gene mutation.
    Show the full solution

    A gene mutation alters one protein, and the effect may range from nothing to severe depending on that protein's role. An extra chromosome changes the number of copies of every gene it carries, which can be hundreds at once, so the cell produces the wrong quantity of a great many proteins simultaneously. Development depends on those quantities being balanced against each other, so a whole-chromosome imbalance disrupts many interacting systems at the same time and is rarely survivable. It changes the dosage of hundreds of genes at once rather than one

  7. Explain why trisomy 21 is survivable when most trisomies are not.
    Show the full solution

    Chromosome 21 is among the smallest human chromosomes and carries comparatively few genes, so an extra copy alters the dosage of a smaller number of proteins than an extra copy of a large chromosome would. The imbalance is therefore milder and development can proceed, although it is still substantially affected. Trisomies of large gene-rich chromosomes disrupt far more systems at once and almost always end in early loss of the pregnancy. Chromosome 21 is small and carries few genes, so the imbalance is smaller

  8. Explain why "cancer cells grow too fast" is an inadequate description.
    Show the full solution

    Some cancer cells divide no faster than healthy cells of the same tissue, and some healthy tissues such as bone marrow and gut lining divide extremely rapidly without being cancerous. The defining problem is the loss of control: the cells divide when signals say they should not, fail to stop when crowded by neighbors, ignore the checkpoints that would arrest a damaged cell, and escape the programmed death that should remove them. Speed is a symptom in some cancers rather than the defect. The defect is loss of control over division, not the rate of it

  9. Why does a single mutation rarely cause cancer?
    Show the full solution

    The controls on cell division are redundant and overlapping, so damage to one of them is usually detected by another. A cell with a broken checkpoint is typically arrested or destroyed by programmed cell death before it can form a tumor, and the immune system removes many abnormal cells as well. Escaping requires several of those safeguards to fail in the same cell lineage, which is improbable as a single event but becomes likely over decades of divisions and mutagen exposure. Control mechanisms are redundant, so several must fail in the same lineage

  10. Why is a mutagen, a substance that increases mutation rate, also usually a carcinogen?
    Show the full solution

    Cancer arises from mutations in genes controlling cell division, so anything raising the overall mutation rate increases the chance that those particular genes are hit. Since several such mutations are normally required in one cell lineage, and each is individually unlikely, raising the rate has a disproportionate effect on the probability of the full combination occurring. The link is statistical rather than specific: the mutagen does not target the control genes, it simply damages DNA more often. More mutations overall means a higher chance of hitting the control genes

Unit 8 review · Cell Division, Meiosis and Variation

Ten questions across the whole unit

Questions 1 to 5 check that you hold the terms. Questions 6 to 10 require you to reason across the six lessons.

  1. Name the three parts of interphase and what happens in each.
    Show the full solution

    G1 growth, S DNA replication, G2 final preparation

  2. What separates in anaphase of mitosis, and in meiosis I?
    Show the full solution

    Sister chromatids in mitosis; homologous chromosomes in meiosis I

  3. A cell with 10 chromosomes undergoes meiosis. Describe the products.
    Show the full solution

    Four genetically different haploid cells, each with 5 chromosomes

  4. How many gamete combinations does independent assortment give for 6 homologous pairs?
    Show the full solution

    2 to the power 6, which is 64

  5. Which source of genetic variation creates new alleles?
    Show the full solution

    Mutation only

  6. In a cell population, 8 percent are in M phase. Explain what that implies about a 20 hour cycle and what it assumes.
    Show the full solution

    In a large unsynchronized population each cell sits at a random point in the cycle, so the proportion found in a stage estimates the fraction of the cycle it occupies. M phase therefore takes about 8 percent of 20 hours, which is 1.6 hours or 96 minutes. The method assumes the population is unsynchronized and that every cell is actively cycling, since cells that have permanently left the cycle accumulate in G1 and inflate its apparent length. About 96 minutes, assuming an unsynchronized population in which all cells cycle

  7. Explain why crossing over between sister chromatids would achieve nothing.
    Show the full solution

    Sister chromatids are the two identical copies produced when a chromosome was replicated in S phase, so they carry the same alleles at every position. Exchanging a segment between them swaps material identical to the material it replaces, leaving both unchanged. Variation requires exchange between chromosomes that differ, which is why crossing over occurs between non-sister chromatids of homologous pairs, one inherited from each parent. Sister chromatids are identical, so exchanging segments changes nothing

  8. Explain why independent assortment gives 2 to the power n rather than 2 times n.
    Show the full solution

    Each homologous pair contributes an independent two-way choice, and independent choices combine by multiplication rather than addition. With two pairs, each option for the first can be combined with either option for the second, giving two times two rather than two plus two, and adding a third pair doubles the total again. Repeated doubling is a power, which is why 23 pairs give over eight million rather than forty six. Independent choices multiply, and repeated doubling is a power

  9. A population has no allele for a needed characteristic. Explain why recombination cannot help.
    Show the full solution

    Crossing over, independent assortment and random fertilization all rearrange alleles that already exist and none of them can create a new one. If the allele is absent from the entire population, no combination of the available alleles will produce it, so selection has nothing to favor however severe the pressure. Only mutation can introduce a genuinely new variant, and it occurs randomly with respect to need, so it may not occur at all. Recombination only shuffles existing alleles; only mutation creates new ones

  10. Explain why an extra whole chromosome is usually more serious than a single gene mutation.
    Show the full solution

    A gene mutation alters one protein, and the effect ranges from nothing to severe depending on that protein's role. An extra chromosome changes the number of copies of every gene it carries, which can be hundreds at once, so the cell produces the wrong quantity of a great many proteins simultaneously. Development depends on those quantities being balanced against each other, so a whole-chromosome imbalance disrupts many interacting systems and is rarely survivable. It changes the dosage of hundreds of genes at once rather than one

Lesson 9.1 · Unit 9 · HS-LS3-3

Mendel's experiments, and why peas were the right choice

Before Mendel, inheritance was widely understood as blending: a tall plant crossed with a short one should give something intermediate, and the parental forms should be lost. Mendel's results were incompatible with that, and the reason he could see it when others could not is largely a matter of what he chose to work with.

The key ideas
  1. He used seven characteristics of the pea plant, each of which came in two clearly distinguishable forms with no intermediates.
  2. He began with true-breeding lines, plants that produced offspring identical to themselves over many generations, so he knew what he was starting with.
  3. The F1 generation was uniform. Crossing tall with short gave only tall offspring, and nothing intermediate appeared.
  4. The lost form reappeared in the F2. Allowing the F1 to self-pollinate produced both forms again, in a ratio close to three to one.
  5. He counted large numbers, thousands of plants rather than dozens, which is what made the ratio visible rather than lost in variation.
  6. He concluded that inherited factors remain discrete, passing intact from generation to generation rather than blending, with one form able to mask the other.

Where students lose marks: describing Mendel as discovering genes. He inferred discrete hereditary factors from breeding ratios, decades before chromosomes were understood and long before DNA. Inferring an unseen mechanism from numerical patterns is what makes the work remarkable.

Worked example

The source. Gregor Mendel, Experiments in Plant Hybridisation, 1866, in the 1901 English translation. Public domain; the translator's British spelling is preserved as written.

Those characters which are transmitted entire, or almost unchanged in the hybridisation, and therefore in themselves constitute the characters of the hybrid, are termed the dominant, and those which become latent in the process recessive.

Step one: notice the word latent. He does not say the recessive character is destroyed or diluted. He says it becomes hidden, which implies it is still present and could reappear. That is the claim blending inheritance cannot make.

Step two: see what the F2 result demands. Short plants reappeared from two tall parents. Anything that can vanish for a generation and return unchanged must have persisted intact, so the hereditary material cannot have blended.

Step three: examine the choice of organism. Peas can self- pollinate, which lets a single plant be crossed with itself to expose hidden factors, and they can also be cross-pollinated by hand, so the parentage of every seed is known.

Step four: examine the choice of characteristics. Tall against short, round against wrinkled, green against yellow. Each is a clean either-or judgment, so counting is unambiguous and no decision about borderline cases is needed.

Step five: contrast with a poor choice. Had he measured height in centimeters in a species where many genes contribute, he would have obtained a continuous distribution with no ratios visible at all, which is what most earlier investigators found.

Step six: explain why sample size mattered. With twelve offspring a three to one ratio is indistinguishable from chance. With several thousand, the ratio is unmistakable, and lesson 1.3 explains why: random departures average out as the sample grows.

Step seven: state what he inferred and what he could not know. He inferred paired discrete factors, one inherited from each parent, separating during gamete formation. He had no knowledge of chromosomes, meiosis or DNA, and the physical basis of his factors was not identified for another half century.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What is a true-breeding line?
    Show the full solution

    A line producing offspring identical to itself over many generations

  2. What did Mendel observe in the F1 generation of a tall by short cross?
    Show the full solution

    All offspring were tall, with no intermediates

  3. What ratio appeared in the F2?
    Show the full solution

    About three tall to one short

  4. Give two features of peas that suited the work.
    Show the full solution

    They can self-pollinate or be crossed by hand, and their characteristics come in two clear forms

  5. What does the word latent tell you about a recessive character?
    Show the full solution

    It is hidden rather than lost, so it can reappear unchanged

  6. Explain why the F2 result contradicts blending inheritance.
    Show the full solution

    Under blending, a tall plant crossed with a short one would give an intermediate offspring, and crossing those intermediates would give further intermediates, so the original forms would be diluted away and could never return. Mendel's F1 plants were all tall rather than intermediate, and short plants reappeared in the F2 exactly as short as the original grandparent. A character that disappears for a generation and comes back unchanged must have been carried intact, which blending cannot accommodate. Short plants reappeared unchanged, so the factor persisted rather than blending away

  7. Explain why Mendel's choice of characteristics was as important as his method.
    Show the full solution

    Each characteristic he studied is controlled largely by a single gene with two clearly different forms, so every plant could be placed unambiguously in one of two categories and counted. That makes a numerical ratio visible. Most visible traits, including height in many species, are influenced by many genes and by the environment, producing a continuous range in which no ratio can be seen. Investigators studying such traits found only blurred averages, which is precisely why blending seemed correct. Single-gene either-or traits produce countable ratios; continuous traits hide them

  8. Why did Mendel need to count thousands of plants?
    Show the full solution

    Because the three to one ratio is a statement about probabilities, and small samples depart from expected proportions by chance. Twelve offspring might easily give seven tall and five short, which suggests nothing, whereas several thousand will approach three to one closely enough that the pattern cannot be accidental. This is the sample size argument of lesson 1.3 applied to inheritance, and it is a large part of why Mendel saw a law where others saw noise. Small samples vary by chance; large ones reveal the underlying ratio

  9. Explain what it means that Mendel inferred an unseen mechanism.
    Show the full solution

    He never observed a gene, a chromosome or a gamete carrying a factor. What he observed were counts of plants across generations, and from the regularity of those numbers he reasoned that the results would follow if each plant carried two discrete factors for each characteristic, one from each parent, which separated when gametes formed. The mechanism was a hypothesis proposed to explain a pattern, exactly as lesson 1.1 describes, and it was confirmed by cytology decades later. He proposed discrete paired factors to explain numerical patterns, with no direct observation

  10. Suggest why Mendel's work was ignored for over thirty years.
    Show the full solution

    His argument was quantitative at a time when most biology was descriptive, so readers were unprepared for a conclusion resting on ratios rather than on observations of structures. Blending inheritance also fitted everyday experience with traits such as human height and skin color, which are polygenic, so his results looked like a peculiarity of peas rather than a general law. Without chromosomes and meiosis, which were described later, there was no visible mechanism his factors could correspond to. Its statistical argument had no known mechanism and conflicted with everyday impressions

Lesson 9.2 · Unit 9 · HS-LS3-3

Gene and allele, genotype and phenotype

Genetics questions are lost on vocabulary more often than on reasoning. The terms come in pairs that are easy to confuse and impossible to substitute for one another, and an answer that uses gene where it means allele is usually marked wrong even when the thinking behind it is correct.

The key ideas
  1. A gene is a length of DNA coding for a characteristic. An allele is one particular version of that gene. Everyone has the gene; people differ in which alleles they have.
  2. Genotype is the alleles an organism carries, written as letters such as Tt. Phenotype is the observable characteristic, such as tall.
  3. Homozygous means two identical alleles, TT or tt. Heterozygous means two different ones, Tt.
  4. A dominant allele is expressed whenever present, so one copy is enough. It is written with a capital letter.
  5. A recessive allele is expressed only when homozygous, so two copies are needed. It is written with the lower case of the same letter.
  6. Dominant does not mean common, strong or better. It describes only whether one copy is sufficient for expression.

Where students lose marks: writing "the gene for tallness" when they mean the allele. The gene is for height; the alleles are the tall version and the short version. Also avoid mixing letters: if tall is T, short must be t, never s.

Worked example

The task. Work from a described situation to the correct vocabulary, which is the direction exam questions run.

GenotypeNamePhenotype
TThomozygous dominanttall
Ttheterozygoustall
tthomozygous recessiveshort

Step one: note that two genotypes give one phenotype. TT and Tt both produce tall plants, so the phenotype does not reveal the genotype for a dominant characteristic. This single fact generates most of the interesting problems in genetics.

Step two: note that one genotype gives one phenotype for the recessive. A short plant must be tt, because a single T would have made it tall. Recessive phenotypes are genetically unambiguous.

Step three: apply it to a real question. "A short plant is crossed with a tall plant and half the offspring are short." The short parent must be tt. Since short offspring appeared, the tall parent must have supplied a t, so it is Tt.

Step four: state the reasoning that did the work. A recessive phenotype in the offspring proves both parents carried the recessive allele. That single inference solves a large proportion of pedigree questions.

Step five: correct a common phrasing error. Do not write that the tall plant "has the gene for tallness". It has the tall allele of the height gene, and so does the short plant, which has two short alleles of the same gene.

Step six: test the dominant equals common misconception. Polydactyly, having extra fingers, is caused by a dominant allele and is rare. Being unable to roll the tongue is recessive and is common in many populations. Frequency is determined by history and selection, not by dominance.

Step seven: state what dominance actually describes. Whether one copy of the allele is enough to produce the phenotype. That is a statement about the biochemistry of a particular protein, not about how good or how widespread the allele is.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Distinguish a gene from an allele.
    Show the full solution

    A gene is a length of DNA coding for a characteristic; an allele is one version of that gene

  2. Distinguish genotype from phenotype.
    Show the full solution

    Genotype is the alleles carried; phenotype is the observable characteristic

  3. What does heterozygous mean?
    Show the full solution

    Carrying two different alleles of a gene

  4. How many copies of a recessive allele are needed for it to be expressed?
    Show the full solution

    Two

  5. Does dominant mean common?
    Show the full solution

    No; it means one copy is enough for expression

  6. Explain why a dominant phenotype does not reveal the genotype but a recessive one does.
    Show the full solution

    A dominant allele is expressed whenever it is present, so both the homozygous dominant and the heterozygous genotype produce the same appearance and cannot be told apart by looking. A recessive phenotype requires two copies of the recessive allele, since a single dominant allele would have masked it, so an organism showing the recessive characteristic must be homozygous recessive. This asymmetry is why test crosses exist and why recessive individuals are so useful in pedigree analysis. Two genotypes give the dominant phenotype but only one gives the recessive

  7. A short plant crossed with a tall plant gives some short offspring. Deduce both genotypes and explain.
    Show the full solution

    The short parent must be tt, since short is recessive and requires two copies. Each short offspring must also be tt, and it received one allele from each parent, so it must have received a t from the tall parent as well. Since that parent is tall it must carry at least one T, so its genotype is Tt. The appearance of a recessive phenotype among the offspring is what proves the dominant-looking parent is heterozygous. Short parent tt and tall parent Tt, since the short offspring needed a t from each

  8. Explain why polydactyly being dominant and rare is not a contradiction.
    Show the full solution

    Dominance describes how an allele behaves when present with a different allele, specifically that one copy suffices for expression. It says nothing about how many people carry it. Frequency depends on how often the allele arises by mutation and on whether it has been favored or disfavored by selection over many generations. A dominant allele that is disadvantageous or simply rare in origin will stay rare, while a common recessive allele can be carried by a large fraction of a population without being expressed. Dominance concerns expression with one copy; frequency depends on mutation and selection

  9. Why must the same letter be used for both alleles of a gene?
    Show the full solution

    Because the two alleles are versions of the same gene occupying the same position on homologous chromosomes, and the notation is meant to show that relationship. Writing T for tall and s for short would suggest two separate genes with no connection, and the Punnett square built from it would be meaningless. Using T and t makes it immediately clear which alleles are alternatives at one locus, which is the information a cross depends on. They are alternatives at the same locus, and the notation must show that

  10. An organism is described as homozygous. What can and cannot be concluded about its phenotype?
    Show the full solution

    Only that its two alleles for that gene are identical, which does not by itself say which phenotype it shows. Homozygous dominant and homozygous recessive are both homozygous and give opposite appearances. What can be concluded is that it is true-breeding for that characteristic, since every gamete it produces carries the same allele, so crossing it with an identical organism gives offspring all showing the same phenotype. It is true-breeding for that gene, but the phenotype depends on which allele is doubled

Lesson 9.3 · Unit 9 · HS-LS3-3

Monohybrid crosses and the Punnett square

A Punnett square is a bookkeeping device for combining gametes. It works because of meiosis: each parent's two alleles separate so that a gamete carries one, and fertilization brings one from each parent together. The square is that biology drawn as a grid.

The key ideas
  1. A monohybrid cross follows one gene. Each parent contributes one allele to each offspring.
  2. Gametes carry one allele each, because homologous chromosomes separate in meiosis I. A Tt parent produces T and t gametes in equal numbers.
  3. The square combines every gamete type from one parent with every type from the other, and each box is equally likely.
  4. Tt crossed with Tt gives a 3 to 1 phenotypic ratio and a 1 to 2 to 1 genotypic ratio.
  5. The result is a probability, not a guarantee. Four offspring will not reliably be three tall and one short, as lesson 1.6 discussed.
  6. Each fertilization is independent, so previous offspring do not affect the next. Three tall offspring do not make a short one more likely.

Where students lose marks: giving the ratio without saying whether it is genotypic or phenotypic. Tt by Tt gives 3 to 1 phenotypes and 1 to 2 to 1 genotypes, and an unlabeled "3:1" can be marked wrong if the question asked for genotypes.

Worked example

The cross. Two heterozygous tall pea plants, Tt by Tt. Tall is dominant.

Step one: find the gametes. Each parent is Tt, so each produces two kinds of gamete, T and t, in equal proportions.

Step two: build the square. Combine each gamete from one parent with each from the other. The four boxes are TT, Tt, Tt and tt.

Tt
TTTTt
tTttt

Step three: read the genotypic ratio. One TT, two Tt, one tt, so 1 to 2 to 1. Each box represents a quarter of the expected offspring.

Step four: convert to phenotypes. TT is tall, both Tt are tall, and tt is short. Three tall to one short, so the phenotypic ratio is 3 to 1.

Step five: express it as probability. Each offspring has a 3 in 4 chance of being tall, which is 75 percent, and a 1 in 4 chance of being short.

Step six: apply it to a stated number. From 120 offspring, expect about 90 tall and 30 short, since three quarters of 120 is 90. The word expect is doing real work, because the actual numbers will differ.

Step seven: answer the question students always ask. If three offspring are tall, the fourth is not more likely to be short. Each fertilization combines a random gamete from each parent independently of what came before, so the chance remains 1 in 4 every time.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What gametes does a Tt parent produce, and in what proportion?
    Show the full solution

    T and t, in equal numbers

  2. Give the genotypic and phenotypic ratios for Tt by Tt.
    Show the full solution

    Genotypic 1 TT to 2 Tt to 1 tt; phenotypic 3 tall to 1 short

  3. What are the offspring of TT by tt?
    Show the full solution

    All Tt, and all showing the dominant phenotype

  4. What is the probability that a Tt by tt cross gives a short offspring?
    Show the full solution

    One half

  5. From 200 offspring of Tt by Tt, how many are expected to be short?
    Show the full solution

    About 50, since one quarter of 200 is 50

  6. Explain why the Punnett square works, in terms of meiosis.
    Show the full solution

    Each parent carries two alleles on homologous chromosomes, and meiosis I separates those homologues so that every gamete receives exactly one. The two rows and two columns of the square represent the equally likely gamete types each parent produces. Fertilization brings one gamete from each parent together at random, which is what each box represents. The grid is therefore a direct picture of segregation followed by random fertilization, not an arbitrary convention. Meiosis separates the alleles into gametes and fertilization recombines them at random

  7. A cross of two tall plants produces some short offspring. Deduce the parental genotypes and justify.
    Show the full solution

    Both parents must be Tt. Each short offspring is tt, since short is recessive and requires two copies, and it received one allele from each parent, so each parent must have supplied a t. Both parents are tall, so each must also carry a T, making both heterozygous. Neither could be TT, because a TT parent can supply only T and no short offspring would be possible at all. Both Tt, since each short offspring needed a t from each tall parent

  8. Explain why four offspring of a Tt by Tt cross are often not three tall and one short.
    Show the full solution

    The three to one ratio is a probability per offspring rather than a quota to be filled. Each fertilization independently has a three in four chance of giving a tall plant, so with only four offspring the outcome is subject to considerable chance, in the same way that four coin tosses frequently do not give exactly two heads. All four could be tall. The ratio becomes reliable only over large numbers, which is why Mendel counted thousands. It is a probability per offspring, and small samples vary by chance

  9. A couple have three children with a recessive condition. Is the fourth less likely to be affected? Explain.
    Show the full solution

    No. If both parents are carriers, each child independently has a one in four chance of inheriting two recessive alleles, and the gametes involved in the fourth conception are unaffected by what happened in the first three. The intuition that the odds must even out treats past independent events as though they influenced future ones. The only thing the three affected children change is the confidence that both parents really are carriers. Each conception is independent, so the chance remains one in four

  10. Why does a cross between a homozygous dominant and a homozygous recessive parent hide the recessive allele?
    Show the full solution

    The TT parent can only supply T and the tt parent can only supply t, so every offspring is Tt. Each of them carries the recessive allele but also carries a dominant one, which is expressed, so all the offspring show the dominant phenotype and none reveals the recessive. The allele has not been lost and reappears in the next generation when two heterozygotes are crossed, which is exactly the F1 and F2 pattern Mendel observed. All offspring are heterozygous, so the dominant allele masks the recessive one

Lesson 9.4 · Unit 9 · HS-LS3-3

Dihybrid crosses and where 9:3:3:1 comes from

Following two genes at once produces a ratio that looks arbitrary until you see where it comes from. It is not a fact to memorize. It is two independent three to one ratios multiplied together, and once that is clear the sixteen-box square becomes optional.

The key ideas
  1. A dihybrid cross follows two genes at once, and requires that they assort independently, which holds when they are on different chromosomes.
  2. A double heterozygote produces four gamete types in equal numbers. TtRr gives TR, Tr, tR and tr.
  3. The square has sixteen boxes, four gamete types from each parent.
  4. The phenotypic ratio is 9 to 3 to 3 to 1: nine showing both dominant characteristics, three showing each single dominant, and one showing both recessives.
  5. The ratio is the product of two monohybrid ratios. Each gene separately gives 3 to 1, and the combinations are three quarters times three quarters and so on.
  6. The probability method is faster and less error prone than drawing sixteen boxes, and it extends to three or more genes where a square becomes impractical.

Where students lose marks: listing gametes wrongly. A TtRr parent gives TR, Tr, tR, tr. Writing TT or rr as a gamete is a common slip: a gamete carries one allele of each gene, never two of the same gene.

Worked example

The cross. TtRr by TtRr, where T is tall dominant to t short, and R is round seed dominant to r wrinkled.

Step one: derive the ratio without the square. Treat each gene separately. For height, Tt by Tt gives three quarters tall and one quarter short. For seed shape, Rr by Rr gives three quarters round and one quarter wrinkled.

Step two: combine for tall and round. The genes assort independently, so multiply the probabilities: three quarters times three quarters is nine sixteenths.

Step three: combine for tall and wrinkled. Three quarters times one quarter is three sixteenths.

Step four: combine for short and round. One quarter times three quarters is three sixteenths.

Step five: combine for short and wrinkled. One quarter times one quarter is one sixteenth.

Step six: check and state the ratio. Nine plus three plus three plus one is sixteen, so every offspring is accounted for. The ratio is 9 to 3 to 3 to 1, derived in five lines rather than sixteen boxes.

Step seven: apply it to a number and note the limit. From 320 offspring, expect nine sixteenths of 320, which is 180, tall and round. The method depends on independent assortment, so it fails for genes close together on the same chromosome, which lesson 8.4 explained are usually inherited together.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What gametes does a TtRr parent produce?
    Show the full solution

    TR, Tr, tR and tr, in equal numbers

  2. State the phenotypic ratio from TtRr by TtRr.
    Show the full solution

    9 to 3 to 3 to 1

  3. How many boxes does a dihybrid Punnett square have?
    Show the full solution

    Sixteen

  4. What condition must hold for the 9:3:3:1 ratio?
    Show the full solution

    The two genes must assort independently, usually meaning they are on different chromosomes

  5. From 160 offspring, how many are expected to show both recessive characteristics?
    Show the full solution

    One sixteenth of 160, which is 10

  6. Explain where the 9:3:3:1 ratio comes from.
    Show the full solution

    It is the product of two independent three to one ratios. Considered alone, each gene in a heterozygous cross gives three quarters showing the dominant characteristic and one quarter showing the recessive. Because the genes assort independently, the probability of any combination is the product of the separate probabilities: three quarters times three quarters gives nine sixteenths, three quarters times one quarter gives three sixteenths twice over, and one quarter times one quarter gives one sixteenth. Those four fractions are the ratio. Two independent 3:1 ratios multiplied together

  7. Explain why the probability method is better than drawing the square.
    Show the full solution

    It is faster, less error prone and it scales. A sixteen-box square requires listing four gamete types twice and filling sixteen cells correctly, and a single slip in the gamete list corrupts everything after it. The probability method needs four multiplications. More importantly, following three genes would need a sixty four box square, which is impractical, while the probability method simply multiplies a third fraction into each result and works for any number of independently assorting genes. It is quicker, less error prone, and extends to three or more genes

  8. Why can a gamete never be TT or rr?
    Show the full solution

    A gamete is haploid and carries one allele of each gene, because meiosis I separates the homologous chromosomes that bear the two alleles. Writing TT would mean the gamete carried both copies of the height gene, which happens only in nondisjunction, and writing rr would mean the same for seed shape. Each gamete must contain exactly one allele from each gene, which is why the four types from TtRr each pair one height allele with one shape allele. Gametes are haploid and carry one allele of each gene

  9. A dihybrid cross gives a ratio close to 3:1 rather than 9:3:3:1. Suggest why.
    Show the full solution

    The two genes are probably linked, meaning they sit close together on the same chromosome and are inherited as a unit rather than assorting independently. Under linkage the parental combinations appear far more often than expected and the four-category ratio collapses toward the pattern of a single gene, with only a small number of recombinant offspring produced by crossing over between the two loci. The departure from the expected ratio is itself the evidence for linkage. The genes are linked on the same chromosome and do not assort independently

  10. Calculate the expected number of tall wrinkled offspring from 480 offspring of TtRr by TtRr.
    Show the full solution

    Tall requires at least one T, which has probability three quarters, and wrinkled requires two r alleles, which has probability one quarter. Multiplying gives three sixteenths for the combination. Three sixteenths of 480 is 480 divided by 16, which is 30, multiplied by 3, giving 90. So about 90 offspring are expected to be tall and wrinkled, remembering that this is an expectation rather than a guarantee. 90, since three sixteenths of 480 is 90

Lesson 9.5 · Unit 9 · HS-LS3-3

Test crosses and reading a pedigree

An organism showing a dominant characteristic may be homozygous or heterozygous, and no amount of looking will say which. A test cross settles it in one generation. Where breeding cannot be arranged, as with humans, the same reasoning is applied backwards to a family record.

The key ideas
  1. A test cross pairs the unknown with a homozygous recessive, which can only contribute recessive alleles and therefore cannot mask anything.
  2. All dominant offspring suggests the unknown is homozygous. Any recessive offspring proves it is heterozygous.
  3. One recessive offspring is conclusive; a run of dominant ones is only strong evidence, since a heterozygote could produce several dominant offspring by chance.
  4. Pedigree conventions: squares are male, circles female, shaded symbols show the characteristic, horizontal lines join partners and vertical lines lead to children.
  5. Two unaffected parents with an affected child proves the characteristic is recessive and both parents are carriers. This is the single most useful deduction.
  6. An affected child of the sex opposite to the affected parent pattern, and affected sons of unaffected mothers, point toward sex linkage, which lesson 9.7 develops.

Where students lose marks: concluding "dominant" because a characteristic appears in every generation. That is consistent with dominance but also with a common recessive allele. The decisive evidence is two unaffected parents producing an affected child, which rules dominance out.

Worked example

Part one: the test cross. A tall pea plant of unknown genotype is crossed with a short plant.

Step one: state the two possibilities. The unknown is TT or Tt. The short plant is certainly tt, since short is recessive.

Step two: predict for TT. TT by tt gives all Tt offspring, so every one is tall. No short offspring can occur.

Step three: predict for Tt. Tt by tt gives half Tt and half tt, so about half the offspring are short.

Step four: state the interpretation. A single short offspring proves the parent is Tt, since the t must have come from somewhere. A run of tall offspring makes TT likely but never certain, because a heterozygote could produce several tall offspring in a row by chance.

Part two: reading a pedigree. A described family: two unaffected parents have four children, of whom one daughter shows the condition.

Step five: apply the key deduction. The affected daughter's parents are both unaffected. If the condition were dominant, at least one parent would show it, since one copy would be enough. It must therefore be recessive.

Step six: deduce the parental genotypes. The affected daughter is homozygous recessive and received one recessive allele from each parent. Both parents are unaffected, so each must be heterozygous, a carrier.

Step seven: check for sex linkage and state the risk. The affected child is female with an unaffected father, which argues against X-linked recessive inheritance, since her father would have to be affected. So this is autosomal recessive, and each further child has a one in four chance of being affected.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What is a test cross, and what is it used for?
    Show the full solution

    Crossing an unknown dominant phenotype with a homozygous recessive to determine its genotype

  2. Why is a homozygous recessive used as the partner?
    Show the full solution

    It can only contribute recessive alleles, so it cannot mask anything

  3. What do squares and circles mean in a pedigree?
    Show the full solution

    Squares are male and circles female

  4. What does an affected child of two unaffected parents prove?
    Show the full solution

    That the condition is recessive and both parents are carriers

  5. What result from a test cross proves the unknown is heterozygous?
    Show the full solution

    Any offspring showing the recessive phenotype

  6. Explain why one recessive offspring is conclusive but ten dominant ones are not.
    Show the full solution

    A recessive offspring must be homozygous recessive, so it received a recessive allele from each parent, and the unknown parent must therefore carry one. That is a logical certainty from a single observation. A run of dominant offspring is only probabilistic: a heterozygote crossed with a homozygous recessive has a one in two chance of a dominant offspring each time, so ten in a row has a probability of about one in a thousand. Unlikely is not impossible. One recessive offspring is logically decisive; a run of dominants is only improbable

  7. Explain why a characteristic appearing in every generation does not prove it is dominant.
    Show the full solution

    Appearing in every generation is what a dominant allele typically produces, but a recessive allele that is common in the population can do the same, because affected individuals frequently have partners who are carriers or affected themselves. The pattern is therefore consistent with both possibilities and cannot distinguish them. What does distinguish them is an affected child born to two unaffected parents, which is impossible under dominance and straightforward under recessive inheritance. A common recessive allele produces the same pattern; only unaffected parents with an affected child is decisive

  8. A tall plant crossed with a short plant gives 12 tall and 0 short. What can be concluded?
    Show the full solution

    That the tall parent is very probably homozygous dominant, but not certainly. If it were heterozygous, each offspring would have a one in two chance of being short, so twelve consecutive tall offspring would have a probability of about one in four thousand. That is strong evidence for TT without being proof, and the honest answer states the conclusion with its strength rather than asserting certainty, which is the habit lesson 1.5 requires. Very probably TT, since twelve tall offspring from a heterozygote is about one in four thousand

  9. In a pedigree, an affected son has an unaffected mother and unaffected father. What are the possibilities?
    Show the full solution

    The condition is recessive, since neither parent shows it. It could be autosomal recessive, in which case both parents are carriers and the son is homozygous recessive. It could equally be X-linked recessive, in which case the mother is a carrier and the son inherited her affected X while receiving a Y from his father, so the father need carry nothing. Distinguishing them requires more of the family: affected daughters would argue for autosomal inheritance. Autosomal recessive with both parents carriers, or X-linked recessive with a carrier mother

  10. Two carriers of a recessive condition have a child. State the probabilities and explain.
    Show the full solution

    Both parents are heterozygous, so the cross is equivalent to Tt by Tt. The child has a one in four chance of being homozygous recessive and affected, a two in four chance of being a heterozygous carrier, and a one in four chance of being homozygous unaffected. Expressed as phenotypes, there is a three in four chance the child is unaffected, though two thirds of those unaffected children will be carriers, which matters for the next generation. One in four affected, two in four carriers, one in four homozygous unaffected

Lesson 9.6 · Unit 9 · HS-LS3-3

Beyond Mendel: when the ratios do not appear

Mendel's rules describe a special case: one gene, two alleles, one completely dominant over the other. Most characteristics are not like that, and the departures are not exceptions to inheritance but the ordinary situation. Each one produces its own recognizable pattern.

The key ideas
  1. Incomplete dominance gives an intermediate heterozygote. A red and a white parent give pink offspring, and the F2 ratio is 1 to 2 to 1 for both genotype and phenotype.
  2. Codominance expresses both alleles fully. The heterozygote shows both characteristics rather than a blend, as in roan cattle with both red and white hairs.
  3. Multiple alleles means more than two versions exist in the population, though any individual still carries only two.
  4. The ABO blood group combines both ideas: three alleles, with A and B codominant with each other and both dominant over O.
  5. Polygenic characteristics are controlled by many genes, each contributing a small amount, which produces a continuous range rather than categories.
  6. Environment affects phenotype too, so the same genotype can give different appearances, which is why identical twins are not identical in every respect.

Where students lose marks: calling incomplete dominance blending inheritance. The alleles themselves are not blended and separate unchanged in the next generation, which is why crossing two pink flowers gives red and white offspring again. The phenotype is intermediate; the genetics is not.

Worked example

Part one: incomplete dominance. In snapdragons, red crossed with white gives pink.

Step one: cross two pink flowers. Both are heterozygous. The Punnett square gives one homozygous red, two heterozygous pink and one homozygous white.

Step two: read the ratio. 1 red to 2 pink to 1 white. The phenotypic and genotypic ratios are identical, because every genotype has its own appearance.

Step three: state why this is not blending. Red and white reappear unchanged from two pink parents. If the factors had blended, pink parents could produce only pink.

Part two: the ABO blood group. Three alleles: IA, IB and i. A and B are codominant with each other; both are dominant over i.

Blood groupPossible genotypes
AIAIA or IAi
BIBIB or IBi
ABIAIB
Oii

Step four: note where codominance appears. Group AB expresses both alleles fully and separately. It is not an intermediate between A and B, which is what distinguishes codominance from incomplete dominance.

Step five: note where multiple alleles appear. Three alleles exist in the population, but each person carries only two, one on each homologous chromosome.

Step six: work a cross. A group AB parent with a group O parent. AB is IAIB and O is ii, so the children are half IAi, which is group A, and half IBi, which is group B.

Step seven: state the counterintuitive result. Two parents of groups AB and O can have no children of either group AB or group O. This kind of deduction is the basis of using blood groups to exclude parentage.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What phenotype does incomplete dominance give in the heterozygote?
    Show the full solution

    An intermediate between the two homozygous phenotypes

  2. How does codominance differ from incomplete dominance?
    Show the full solution

    Both alleles are fully expressed rather than producing an intermediate

  3. How many ABO alleles exist, and how many does one person carry?
    Show the full solution

    Three exist; each person carries two

  4. Give the genotypes for blood group O and group AB.
    Show the full solution

    O is ii; AB is IAIB

  5. What kind of variation do polygenic characteristics produce?
    Show the full solution

    Continuous variation rather than distinct categories

  6. Explain why incomplete dominance is not blending inheritance.
    Show the full solution

    Blending inheritance claims the hereditary material itself mixes, so the parental forms are permanently diluted and cannot return. In incomplete dominance only the phenotype is intermediate: the two alleles remain distinct in the heterozygote and separate unchanged during meiosis. Crossing two pink snapdragons therefore produces red and white offspring again, in a quarter of cases each, which is impossible under blending and is decisive evidence that the alleles stayed intact. The alleles stay distinct and separate unchanged, so red and white reappear

  7. Explain why the F2 ratio for incomplete dominance is 1:2:1 rather than 3:1.
    Show the full solution

    The genotypic ratio from a heterozygous cross is always 1 to 2 to 1, whatever the dominance relationship. Under complete dominance the homozygous dominant and the heterozygote look identical, so two of the three categories merge and the phenotypic ratio collapses to 3 to 1. Under incomplete dominance each genotype produces a distinguishable appearance, so nothing merges and the phenotypic ratio simply matches the genotypic one. Each genotype is visibly different, so no categories merge

  8. A group A parent and a group B parent have a group O child. Explain how.
    Show the full solution

    Both parents must be heterozygous, carrying the recessive i allele alongside their expressed allele, so their genotypes are IAi and IBi. Each can pass on i, and a child receiving i from both parents is ii and therefore group O. The parents' own appearance gives no hint of this, because a single IA or IB allele is enough to determine their group, which is the standard behavior of a dominant allele. Both parents are heterozygous carriers of i and each passed it on

  9. Explain why human height shows a continuous range rather than tall and short categories.
    Show the full solution

    Height is polygenic, influenced by many genes each contributing a small amount, so the possible totals form a near continuous scale rather than two groups. With many genes involved, most people inherit a mixture of increasing and decreasing alleles and fall near the middle, while extremes require an unusual combination and are rarer. Environment adds further variation through nutrition and health, smoothing the distribution further. This is why Mendel's approach would have failed on such a trait. Many genes each contribute a little, and environment adds more variation

  10. Why can blood groups exclude a parent but not prove parentage?
    Show the full solution

    Certain combinations are impossible, so finding one excludes a person definitively: a group AB individual cannot be the parent of a group O child, because they carry no i allele to pass on. But the possible combinations are shared by very large numbers of people, since only four groups exist, so a compatible result shows only that the person is not excluded. Exclusion is logically decisive while inclusion is not, which is a general feature of tests with few categories. Impossible combinations exclude definitively, but compatibility is shared by millions

Lesson 9.7 · Unit 9 · HS-LS3-2, HS-LS3-3

Sex linkage and the notation that earns marks

Some conditions appear far more often in males than in females, and the pattern has a structural explanation rather than a statistical one. The X and Y chromosomes are not a matched pair, so genes carried on the X have no partner allele in a male, and a single recessive allele is enough to produce the condition.

The key ideas
  1. Females are XX and males are XY. The X carries many genes unrelated to sex; the much smaller Y carries few.
  2. A sex-linked gene is carried on the X chromosome and has no corresponding allele on the Y.
  3. A male expresses whatever allele his single X carries, since there is no second copy to mask it. He cannot be a carrier.
  4. A female needs two copies to be affected by an X-linked recessive condition, and with one she is an unaffected carrier.
  5. The notation must show the chromosome: write XN, Xn and Y, never N and n alone. Marks are awarded for the notation itself.
  6. Fathers pass their X only to daughters, and their Y only to sons, so an affected father cannot pass an X-linked condition to a son.

Where students lose marks: writing the genotypes as Nn and nn without the X and Y. A sex-linked cross written that way cannot show why males and females differ, and it usually loses every mark in the question regardless of whether the ratios are right.

Worked example

The cross. A woman who carries the allele for red-green color blindness has children with a man who has normal vision. Color blindness is X-linked recessive.

Step one: write the genotypes correctly. The mother is a carrier, so she is XNXn. The father has normal vision, so he is XNY.

Step two: list the gametes. The mother produces XN and Xn eggs in equal numbers. The father produces XN and Y sperm in equal numbers.

Step three: build the square. The four equally likely combinations are XNXN, XNXn, XNY and XnY.

XN (egg)Xn (egg)
XN (sperm)XNXN normal daughterXNXn carrier daughter
Y (sperm)XNY normal sonXnY color blind son

Step four: read the daughters. Both are unaffected. One is a carrier and one is not, so no daughter is color blind, since each received a normal X from her father.

Step five: read the sons. One in two is color blind. A son receives his only X from his mother, and if it carries the recessive allele he is affected, because his Y has no allele to mask it.

Step six: state the results precisely. Overall, one quarter of the children are color blind, but expressed by sex it is half the sons and none of the daughters. Stating both figures is what a full answer requires.

Step seven: explain the asymmetry in general. A male needs one copy of a recessive X-linked allele to be affected while a female needs two, so such conditions are far commoner in males. A father cannot pass the condition to a son at all, since he gives a son only his Y.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What are the sex chromosome genotypes of females and males?
    Show the full solution

    Females XX, males XY

  2. Why can a male not be a carrier of an X-linked condition?
    Show the full solution

    He has only one X, so any allele on it is expressed

  3. Write the genotype of a carrier female for an X-linked recessive condition.
    Show the full solution

    XNXn

  4. From which parent does a son inherit his X chromosome?
    Show the full solution

    His mother

  5. In the worked cross, what proportion of sons are affected?
    Show the full solution

    One half

  6. Explain why X-linked recessive conditions are commoner in males.
    Show the full solution

    A male has a single X chromosome and a Y that carries no corresponding allele, so whatever version of the gene sits on his X is expressed with nothing to mask it. One copy of the recessive allele is therefore sufficient. A female has two X chromosomes, so a recessive allele on one is masked by a normal allele on the other unless she happens to inherit the recessive version from both parents, which is far less likely. The requirement is one copy against two. Males need one copy to be affected, females need two

  7. Explain why an affected father cannot pass the condition to his sons.
    Show the full solution

    A father gives each son a Y chromosome and each daughter his X. Since the gene is carried on the X, the allele he possesses goes only to his daughters, who receive it alongside an X from their mother and are usually carriers rather than affected. His sons receive their single X from their mother, so whether they are affected depends entirely on her. This is why X-linked conditions appear to skip from grandfather to grandson through an unaffected daughter. Sons receive his Y, not his X, so the allele goes only to daughters

  8. A color blind woman has sons with a man of normal vision. Predict the outcome.
    Show the full solution

    She is XnXn and he is XNY. Every son receives an Xn from his mother and a Y from his father, so every son is XnY and color blind. Every daughter receives an Xn from her mother and an XN from her father, so every daughter is XNXn, a carrier with normal vision. All sons affected and all daughters carriers is the characteristic signature of an affected mother. All sons color blind, all daughters unaffected carriers

  9. Why does writing the genotypes as Nn and nn lose marks?
    Show the full solution

    Because that notation describes an autosomal gene, where both sexes carry two alleles, and it therefore cannot represent the situation that makes sex linkage work. It gives no way to show that a male has a single allele and a Y with no partner, so it predicts the same outcome for sons and daughters, which is exactly the result the question is testing. Writing XN, Xn and Y makes the asymmetry explicit and produces the correct ratios automatically. It cannot represent the Y chromosome, so it predicts no difference between the sexes

  10. A condition appears in a pedigree only in males, passed through unaffected females. What does this suggest?
    Show the full solution

    X-linked recessive inheritance. Affected males inherit the allele on the single X they receive from their mothers, who are unaffected carriers because their second X carries a normal allele. The condition therefore appears to skip generations, passing invisibly through women and surfacing in their sons. An autosomal recessive condition would affect both sexes about equally, so a strong male bias combined with transmission through unaffected women is the characteristic signature. X-linked recessive, carried invisibly by female carriers and expressed in their sons

Unit 9 review · Inheritance

Ten questions across the whole unit

Questions 1 to 5 check that you hold the terms. Questions 6 to 10 require you to reason across the seven lessons.

  1. Distinguish a gene from an allele, and genotype from phenotype.
    Show the full solution

    A gene codes for a characteristic and an allele is one version of it; genotype is the alleles carried and phenotype is the observable characteristic

  2. Give the genotypic and phenotypic ratios from Tt crossed with Tt.
    Show the full solution

    1 TT to 2 Tt to 1 tt; 3 dominant to 1 recessive

  3. From 240 offspring of TtRr by TtRr, how many are expected to show both recessive characteristics?
    Show the full solution

    One sixteenth of 240, which is 15

  4. What does an affected child of two unaffected parents prove?
    Show the full solution

    That the condition is recessive and both parents are carriers

  5. Write the genotype of a carrier female and an affected male for an X-linked recessive condition.
    Show the full solution

    XNXn and XnY

  6. Explain why a recessive phenotype reveals the genotype but a dominant one does not.
    Show the full solution

    A dominant allele is expressed whenever present, so the homozygous dominant and the heterozygous genotypes produce the same appearance and cannot be distinguished by looking. A recessive phenotype requires two copies of the recessive allele, since a single dominant allele would have masked it, so an organism showing the recessive characteristic must be homozygous recessive. This asymmetry is why test crosses exist and why recessive individuals are so informative in pedigrees. Two genotypes give the dominant phenotype but only one gives the recessive

  7. Explain where the 9:3:3:1 ratio comes from without drawing a square.
    Show the full solution

    It is the product of two independent three to one ratios. Considered alone, each gene in a heterozygous cross gives three quarters dominant and one quarter recessive, and because the genes assort independently the probability of any combination is the product of the separate probabilities. Three quarters times three quarters gives nine sixteenths, three quarters times one quarter gives three sixteenths twice, and one quarter times one quarter gives one sixteenth. Two independent 3:1 ratios multiplied together

  8. A couple have three affected children. Explain whether the fourth is less likely to be affected.
    Show the full solution

    No. If both parents are carriers, each child independently has a one in four chance of inheriting two recessive alleles, and the gametes involved in the fourth conception are unaffected by what happened in the first three. The intuition that the odds must even out treats past independent events as though they influenced future ones. The only thing the three affected children change is the confidence that both parents really are carriers. Each conception is independent, so the chance remains one in four

  9. Explain why incomplete dominance is not blending inheritance.
    Show the full solution

    Blending inheritance claims the hereditary material itself mixes, so parental forms are permanently diluted and cannot return. In incomplete dominance only the phenotype is intermediate: the two alleles remain distinct in the heterozygote and separate unchanged during meiosis. Crossing two pink snapdragons therefore produces red and white offspring again in a quarter of cases each, which is impossible under blending and shows the alleles stayed intact. The alleles stay distinct, so red and white reappear from pink parents

  10. Explain why X-linked recessive conditions appear far more often in males.
    Show the full solution

    A male has one X chromosome and a Y that carries no corresponding allele, so whatever version sits on his X is expressed with nothing to mask it and one copy of the recessive allele is sufficient. A female has two X chromosomes, so a recessive allele on one is masked by a normal allele on the other unless she inherits the recessive version from both parents, which is far less likely. The requirement is one copy against two. Males need one copy to be affected, females need two

Lesson 10.1 · Unit 10 · HS-LS4-2

Darwin's argument, stated as four conditions

Natural selection is not a force and not a tendency. It is an outcome that follows necessarily whenever four conditions hold together, and the argument is close to arithmetic: given the four, the conclusion cannot be avoided. Learning it as four conditions rather than as a story is what makes it usable.

The key ideas
  1. Variation: individuals within a population differ from one another.
  2. Heritability: some of that variation is passed from parents to offspring, through the mechanisms of units 7 and 8.
  3. Overproduction: more offspring are produced than can survive to reproduce, given finite resources, which is the carrying capacity argument of lesson 3.3.
  4. Differential survival and reproduction: which individuals survive and reproduce is not random with respect to their variation.
  5. The conclusion follows: the heritable characteristics of individuals that reproduce more become commoner in the next generation. Repeat for many generations and the population changes.
  6. Selection acts on individuals; populations evolve. An individual does not evolve during its life, and this distinction is worth stating in every answer.

Where students lose marks: describing natural selection as something that happens to an individual. Individuals survive or die; allele frequencies in the population change. An organism cannot evolve, and writing that it did is marked wrong.

Worked example

The source. Charles Darwin, On the Origin of Species, 1859, from the chapter on natural selection. Public domain.

Owing to this struggle for life, any variation, however slight and from whatever cause proceeding, if it be in any degree profitable to an individual of any species, in its infinitely complex relations to other organic beings and to external nature, will tend to the preservation of that individual, and will generally be inherited by its offspring.

Step one: find the four conditions inside the sentence. Variation is named directly. Heritability appears as "will generally be inherited by its offspring". The struggle for life implies overproduction. Profitability implies differential survival.

Step two: note the phrase "from whatever cause proceeding". Darwin did not know where variation came from, having no knowledge of genes or mutation, and he says so. The argument works without that knowledge, which is why it survived the arrival of genetics intact.

Step three: note what he does not claim. He does not say the variation arose because it was useful. It exists first and is then preserved if it happens to be profitable, which is the subject of the next lesson.

Step four: apply the conditions to a case. A beetle population on dark bark, in which shell color varies and is heritable, produces far more offspring than the habitat supports, and birds hunting by sight take the conspicuous ones more often.

Step five: check each condition. Variation, present. Heritability, present. Overproduction, present. Differential survival related to the variation, present, because color affects the chance of being seen.

Step six: state the conclusion, and only the conclusion. Dark beetles leave more offspring, so the proportion of dark beetles rises over generations. Nothing has been said about beetles wanting to be dark, and nothing needs to be.

Step seven: test the argument by removing a condition. If shell color were not heritable, survivors could not pass it on and the population would not change. Each of the four is necessary, which is why naming all four earns the marks.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. List the four conditions for natural selection.
    Show the full solution

    Variation, heritability, overproduction, and differential survival and reproduction

  2. What evolves: an individual or a population?
    Show the full solution

    A population

  3. Where does overproduction lead, according to unit 3?
    Show the full solution

    To competition, because populations exceed what resources can support

  4. Did Darwin know the source of variation?
    Show the full solution

    No; he wrote "from whatever cause proceeding"

  5. What happens if a variation is not heritable?
    Show the full solution

    Natural selection cannot change the population, since survivors cannot pass it on

  6. Explain why all four conditions are necessary.
    Show the full solution

    Without variation every individual is equivalent, so survival cannot depend on any difference. Without heritability the survivors' advantages die with them and the next generation starts over. Without overproduction almost everyone survives and there is no differential to act on. Without differential survival related to the variation, who reproduces is effectively random and allele frequencies drift rather than adapt. Remove any one and the conclusion fails, which is why the list is a set of conditions rather than a description. Removing any one breaks the chain from variation to changed frequencies

  7. Explain why Darwin's argument survived the discovery of genetics.
    Show the full solution

    His argument requires only that variation exists and is heritable, not any particular explanation of how. Genetics supplied the mechanism he lacked, showing that variation arises through mutation and is shuffled by recombination, and that inheritance is particulate rather than blending. Far from overturning the argument, this strengthened it: blending inheritance would actually have destroyed variation each generation and undermined selection, so Mendel's results rescued a difficulty Darwin could not resolve. It assumed only that variation is heritable, and genetics supplied the mechanism

  8. A farmer breeds only from the highest-yielding wheat plants each year. Identify the four conditions.
    Show the full solution

    Variation: the plants differ in yield. Heritability: some of that difference is genetic and passes to the next generation. Overproduction: far more seed is produced than the farmer replants, so most does not contribute. Differential reproduction: which plants contribute seed is decided by yield rather than at random. All four hold, so the population changes, and the only difference from natural selection is that a farmer rather than the environment is doing the selecting. All four hold, with the farmer supplying the differential reproduction

  9. Explain why "the individual evolved to be darker" is wrong.
    Show the full solution

    An individual's genotype is fixed at fertilization and does not change over its life in response to the environment, so a light beetle cannot become dark. What changes is the proportion of dark individuals in the population across generations, as light ones are eaten more often and leave fewer offspring. Evolution is a change in allele frequencies within a population over time, so an individual is the thing selected rather than the thing that evolves, and the two must not be run together. An individual's genotype is fixed; only population frequencies change

  10. Why does Darwin's phrase "in its infinitely complex relations" matter?
    Show the full solution

    It makes clear that whether a variation is profitable depends entirely on circumstances rather than being a fixed property of the organism. A dark shell helps on dark bark and harms on pale bark; thick fur helps in cold and harms in heat. Advantage is defined relative to a particular environment, including other organisms, so there is no such thing as a generally superior variant. This is why selection produces organisms suited to conditions rather than progressively better organisms. Advantage is relative to a specific environment, not an absolute property

Lesson 10.2 · Unit 10 · HS-LS4-2, HS-LS4-3

Variation comes first: the error this lesson exists to correct

"The bacteria mutated because they needed to resist the antibiotic." That sentence is the single most common error in biology, and it is not a slip of wording. It states the causal sequence backwards, and a student who writes it has a picture of evolution that will generate wrong answers for the rest of the course.

The key ideas
  1. Mutation is random with respect to need. It arises from copying errors and chemical damage, processes with no connection to what the organism is experiencing.
  2. The variation exists before the pressure arrives, usually at low frequency, and the pressure then changes which variants survive.
  3. Organisms do not adapt during their lifetimes in a heritable way. Populations adapt across generations.
  4. The environment selects; it does not instruct. It cannot reach into a genome and produce a helpful change.
  5. Teleological language is the warning sign: "in order to", "so that", "needed to", "wanted to", "tried to". Any of these in an evolutionary explanation usually signals the error.
  6. The correct form is always the same: variation existed, something changed which variants reproduced, frequencies shifted.

Where students lose marks: writing that a species developed a feature because it needed it. Even when the rest of the answer is correct, this phrasing is usually penalized, because it describes a mechanism that does not exist.

Worked example

The case. A population of bacteria is exposed to an antibiotic. Most die; the survivors multiply and the infection returns, now untreatable by that drug. Write the explanation correctly.

Step one: write the wrong version, to see it clearly. "The bacteria were exposed to the antibiotic, so they mutated to become resistant and survived." This says exposure caused the mutation.

Step two: state why it is wrong. The antibiotic has no mechanism for altering a specific base in a specific gene in a useful direction. It kills bacteria. Nothing about being poisoned produces a helpful genetic change.

Step three: establish what existed beforehand. In any large bacterial population, random mutations have already produced a few individuals carrying a variant that happens to confer resistance, perhaps an altered protein the drug can no longer bind. They were present before any antibiotic appeared.

Step four: note that those variants had no advantage before. Resistance often carries a cost, so resistant cells may reproduce more slowly in the absence of the drug and remain rare. The variation was there without being favored.

Step five: apply the pressure. The antibiotic kills the susceptible majority. The rare resistant cells survive, not because they responded but because they already differed.

Step six: let the population recover. The survivors reproduce, and since resistance is heritable, their descendants are resistant. The population is now largely resistant, though no individual bacterium ever changed.

Step seven: state the finished explanation. "Random mutation had already produced rare resistant bacteria. The antibiotic killed the susceptible ones, so the resistant ones survived and reproduced, and the proportion of resistant bacteria in the population rose." Every clause is a fact about frequencies.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Is mutation directed toward what an organism needs?
    Show the full solution

    No; it is random with respect to need

  2. Which comes first, the variation or the selection pressure?
    Show the full solution

    The variation

  3. Name three phrases that signal the teleology error.
    Show the full solution

    Any three of: in order to, so that, needed to, wanted to, tried to

  4. Does the environment instruct or select?
    Show the full solution

    It selects

  5. Why might a resistant bacterium be rare before the antibiotic appears?
    Show the full solution

    Resistance often carries a cost, so those cells reproduce more slowly without the drug

  6. Explain why the antibiotic cannot cause the useful mutation.
    Show the full solution

    Mutations arise from errors during DNA replication and from chemical or radiation damage, and none of those processes has any means of identifying which change would help the cell survive a particular poison. An antibiotic interferes with a bacterial process in order to kill the cell; it has no mechanism for editing a specific base in a specific gene in a beneficial direction. Even mutagens that raise the overall mutation rate raise it indiscriminately, producing far more harmful changes than useful ones. No process connects a poison to a specific beneficial base change

  7. Rewrite correctly: "Giraffes stretched their necks to reach higher leaves, so their necks got longer."
    Show the full solution

    A correct version: neck length varied among ancestral giraffes and that variation was heritable. Where food was concentrated in higher branches, individuals with longer necks obtained more food, survived better and left more offspring, so the alleles associated with longer necks became commoner over many generations. The original sentence contains two errors: it treats a characteristic acquired by stretching as heritable, which lesson 8.5 rules out, and it makes the need the cause of the change. Existing heritable variation in neck length was favored, rather than stretching being inherited

  8. Why is finishing a course of antibiotics important, in these terms?
    Show the full solution

    A short course kills the most susceptible bacteria first, leaving those with partial resistance alive in a body where competition has just been removed. Those survivors then multiply freely, and the population that regrows is enriched for resistance, which is selection operating exactly as described. Completing the course aims to eliminate the partially resistant cells as well, before they can reproduce and before further mutations can add to their resistance. Stopping early leaves the most resistant cells to multiply without competition

  9. An experiment shows resistant bacteria exist in a culture never exposed to the antibiotic. Explain its significance.
    Show the full solution

    It demonstrates directly that resistance arises before exposure rather than in response to it, which is the whole question at issue. If the drug caused the mutation, a culture that had never encountered it should contain no resistant cells at all. Finding them shows that random mutation supplies the variation independently and that the antibiotic's only role is to select among variants that already exist. It is a designed test with a clear falsifying outcome, in the sense of lesson 1.1. Resistance arising without exposure shows mutation is independent of the pressure

  10. Explain why teleological language is treated so seriously rather than as a stylistic problem.
    Show the full solution

    Because it describes a mechanism that does not exist and generates wrong predictions. A student who believes organisms produce the variation they need will expect any population under pressure to adapt, and will be unable to explain why species go extinct, why the same pressure produces different outcomes in different populations, or why a population lacking a suitable allele cannot respond at all. The phrasing is the visible symptom of a model that fails on exactly the cases the subject cares about. It encodes a false mechanism that predicts adaptation is always available

Lesson 10.3 · Unit 10 · HS-LS4-3

Fitness: a word that does not mean what it sounds like

In ordinary speech fitness means health, strength or athletic ability. In biology it means one thing only: how many surviving offspring an individual produces relative to others in the population. The two meanings come apart constantly, and cases where they point in opposite directions are the ones worth studying.

The key ideas
  1. Fitness is relative reproductive success, measured by surviving offspring, not by strength, size, health or lifespan.
  2. Survival matters only because it enables reproduction. An organism that lives a long time and never reproduces has a fitness of zero.
  3. Fitness is relative to a population and an environment. The same genotype can have high fitness in one place and low fitness elsewhere.
  4. "Survival of the fittest" is a poor summary, since it is circular as usually stated and emphasizes survival over reproduction. Differential reproductive success is the accurate phrase.
  5. Traits that shorten life can raise fitness if they increase offspring number sufficiently, which is why some organisms reproduce once and die.
  6. Sexual selection acts on mating success, and can favor features that reduce survival, such as conspicuous displays, as long as the reproductive gain exceeds the cost.

Where students lose marks: defining fitness as being strong or well adapted to survive. Write "produces more surviving offspring than others in the population" and the definition is safe.

Worked example

The data. Three male birds in one population, with constructed figures chosen to separate the two meanings of the word.

MaleBody conditionLifespan (years)Surviving offspring
Aexcellent82
Baverage411
Cpoor60

Step one: rank by the everyday meaning. On health and longevity, A is clearly the best specimen: excellent condition and the longest life.

Step two: rank by the biological meaning. Count surviving offspring. B has 11, A has 2, C has none. B has by far the highest fitness.

Step three: state the result plainly. The healthiest, longest-lived male has low fitness. The bird in average condition that died young has the highest. The two rankings are almost reversed.

Step four: consider what could produce this. B may have invested heavily in display or in raising young, at a cost to its own condition and survival. That investment shortened its life and multiplied its offspring.

Step five: work out which alleles increase. Whatever heritable characteristics B carried are represented eleven times in the next generation, against twice for A and not at all for C. Selection tracks offspring, not quality.

Step six: state the consequence for the population. Over generations the population may shift toward shorter-lived birds that invest heavily in reproduction. Nothing is being improved in any general sense.

Step seven: apply the same logic to C. C survived six years, longer than B, and contributed nothing. Survival without reproduction has no evolutionary consequence whatever, which is the sharpest way to see what fitness measures.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Define biological fitness.
    Show the full solution

    The number of surviving offspring an individual produces relative to others in the population

  2. What is the fitness of an organism that lives long but never reproduces?
    Show the full solution

    Zero

  3. Why is survival relevant at all?
    Show the full solution

    Only because it enables reproduction

  4. In the worked example, which male has the highest fitness?
    Show the full solution

    B, with 11 surviving offspring

  5. What does sexual selection act on?
    Show the full solution

    Mating success

  6. Explain why "survival of the fittest" is an unsatisfactory summary.
    Show the full solution

    It emphasizes survival, which matters only as a means to reproduction, and it invites the everyday reading of fittest as strongest or healthiest. As usually stated it is also close to circular, since the fittest are identified by their survival and their survival is then explained by their fitness. Describing the process as differential reproductive success avoids all three problems, because offspring number is measurable independently of the outcome being explained. It stresses survival over reproduction, invites the wrong sense of fittest, and risks circularity

  7. Explain how a trait that shortens life can be favored.
    Show the full solution

    Selection counts offspring, not years. If a characteristic causes an organism to invest very heavily in a single large reproductive effort, it may leave far more surviving young than a cautious individual that lives twice as long and breeds modestly, and the alleles involved will therefore increase in frequency. Salmon that spawn once and die illustrate the extreme case. The cost in lifespan is simply irrelevant provided the reproductive gain exceeds it. If it raises offspring number enough, the loss of lifespan does not matter

  8. Explain how an elaborate tail that makes escape harder can still be favored.
    Show the full solution

    Such a feature reduces survival but can increase mating success enough to more than compensate. If females prefer larger displays, males carrying the alleles for them obtain more matings and leave more offspring despite a higher risk of predation, so those alleles spread. Fitness is the net outcome of all effects on reproductive success, and a survival cost is only decisive if it is not outweighed. This is sexual selection, and it explains features that look positively unhelpful. The gain in mating success outweighs the cost to survival

  9. Why is fitness described as relative rather than absolute?
    Show the full solution

    Because what matters to the composition of the next generation is how an individual's reproductive output compares with that of others in the same population. Two surviving offspring is high fitness where the average is one and low where the average is ten, so the same number means opposite things in different contexts. Fitness also depends on the environment, since a characteristic favored on dark bark is penalized on pale bark, so a genotype has no fixed fitness value at all. It is measured against the rest of the population and depends on the environment

  10. A sterile worker bee raises its mother's offspring. Explain how this can make evolutionary sense.
    Show the full solution

    Its own direct fitness is zero, since it never reproduces, but the siblings it helps raise carry many of the same alleles, having the same mother. Alleles causing an individual to help close relatives reproduce can therefore increase in frequency even when their carrier has no offspring, because copies of those alleles are being passed on through the relatives. Fitness is counted in copies of alleles reaching the next generation, and helping relatives is one route to that. Relatives carry the same alleles, so helping them raise young passes copies on

Lesson 10.4 · Unit 10 · HS-LS4-3, HS-LS4-4

Directional, stabilizing and disruptive selection

For a characteristic that varies continuously, such as body size, selection can act in three different ways, and each leaves a recognizable signature on the distribution. Identifying which pattern a described case shows is a standard question, and the answer is read directly off the shape of the curve.

The key ideas
  1. Directional selection favors one extreme, so the whole distribution shifts toward it over generations.
  2. Stabilizing selection favors the intermediate, so both extremes are removed, the mean stays put and the spread narrows.
  3. Disruptive selection favors both extremes against the intermediate, so the distribution becomes two-peaked.
  4. Stabilizing selection is the commonest, because most populations are already reasonably suited to a stable environment.
  5. Directional selection dominates after a change, such as a new predator, a new climate or a new food source.
  6. Artificial selection is directional selection applied by people, and its speed demonstrates how much change is possible when the differential is strong.

Where students lose marks: saying the mean shifts in stabilizing selection. It stays where it is; what changes is the spread, which narrows. Describing the effect on both mean and spread is what a full answer needs.

Worked example

The task. Classify four described cases, giving the effect on the mean and on the spread in each.

Step one: human birth mass. Very small babies have poorer survival, and very large ones historically caused difficult deliveries with risk to both. Intermediate mass survives best, so both extremes are removed. This is stabilizing selection: the mean stays similar and the spread narrows.

Step two: beetles on darkening bark. Pale beetles are taken by birds more often on a dark background, so dark beetles leave more offspring and the whole population shifts darker. This is directional selection: the mean moves toward one extreme.

Step three: birds on an island with only very small and very large seeds. Small beaks handle small seeds efficiently and large beaks crack large ones, while intermediate beaks do neither well. Both extremes are favored, so this is disruptive selection and the distribution becomes two-peaked.

Step four: dairy cattle bred for milk yield. Only the highest-yielding animals are bred from, so yield rises steadily across generations. This is directional selection, imposed deliberately, which makes it artificial selection.

Step five: apply the test that distinguishes them. Ask which part of the distribution is being removed. One tail means directional, both tails means stabilizing, the middle means disruptive. That one question settles every case.

Step six: note what disruptive selection can lead to. If the two favored groups also come to mate preferentially within themselves, gene flow between them falls and the population may eventually split, which is the route to speciation in unit 11.

Step seven: state why stabilizing selection is commonest. A population that has occupied an environment for a long time is already close to the best available compromise, so most departures from the mean are worse and are removed. Directional selection requires something to have changed.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Name the three patterns of selection.
    Show the full solution

    Directional, stabilizing and disruptive

  2. Which pattern shifts the mean toward one extreme?
    Show the full solution

    Directional

  3. What happens to the spread under stabilizing selection?
    Show the full solution

    It narrows, while the mean stays about the same

  4. What shape of distribution does disruptive selection produce?
    Show the full solution

    A two-peaked distribution

  5. State the test for classifying a case.
    Show the full solution

    Ask which part of the distribution is being removed: one tail, both tails, or the middle

  6. Explain why human birth mass is a case of stabilizing selection.
    Show the full solution

    Both extremes suffer higher mortality while the middle does best. Very small babies have poorer survival because they are less able to maintain temperature and are more vulnerable to infection, and very large babies historically made delivery dangerous for both mother and infant. Infants of intermediate mass therefore survived most often, removing both tails of the distribution. The mean stays roughly where it is and the spread narrows, which is exactly the stabilizing signature. Both extremes have higher mortality, so the spread narrows around an unchanged mean

  7. Explain why stabilizing selection is the commonest pattern.
    Show the full solution

    A population that has lived in an environment for many generations has already been shaped by selection toward the best available compromise for those conditions, so the current mean is close to optimal. Most individuals departing from it in either direction do slightly worse, and those departures are removed each generation. Directional selection requires something to have changed, such as a new predator or a shifting climate, and environments are stable more often than they change. Populations are usually already near the optimum for a stable environment

  8. Explain how disruptive selection can begin the formation of two species.
    Show the full solution

    It favors individuals at both extremes while removing intermediates, so the population develops two increasingly distinct groups. If members of each group also begin to mate preferentially with others like themselves, perhaps because they feed in different places or breed at different times, gene flow between the groups falls. With reduced interbreeding the two groups accumulate further genetic differences independently, and if the separation becomes complete they may eventually be unable to interbreed at all. It splits the population into two groups, and reduced gene flow lets them diverge

  9. Artificial selection produces change very quickly. Explain why.
    Show the full solution

    Because the selection differential is far stronger and more consistent than anything natural conditions usually impose. A breeder may allow only the most extreme few percent of individuals to reproduce, and applies that same criterion every generation without interruption, whereas natural selection typically acts weakly, inconsistently, and on many characteristics at once that trade off against each other. Concentrating intense selection on a single trait produces rapid change, and the variety of dog breeds shows how much. Breeders impose far stronger, more consistent selection on one trait

  10. A population of moths shifts from mostly pale to mostly dark within fifty years. Classify and explain.
    Show the full solution

    Directional selection, since one extreme of the existing variation is being favored and the whole distribution has moved toward it. Heritable variation in color was already present, and a change in the environment, such as darkening of the surfaces the moths rest on, made pale individuals more conspicuous to predators hunting by sight. Pale moths left fewer offspring, the proportion of dark moths rose each generation, and the population mean shifted without any individual moth changing color. Directional: an environmental change favored one existing extreme and shifted the mean

Lesson 10.5 · Unit 10 · HS-LS4-1

Evidence I: what fossils can and cannot show

The fossil record is the most direct evidence that life has changed over time, and it is also the most commonly misrepresented, in both directions. It is genuinely incomplete, and the reasons for its incompleteness are understood well enough to be predicted in advance, which turns an apparent weakness into a test.

The key ideas
  1. Fossilization requires unusual conditions: rapid burial in sediment, absence of oxygen to prevent decomposition, and hard parts in most cases.
  2. The record is therefore biased, heavily favoring marine organisms, hard-shelled animals and bones, and under-representing soft-bodied organisms and those living where sediment does not accumulate.
  3. Relative dating uses the order of rock layers, with deeper layers older, which establishes sequence without giving ages.
  4. Absolute dating uses radioactive decay, which gives numerical ages and allows rates of change to be estimated.
  5. Transitional forms exist and are predicted, showing combinations of features found in different later groups.
  6. Gaps are expected rather than embarrassing, because the conditions for fossilization are rare. The strong evidence is the consistent order in which forms appear.

Where students lose marks: describing a transitional fossil as "half one animal and half another". It is an organism in its own right showing a mixture of features, and it is not an ancestor of anything in particular unless there is specific evidence for that.

Worked example

The argument. Why is the order of appearance stronger evidence than any single fossil?

Step one: state what the record shows. Simple single-celled organisms appear in the oldest rocks. Fish appear before amphibians, amphibians before reptiles, and mammals and flowering plants appear relatively late.

Step two: state what this order is not. It is not a ladder of progress toward humans. Bacteria appear first and are still here and enormously successful, so the sequence records when groups originated rather than ranking them.

Step three: identify the prediction being tested. If species descend from earlier species with modification, no group can appear before the group it descends from. Mammals cannot be found beneath the first fish.

Step four: note that this is falsifiable. A single well-documented mammal fossil in rock older than the first fish would be extremely hard to reconcile with common descent. Millions of fossils have been dated and the order has held.

Step five: explain the gaps positively. Fossilization needs rapid burial without oxygen, which happens in some environments and almost never in others, so an organism living in an upland forest is far less likely to be preserved than one dying in a shallow sea. Absence of a fossil is weak evidence of absence.

Step six: use a transitional form correctly. A fossil showing feathers together with teeth and a bony tail has features later associated with birds and features associated with reptiles. It demonstrates that such combinations existed, which is what descent with modification requires.

Step seven: state the limit of this evidence honestly. Fossils show that forms changed over time and in what order. They rarely establish that one species was the direct ancestor of another, since the chance of having sampled the actual ancestral population is small. That is why the next two lessons matter.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Name two conditions required for fossilization.
    Show the full solution

    Rapid burial in sediment and absence of oxygen

  2. What is relative dating based on?
    Show the full solution

    The order of rock layers, with deeper layers older

  3. What does absolute dating use?
    Show the full solution

    Radioactive decay

  4. Which organisms are over-represented in the fossil record?
    Show the full solution

    Marine organisms and those with hard parts such as shells and bones

  5. What is a transitional form?
    Show the full solution

    An organism showing a combination of features found in different later groups

  6. Explain why the order of appearance is stronger evidence than any single fossil.
    Show the full solution

    A single fossil can always be questioned on dating, identification or context, and an individual specimen shows only that one organism existed. The order is a pattern across millions of specimens from sites all over the world, and it matches a prediction that could have failed at any time: no group appears in rocks older than the group it descends from. That the prediction has held across such an enormous and independently collected sample is far harder to explain away than any one find. It is a testable pattern across millions of specimens, not a single claim

  7. Explain why gaps in the record are expected.
    Show the full solution

    Fossilization requires a rare combination of circumstances: the organism must die where sediment accumulates rapidly, be buried before scavengers and decomposers destroy it, avoid oxygen, and then survive hundreds of millions of years of geological activity without being eroded or melted. Most organisms die in places where none of this happens. Soft-bodied organisms and those living in uplands are especially unlikely to be preserved, so absence from the record is weak evidence that something never existed. The conditions for preservation are rare and biased toward particular environments

  8. Explain why "half reptile and half bird" is a poor description of a transitional fossil.
    Show the full solution

    It suggests an incomplete or intermediate creature assembled from two modern categories, when in fact the animal was a functioning organism well suited to its own environment. The categories reptile and bird are labels applied afterward to groups defined by features that had not yet fully separated at the time the animal lived. A better description is that it shows a combination of characteristics later found in different groups, which is exactly what descent with modification predicts should have existed. It was a complete organism showing a mixture of features, not a half-formed hybrid

  9. Why does finding a fossil rarely prove direct ancestry?
    Show the full solution

    Because the fraction of organisms preserved is tiny and the fraction discovered smaller still, so the probability that any particular specimen belonged to the actual ancestral population rather than to a related side branch is low. A fossil showing the right combination of features at the right time demonstrates that such forms existed and shows the kind of change that occurred, which is what the argument needs. Claiming a specific ancestor requires much stronger evidence and is usually avoided. Most fossils are from related branches, not the exact ancestral line

  10. What would a mammal fossil in rock older than the first fish imply?
    Show the full solution

    It would be a serious problem for common descent as currently understood, since mammals are held to descend from earlier vertebrate groups that descend in turn from fish, and nothing can precede its own ancestors. A single well-documented case would demand either a major revision of the sequence or an explanation of how the specimen came to be in that layer. The fact that such a find is possible in principle, and has not occurred despite enormous sampling, is what makes the order genuine evidence. It would contradict common descent, which is why the untroubled order is meaningful

Lesson 10.6 · Unit 10 · HS-LS4-1

Evidence II: homology, vestigial structures and embryos

The most persuasive anatomical evidence is not similarity between organisms doing the same job. It is similarity between organisms doing quite different jobs, where there is no functional reason for the resemblance and inheritance is the only remaining explanation.

The key ideas
  1. Homologous structures share underlying structure and origin but may perform different functions. They indicate common ancestry.
  2. Analogous structures share a function but not underlying structure or origin. They indicate similar selective pressures, not relatedness.
  3. The pentadactyl limb is the standard example: the same arrangement of bones appears in a human arm, a whale flipper, a bat wing and a horse leg, despite doing entirely different things.
  4. Convergent evolution produces analogy. A bird wing and an insect wing both achieve flight with completely different internal structure.
  5. Vestigial structures are reduced remnants with little or no current function, such as the pelvic bones of whales.
  6. Shared embryonic features appear in the early development of related groups even when the adults differ greatly.

Where students lose marks: confusing homologous and analogous, which is the single commonest category error in this unit. Ask about underlying structure and origin, never about what the structure is used for. Same job is not evidence of relatedness.

Worked example

The task. Classify four comparisons, applying the structure test rather than the function test.

ComparisonFunctionUnderlying structureType
Human arm and bat wingdifferentsame bone arrangementhomologous
Bird wing and insect wingsamecompletely differentanalogous
Whale flipper and horse legdifferentsame bone arrangementhomologous
Shark and dolphin body shapesamedifferent, one fish one mammalanalogous

Step one: apply the test to the human arm and bat wing. One manipulates objects and the other flies, so the functions are unrelated. Both contain one upper bone, two lower bones, a cluster of wrist bones and five digits. Same structure, different function: homologous.

Step two: explain why that is the strong case. If the bat wing had been built from scratch for flight, there would be no reason to use exactly the bone arrangement found in a digging, walking or grasping limb. Inheritance from a common ancestor explains the constraint; design for the job does not.

Step three: apply the test to the two wings. Both fly, so the function is identical. A bird wing contains bone, muscle and feathers; an insect wing is a thin extension of the exoskeleton with no bones at all. Same function, different structure: analogous.

Step four: state what analogy shows. That similar selective pressures produce similar solutions in unrelated lineages, which is convergent evolution. It is evidence about the pressure, not about ancestry.

Step five: bring in vestigial structures. Whales have small pelvic bones embedded in the body wall, unconnected to any limb. They are hard to explain in an animal designed for swimming and straightforward in a mammal descended from four-legged ancestors.

Step six: bring in embryology. Vertebrate embryos, including humans, show structures such as pharyngeal arches and a tail early in development, which are modified or lost later. Shared development reflects shared inherited programs.

Step seven: state the logic that runs through all three. Each is a feature that functional design would not predict and inheritance does. That is why they count as evidence rather than as description.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Define homologous structures.
    Show the full solution

    Structures sharing underlying structure and origin, though possibly with different functions

  2. Define analogous structures.
    Show the full solution

    Structures sharing a function but not underlying structure or origin

  3. Which type indicates common ancestry?
    Show the full solution

    Homologous

  4. Give an example of a vestigial structure.
    Show the full solution

    The pelvic bones of whales

  5. What does convergent evolution produce?
    Show the full solution

    Analogous structures, from similar selective pressures on unrelated lineages

  6. Explain why homologous structures with different functions are stronger evidence than similar structures doing the same job.
    Show the full solution

    When two organisms do the same job, similarity might simply reflect the best solution to that problem, so it could arise independently and says little about relatedness. When the jobs are entirely different, as with a bat wing and a human arm, there is no functional reason for the same bone arrangement to appear in both, and design for the task would predict different structures. Inheritance from a shared ancestor that already had that arrangement is the remaining explanation. Different functions rule out the possibility that the similarity is required by the job

  7. A dolphin and a shark have similar body shapes. Explain what this does and does not show.
    Show the full solution

    It shows that fast swimming in open water imposes strong constraints, so a streamlined shape with fins is favored in any lineage occupying that role. It does not show close relatedness, because the underlying structures differ fundamentally: a dolphin is a mammal that breathes air, bears live young and has the bone arrangement of a four-limbed ancestor in its flippers, while a shark is a fish with a cartilaginous skeleton. This is analogy produced by convergent evolution. Shared selective pressure, not shared ancestry: the structures differ

  8. Why are vestigial structures difficult to explain without common descent?
    Show the full solution

    They are features that cost something to build and maintain while serving little or no current purpose, which is what an organism designed for its present way of life would not have. Pelvic bones in a whale, unconnected to any limb, make sense as a reduced remnant inherited from four-legged ancestors and progressively lost as the lineage returned to water. Their presence is predicted by descent with modification, which can only modify what is already there, and is otherwise puzzling. They are useless leftovers that descent predicts and design does not

  9. What does shared early embryonic development suggest?
    Show the full solution

    That related groups inherit not only adult structures but the developmental programs that build them. Vertebrate embryos pass through stages showing features such as pharyngeal arches and a tail even in species whose adults have neither, because the early stages of a shared program are harder to modify than the later ones without disrupting everything downstream. The resemblance is therefore a trace of common ancestry preserved in development rather than in the finished animal. Related groups inherit shared developmental programs, whose early stages resist change

  10. A student says a bird wing and a bat wing are analogous because both fly. Correct them.
    Show the full solution

    The function is indeed the same, but classification depends on underlying structure and origin rather than on use. Both wings contain the same basic vertebrate limb arrangement of one upper bone, two lower bones, wrist bones and digits, inherited from a common four-limbed ancestor, and they differ only in how that framework has been modified, with feathers in the bird and a membrane stretched between elongated fingers in the bat. They are therefore homologous structures that happen also to share a function. Both share the vertebrate limb arrangement, so they are homologous despite the shared function

Lesson 10.7 · Unit 10 · HS-LS4-1

Evidence III: molecules, and why independent agreement matters

The molecular evidence arrived a century after Darwin, from a field he could not have imagined, and it could have contradicted everything. Instead it produced the same family tree that anatomists had built from bones. That agreement, between methods with nothing in common, is the strongest part of the argument.

The key ideas
  1. The genetic code is essentially universal, reading the same in bacteria, plants, fungi and animals, which points to a single origin.
  2. Some proteins are found across enormous ranges of organisms, and their sequences can be compared directly.
  3. The number of differences tracks relatedness. Closely related species differ in few positions; distantly related ones differ in many.
  4. DNA comparison works the same way and is more sensitive, since it detects changes that do not alter the protein.
  5. The molecular tree matches the anatomical tree, built independently from fossils and structures long before sequencing existed.
  6. Independent agreement is what carries the weight. Two methods with unrelated assumptions and unrelated sources of error reaching the same conclusion is far stronger than either alone.

Where students lose marks: treating molecular evidence as merely another example. Its force comes from being independent of the anatomical evidence, so it could have disagreed and did not. Say that explicitly and the point lands.

Worked example

The data. Number of amino acid differences from the human version of cytochrome c, a protein used in the electron transport chain of lesson 6.6 and found in almost all organisms that respire aerobically.

OrganismChimpanzeeRhesus monkeyHorseChickenTunaYeast
Differences from human0112132145

Step one: describe the pattern before explaining it. The number of differences rises steadily from chimpanzee through monkey, horse and chicken to tuna and yeast.

Step two: compare with the anatomical ranking. Anatomy places chimpanzees closest to humans, then other primates, then other mammals, then birds, then fish, with yeast far outside the animals altogether. The two orders are the same.

Step three: state why that agreement is significant. Bone structure and amino acid sequence have no common source of error. A mistake in reading a skeleton has no reason to produce a matching mistake in a protein sequence, so agreement between them is not a coincidence that can be waved away.

Step four: note what the zero means. Human and chimpanzee cytochrome c are identical, so this protein cannot distinguish them. A protein that changes slowly is useful for comparing distant relatives and useless for close ones.

Step five: draw the methodological point. Choose a fast-changing sequence for closely related species and a slow-changing one for distant comparisons. Using the wrong molecule gives no resolution rather than a wrong answer.

Step six: explain why cytochrome c changes slowly. It performs an essential job in respiration, so most changes to it are harmful and are removed by selection. Its conservation across yeast and humans is itself evidence that the respiratory machinery of lesson 6.6 is ancient and shared.

Step seven: state the overall argument. Fossils show change over time in a consistent order. Anatomy shows shared structure where function does not require it. Molecules show a pattern of difference matching both. Three independent lines converging is the argument, and no one of them carries it alone.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What does the near-universality of the genetic code suggest?
    Show the full solution

    A single common origin for life

  2. How does the number of sequence differences relate to relatedness?
    Show the full solution

    More closely related species have fewer differences

  3. From the table, which organism differs most from humans?
    Show the full solution

    Yeast, with 45 differences

  4. Why is DNA comparison more sensitive than protein comparison?
    Show the full solution

    It detects changes that do not alter the amino acid sequence

  5. What makes molecular evidence powerful alongside anatomical evidence?
    Show the full solution

    It is independent, so it could have disagreed and did not

  6. Explain why independent agreement between two methods is stronger than either alone.
    Show the full solution

    Each method has its own assumptions and its own possible errors, and those are unrelated between anatomy and molecular sequencing. A mistaken interpretation of a skeleton has no reason to produce a matching mistake in an amino acid sequence, so an alternative explanation would have to account for both patterns separately while denying the conclusion they share. That is far harder than questioning one method. Convergence of unrelated approaches is the general structure of strong evidence in science. Unrelated methods have unrelated errors, so agreement is hard to explain away

  7. Human and chimpanzee cytochrome c are identical. Does this mean the species are identical? Explain.
    Show the full solution

    No. It means this particular protein has not accumulated any differences between the two lineages since they diverged, which is expected for a slowly changing protein over a relatively short period. The species differ at a great many other positions in their genomes, and comparisons using faster-changing sequences reveal those differences clearly. The result is a statement about the resolution of one molecule, not about overall similarity. Only that this slowly changing protein has not diverged; other sequences have

  8. Explain why cytochrome c changes so slowly over evolutionary time.
    Show the full solution

    It has an essential role in the electron transport chain, which supplies most of a cell's ATP, and its function depends on a precise structure. Most mutations altering it therefore impair respiration and are strongly selected against, so they do not persist in populations. Only the rare changes that leave function intact accumulate. Proteins under weaker constraint, or regions of DNA that do not code for anything, change much faster because harmful variants are not removed as efficiently. Strong selection removes most changes to an essential protein

  9. Which molecule would you choose to compare two closely related species, and why?
    Show the full solution

    A fast-changing sequence, such as a region of DNA that does not code for a protein or a gene under weak selective constraint. Closely related species have had little time since diverging, so a slowly changing protein like cytochrome c may show no differences at all and provide no resolution, as the human and chimpanzee result illustrates. A sequence that accumulates changes quickly will have registered enough differences in that short interval to allow a meaningful comparison. A fast-changing sequence, since a conserved one may show no differences at all

  10. Summarize the three lines of evidence and state what each contributes.
    Show the full solution

    Fossils show that life has changed over time and establish the order in which groups appeared, which no other evidence can supply directly. Comparative anatomy shows shared underlying structure where the function does not require it, along with vestigial features and shared embryonic development, pointing to inheritance rather than independent design. Molecular comparison shows a pattern of sequence differences matching relatedness, and does so independently of the other two. The argument rests on their convergence rather than on any one. Fossils give the sequence, anatomy gives unnecessary shared structure, molecules confirm it independently

Unit 10 review · Evolution, Mechanism and Evidence

Ten questions across the whole unit

Questions 1 to 5 check that you hold the terms. Questions 6 to 10 require you to reason across the seven lessons.

  1. List the four conditions for natural selection.
    Show the full solution

    Variation, heritability, overproduction, and differential survival and reproduction

  2. Define biological fitness.
    Show the full solution

    The number of surviving offspring produced relative to others in the population

  3. Name the three patterns of selection and what each does to the distribution.
    Show the full solution

    Directional shifts the mean; stabilizing narrows the spread; disruptive produces two peaks

  4. Distinguish homologous from analogous structures.
    Show the full solution

    Homologous share underlying structure and origin; analogous share only a function

  5. Name the three independent lines of evidence for evolution.
    Show the full solution

    The fossil record, comparative anatomy and development, and molecular sequence comparison

  6. Rewrite correctly: "The bacteria mutated because they needed to resist the antibiotic."
    Show the full solution

    A correct version: random mutation had already produced rare resistant bacteria before the antibiotic was used. The antibiotic killed the susceptible majority, so the resistant individuals survived and reproduced, and the proportion of resistant bacteria in the population rose. The original sentence reverses the causal sequence, treating exposure as the cause of the mutation, when no process connects a poison to a specific beneficial base change. Variation existed first; the antibiotic only selected among it

  7. Explain why a healthy long-lived organism can have lower fitness than a sickly short-lived one.
    Show the full solution

    Fitness counts surviving offspring, not condition or lifespan. An organism that invests heavily in a single large reproductive effort may leave far more surviving young than a cautious individual that lives twice as long and breeds modestly, and the alleles involved will increase in frequency accordingly. An organism that lives a long time and never reproduces has a fitness of zero, which is the sharpest illustration of what the term measures. Fitness counts offspring, so investment in reproduction can outweigh longevity

  8. Explain why homologous structures with different functions are stronger evidence than structures doing the same job.
    Show the full solution

    When two organisms do the same job, similarity might simply reflect the best solution to that problem and could arise independently, so it says little about relatedness. When the jobs are entirely different, as with a bat wing and a human arm, there is no functional reason for the same bone arrangement to appear in both, and design for the task would predict different structures. Inheritance from a shared ancestor that already had that arrangement is the remaining explanation. Different functions rule out the possibility that the job required the similarity

  9. Explain why the order of appearance in the fossil record is stronger evidence than any single fossil.
    Show the full solution

    A single fossil can be questioned on dating, identification or context, and shows only that one organism existed. The order is a pattern across millions of specimens collected independently worldwide, and it matches a prediction that could have failed at any time: no group appears in rocks older than the group it descends from. That the prediction has held across so vast a sample is far harder to explain away than any one find. It is a testable pattern across millions of specimens, not a single claim

  10. Explain why molecular evidence agreeing with anatomical evidence matters so much.
    Show the full solution

    The two methods have unrelated assumptions and unrelated sources of error: a mistaken reading of a skeleton has no reason to produce a matching mistake in an amino acid sequence. Molecular data arrived a century after the anatomical trees were built and could have contradicted them entirely. That it produced the same branching pattern means any alternative explanation must account for both independently, which is far harder than questioning either alone. Unrelated methods with unrelated errors agreeing is very hard to explain away

Lesson 11.1 · Unit 11 · HS-LS4-5

What a species is, and why the definition is awkward

Everyone can tell a horse from a dog, so defining species sounds like it should be easy. It is not, and the difficulty is not a failure of biologists. Species are populations caught in the middle of a continuous process, and any sharp line drawn through a continuous process will have cases it handles badly.

The key ideas
  1. The biological species concept: a species is a group of populations whose members can interbreed and produce fertile offspring, and which do not do so with other such groups.
  2. Fertile is the crucial word. A horse and a donkey produce a mule, which is almost always sterile, so they remain separate species.
  3. It fails for asexual organisms. Bacteria do not interbreed at all, so the test cannot be applied, and other criteria based on sequence similarity are used instead.
  4. It fails for fossils, since no breeding test is possible, so fossil species are defined by structure.
  5. Ring species show the boundary problem directly: neighboring populations around a ring interbreed, but the two ends meet and do not.
  6. The definition is a tool, not a fact of nature. Its awkward cases are exactly what a gradual process of divergence predicts, so they support the underlying model rather than undermining it.

Where students lose marks: defining a species as organisms that can interbreed, omitting fertile offspring. Lions and tigers can produce offspring; those offspring are generally sterile, so the two remain distinct species and the omission makes the definition wrong.

Worked example

The task. Apply the biological species concept to four cases and note where it succeeds and where it strains.

Step one: two populations of deer that interbreed freely where their ranges overlap. Gene flow is continuous, so they are one species. The concept applies cleanly and gives the intuitive answer.

Step two: horses and donkeys. They interbreed and produce mules, so the first half of the test is satisfied. Mules are almost always sterile, so no genes flow from one population into the other across generations. Two species, and the word fertile is what decides it.

Step three: a bacterium. It reproduces by dividing, so there is no interbreeding to test. The concept cannot be applied at all, and biologists use sequence similarity thresholds instead, which is a different kind of definition entirely.

Step four: a fossil. Breeding cannot be observed, so fossil species are distinguished by structure. This means fossil species and living species are identified by different criteria, which is a real inconsistency to be aware of.

Step five: the ring species case. Imagine populations spread around a mountain range. Each neighboring pair interbreeds, so by the test each pair is one species. Where the two ends of the ring meet, those populations do not interbreed, so by the same test they are different species.

Step six: state why that is not a contradiction in nature. Divergence is gradual, so there is no moment at which two populations abruptly become separate species. A ring species is that gradual continuum laid out in space, letting us see the whole process at once.

Step seven: apply lesson 1.6. The species concept is a model. It is judged by whether it is useful for its purpose, and for sexually reproducing living organisms it captures exactly the boundary that matters, which is whether genes are being exchanged.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. State the biological species concept.
    Show the full solution

    Populations whose members can interbreed and produce fertile offspring, and which do not do so with other groups

  2. Why are horses and donkeys different species?
    Show the full solution

    Their offspring, mules, are almost always sterile, so no genes flow between the populations

  3. Why can the concept not be applied to bacteria?
    Show the full solution

    They reproduce asexually, so there is no interbreeding to test

  4. How are fossil species distinguished?
    Show the full solution

    By structure, since breeding cannot be observed

  5. What is a ring species?
    Show the full solution

    A chain of populations in which neighbors interbreed but the two ends do not

  6. Explain why omitting the word fertile makes the definition wrong.
    Show the full solution

    The purpose of the definition is to identify groups between which genes are actually exchanged across generations, and sterile offspring transmit nothing. A lion and a tiger can produce a liger, and a horse and a donkey a mule, so a definition requiring only that offspring be produced would merge species that remain genetically separate and evolve independently. Fertility is what makes the offspring a bridge between the two gene pools rather than a dead end. Sterile offspring transmit no genes, so the populations stay separate

  7. Explain why the awkward cases support rather than undermine evolutionary theory.
    Show the full solution

    If species had been created separately and independently, sharp unambiguous boundaries would be expected everywhere and intermediate cases would be puzzling. Descent with gradual divergence predicts the opposite: populations separate slowly, so at any moment some pairs will be partway through the process and impossible to classify cleanly. Ring species, hybrids of varying fertility and populations that interbreed occasionally are exactly what a continuous process should produce, so the difficulty is evidence for the model. Gradual divergence predicts intermediate cases; separate creation would not

  8. Two populations are separated by a mountain range and never meet. Are they one species? Explain the difficulty.
    Show the full solution

    The test cannot be applied directly, because they have no opportunity to interbreed and the concept asks what would happen if they did. Biologists sometimes bring individuals together in captivity, but behavior in an artificial setting may not predict what would happen in the wild, where mate choice and timing matter. The honest answer is that the question is undecidable on current evidence, which is common for geographically separated populations. They cannot be tested, and captive breeding may not predict natural behavior

  9. Why is defining species by physical appearance unreliable?
    Show the full solution

    Appearance varies within a species, sometimes dramatically between the sexes or across a geographic range, so two members of one species can look less alike than members of different species. Conversely, some genuinely separate species are almost identical in appearance and are distinguished only by behavior, call or genetics. Convergent evolution can also make unrelated organisms resemble each other closely, as lesson 10.6 showed, so appearance tracks neither ancestry nor gene flow reliably. Appearance varies within species and converges between them

  10. Explain why a definition can be useful without handling every case.
    Show the full solution

    Because a definition is a tool built for a purpose, and lesson 1.6 established that models are judged by usefulness within a stated domain rather than by universal applicability. The biological species concept captures precisely the boundary that governs evolution in sexually reproducing organisms, namely whether gene flow occurs, and for those organisms it is the right tool. Knowing where it fails and which alternative to use there is part of using it competently rather than a reason to abandon it. Models are judged by usefulness in a stated domain, not universal coverage

Lesson 11.2 · Unit 11 · HS-LS4-5

Reproductive isolation: the barriers that keep species apart

If two populations exchange genes, selection and drift cannot pull them apart, because every difference that arises is shared out again. Speciation therefore requires something to stop gene flow, and the barriers that do it fall into two groups separated by a single event: fertilization.

The key ideas
  1. Gene flow is the movement of alleles between populations through interbreeding. It keeps populations genetically similar and prevents divergence.
  2. Prezygotic barriers act before fertilization, preventing a zygote from forming at all.
  3. The main prezygotic types: geographic, temporal (breeding at different times), behavioral (different courtship), mechanical (incompatible anatomy) and gametic (gametes fail to fuse).
  4. Postzygotic barriers act after fertilization, so a zygote forms but the genes still do not spread.
  5. The main postzygotic types: the hybrid fails to develop, the hybrid is sterile like a mule, or the hybrid is viable but its own offspring are weak.
  6. Prezygotic barriers are less costly because no gametes or parental effort are wasted, so selection tends to strengthen them where hybrids do badly.

Where students lose marks: classifying by whether the organisms mate, rather than by whether a zygote forms. Gametic isolation, where sperm cannot fertilize the egg, happens after mating but before fertilization, so it is prezygotic.

Worked example

The task. Classify six described barriers, applying the fertilization test to each.

BarrierZygote formed?Type
Two frog species breed in different monthsnoprezygotic, temporal
Two bird species have different courtship songsnoprezygotic, behavioral
Sperm cannot penetrate the egg of the other speciesnoprezygotic, gametic
The hybrid embryo dies early in developmentyespostzygotic
The hybrid is healthy but sterileyespostzygotic
Populations live on separate islandsnoprezygotic, geographic

Step one: apply the single test. Ask only whether a zygote is formed. Everything before that point is prezygotic; everything after is postzygotic.

Step two: work the trickiest case. Gametic isolation involves mating, which makes it feel late in the process, but no zygote results because the sperm never fertilizes the egg. Prezygotic, and this is the one most often misclassified.

Step three: work the sterile hybrid. A mule is a living animal, so a zygote certainly formed and developed. Postzygotic, because the barrier operates on the hybrid's own reproduction rather than on its creation.

Step four: explain why prezygotic barriers are favored. Producing a hybrid that dies or cannot breed wastes gametes, energy and often a whole breeding season. An individual that avoids mating with the other population loses nothing, so selection favors alleles causing that avoidance.

Step five: follow the consequence. Where two diverging populations overlap and hybrids do badly, differences in courtship or breeding time tend to become exaggerated over generations, strengthening the barrier.

Step six: note the effect on gene flow. Every one of these barriers reduces the exchange of alleles between the populations, which is the condition divergence requires.

Step seven: state the connection to the next lesson. Isolation is the requirement; speciation is what happens next, as the separated populations accumulate differences independently through selection and drift.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What is gene flow, and what does it do to two populations?
    Show the full solution

    Movement of alleles between populations through interbreeding; it keeps them genetically similar

  2. What distinguishes prezygotic from postzygotic barriers?
    Show the full solution

    Whether a zygote is formed

  3. Name three prezygotic barriers.
    Show the full solution

    Any three of geographic, temporal, behavioral, mechanical and gametic

  4. Give two postzygotic barriers.
    Show the full solution

    The hybrid fails to develop, or the hybrid is sterile

  5. Is gametic isolation prezygotic or postzygotic?
    Show the full solution

    Prezygotic, since no zygote forms

  6. Explain why gene flow prevents two populations from diverging.
    Show the full solution

    Divergence requires each population to accumulate its own genetic changes, and interbreeding distributes any new allele arising in one population into the other. The two gene pools are effectively mixed each generation, so differences are averaged out as fast as they appear and neither population can develop a distinct genetic character. Even a low rate of exchange is enough to hold populations together, which is why some barrier to gene flow is the necessary first step in speciation. Interbreeding redistributes new alleles, averaging out differences as they arise

  7. Explain why selection tends to strengthen prezygotic barriers where hybrids do badly.
    Show the full solution

    An individual that mates across the boundary and produces a sterile or short-lived hybrid has expended gametes, energy and often an entire breeding season for no surviving offspring, so its fitness is reduced. Any heritable tendency to avoid such mating, through preference for a particular song, appearance or breeding time, therefore leaves more surviving offspring and spreads. Over generations the populations become increasingly distinct in courtship or timing, which reinforces the separation. Wasted reproductive effort selects for alleles causing avoidance before mating

  8. Two plant species flower two months apart. Classify the barrier and explain its effect.
    Show the full solution

    Temporal isolation, which is prezygotic, because pollen from one species is not being produced when the other is receptive, so fertilization cannot occur and no zygote forms. The effect is complete separation of the gene pools without any physical or behavioral difference being necessary, and it can arise from a small shift in response to temperature or day length. Since nothing is wasted, it is also a cheap barrier in the sense of the previous question. Prezygotic temporal isolation: they are never fertile at the same time

  9. Why is a sterile hybrid still an effective barrier even though it is alive and healthy?
    Show the full solution

    Because the function of a barrier is to stop alleles moving between populations, not to stop organisms being produced. A mule is a living animal but it leaves no offspring, so no gene from the horse population reaches the donkey population through it and the two gene pools remain entirely separate across generations. The hybrid is a dead end for inheritance, which is exactly what isolation requires, whatever its own health. It leaves no offspring, so no alleles cross between the populations

  10. Why is geographic isolation usually the starting point for speciation?
    Show the full solution

    Because it stops gene flow completely and immediately without requiring any prior genetic difference between the populations. Other barriers, such as differences in courtship or breeding time, must themselves evolve, and they cannot readily do so while interbreeding is still mixing the populations. A physical separation caused by a river, a mountain range or a new island removes gene flow first, allowing selection and drift to act independently on each side and produce the differences that may later become barriers in their own right. It halts gene flow immediately without needing a genetic difference first

Lesson 11.3 · Unit 11 · HS-LS4-5

Two routes to a new species

Speciation happens either with a physical barrier or without one, and the two cases are treated separately because the second is much harder to explain. Dividing a population with a mountain range is easy to imagine. Splitting one that continues to live in the same place requires something more specific.

The key ideas
  1. Allopatric speciation involves geographic separation. A physical barrier divides a population and the two parts diverge independently.
  2. The sequence is: separation, then independent divergence, then reproductive isolation. Different selection pressures and independent drift act on each side.
  3. The test comes if they meet again. If the populations can still interbreed, they are one species; if not, speciation is complete.
  4. Sympatric speciation happens without geographic separation, so some other barrier must arise within a single area.
  5. Polyploidy is the clearest sympatric mechanism, and it is common in plants. An error in cell division doubles the chromosome number, and the new form cannot breed with the original.
  6. Allopatric speciation is thought to be far commoner in animals, because gene flow within a single area is difficult to interrupt.

Where students lose marks: writing that populations separate "in order to" become new species, or that isolation causes the differences. Isolation permits divergence; mutation, selection and drift produce it. The barrier removes an obstacle rather than doing the work.

Worked example

Part one: allopatric speciation. A river changes course and divides a population of ground-dwelling beetles.

Step one: gene flow stops. The beetles cannot cross, so alleles arising on one bank no longer reach the other. This is the necessary condition from lesson 11.2.

Step two: the two environments differ. One bank is shaded woodland and the other open grassland, so selection favors different colors, sizes and behaviors on each side.

Step three: drift acts independently. Even where selection is similar, chance changes in allele frequency accumulate separately in the two populations, which lesson 11.4 develops.

Step four: differences accumulate. Over many generations the populations diverge in appearance, in the timing of breeding and in courtship behavior. None of this is aimed at producing a new species.

Step five: the river shifts back and they meet. If they still interbreed and produce fertile offspring, they remain one species and gene flow resumes. If courtship differences now prevent mating, or hybrids are sterile, speciation has occurred.

Part two: sympatric speciation by polyploidy.

Step six: the error occurs. A failure of chromosome separation during cell division, as in lesson 8.6, produces a plant with four sets of chromosomes instead of two.

Step seven: isolation is immediate. Crossing the four-set plant with a normal two-set plant gives offspring with three sets, which cannot pair their chromosomes evenly in meiosis and are sterile. The new plant can self-pollinate or breed with others like itself, so it is reproductively isolated in a single generation, in the same place, with no barrier at all.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Define allopatric speciation.
    Show the full solution

    Speciation following geographic separation of populations

  2. Give the three-step sequence of allopatric speciation.
    Show the full solution

    Separation, independent divergence, then reproductive isolation

  3. Define sympatric speciation.
    Show the full solution

    Speciation without geographic separation

  4. What is polyploidy?
    Show the full solution

    Having more than two complete sets of chromosomes

  5. Why is a three-set plant sterile?
    Show the full solution

    Its chromosomes cannot pair evenly during meiosis

  6. Explain why sympatric speciation is harder to achieve than allopatric.
    Show the full solution

    Populations living in the same area continue to encounter each other, so gene flow persists and continually mixes any differences that begin to appear. A barrier must therefore arise from within the population itself while interbreeding is still possible, which is a much more demanding requirement than having a river or mountain range imposed from outside. Polyploidy works because it creates complete isolation in a single generation rather than requiring gradual divergence against ongoing gene flow. Gene flow continues, so a barrier must arise despite ongoing interbreeding

  7. Explain why "the populations separated in order to become new species" is wrong.
    Show the full solution

    Rivers change course, sea levels rise and populations disperse for reasons that have nothing to do with the genetic consequences. Separation is an accident of geology or chance, and the populations have no goal and no way of pursuing one. What follows is that mutation, selection and drift act independently on each side, and differences accumulate as a result. Speciation is an outcome of that process, not its purpose, and the phrasing is the teleology error of lesson 10.2. Separation happens for physical reasons; speciation is a consequence, not a goal

  8. Two separated populations meet again and interbreed freely. What does this show?
    Show the full solution

    That speciation did not occur during the separation, so they remain a single species. Differences may well have accumulated in appearance or behavior, but not enough to prevent successful interbreeding, and now that they have met again gene flow will resume and those differences will begin to be averaged out. The episode shows that isolation permits divergence without guaranteeing it, and that the outcome depends on how long the separation lasted and how different the selection pressures were. They are still one species: isolation permits divergence but does not guarantee it

  9. Explain how polyploidy produces a new species in one generation.
    Show the full solution

    A failure of chromosome separation during cell division gives a plant four complete sets of chromosomes instead of two. Crossed with an ordinary two-set plant, it produces offspring with three sets, and an odd number cannot be divided evenly into pairs during meiosis, so those offspring are sterile. The four-set plant can still reproduce with others like itself or by self-pollination, so it is reproductively isolated from the parent population immediately, in the same location, without any geographic barrier. Odd-numbered hybrids are sterile, so the doubled plant is isolated at once

  10. Why is polyploidy common in plants but rare in animals?
    Show the full solution

    Many plants can self-pollinate, so a single polyploid individual can reproduce without needing to find another of its kind, which would otherwise be an insurmountable obstacle for a brand new chromosome number. Plants also tolerate extra chromosome sets relatively well and can propagate vegetatively while a population builds up. Most animals must find a mate, cannot self-fertilize, and have sex determination systems that are disrupted by changes in chromosome number, so a polyploid animal usually has no viable route to reproduce. Plants can self-pollinate and tolerate extra sets; animals must find a mate

Lesson 11.4 · Unit 11 · HS-LS4-3, HS-LS4-5

Genetic drift: change without selection

Not every change in a population is an adaptation. Allele frequencies also shift by chance, because the individuals that happen to reproduce are a sample of the population and samples are not perfectly representative. In small populations this sampling effect can overwhelm selection entirely.

The key ideas
  1. Genetic drift is change in allele frequency due to chance, arising because which individuals reproduce is partly random.
  2. It is a sampling effect, so its strength depends on population size: large samples are representative, small ones are not.
  3. Drift is powerful in small populations and negligible in very large ones, which is the reverse of an intuition many students have.
  4. A bottleneck is a sharp reduction in population size, after which the survivors carry only a fraction of the original variation.
  5. The founder effect occurs when a few individuals start a new population, so the new group's allele frequencies reflect that small sample rather than the source.
  6. Drift is not selection. It has no direction, can increase harmful alleles, and does not produce adaptation.

Where students lose marks: explaining a change in allele frequency as selection without checking whether drift could account for it. If the population is small and the allele has no obvious effect on survival or reproduction, drift is the better explanation and saying so earns credit.

Worked example

The setup. Two populations, each starting at 50 percent allele A and 50 percent allele a, with the allele having no effect on survival. Figures are constructed to make the contrast clear.

PopulationSizeFrequency of A after 1 generationAfter 10 generations
Large10,00050.3%49.8%
Small1065%100%

Step one: note that selection is absent. The allele has no effect on survival or reproduction, so any change must come from chance alone. This isolates drift.

Step two: read the large population. The frequency wanders slightly around 50 percent and returns close to it. With 10,000 individuals, random departures in one direction are largely canceled by departures in the other.

Step three: read the small population. The frequency jumps to 65 percent in one generation and reaches 100 percent within ten. Allele a has been lost entirely, and no selection was involved.

Step four: explain the difference using lesson 1.3. This is sample size. Ten individuals are a small sample of the possible gametes, so the frequency in the next generation can differ considerably from the parent generation by chance alone. Ten thousand individuals average out.

Step five: state what fixation means. Once allele A reaches 100 percent it is fixed, and a cannot return except by a new mutation or by migration from elsewhere. Drift permanently removes variation.

Step six: apply it to a bottleneck. If a population of 10,000 is reduced to 10 by a disease or a storm, the survivors carry only the alleles that happened to be in those ten. Rare alleles are almost certainly lost, whether or not they were useful.

Step seven: apply it to a founder event. If ten individuals colonize an island, the new population is built from that sample, so its allele frequencies may differ sharply from the mainland source. Any subsequent divergence has an unrepresentative starting point, which is one reason island populations are often distinctive.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Define genetic drift.
    Show the full solution

    Change in allele frequency due to chance rather than selection

  2. In which populations is drift strongest?
    Show the full solution

    Small ones

  3. What is a bottleneck?
    Show the full solution

    A sharp reduction in population size that removes much of the variation

  4. What is the founder effect?
    Show the full solution

    A new population started by a few individuals, whose allele frequencies reflect that small sample

  5. What does it mean for an allele to be fixed?
    Show the full solution

    It has reached 100 percent frequency, and the alternative is lost

  6. Explain why drift is stronger in small populations.
    Show the full solution

    Drift is a sampling effect, and the reliability of a sample depends on its size, exactly as in lesson 1.3. In a population of ten, the handful of gametes that happen to form the next generation can easily be unrepresentative, so frequencies can swing sharply in one generation. In a population of ten thousand, departures in one direction are offset by departures in the other and the overall frequency stays close to the previous value. The random element is present in both; only its relative size differs. Small samples depart from expectation; large ones average out

  7. Explain why drift cannot produce adaptation.
    Show the full solution

    Adaptation requires a consistent relationship between a characteristic and reproductive success, so that useful variants become commoner generation after generation. Drift has no such relationship: which alleles increase is determined by chance, so it is as likely to raise the frequency of a harmful allele as a useful one and has no direction at all. Over time it removes variation without improving the fit between the population and its environment, which is precisely what distinguishes it from selection. Its direction is random, so it can raise harmful alleles as readily as useful ones

  8. Why are bottlenecked populations vulnerable even after numbers recover?
    Show the full solution

    Numbers can be restored by breeding, but the genetic variation lost in the bottleneck cannot, since it can only be replaced by new mutation over very long periods. The recovered population is descended from a few survivors, so it has far fewer alleles than the original and individuals are more genetically similar. That leaves it less able to respond to a new disease or environmental change, as lesson 8.5 argued, and more likely to express harmful recessive alleles as close relatives breed. Numbers recover but lost alleles do not, leaving little variation to respond with

  9. Island populations often differ sharply from mainland ones. Give two reasons from this unit.
    Show the full solution

    First, the founder effect: the island population began from a few individuals whose allele frequencies were an unrepresentative sample of the mainland, so it started out different by chance. Second, the population is small and isolated, so drift continues to act strongly while gene flow from the mainland is absent or rare, allowing frequencies to wander freely. Different selection pressures on the island add a third cause, but the first two operate even without any difference in environment. An unrepresentative founding sample, plus continuing strong drift with no gene flow

  10. A rare allele disappears from a population of thirty. Is selection the best explanation? Explain.
    Show the full solution

    Not necessarily, and drift should be considered first. In a population of thirty, a rare allele may be carried by only one or two individuals, and if those individuals happen not to reproduce, or happen to pass on their other allele, it is lost through chance alone. Concluding selection would require evidence that the allele actually reduced survival or reproduction. Attributing every frequency change to selection is a standard error, and naming drift as a plausible alternative is what earns the mark. Drift alone can remove a rare allele from so small a population

Lesson 11.5 · Unit 11 · HS-LS4-1, HS-LS4-5

Phylogenetic trees: read the nodes, not the tips

A phylogenetic tree is a hypothesis about how groups are related, drawn from the evidence of units 10 and 11. It is also the diagram students misread most often, because the eye is drawn to the order of the labels along the top when the information is entirely in the branching points underneath.

The key ideas
  1. The tips are the groups being compared, usually living species or larger groups.
  2. A node is a branching point representing the most recent common ancestor of everything above it.
  3. Relatedness is measured by the node, not by distance along the top. Two groups are more closely related if they share a more recent common ancestor.
  4. Branches can be rotated at any node without changing the tree's meaning, exactly as a mobile can be spun. The order of the tips carries no information.
  5. Nothing on a tree evolved from anything else at a tip. Living groups share ancestors with each other; they do not descend from one another.
  6. The tree is a hypothesis supported by evidence and open to revision, and molecular data has revised many trees built from anatomy alone.

Where students lose marks: saying one modern group evolved from another modern group, or treating the rightmost tip as the most advanced. There is no direction along the top of a tree, and every tip has been evolving for exactly the same length of time.

Worked example

The tree, described in words. A node at the base splits into two branches. The left branch leads to lamprey. The right branch leads to a second node, which splits into shark and a third node. That third node splits into frog and a fourth node, which splits into lizard and mouse.

Step one: identify the tips. Lamprey, shark, frog, lizard and mouse, reading left to right. All five are living groups, so all five have been evolving for the same length of time since the base of the tree.

Step two: find the most recent common ancestor of lizard and mouse. The fourth node, which is the highest in the diagram. They share the most recent node, so they are the most closely related pair shown.

Step three: compare frog and mouse with shark and mouse. Frog and mouse meet at the third node. Shark and mouse meet at the second, which is older. So the mouse is more closely related to the frog than to the shark.

Step four: test the common misreading. Lamprey and shark sit next to each other along the top, which suggests closeness. But their most recent common ancestor is the basal node, the oldest on the tree, so they are the least closely related pair. Adjacency means nothing.

Step five: rotate a branch to prove the point. Swap lizard and mouse so the order reads lamprey, shark, frog, mouse, lizard. Every node is unchanged and every relationship is identical. The tree contains exactly the same information with a different-looking top row.

Step six: correct a descent error. It is wrong to say mice evolved from lizards. They share a common ancestor at the fourth node, which was neither a lizard nor a mouse but an extinct animal from which both lineages descend.

Step seven: connect to the evidence. A tree like this can be built from anatomy, from the fossil record or from molecular sequences. That the three approaches produce matching trees is the convergence argument of lesson 10.7.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. What does a node on a phylogenetic tree represent?
    Show the full solution

    The most recent common ancestor of everything above it

  2. How is relatedness measured on a tree?
    Show the full solution

    By how recent the shared node is, not by distance along the top

  3. In the worked example, which two groups are most closely related?
    Show the full solution

    Lizard and mouse

  4. Is the mouse more closely related to the frog or the shark?
    Show the full solution

    The frog, because they share a more recent node

  5. Does rotating a branch change the tree's meaning?
    Show the full solution

    No; the nodes and therefore the relationships are unchanged

  6. Explain why two tips being adjacent does not mean they are closely related.
    Show the full solution

    The horizontal order of tips is an arbitrary consequence of how the diagram was drawn, since any branch can be rotated at its node without altering a single relationship. Two groups can therefore end up side by side while their most recent common ancestor is the oldest node on the tree, as with lamprey and shark in the worked example. Relatedness is defined entirely by where lineages join, so the only reliable method is to trace both tips downward and find the node where they meet. Tip order is arbitrary because branches rotate freely; only nodes carry information

  7. Explain why saying "mice evolved from lizards" is wrong.
    Show the full solution

    Both are living groups at the tips of the tree, and neither descends from the other. What the tree shows is that their lineages diverged from a shared ancestor at a node, and that ancestor was an extinct animal which was neither a modern lizard nor a modern mouse. Both lineages have been changing independently ever since, for precisely the same length of time. Treating one living group as the ancestor of another is the commonest error in reading trees. They share an extinct common ancestor; neither descends from the other

  8. Why has no living group been evolving longer than any other?
    Show the full solution

    Because every living lineage traces back through an unbroken chain of ancestors to the same origin of life, so all of them have exactly the same amount of evolutionary history behind them. A bacterium alive today is not an ancient organism; it is the current end of a lineage as long as our own, and it has been subject to selection throughout. Describing some living groups as primitive confuses retaining ancestral features with having stopped evolving. All living lineages trace back to the same origin, so all have equal history

  9. A tree built from anatomy is revised after molecular data. Is this a weakness?
    Show the full solution

    No, it is the method working. A tree is a hypothesis about relationships built from the available evidence, and new evidence of a different kind can test it. Anatomy can be misled by convergent evolution, where unrelated organisms resemble each other because they face similar pressures, so molecular data sometimes reveals that a grouping based on appearance was mistaken. Revising a conclusion when better evidence arrives is what distinguishes a scientific hypothesis from a fixed classification. It is a hypothesis being tested by independent evidence, as it should be

  10. How would you find the most recent common ancestor of shark and lizard?
    Show the full solution

    Trace downward from each tip along its branches until the two paths meet, and the node where they join is the answer. Starting at lizard, move down past the node it shares with mouse and then past the node it shares with frog. Starting at shark, move down one step. The two paths meet at the second node from the base, so that node represents their most recent common ancestor, and everything above it descends from that single ancestral population. Trace both tips downward until the paths meet: the second node from the base

Lesson 11.6 · Unit 11 · HS-LS2-7, HS-LS4-6

Biodiversity: what it measures and why it matters

Biodiversity is more than a count of species, and the difference matters when decisions are being made about what to protect. A field with fifty species evenly represented is not the same as a field with fifty species where one makes up almost everything, and the measures used reflect that.

The key ideas
  1. Biodiversity has three levels: genetic diversity within a species, species diversity within an ecosystem, and ecosystem diversity across a region.
  2. Species richness is the number of species present. It is easy to measure and ignores how common each one is.
  3. Evenness describes how equally individuals are distributed among those species. A diversity index combines richness and evenness into one figure.
  4. Genetic diversity determines a species' capacity to respond to disease and environmental change, which is the argument of lessons 8.5 and 11.4.
  5. Ecosystem services are the processes ecosystems perform that people depend on: pollination, water purification, soil formation, carbon storage, flood control.
  6. Diverse ecosystems tend to be more stable, because alternative species can take over a function when one declines, which is the food web argument of lesson 2.2.

Where students lose marks: equating biodiversity with the number of species. A count ignores evenness and ignores genetic diversity entirely, so a population of ten thousand genetically near-identical individuals counts the same as a genetically varied one while being far more vulnerable.

Worked example

The data. Two meadows, each with 100 individuals across 5 species. Figures constructed to isolate evenness.

SiteSp. ASp. BSp. CSp. DSp. E
Meadow 12020202020
Meadow 2961111

Step one: compare species richness. Both meadows contain 5 species and 100 individuals, so on richness alone they are identical.

Step two: compare evenness. Meadow 1 has individuals spread equally across the five species. Meadow 2 is 96 percent one species, with four species represented by a single individual each.

Step three: state which is more diverse and why. Meadow 1. A visitor walking through meadow 2 would encounter species A almost exclusively and might never see the others, so describing them as equally diverse misrepresents both.

Step four: test them against a disturbance. A disease specific to species A removes 96 percent of meadow 2's individuals and 20 percent of meadow 1's. The same event is catastrophic in one site and absorbed in the other.

Step five: consider the four rare species. With one individual each they cannot reproduce within the site and are effectively already lost. A richness count records five species where the functioning community has one.

Step six: bring in genetic diversity. Neither figure says anything about variation within species. If meadow 1's species A population is genetically uniform, it is vulnerable in the way lesson 11.4 described, and no species count would reveal it.

Step seven: state the practical conclusion. Use richness for a quick comparison, evenness or an index when abundance matters, and a genetic measure when the question is whether a species can survive a change. Choosing the wrong measure gives a confident and misleading answer.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Name the three levels of biodiversity.
    Show the full solution

    Genetic diversity, species diversity and ecosystem diversity

  2. What is species richness?
    Show the full solution

    The number of species present

  3. What does evenness describe?
    Show the full solution

    How equally individuals are distributed among the species present

  4. Give three ecosystem services.
    Show the full solution

    Any three of pollination, water purification, soil formation, carbon storage, flood control

  5. In the worked example, which meadow is more diverse and why?
    Show the full solution

    Meadow 1, because its individuals are evenly distributed across the five species

  6. Explain why species richness alone can be misleading.
    Show the full solution

    It treats a species represented by one individual exactly as it treats one represented by thousands, so two sites with identical counts can be completely different in practice. In the worked example both meadows contain five species, but one is effectively a monoculture in which the other four cannot even reproduce. Richness also says nothing about genetic variation within species, so a count can look healthy while every population in the site is genetically uniform and vulnerable. It ignores abundance and genetic variation, so identical counts can describe very different communities

  7. Explain why a diverse ecosystem tends to be more stable.
    Show the full solution

    Where several species perform a similar role, the loss or decline of one can be compensated by others, so the ecosystem's overall functioning is buffered. This is the food web argument of lesson 2.2: alternative routes mean a disturbance causes a shift rather than a collapse. A community dominated by a single species has no such alternatives, so a disease or change affecting that species affects the whole system at once, as the worked example showed. Overlapping roles mean other species can compensate when one declines

  8. Why does genetic diversity within a species matter as much as the number of species?
    Show the full solution

    Because a species' ability to survive change depends on the variation it contains, as lesson 8.5 established: selection can only favor variants that already exist. A large population that is genetically near-uniform has no raw material to respond to a new disease or a shifting climate, so every individual is vulnerable to the same threat and the species can be lost despite its numbers. Counting species without considering variation within them therefore overstates how secure a community is. Without variation a species cannot adapt, whatever its numbers

  9. A forest is replaced by a plantation of one tree species. Discuss the effect on all three levels.
    Show the full solution

    Species diversity falls sharply, since one tree species replaces many and the animals, fungi and plants depending on the others lose their habitat. Genetic diversity usually falls too, because plantation trees are often grown from a narrow selection of stock and may be near-identical. Ecosystem diversity declines because varied habitats within the forest, such as clearings, dead wood and understorey, are replaced by a single uniform structure. The plantation may still store carbon, but most other services are reduced. All three fall: fewer species, narrower genetic stock, and uniform habitat structure

  10. Why might a conservation program protect a genetically varied small population over a uniform large one?
    Show the full solution

    Because the varied population has a future and the uniform one may not. Numbers can be rebuilt by successful breeding, but genetic variation lost cannot be restored except by mutation over very long periods, so a large uniform population is one disease or environmental shift away from collapse with nothing to respond with. The varied population contains the raw material for adaptation, which is the resource that actually cannot be replaced, and protecting it preserves options rather than numbers. Numbers can recover but lost variation cannot, so the varied population retains the capacity to adapt

Lesson 11.7 · Unit 11 · HS-LS4-5, HS-LS4-6, HS-ESS3-1, HS-ESS3-4

Extinction, a changing climate, and evaluating a solution

This final lesson connects the whole course. The carbon cycle of unit 4, the photosynthesis of unit 6, the population limits of unit 3 and the selection of unit 10 all bear on one question: what happens to living things when the conditions they are adapted to change faster than they can respond.

The key ideas
  1. Extinction is normal and continuous, and the great majority of species that have ever lived are extinct. What matters is the rate.
  2. Mass extinctions are episodes of unusually rapid loss, visible in the fossil record, each followed by long periods of recovery and diversification.
  3. The evidence for current warming is from federal datasets including the atmospheric record of lesson 4.6, alongside ocean heat content, sea level and ice extent measurements.
  4. Biological responses are already measurable: range shifts toward the poles and to higher elevations, and phenology shifts, meaning changes in the timing of seasonal events.
  5. Rate is the central biological problem. Populations can track slow change through migration or selection; the constraint is whether change outpaces those mechanisms.
  6. Mitigation reduces the cause; adaptation reduces the harm. Cutting emissions is mitigation; building flood defenses or planting heat-tolerant crops is adaptation.

Where students lose marks: treating any single measurement as proof. The argument rests on several independent lines agreeing, as in lesson 10.7, and an answer that names two or three independent measurements is stronger than one that describes a single graph in detail.

Worked example

The task. A proposal suggests planting fast-growing trees across a large area to offset national emissions. Evaluate it using the course.

Step one: state the mechanism it relies on. Photosynthesis removes carbon dioxide from the atmosphere and fixes it into wood, as lesson 6.4 established and lesson 4.2 placed in the carbon cycle. The mechanism is real.

Step two: check which cycle the carbon enters. Tree carbon is in the fast cycle. It returns to the atmosphere when the tree dies, decomposes or burns, so the storage lasts decades to centuries rather than the millions of years that fossil carbon had been out of circulation.

Step three: check the rate against the problem. Trees take decades to reach full growth and the absorption stops once a forest matures, while emissions continue annually. The measure buys time rather than resolving the imbalance of lesson 4.2.

Step four: apply unit 11. A single fast-growing species planted at scale is a monoculture, with the biodiversity consequences of lesson 11.6 at all three levels, and genetic uniformity leaves it vulnerable to a single disease.

Step five: check the land. Land used for planting is unavailable for other purposes, and planting on existing grassland or wetland can release soil carbon and destroy an established community. Where the trees go matters as much as how many.

Step six: state what would strengthen the proposal. Mixed native species rather than one; planting on degraded land rather than intact ecosystems; and treating it as a complement to emissions reduction rather than a substitute, since only mitigation addresses the unmatched flux.

Step seven: state a defensible judgment. Reforestation is a genuine but limited and temporary sink with real co-benefits for biodiversity if done well, and it cannot offset continued fossil fuel use because it moves carbon into the fast cycle rather than removing it. That is the reasoning this course has been training you to produce: mechanism, magnitude, timescale, side effects, then a judgment that names what it sets aside.

Practice · 10 questions

Questions 1 to 5 are recall. Questions 6 to 10 ask for reasoning.

  1. Is extinction normal?
    Show the full solution

    Yes; most species that have ever lived are extinct, and the rate is what matters

  2. Name two biological responses to warming already observed.
    Show the full solution

    Range shifts toward the poles or higher elevations, and changes in the timing of seasonal events

  3. Define phenology.
    Show the full solution

    The timing of seasonal biological events such as flowering or migration

  4. Distinguish mitigation from adaptation.
    Show the full solution

    Mitigation reduces the cause; adaptation reduces the harm

  5. Why is the rate of change more important biologically than the amount?
    Show the full solution

    Populations can track slow change by moving or adapting, but not change that outpaces those mechanisms

  6. Explain why rate rather than magnitude is the central biological problem.
    Show the full solution

    Species have survived large climate changes before, because those changes took place over thousands of years and populations could shift their ranges gradually or accumulate adaptations through selection. Both responses have speed limits: migration depends on suitable connected habitat existing nearby, and adaptation depends on suitable variation already being present and on generation time. A change of the same magnitude occurring in a century outruns both, so the same temperature difference is survivable slowly and lethal quickly. Migration and adaptation both have speed limits that fast change exceeds

  7. Explain why phenology shifts can damage a species even if temperature itself is tolerable.
    Show the full solution

    Species depend on being synchronized with others, and different species cue their timing from different signals. If insects emerge earlier because they respond to temperature, while a migratory bird arrives on a schedule cued by day length, the birds may reach the breeding grounds after the peak food supply has passed. The temperature harms nobody directly; the mismatch between two timings does, and the same applies to plants and their pollinators. Species cue timing from different signals, so warming desynchronizes dependent pairs

  8. A species shifts its range upslope until it reaches a mountain top. Explain the outcome.
    Show the full solution

    Moving upslope tracks the cooler conditions the species is adapted to, and works while higher ground remains. At the summit there is nowhere further to go, so continued warming leaves the population in conditions outside its tolerance with no escape route. The available area also shrinks as it climbs, since mountains narrow toward the top, so the population declines and becomes more vulnerable to drift and chance events before the limit is even reached. The escape route ends and the available area shrinks, so the population is trapped

  9. Why does the argument for current warming rest on several independent measurements?
    Show the full solution

    Because any single measurement can be questioned on grounds of instrument error, station siting or the choice of period, and a single line of evidence leaves those objections open. Atmospheric composition, ocean heat content, sea level and ice extent are measured by unrelated methods with unrelated sources of error, so an alternative explanation would have to account for all of them separately. This is the convergence argument of lesson 10.7, and it is why naming several measurements is worth more than describing one. Unrelated methods with unrelated errors agreeing is far harder to explain away

  10. Set out how this course has taught you to evaluate a proposed environmental solution.
    Show the full solution

    Name the mechanism it relies on and check that it is real. Check the magnitude against the size of the problem, and the timescale against how fast the problem is developing. Ask which reservoir or cycle the change actually affects, since moving carbon within the fast cycle is not the same as removing it. Identify side effects on biodiversity, land use and the people involved. Then give a judgment that states what it sets aside, rather than an endorsement or a dismissal. Mechanism, magnitude, timescale, which cycle, side effects, then a judgment that names its limits

Unit 11 review · Speciation, Biodiversity and a Changing Planet

Ten questions across the whole unit

Questions 1 to 5 check that you hold the terms. Questions 6 to 10 require you to reason across the seven lessons.

  1. State the biological species concept, including the word that decides the horse and donkey case.
    Show the full solution

    Populations able to interbreed and produce fertile offspring; fertile is the decisive word

  2. What distinguishes prezygotic from postzygotic barriers?
    Show the full solution

    Whether a zygote is formed

  3. Give the three-step sequence of allopatric speciation.
    Show the full solution

    Geographic separation, independent divergence, then reproductive isolation

  4. Define genetic drift and say in which populations it is strongest.
    Show the full solution

    Change in allele frequency by chance rather than selection; strongest in small populations

  5. How is relatedness read from a phylogenetic tree?
    Show the full solution

    By how recent the shared node is, not by position along the top

  6. Explain why the awkward cases for the species concept support rather than undermine evolutionary theory.
    Show the full solution

    Separate creation of species would predict sharp unambiguous boundaries everywhere, and intermediate cases would be puzzling. Descent with gradual divergence predicts the opposite: populations separate slowly, so at any moment some pairs will be partway through the process and impossible to classify cleanly. Ring species, hybrids of varying fertility and populations that interbreed occasionally are exactly what a continuous process should produce. Gradual divergence predicts intermediate cases; separate creation would not

  7. Explain why gene flow must stop before two populations can diverge.
    Show the full solution

    Divergence requires each population to accumulate its own genetic changes, and interbreeding distributes any new allele arising in one into the other, so the two gene pools are effectively mixed each generation and differences are averaged out as fast as they appear. Even a low rate of exchange is enough to hold populations together, which is why some barrier to gene flow is the necessary first step in every route to speciation. Interbreeding redistributes new alleles, averaging out differences as they arise

  8. Explain why drift is stronger in small populations and why it cannot produce adaptation.
    Show the full solution

    Drift is a sampling effect, so its size depends on sample size: in a population of ten the gametes forming the next generation can easily be unrepresentative and frequencies swing sharply, while in ten thousand departures cancel out. Adaptation requires a consistent relationship between a characteristic and reproductive success, and drift has none, so it is as likely to raise a harmful allele as a useful one and has no direction at all. Small samples depart from expectation, and drift has no direction

  9. Explain why species richness alone is a poor measure of biodiversity.
    Show the full solution

    It treats a species represented by one individual exactly as one represented by thousands, so two sites with identical counts can be completely different in practice, one evenly balanced and the other effectively a monoculture in which the rare species cannot even reproduce. Richness also ignores genetic variation within species, so a count can look healthy while every population present is genetically uniform and unable to respond to change. It ignores evenness and genetic variation, so identical counts can describe very different communities

  10. A proposal offsets emissions by planting one fast-growing tree species. Evaluate it using the course.
    Show the full solution

    The mechanism is real, since photosynthesis fixes atmospheric carbon into wood, but the carbon enters the fast cycle and returns when the trees die, decompose or burn, so storage lasts decades rather than the millions of years fossil carbon had been out of circulation. Absorption also stops once the forest matures while emissions continue. A single species planted at scale is a monoculture with biodiversity costs at all three levels and vulnerability to one disease. Mixed native species on degraded land, treated as a complement to emissions reduction rather than a substitute, would be defensible. A real but temporary fast-cycle sink with monoculture costs; it cannot substitute for mitigation

Reference · always available

How to write the three kinds of response this course asks for

The writing tasks in this course are not essays in the English sense. Each one has a structure that a scientific reader expects, and most of the marks are for producing that structure rather than for style. This sheet sets out all three, with what each part is and what it is not. Keep it open while you write; it is meant to be looked at, not memorized.

The one rule behind all three. A scientific claim is only as good as the link between the evidence and the conclusion, and that link is something you supply from what you know about biology. Data never speak for themselves. Nearly every response that loses marks has plenty of numbers and no reasoning connecting them to the claim.

Claim, evidence, reasoning

The frame for every "argument from evidence" task. Write the four parts in this order and label them in your head, even when the finished paragraph reads as continuous prose.

PartWhat it has to do
ClaimOne sentence that answers the question asked. It takes a position that someone could disagree with.
EvidenceSpecific figures from the data, with units, selected because they bear on the claim. Include the comparison that makes them mean something.
ReasoningThe biological principle that explains why that evidence supports that claim. This is the part you bring; it is not in the data.
LimitsWhat these data cannot establish, and what further evidence would settle it. Stating this strengthens an argument rather than weakening it.

The same four parts, done well and done badly

Done wellDone badly, and why
"The decline at Pond D is very unlikely to be part of a regional trend."Claim. "The table shows the frog numbers changed." That describes the data instead of answering the question, so there is nothing to argue about.
"Pond D fell from 260 to 52, a loss of 80 percent, while the other three lost 4 to 6 percent."Evidence. "Pond D dropped a lot more than the others." No figures, no units, and no comparison the reader can check.
"Amphibians absorb water and dissolved substances directly across a permeable skin at every life stage, so a waterborne chemical reaches them more directly than it would an animal with a waterproof covering."Reasoning. "So the fungicide must have caused the decline." That restates the claim rather than explaining it. A restatement is the single most common way to lose these marks.
"This is observational, and the fungicide is confounded with the orchard, which also differs in drainage and bankside vegetation."Limits. Saying nothing. A response that presents an observational association as settled has overclaimed, and a reader will mark it down even when the claim happens to be right.

Why reasoning is the part that goes missing

The claim and the evidence are both on the page in front of you: one is the question turned into a sentence, the other is read off the table. Reasoning is the only part that has to come out of what you have learned, so under time pressure it is the part that quietly disappears. A response with a claim and figures and nothing between them has shown that two things occur together and then asserted that one caused the other. Naming a mechanism is what converts an association into an argument. If you cannot name one, that is worth knowing before you commit to the claim.

Designing an investigation

A different task with a different structure. The question is not "what do these data show?" but "what would have to be true of an investigation for its data to show anything at all?"

PartWhat it has to do
Independent variableThe one thing you change, with the levels you will set it to actually stated.
Dependent variableWhat you measure, in units, by a method that genuinely produces a number.
Controlled variablesNamed individually and held constant. "All other variables were controlled" earns nothing; naming the four that matter here earns the mark.
ReplicationHow many trials, and how the results will be summarized across them.
Hypothesis with a mechanismA prediction and the biological reason you expect it. A prediction alone is a guess.
Falsifying resultStated before any data exist. A design that no possible result could contradict is not an investigation.

Writing a scientific explanation

Here the answer is already known and the task is to make the causal chain visible. The marks are for the transitions, not for the endpoints.

PartWhat it has to do
The phenomenonState plainly what is being explained, before explaining it.
The scalesMove through them in order and make every transition explicit: molecule, cell, tissue, organism, population. Skipping a level is where explanations fail.
A mechanism at each stepSay how each level produces the next, not merely that it does.
Figures where they existUse the numbers from the sources rather than referring to them.
No teleologyNothing in biology happens in order to achieve an outcome. See the note below.
Teleology, and why it costs marks. Writing that an allele is maintained "because it is useful", or that a structure developed "in order to" do something, reverses the causation. Variation arises without regard to what would be useful, and the variants that happen to leave more offspring become more common. The difference is not a quibble about wording: the teleological version implies a process that does not exist, and a reader cannot tell whether you have the mechanism right. Write "the allele became more common because carriers survived malaria more often", not "the allele developed to protect against malaria."

Using sources and data

Quote figures, do not gesture at them"Source 2 shows 28 percent" rather than "Source 2 shows a high rate".
Give units every timeA number without units is not evidence.
Say where a figure came fromName the source or the row, so a reader can check it.
Use every source you are givenA source left untouched is usually the one carrying the evidence against your first instinct.
Ruling a candidate out is evidenceShowing that dissolved oxygen cannot account for the difference is part of the argument, not a digression.

The four errors this course names

Reasoning that restates the claim"so the fungicide caused it" is the claim again, not a reason for it.
Evidence without figures or units"much higher" is an impression; 14 micrograms per liter against zero is evidence.
Correlation presented as causeLegitimate to argue for a cause, never legitimate to leave the distinction unstated.
Teleological language"In order to", "so that the organism can", "because it needed to".

A response that has all four CER parts, names one mechanism, and states one honest limitation will score well even if it is short. A response that reviews the entire table and reaches a confident conclusion with no mechanism will not, however long it is. Length is not what is being measured.

Argument from evidence 1 · 45 minutes

Using the data below, make and defend a claim about why the frog population at Pond D has declined.

Directions

Structure: claim, evidence, reasoning, limits. You have forty-five minutes. Open with a claim that answers the question in one sentence. Support it with figures from the table, with units, including the comparison that gives them meaning. Then give the reasoning: the biological principle that explains why that evidence supports that claim, which is the part that has to come from you rather than from the data. Close with what these data cannot establish and what further evidence would settle it. The writing reference sets out all four parts and stays free.

The data

Source: a constructed dataset. The figures are invented so the arithmetic is checkable and are not taken from any survey.

PondFrogs 2019Frogs 2024Dissolved oxygen (mg/L)Fungicide in water (µg/L)Adjacent land
A2402258.10woodland
B3102988.40woodland
C1801717.90pasture
D260527.814orchard

All four ponds are within six kilometers of one another and were surveyed by the same method in both years.

Your response
What a reader looks for
  • Claim. A claim that answers the question asked rather than describing the table.
  • Evidence. Specific figures with units, chosen because they bear on the claim.
  • Evidence. Use of the three comparison ponds as a control, and a reason for trusting them.
  • Reasoning. A named biological mechanism, not a restatement of the numbers.
  • Limits. An explicit statement of what the data cannot establish, and what would settle it.
Show a top-score response

The decline at Pond D is very unlikely to be part of a general regional trend, and the data point toward the fungicide as the most plausible cause, although they cannot establish it.

Start with the comparison. Ponds A, B and C fell from 240 to 225, from 310 to 298 and from 180 to 171 over the same five years. Those are losses of 15, 12 and 9 frogs, which are around 6, 4 and 5 percent of each starting population. Pond D fell from 260 to 52, a loss of 208 frogs, which is 80 percent. The three unaffected ponds are doing something quite different from Pond D, and the gap is not marginal: Pond D's proportional loss is more than fifteen times the largest of the others.

This comparison is what makes the argument possible. The three ponds function as a control group in the sense of lesson 1.2, because they were surveyed by the same method in the same two years and lie within six kilometers, so they share weather, climate and most regional pressures. If a widespread cause such as a dry decade or a regional disease were responsible, it should have affected all four. Something specific to Pond D is doing the work.

Now isolate what is specific to Pond D. Two things differ: it is the only pond with fungicide in the water, at 14 micrograms per liter against zero elsewhere, and it is the only pond adjacent to an orchard. Dissolved oxygen is not the difference. Pond D reads 7.8 mg/L against 7.9, 8.1 and 8.4 at the others, a spread of 0.6 mg/L across all four, and Pond C at 7.9 is almost identical to Pond D while losing only 5 percent of its frogs. Oxygen can therefore be set aside, and ruling out a candidate is part of the argument rather than a digression.

The reasoning that connects the fungicide to the decline has to name a mechanism. Amphibians absorb water and dissolved substances directly across a permeable skin, which is how they exchange gases, so they are exposed to waterborne chemicals far more directly than animals with a waterproof covering. Their eggs and larvae develop in the water with no protective shell at all. A fungicide is designed to disrupt a biological process in fungi, and the molecules it targets are often present in modified form in other groups, so effects on non-target organisms are plausible rather than far-fetched. A substance entering the water from an adjacent orchard, in a pond whose inhabitants absorb across their skin at every life stage, is a mechanism that fits both the location and the size of the effect.

That is as far as the data can carry the claim, and the limits need stating plainly. This is an observational study, not an experiment: nothing was changed on purpose, no variable was controlled, and the fungicide is confounded with the orchard. Orchards differ from woodland and pasture in more than their chemicals. They are managed, which may mean altered drainage, removal of bankside vegetation, different shade, or machinery disturbance. Any of those could reduce breeding success, and the data cannot separate them from the fungicide because every one of them arrived with the orchard. The correlation between fungicide presence and frog decline is based on a single affected pond, which is a sample of one in the sense of lesson 1.3, and one site cannot show how often the association holds.

There is also no information on what happened in between. The two survey years are five years apart, so the decline may have been gradual, or it may have occurred in a single season, and those point toward different causes. A sudden collapse would suggest a discrete event such as a spraying episode, while a steady fall would suggest chronic exposure or a slower change in the habitat.

Three things would strengthen or refute the claim. First, more ponds: if a dozen orchard-adjacent ponds with measurable fungicide showed similar declines while a dozen orchard-adjacent ponds without it did not, the fungicide would be separated from the orchard itself. Second, a controlled laboratory experiment exposing frog larvae to 14 micrograms per liter alongside an otherwise identical control, measuring survival and development, which would test the mechanism directly at a realistic concentration. Third, annual rather than five-yearly counts, to establish the shape of the decline.

The defensible conclusion is therefore narrower than the obvious one. The data establish that Pond D's decline is real, severe and not regional, and they identify the fungicide as the leading candidate while ruling out dissolved oxygen. They do not establish causation, because a single site cannot distinguish the chemical from everything else an orchard brings with it.

Check it against the frame. A claim that answers the question, then evidence with figures and units together with the comparison that gives them meaning, then reasoning that names a mechanism rather than repeating the claim, then the limits and what would settle them. If you can point to all four parts in your own response, it is structured correctly however different the wording.

Argument from evidence 2 · 45 minutes

Using the data below, argue whether natural selection occurred in this finch population, using the four conditions from lesson 10.1.

Directions

Structure: claim, evidence, reasoning, limits. You have forty-five minutes. Your claim is whether natural selection occurred. Take each of the four conditions in turn as your evidence, quoting figures, and give the reasoning that links each condition to the outcome rather than restating it. State explicitly which condition the data do not demonstrate and why that matters.

The data

Source: a constructed dataset. The figures are invented so the arithmetic is checkable, though the pattern resembles findings from real long-term studies of island finches.

MeasurementBefore droughtAfter drought
Birds in population1,400210
Mean beak depth (mm)9.410.6
Range of beak depth (mm)7.2 to 11.88.9 to 11.9
Small soft seeds availableabundantalmost none
Large hard seeds availablecommoncommon

Offspring of the surviving birds had a mean beak depth of 10.3 mm, measured the following year.

Your response
What a reader looks for
  • Claim. A position on whether natural selection occurred, not a summary of the measurements.
  • Evidence. All four conditions addressed in turn, each against specific figures.
  • Evidence. Correct use of the offspring measurement as the evidence for heritability.
  • Reasoning. The mechanism connecting beak depth to survival on hard seeds.
  • Limits. Recognition that drift is an alternative explanation given the crash, and a reason for preferring selection.
  • Limits. No teleological language anywhere in the response.
Show a top-score response

The data support natural selection on beak depth, and three of the four conditions are demonstrated directly by the figures. The fourth is supported by the offspring measurement, which is the single most important number in the table.

Variation is established before anything else happens. Before the drought, beak depth ranged from 7.2 to 11.8 mm around a mean of 9.4 mm, a spread of 4.6 mm. The population was not uniform, and this matters for the sequence of the argument: variation was present before the drought arrived, not produced by it. Nothing about a dry season can reach into a bird and deepen its beak, and no bird changed during its life. The drought changed which of the existing variants survived.

Overproduction and differential survival can be taken together, because the figures show both. The population fell from 1,400 to 210, so 1,190 birds died, which is 85 percent. That the population was far larger than the drought conditions could support is exactly the overproduction Darwin's argument requires, and it is the carrying capacity idea of lesson 3.3 appearing in a real case.

The survival was not random with respect to beak depth. The mean rose from 9.4 to 10.6 mm, an increase of 1.2 mm, and the lower end of the range moved from 7.2 to 8.9 mm. Birds with the shallowest beaks are absent from the survivors. Had mortality been indiscriminate, the mean would have stayed near 9.4 and the range would have narrowed at both ends rather than only at the bottom. The upper limit barely moved, from 11.8 to 11.9, so the loss was concentrated entirely among shallow-beaked birds.

The mechanism connecting beak depth to survival is supplied by the seed data. Small soft seeds went from abundant to almost none, while large hard seeds remained common. A deeper beak generates greater force and can crack a hard seed that a shallow beak cannot open, so when the easy food disappeared the birds able to exploit the remaining supply could still feed. Shallow-beaked birds faced a food source they were unable to use and starved. This is the reasoning step, and without it the correlation between beak depth and survival would be unexplained.

Heritability is the condition the surviving-bird data cannot establish, and it is where a weaker answer stops. A shift in the mean of the survivors shows only that selection acted within one generation. If beak depth were determined entirely by diet or by conditions during growth, the survivors' offspring would revert toward the original population mean and nothing would have been inherited. The offspring measurement settles it: the next generation had a mean beak depth of 10.3 mm, close to their parents' 10.6 mm and clearly above the pre-drought 9.4 mm. The shift persisted into a generation that never experienced the drought, which is what heritable variation means. All four conditions therefore hold, and evolution by natural selection has occurred: the allele frequencies underlying beak depth have changed.

There is a serious alternative that has to be addressed. The population crashed to 210, and lesson 11.4 established that genetic drift is powerful in small populations, so a change in the mean could in principle reflect chance rather than selection. Two features of the data argue against drift as the main explanation. First, drift has no direction, so it would be as likely to lower the mean as raise it, and it would be unlikely to remove specifically the shallow end of the range while leaving the deep end untouched. Second, there is an independent reason to expect this particular direction: the food supply changed in a way that disadvantages shallow beaks. A predicted direction that then occurs is much stronger than an unexplained shift. Drift almost certainly contributed, since 85 percent mortality must have removed alleles by chance as well as by selection, but it does not account for the pattern.

Two limits are worth stating. The offspring mean of 10.3 mm is slightly below the parental 10.6 mm, which is consistent with beak depth being polygenic and influenced by environment as well as genes, so inheritance is partial rather than complete. And a single drought is a single event; whether the change persists depends on what follows, since a return of small soft seeds would favor shallower beaks again and could reverse the shift. Selection tracks current conditions and produces no permanent direction.

The conclusion is that all four conditions are met, with heritability resting specifically on the offspring measurement, and that natural selection is a better explanation than drift because the direction of change was predictable from the change in food supply.

Check it against the frame. A claim that answers the question, then evidence with figures and units together with the comparison that gives them meaning, then reasoning that names a mechanism rather than repeating the claim, then the limits and what would settle them. If you can point to all four parts in your own response, it is structured correctly however different the wording.

Investigation design 1 · 45 minutes

Design a controlled investigation into whether the wavelength of light affects the rate of photosynthesis in a water plant.

Directions

Structure: variables, method, hypothesis with mechanism, falsification. You have forty-five minutes. Name your independent variable with its levels, your dependent variable with units, and your controlled variables individually. Describe the method in enough detail that someone else could repeat it, state your hypothesis together with the mechanism behind it, and say what result would falsify it. A design that cannot fail is not a design.

Your response
What a reader looks for
  • Variables. One independent variable, with the levels stated.
  • Variables. A dependent variable that is genuinely measurable, with units.
  • Variables. Controlled variables named individually, with light intensity handled explicitly.
  • Method. Replication, and a statement of how the results will be summarized.
  • Falsification. A falsifying result stated before any data are collected.
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Question. Does the wavelength of light affect the rate of photosynthesis in pond weed?

Hypothesis with a mechanism. Red and blue light will produce a higher rate of photosynthesis than green light of the same intensity, because chlorophyll absorbs strongly in the red and blue regions of the spectrum and reflects or transmits green. Light that is not absorbed by a pigment cannot supply energy to the light-dependent reactions, so the rate should follow absorption rather than apparent brightness.

Independent variable. Wavelength of light, set at four levels using colored filters: red, blue, green, and clear as a comparison condition. Four levels rather than two, because two points cannot show the shape of a relationship.

Dependent variable. Rate of oxygen production, measured as the number of bubbles released from the cut stem per minute, counted over five minutes and divided by five. Counting bubbles is crude, so a better version collects the gas in an inverted measuring cylinder and records the volume in cubic centimeters per minute, which avoids the assumption that all bubbles are the same size.

Controlled variables, and why each matters.

Light intensity is the critical one and the place most designs fail. A colored filter removes some light, so a green filter and a red filter placed at the same distance from the same lamp do not deliver the same intensity. If intensity is not equalized the experiment has two variables and becomes uninterpretable, exactly the confound of lesson 1.2. I would measure the intensity reaching the plant with a light meter for each filter and adjust the lamp distance until all four readings match, recording the readings as part of the results.

Temperature must be held constant, because photosynthesis is enzyme-controlled and the rate rises with temperature up to an optimum. A lamp heats the water, so the specimen tube sits in a water bath of fixed temperature, with a heat shield of clear water between lamp and tube, and the temperature is checked at the start and end of each trial.

Carbon dioxide concentration must be constant and not limiting, since lesson 6.4 establishes that the rate is set by whichever factor is in shortest supply. I would use the same volume of the same sodium hydrogen carbonate solution for every trial, at a concentration high enough that carbon dioxide is not the constraint, otherwise all four filters could give the same rate and the experiment would show nothing.

Also controlled: the species of pond weed, the length and mass of the shoot, the time allowed to acclimatize before counting begins (five minutes), the volume of water, and the same freshly cut stem for the whole run.

Method. Cut a 6 cm shoot and place it inverted in a boiling tube of the carbonate solution in the water bath. Set the lamp at the distance determined for the first filter. Allow five minutes to acclimatize, then collect gas for five minutes and record the volume. Repeat with a fresh shoot of the same length. Do five shoots for each of the four filters, changing the filter and resetting the lamp distance between conditions, and randomize the order in which the filters are tested so that any drift in conditions across the session does not fall systematically on one color.

Replication and analysis. Five shoots per condition, twenty trials in total. For each filter I calculate the mean rate and the range, following lesson 1.3, and report both, because a difference between means is meaningless if the ranges overlap heavily. I would plot mean rate against filter color as a bar chart, since the four conditions are separate categories rather than a continuous scale, and a line joining them would imply intermediate wavelengths that were never tested.

What would falsify the hypothesis. If the mean rate under green light equals or exceeds the rates under red and blue, with non-overlapping ranges, the hypothesis is wrong. If all four conditions including clear give the same rate within the spread, then either wavelength does not matter or, more likely, something else is limiting and the experiment has failed to test its own question, which would send me back to check the carbon dioxide supply and the intensity matching.

Known weaknesses. Bubble counting is imprecise; filters transmit a band of wavelengths rather than a single one, so red and blue are not pure; cut shoots deteriorate over a session, which is why the order of conditions is randomized; and oxygen production slightly understates photosynthesis because the plant is respiring at the same time, consuming some of the oxygen it makes. That last point means every measured rate is a net rate, and the comparison between filters is still valid because respiration is similar in all four.

Check it against the frame. One independent variable with its levels, a dependent variable with units, controlled variables named individually, replication with a summary method, a hypothesis carrying its mechanism, and a falsifying result written down before any data exist. A design missing the last of those cannot be tested.

Investigation design 2 · 45 minutes

Design an investigation into whether a fertilizer causes algal growth in pond water, and explain how the limits of working at field scale change the conclusions available.

Directions

Structure: variables, method, hypothesis with mechanism, falsification, then the field comparison. You have forty-five minutes. Give a full laboratory design first, with every part the writing reference lists. Then explain what would have to change to test the question in a real pond, which controls become impossible, and how that affects the strength of the conclusion you could draw. The second part carries as much credit as the first.

Your response
What a reader looks for
  • Variables. A complete laboratory design with variables, replication and a falsifying result.
  • Method. A measurable proxy for algal growth, with its weakness acknowledged.
  • Method. A clear account of why a real pond cannot be controlled the same way.
  • Limits. Recognition that field work trades internal validity for realism.
  • Limits. An ethical or practical constraint identified, with its effect on the design.
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Question. Does adding a phosphate fertilizer increase the growth of algae in pond water?

Hypothesis with a mechanism. Adding phosphate increases algal growth, because phosphorus is required for DNA, RNA, ATP and phospholipid membranes, and lesson 4.4 establishes that phosphate is usually the limiting nutrient in fresh water. Relieving the limiting factor should allow the population to grow until something else limits it.

Laboratory design.

Independent variable: phosphate concentration, at five levels of 0, 0.5, 1.0, 2.0 and 4.0 milligrams per liter, made by diluting a stock solution. The zero flask is the comparison condition, showing what the water does untreated.

Dependent variable: algal density, measured as turbidity using a colorimeter and recorded in arbitrary absorbance units every two days for fourteen days. Turbidity is a proxy rather than a direct count: it responds to anything suspended in the water, so a flask clouded by bacteria or by disturbed sediment would read as algal growth. I would check the proxy by counting cells under a microscope on a hemocytometer for a sample of flasks at the start and end, and report both measures.

Controlled variables: the same pond water in every flask, drawn from one container on one day and mixed thoroughly so the starting algal community is identical; the same volume, 200 cm³; identical flasks; the same light intensity and photoperiod, achieved by placing all flasks at the same distance from the same lamp on a timer; the same temperature in a controlled room; and nitrate concentration, since if nitrate rather than phosphate is limiting, adding phosphate will change nothing and the result would be a false negative.

Replication: five flasks at each of the five concentrations, twenty five in total, with positions randomized and rotated every two days so that no concentration sits permanently in a brighter or warmer spot.

Analysis and falsification: plot mean absorbance against time for each concentration, and mean final absorbance against phosphate concentration, with the range shown. The hypothesis is falsified if final density at 4.0 mg/L does not exceed that at 0 mg/L, with non-overlapping ranges. A rise that then levels off at higher concentrations would support the hypothesis while indicating that phosphate has ceased to be limiting, which is a different and informative result.

Field scale: what changes.

Almost every control above becomes impossible. A real pond cannot be given a matched control, because no second pond is identical in depth, volume, shading, inflow, sediment, fish population or history, so comparing two ponds means comparing things that differ in dozens of ways at once. Light, temperature and rainfall vary daily and cannot be held constant. Water flows in and out, so an added nutrient is diluted and exported at a rate set by residence time, which lesson 4.1 shows can differ enormously between ponds. Grazing by zooplankton removes algae at a rate nobody has measured, so a bloom may be suppressed for reasons unrelated to nutrients. Replication in the laboratory sense is unavailable: twenty five ponds cannot be obtained, and each pond is a single unit, so a study of two ponds is effectively a sample of one in each condition.

The ethical and practical constraint. Deliberately fertilizing a real pond to cause a bloom risks the sequence of lesson 4.4: dead algae, bacterial decomposition, oxygen collapse, and the death of fish and invertebrates. That is real and possibly irreversible harm to a community for the sake of a measurement, and it may also be unlawful. The honest response is not to do it. Instead I would either enclose columns of water within the pond in transparent bags, so the treatment affects a confined volume and can be replicated, or use existing variation, surveying many ponds that already differ in phosphate because of surrounding land use.

How this changes the conclusion available. The laboratory experiment can support a causal claim, because one variable was changed deliberately while others were held constant, but it says nothing about whether the effect occurs at realistic concentrations in a pond with grazers, flow and sediment. The survey of existing ponds has realism and no control, so it can show only that phosphate concentration and algal density are associated, and land use may be driving both, as in the frog data of the first argument task. Neither approach alone is sufficient. The strongest position is the two together: a mechanism demonstrated under control, and a pattern consistent with it in the field. That is the same structure as the converging evidence of lesson 10.7, and it is the realistic answer to a question that cannot be settled in one study.

Check it against the frame. A complete laboratory design first, with variables, replication and a falsifying result, then an honest account of which of those controls survives the move to a real pond and which does not. Field work buys realism with internal validity, and saying so is part of the answer rather than an admission.

Scientific explanation 1 · 60 minutes

Explain how a change in a single DNA base produces an effect visible at the level of a whole population, using the sources below.

Directions

Structure: name the phenomenon, then move through the scales with a mechanism at each step. You have sixty minutes. Your explanation must pass explicitly through DNA base, protein, cell, organism and population, and every transition must say how one level produces the next rather than only that it does. Use both sources and quote their figures. Watch for teleological phrasing, which the writing reference explains.

Source 1: the molecular change

Source: a description prepared for this course from established findings, not a quotation.

The sickle cell allele differs from the usual allele of the beta-globin gene by a single base substitution. The change alters one codon, so one amino acid in the beta-globin protein chain is replaced by a different one. The substituted amino acid is non-polar where the original is polar, which allows hemoglobin molecules to associate with one another when oxygen concentration is low. The resulting fibers distort the red blood cell into a curved, rigid shape.

Source 2: allele frequency and malaria

Source: a constructed dataset. The figures are invented so the arithmetic is checkable, and the pattern reflects the association reported in regions where malaria is endemic.

RegionMalariaSickle allele frequencyHeterozygotes per 1,000
Lowland Aendemic0.12211
Lowland Bendemic0.10180
Highland Cabsent0.0120
Highland Dabsent0.0239
Your response
What a reader looks for
  • Scales. Every scale transition made explicit, from base to population.
  • Mechanism. Correct use of the codon and protein reasoning from unit 7.
  • Mechanism. The heterozygote advantage stated precisely, with all three genotypes considered.
  • Figures. Figures from Source 2 used, not merely referred to.
  • Teleology. The allele is not maintained because it is useful, and nothing is said to have developed in order to.
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This case connects the smallest unit of genetic information to the composition of an entire population, and every step in the chain is a mechanism established earlier in this course.

From base to protein. Source 1 describes a single base substitution in the beta-globin gene. Lesson 7.6 sets out why the consequence is limited: a substitution alters at most one codon, unlike an insertion or deletion, which shifts the reading frame and corrupts everything downstream. Here the altered codon specifies a different amino acid, so this is a missense mutation, and exactly one position in the beta-globin chain is changed out of well over a hundred.

From protein to cell. The single substitution matters because of which amino acid replaces which. Source 1 states that the new amino acid is non-polar where the original was polar, and lesson 5.5 established that non-polar regions avoid contact with water and tend to associate with one another. A non-polar patch on the surface of the hemoglobin molecule therefore lets molecules stick together when oxygen is low, forming fibers that distort the cell into a rigid curved shape. This is the transition lesson 6.2 predicts in general terms: a change in one amino acid changes a protein's shape, and shape determines behavior.

From cell to organism. The consequences depend on genotype, and all three must be considered. A homozygote for the sickle allele has no normal beta-globin at all, so a large proportion of cells distort. Rigid curved cells block small blood vessels, causing pain and tissue damage, and are destroyed faster than normal cells, causing anemia. A homozygote for the usual allele has no sickling and no protection. A heterozygote produces both forms of the protein, so sickling occurs only under unusual conditions and health is generally normal.

From organism to population. The heterozygote is the key to Source 2. The malaria parasite spends part of its life cycle inside red blood cells, and cells containing some sickle hemoglobin are more likely to distort and be removed when infected, which interrupts the parasite's cycle. A heterozygote in a malarial region is therefore more likely to survive childhood malaria than someone with two usual alleles, and is not seriously harmed by sickling, unlike someone with two sickle alleles.

What the figures show. In the two lowland regions where malaria is endemic, the sickle allele frequency is 0.12 and 0.10. In the two highland regions where malaria is absent, it is 0.01 and 0.02. The allele is roughly six to twelve times commoner where malaria is present. The heterozygote counts make the same point in people: 211 and 180 per thousand in the lowlands against 20 and 39 in the highlands, so roughly one person in five carries a copy where malaria is endemic against one in thirty or fifty where it is not. The comparison is what carries the argument, since either pair of regions alone would show nothing.

Why both alleles persist. Selection here does not push toward a single outcome, because each homozygote is at a disadvantage in a malarial region: one from sickle cell disease and the other from malaria, while the heterozygote is better off than either. The population therefore retains both alleles at intermediate frequency rather than losing one. This is why frequency settles around 0.10 to 0.12 rather than rising toward fixation, and it explains what would otherwise be a puzzle: how an allele that causes a serious disease in homozygotes can be common at all.

Why it is rare where malaria is absent. Remove the parasite and the heterozygote advantage disappears, since there is nothing to be protected from. The allele then carries only its cost, because homozygotes still develop the disease, so selection acts against it and its frequency stays low, as the highland figures show. The same allele is advantageous in one environment and disadvantageous in another, which is precisely Darwin's point in lesson 10.1 that a variation is profitable only in relation to particular circumstances.

Stating the causal order correctly. The mutation was not produced because malaria was present. Lesson 10.2 establishes that mutation is random with respect to need, and the base substitution will have occurred independently of the parasite, as it presumably has in populations where it never spread. What malaria changed was which carriers survived and reproduced. The allele is not maintained because it is useful; it is common because its carriers left more offspring, which is a statement about frequencies rather than about purposes.

Limits. These data are observational, so they show association rather than causation, and the lowland and highland regions differ in more than malaria, including altitude, temperature and possibly ancestry and migration history. Drift and founder effects, from lesson 11.4, could contribute to differences between regions. The reason the malarial explanation is nonetheless persuasive is that it is supported independently by a mechanism at the cellular level, by the pattern holding across many separate populations worldwide, and by the otherwise inexplicable persistence of a harmful allele. That is convergence of the kind lesson 10.7 describes, rather than one correlation.

Check it against the frame. The phenomenon named first, then every scale transition made explicit with a mechanism saying how one level produces the next, figures quoted rather than gestured at, and no language suggesting anything happened in order to achieve an outcome.

Scientific explanation 2 · 60 minutes

Explain how photosynthesis by early organisms changed Earth's atmosphere, and why that change made large active animals possible.

Directions

Structure: name the phenomenon, then move through the scales with a mechanism at each step. You have sixty minutes. Connect at least three scales: the biochemical reaction, the planetary reservoir, and the organisms that followed. Make every transition explicit, use both sources with their figures, and draw on units 4, 6 and 11.

Source 1: banded iron formations

Source: description prepared from United States Geological Survey material, a work of the US federal government.

Banded iron formations are sedimentary rocks consisting of alternating layers rich and poor in iron oxides. They formed in large quantities during a long interval of Earth's early history and then largely ceased to form. Their deposition requires dissolved iron in seawater and a supply of oxygen with which it can react, since the iron oxides are insoluble and settle out.

Source 2: energy yield with and without oxygen

Source: figures from unit 6 of this course, standard values for the yield of respiration per molecule of glucose.

ProcessATP per glucoseRequires oxygen?
Anaerobic respirationabout 2no
Aerobic respirationabout 30yes
Your response
What a reader looks for
  • Mechanism. The oxygen correctly traced to the splitting of water, not to carbon dioxide.
  • Mechanism. Banded iron formations explained as a sink that delayed atmospheric accumulation.
  • Figures. The energy argument used quantitatively, with the factor of fifteen.
  • Scales. An explicit link between ATP supply and body size or activity.
  • Teleology. Recognition that oxygen was a waste product and was toxic to existing life, rather than something produced for a purpose.
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The oxygen in the air is a waste product. It was released by organisms that had no use for it, it poisoned much of the life existing at the time, and it eventually made large active animals possible. Following it from a single reaction to a planetary reservoir to a body plan is the clearest example in this course of one mechanism operating at three scales.

The biochemical scale. Lesson 6.5 establishes where the oxygen comes from, and it is not where students usually assume. In the light-dependent reactions, water is split to supply hydrogen and electrons for making NADPH and driving ATP synthesis. The oxygen atoms left over are surplus to the plant's requirements and diffuse away. This was confirmed by isotope labeling: when water containing a heavier isotope of oxygen was supplied, the released gas carried the label, and when the carbon dioxide carried it instead, the released gas did not. The organisms that first did this were photosynthetic bacteria, and nothing about the process required or used the oxygen it produced.

Why the atmosphere did not change immediately. Source 1 explains the delay. The early oceans contained large quantities of dissolved iron, which is soluble in the absence of oxygen. Oxygen released by photosynthesis reacted with that iron to form insoluble iron oxides, which settled to the sea floor and built up as banded iron formations. For a long interval, essentially all the oxygen produced was consumed by this reaction, so it accumulated in the rock record rather than in the air. This is the reservoir and flux reasoning of lesson 4.1: a flux into a reservoir changes nothing while an equally large flux removes it. Only once the dissolved iron was largely exhausted could oxygen begin to accumulate in the atmosphere, and the fact that these formations largely ceased to form marks approximately when that happened. The rock is a record of a chemical sink being filled.

The consequence for existing life. Oxygen is chemically reactive and damages many biological molecules, so to organisms adapted to an atmosphere without it, it was a poison. A great deal of the life existing at the time would have been killed or confined to oxygen-free environments, where descendants of those lineages still live today in sediments, deep water and animal guts. It is worth stating plainly that the largest change ever made to the planet's chemistry by living things was a catastrophe for most of the organisms then alive, and that it was produced by organisms acting with no purpose beyond their own metabolism.

The energetic scale. Source 2 gives the reason oxygen mattered so much once organisms evolved to use it. Anaerobic respiration yields about 2 ATP per glucose, because it completes only glycolysis and stops. Aerobic respiration yields about 30, because oxygen acts as the final electron acceptor at the end of the electron transport chain, as lesson 6.6 sets out, and the chain produces the great majority of the ATP. That is a factor of about fifteen. A cell doing 300 ATP of work needs 10 glucose molecules aerobically and 150 anaerobically.

From energy yield to body size. This is the transition that has to be made explicit. A large, active animal has an enormous ATP demand: muscle contraction, nerve signaling, active transport across vast numbers of membranes and the maintenance of body temperature in some groups. Meeting that demand anaerobically would require fifteen times the food intake for the same work, which imposes a limit no amount of efficient foraging can overcome, since the animal would spend more energy obtaining food than the food supplied. Aerobic respiration lifted the ceiling. It also matters for the arguments of unit 2: with only about 2 ATP per glucose, transfer between trophic levels would be so poor that food chains supporting large predators could not exist at all.

The order of events. The causal sequence must be stated carefully to avoid the error of lesson 10.2. Organisms did not evolve aerobic respiration because oxygen would be useful, and cyanobacteria did not release oxygen in order to make animals possible. Photosynthesis released oxygen as waste for hundreds of millions of years. Once it accumulated, any lineage that happened to possess variation allowing it to tolerate and then exploit oxygen had a very large advantage, and those lineages left more descendants. The opportunity came first; the adaptation followed. Mitochondria, the organelles that carry out aerobic respiration, are themselves thought to descend from free-living bacteria taken up by another cell, which is why their existence connects the whole story back to lesson 5.2.

Closing the loop. The result is the coupled pair of lesson 6.7 and the carbon cycle of lesson 4.2. Photosynthesis removes carbon dioxide and releases oxygen; aerobic respiration consumes oxygen and returns carbon dioxide. The atmosphere that supports animal life is maintained by the continuing activity of photosynthetic organisms, and it is not a fixed backdrop but a product of biology. That is also why the changes traced in unit 4 are significant: an atmosphere built by living things can be altered by them, and it has been before.

Check it against the frame. The phenomenon named first, then every scale transition made explicit with a mechanism saying how one level produces the next, figures quoted rather than gestured at, and no language suggesting anything happened in order to achieve an outcome.

Unit recap

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